Topic 9 - Redox Reactions
Whilst acid/base reactions were proton (H+) reactions, redox reactions are electron reactions.
Oxidation – loss of electrons
Reduction – gain of electrons
Oxidation States/Numbers
Oxidation state – charge of an atom if all of its bonds were hypothetical
The number of electrons an atom has gained or lost by forming bonds
Also involves covalent bonds
Notation: symbol first, and then number
Example: +2, -3
Oxidation number – given in roman numerals
This is important as the oxidation state of an atom has a significant impact on its chemistry.
★ Oxidation = hypothetical charge which applies to both ionic and covalent bonds
Charge = actual charge which only applies to ionic bonds ★
Calculating Oxidation States
Oxidation state of an element = 0
Oxidation states of a compound sum to zero, and of an ion sum to the ion’s charge
The more electronegative atom in an ion assumes a negative oxidation state
The less electronegative atom in an ion assumes a positive oxidation state
Some rules of thumb: //need to know this//
Element | Oxidation State | Notes |
Fluorine | -1 | Fluorine is always -1 |
Oxygen | -2 | Except in peroxides = -1 Except in F2O = +2 |
Chlorine | -1 | Except with Oxygen or Fluorine = +1 |
Gr I Metal | +1 | Always |
Gr II Metal | +2 | Always |
Hydrogen | +1 | Except in metal hydrides = -1 |
Oxidation States & Names
Oxidation states are used in the names of compounds
‘-ate’ → an element is in a positive oxidation state (usually because it bonded with oxygen)
‘-ide’ → an element is in a negative oxidation state
Oxidation state of transition metals is given in Roman numerals.
Examples:
FeCl → iron (II) chloride
Iron (II) means that Fe = +2 (ox. state)
Chloride means that Cl = neg. ox. state
FeCl3 → iron (III) chloride
Iron (III) means that Fe = +3 (ox. state)
KClO3 → potassium chlorate
Chlorate means that Cl = pos. ox. state
Redox Reactions
Whenever an oxidation occurs, a reduction also occurs, hence, redox.
Examples:
Zn (s) + Cu2+ (aq) → Cu (s) + Zn2+ (aq)
0 +2 0 +2
Zn = oxidised; it loses 2 electrons
Zn is the reducing agent because it reduces the copper
Cu = reduced; it gains 2 electrons
Cu2+ is the oxidising agent because it oxidises the zinc
Disproportionation * not part of syllabus *
When some atoms of an element are oxidised and others are reduced.
Example:
2H2O2 →2H2O + O2
+1 -1 +1 -2 0
The oxygen ending in the H2O gained an e- and is reduced
The oxygen ending in the O2 lost an e- and is oxidised
Activity Series of Metals
The activity series of metals shows which metals can reduce other metals. The metals at the top of the series can reduce the metals below it, in other words, they oxidise the easiest. //can be found in the data booklet//
Redox & Reactivity
Redox behaviour is closely linked to reactivity
The most reactive metals = best reducing agents
The most reactive nonmetals = best oxidising agents
The least reactive elements = bad at both, oxidation and reduction
Reactivity & Displacement Reactions
Reactive metals = better reducing agents than unreactive metals
As such, a reactive metal can displace less reactive metals from their compounds
Example:
Zn (s) + CuSO4 (aq) → ZnSO4 (aq) + Cu (s)
Zn (s) + Cu2+ (aq) → Zn2+ (aq) + Cu (s)
As a good reducing agent, the zinc reduces the Cu2+, causing it to gain 2 electrons
Half equations/reactions
Show changes to individual species in redox reactions
Example:
Fe2O3 + 2Al → 2Fe + Al2O3
Fe3+ + 3e- → Fe ←reduction
Al → Al3+ + 3e- ← oxidation
//can be found in the data booklet//
Balancing Redox Reactions
Step #1: Write the skeletons of the oxidation and reduction half-reactions
Step #2: Balance all elements other than H and O
Step #3: Balance oxygen atoms by adding H2O molecules where needed
Step #4: Balance hydrogen atoms by adding H+ ions where needed
Step #5: Balance the charge by e-
Step #6: If the # of e- lost in the oxidation half-reaction is not equal to the # of e- gained in the reduction half-reaction, multiple one or both of the half-reactions to make the # of e- gained equal to the # of e- lost
Step #7: Add the 2 half-reactions: electrons always cancel out; if the same formulas are found on opposite sides, cancel them; if they are on the same side, add them
Step #8: Check that the atoms and charges are balanced
Example: Cr2O72- (aq) + HNO2 (aq) → Cr3+ (aq) + NO3-
Cr2O72- → Cr3+
HNO2 → NO3-
Cr2O72- → 2Cr3+
HNO2 → NO3-
Cr2O72- → 2Cr3+ + 7H2O
HNO2 + H2O → NO3-
Cr2O72- + 14H+→ 2Cr3+ + 7H2O
HNO2 + H2O → NO3- + 3H+
Cr2O72- + 14H+ + 6e- → 2Cr3+ + 7H2O
HNO2 + H2O → NO3- + 3H+ + 2e-
Cr2O72- + 14H+ + 6e- → 2Cr3+ + 7H2O
3(HNO2 + H2O → NO3- + 3H+ + 2e-)
Cr2O72- + 14H+ + 3HNO2 + 3H2O → 2Cr3+ + 7H2O + 3NO3- + 9H+
Cr2O72- + 5H+ + 3HNO2 + 3H2O → 2Cr3+ + 4H2O + 3NO3-
Redox Titration
Redox titrations are done the same way as an acid-base titration.
CaVan=CbVbn n = molar ratio
Example:
5Fe2+ + MnO4- + 8H+ → 5Fe3+ + Mn2+ + 4H2O
V: 25.0 20.0
C: _____ 0.050
∴ C25.05=0.05020.01
C = 0.200 mol dm-3
Connection between O2 and Organic Matter
Organic substances need O2 to break down. When the organic substance is in water, O2 comes from the supply of dissolved oxygen in the water. There is only a limited amount of dissolved O2 as water is polar and O2 is nonpolar. If the organic material uses O2, then the aquatic life that is dependent on it [dissolved O2] suffocate.
Winkler Method
Used to measure the amount of dissolved O2 in water
High concentration = little to no pollution
Biochemical oxygen demand – amount of O2 required to oxidise organic matter in water samples at a definite temperature over a period of 5 days
Measured in ppm (parts per million)
Measures degree of organic pollution in water sample
Voltaic Cells
Forces each half of the reaction to take place in a separate container with the electrons moving through a circuit to get from one side to the next
exothermic reaction; energy is lost as electrical energy
Usually involves metals, but does not have to
Example: reaction of Mg and Cu2+ ions:
Mg (s) + Cu2+ → Mg2+ (aq) + Cu (s)
The magnesium reduces the copper ions as it is more reactive
Energy is released as heat
//need to know how to draw//
CROA → cathode = reduction; anode = oxidation
Cations go towards the cathode → reduction ∴ maintain charge
Anions go towards the anodes → oxidation ∴ balance out charges
★not 100% efficient → Mg loses ability to become Mg2+★
Voltaic cell notation – anode II cathode; solids on the exterior, ions on the interior
★always use K+ and NO3- for the salt bridge★
Electron flow – anode to cathode
Key Parts of a Voltaic Cell
Anode:
electrode/half-cell where oxidation happens
Contains the more reactive metal
Negative electrode →produces electrons
Cathode:
electrode/half-cell where reduction happens
Contains the least reactive metal
Positive electrode → accepts electrons
Salt bridge:
Contains a neutral salt; example: KNO3
Made of a tube of jelly or a filter paper soaked in the salt solution
Ions diffuse in and out to balance the charge and complete the circuit
Voltmeter:
Measures the difference in potential between half-cells
Could be replaced by other circuitry to do useful work
★ over time, anode mass decreases (it dissolves) ★
★ over time, cathode mass increases (it grows) ★
Electrolytic Cells
Opposite of a voltaic cell
Uses electricity to provide the energy for an endothermic reaction
Cathode and anode determined by reactivity of the metal
Current (anode to cathode) is carried by moving ions:
Cations (+) move to the cathode (negative electrode)
Anode (-) move to the anode (positive electrode)
Ionic compounds must be either molten or dissolved in a solution, so that the ions can be able to move
Anode forms a gas and the cathode forms a precipitate
Example: electrolysis of lithium chloride
Li+ (l) + Cl- (l) → Li (s) + ½ Cl2 (g)
//need to know how to draw//
Whilst acid/base reactions were proton (H+) reactions, redox reactions are electron reactions.
Oxidation – loss of electrons
Reduction – gain of electrons
Oxidation States/Numbers
Oxidation state – charge of an atom if all of its bonds were hypothetical
The number of electrons an atom has gained or lost by forming bonds
Also involves covalent bonds
Notation: symbol first, and then number
Example: +2, -3
Oxidation number – given in roman numerals
This is important as the oxidation state of an atom has a significant impact on its chemistry.
★ Oxidation = hypothetical charge which applies to both ionic and covalent bonds
Charge = actual charge which only applies to ionic bonds ★
Calculating Oxidation States
Oxidation state of an element = 0
Oxidation states of a compound sum to zero, and of an ion sum to the ion’s charge
The more electronegative atom in an ion assumes a negative oxidation state
The less electronegative atom in an ion assumes a positive oxidation state
Some rules of thumb: //need to know this//
Element | Oxidation State | Notes |
Fluorine | -1 | Fluorine is always -1 |
Oxygen | -2 | Except in peroxides = -1 Except in F2O = +2 |
Chlorine | -1 | Except with Oxygen or Fluorine = +1 |
Gr I Metal | +1 | Always |
Gr II Metal | +2 | Always |
Hydrogen | +1 | Except in metal hydrides = -1 |
Oxidation States & Names
Oxidation states are used in the names of compounds
‘-ate’ → an element is in a positive oxidation state (usually because it bonded with oxygen)
‘-ide’ → an element is in a negative oxidation state
Oxidation state of transition metals is given in Roman numerals.
Examples:
FeCl → iron (II) chloride
Iron (II) means that Fe = +2 (ox. state)
Chloride means that Cl = neg. ox. state
FeCl3 → iron (III) chloride
Iron (III) means that Fe = +3 (ox. state)
KClO3 → potassium chlorate
Chlorate means that Cl = pos. ox. state
Redox Reactions
Whenever an oxidation occurs, a reduction also occurs, hence, redox.
Examples:
Zn (s) + Cu2+ (aq) → Cu (s) + Zn2+ (aq)
0 +2 0 +2
Zn = oxidised; it loses 2 electrons
Zn is the reducing agent because it reduces the copper
Cu = reduced; it gains 2 electrons
Cu2+ is the oxidising agent because it oxidises the zinc
Disproportionation * not part of syllabus *
When some atoms of an element are oxidised and others are reduced.
Example:
2H2O2 →2H2O + O2
+1 -1 +1 -2 0
The oxygen ending in the H2O gained an e- and is reduced
The oxygen ending in the O2 lost an e- and is oxidised
Activity Series of Metals
The activity series of metals shows which metals can reduce other metals. The metals at the top of the series can reduce the metals below it, in other words, they oxidise the easiest. //can be found in the data booklet//
Redox & Reactivity
Redox behaviour is closely linked to reactivity
The most reactive metals = best reducing agents
The most reactive nonmetals = best oxidising agents
The least reactive elements = bad at both, oxidation and reduction
Reactivity & Displacement Reactions
Reactive metals = better reducing agents than unreactive metals
As such, a reactive metal can displace less reactive metals from their compounds
Example:
Zn (s) + CuSO4 (aq) → ZnSO4 (aq) + Cu (s)
Zn (s) + Cu2+ (aq) → Zn2+ (aq) + Cu (s)
As a good reducing agent, the zinc reduces the Cu2+, causing it to gain 2 electrons
Half equations/reactions
Show changes to individual species in redox reactions
Example:
Fe2O3 + 2Al → 2Fe + Al2O3
Fe3+ + 3e- → Fe ←reduction
Al → Al3+ + 3e- ← oxidation
//can be found in the data booklet//
Balancing Redox Reactions
Step #1: Write the skeletons of the oxidation and reduction half-reactions
Step #2: Balance all elements other than H and O
Step #3: Balance oxygen atoms by adding H2O molecules where needed
Step #4: Balance hydrogen atoms by adding H+ ions where needed
Step #5: Balance the charge by e-
Step #6: If the # of e- lost in the oxidation half-reaction is not equal to the # of e- gained in the reduction half-reaction, multiple one or both of the half-reactions to make the # of e- gained equal to the # of e- lost
Step #7: Add the 2 half-reactions: electrons always cancel out; if the same formulas are found on opposite sides, cancel them; if they are on the same side, add them
Step #8: Check that the atoms and charges are balanced
Example: Cr2O72- (aq) + HNO2 (aq) → Cr3+ (aq) + NO3-
Cr2O72- → Cr3+
HNO2 → NO3-
Cr2O72- → 2Cr3+
HNO2 → NO3-
Cr2O72- → 2Cr3+ + 7H2O
HNO2 + H2O → NO3-
Cr2O72- + 14H+→ 2Cr3+ + 7H2O
HNO2 + H2O → NO3- + 3H+
Cr2O72- + 14H+ + 6e- → 2Cr3+ + 7H2O
HNO2 + H2O → NO3- + 3H+ + 2e-
Cr2O72- + 14H+ + 6e- → 2Cr3+ + 7H2O
3(HNO2 + H2O → NO3- + 3H+ + 2e-)
Cr2O72- + 14H+ + 3HNO2 + 3H2O → 2Cr3+ + 7H2O + 3NO3- + 9H+
Cr2O72- + 5H+ + 3HNO2 + 3H2O → 2Cr3+ + 4H2O + 3NO3-
Redox Titration
Redox titrations are done the same way as an acid-base titration.
CaVan=CbVbn n = molar ratio
Example:
5Fe2+ + MnO4- + 8H+ → 5Fe3+ + Mn2+ + 4H2O
V: 25.0 20.0
C: _____ 0.050
∴ C25.05=0.05020.01
C = 0.200 mol dm-3
Connection between O2 and Organic Matter
Organic substances need O2 to break down. When the organic substance is in water, O2 comes from the supply of dissolved oxygen in the water. There is only a limited amount of dissolved O2 as water is polar and O2 is nonpolar. If the organic material uses O2, then the aquatic life that is dependent on it [dissolved O2] suffocate.
Winkler Method
Used to measure the amount of dissolved O2 in water
High concentration = little to no pollution
Biochemical oxygen demand – amount of O2 required to oxidise organic matter in water samples at a definite temperature over a period of 5 days
Measured in ppm (parts per million)
Measures degree of organic pollution in water sample
Voltaic Cells
Forces each half of the reaction to take place in a separate container with the electrons moving through a circuit to get from one side to the next
exothermic reaction; energy is lost as electrical energy
Usually involves metals, but does not have to
Example: reaction of Mg and Cu2+ ions:
Mg (s) + Cu2+ → Mg2+ (aq) + Cu (s)
The magnesium reduces the copper ions as it is more reactive
Energy is released as heat
//need to know how to draw//
CROA → cathode = reduction; anode = oxidation
Cations go towards the cathode → reduction ∴ maintain charge
Anions go towards the anodes → oxidation ∴ balance out charges
★not 100% efficient → Mg loses ability to become Mg2+★
Voltaic cell notation – anode II cathode; solids on the exterior, ions on the interior
★always use K+ and NO3- for the salt bridge★
Electron flow – anode to cathode
Key Parts of a Voltaic Cell
Anode:
electrode/half-cell where oxidation happens
Contains the more reactive metal
Negative electrode →produces electrons
Cathode:
electrode/half-cell where reduction happens
Contains the least reactive metal
Positive electrode → accepts electrons
Salt bridge:
Contains a neutral salt; example: KNO3
Made of a tube of jelly or a filter paper soaked in the salt solution
Ions diffuse in and out to balance the charge and complete the circuit
Voltmeter:
Measures the difference in potential between half-cells
Could be replaced by other circuitry to do useful work
★ over time, anode mass decreases (it dissolves) ★
★ over time, cathode mass increases (it grows) ★
Electrolytic Cells
Opposite of a voltaic cell
Uses electricity to provide the energy for an endothermic reaction
Cathode and anode determined by reactivity of the metal
Current (anode to cathode) is carried by moving ions:
Cations (+) move to the cathode (negative electrode)
Anode (-) move to the anode (positive electrode)
Ionic compounds must be either molten or dissolved in a solution, so that the ions can be able to move
Anode forms a gas and the cathode forms a precipitate
Example: electrolysis of lithium chloride
Li+ (l) + Cl- (l) → Li (s) + ½ Cl2 (g)
//need to know how to draw//