Discuss the P-v, T-v, and P-T property diagrams and P-v-T surfaces of pure substances.
Evaluate thermodynamic properties of pure substances from property tables.
Pure Substances
Definition: A pure substance is any material with a fixed chemical composition throughout.
Examples:
Homogeneous mixtures like air (a mixture of various gases) are considered pure substances.
Phases of a Pure Substance
States of Matter: Three primary phases of a pure substance are:
Solid
Liquid
Gas
Phase Diagrams
p-v-T Surface:
Displays the relationship between pressure (P), specific volume (v), and temperature (T) for a pure substance.
Different states of matter are visible in the diagrams:
Solid and Liquid
Liquid and Vapor
Solid and Vapor
Triple State (where all three phases coexist)
Critical State: Is a unique phase where properties of the liquid and gas merge, seen at the critical temperature.
Property Diagrams Explained
T-v Diagram:
Illustrates temperature (T) vs. specific volume (v).
States such as saturated liquid and saturated vapor are indicated along with heat addition.
P-v Diagram:
Shows how pressure (P) relates to specific volume (v).
Contains regions for:
Saturated Liquid
Saturated Vapor
Superheated vapor
Thermodynamic Properties and Fluid Tables
Fluid property tables provide essential data for evaluating properties of pure substances:
Specific Volume (v)
Internal Energy (u)
Enthalpy (h)
Entropy (s)
Example Problems
Example A:
A reservoir holds 10 kg of saturated vapor water at 80 °C. Find the pressure and tank volume using fluid property tables.
Example B:
Saturated water vapor (m = 1 kg) is condensed at 44 kPa. Determine the volume change and energy transferred.
Saturated Liquid-Vapor Mixture
Volume Relationships:
Total Volume: V = Vf + Vg where (Vf) is the volume of the saturated liquid and (Vg) is the volume of the saturated vapor.
The quality (x), defined as the ratio of the mass of vapor to the total mass, can be calculated as: x = \frac{m_g}{m}
The specific volume can be calculated as: v = Vf + x(vg - v_f)
Example Calculation
Example: For 2 kg of refrigerant 134a in a 100-L tank at $P = 200$ kPa, determine temperature, quality, enthalpy, and vapor volume.
Summary of Property Determination
For thermodynamic analysis:
Identify which two independent properties are known. These could include pressure (P), temperature (T), specific volume (v), internal energy (u), enthalpy (h), entropy (s), or quality (x).
Depending on the known properties, follow the appropriate tables and calculations to find other desired properties.