Properties of Pure Substances - ABE 210 Lecture 3
Objectives
- Introduce the concept of a pure substance.
- Illustrate the phase-change processes.
- Discuss the P-v, T-v, and P-T property diagrams and P-v-T surfaces of pure substances.
- Evaluate thermodynamic properties of pure substances from property tables.
Pure Substances
- Definition: A pure substance is any material with a fixed chemical composition throughout.
- Examples:
- Homogeneous mixtures like air (a mixture of various gases) are considered pure substances.
Phases of a Pure Substance
- States of Matter: Three primary phases of a pure substance are:
- Solid
- Liquid
- Gas
Phase Diagrams
- p-v-T Surface:
- Displays the relationship between pressure (P), specific volume (v), and temperature (T) for a pure substance.
- Different states of matter are visible in the diagrams:
- Solid and Liquid
- Liquid and Vapor
- Solid and Vapor
- Triple State (where all three phases coexist)
- Critical State: Is a unique phase where properties of the liquid and gas merge, seen at the critical temperature.
Property Diagrams Explained
T-v Diagram:
- Illustrates temperature (T) vs. specific volume (v).
- States such as saturated liquid and saturated vapor are indicated along with heat addition.
P-v Diagram:
- Shows how pressure (P) relates to specific volume (v).
- Contains regions for:
- Saturated Liquid
- Saturated Vapor
- Superheated vapor
Thermodynamic Properties and Fluid Tables
- Fluid property tables provide essential data for evaluating properties of pure substances:
- Specific Volume (v)
- Internal Energy (u)
- Enthalpy (h)
- Entropy (s)
Example Problems
Example A:
- A reservoir holds 10 kg of saturated vapor water at 80 °C. Find the pressure and tank volume using fluid property tables.
Example B:
- Saturated water vapor (m = 1 kg) is condensed at 44 kPa. Determine the volume change and energy transferred.
Saturated Liquid-Vapor Mixture
- Volume Relationships:
- Total Volume: V = Vf + Vg where (Vf) is the volume of the saturated liquid and (Vg) is the volume of the saturated vapor.
- The quality (x), defined as the ratio of the mass of vapor to the total mass, can be calculated as: x = \frac{m_g}{m}
- The specific volume can be calculated as: v = Vf + x(vg - v_f)
Example Calculation
- Example: For 2 kg of refrigerant 134a in a 100-L tank at $P = 200$ kPa, determine temperature, quality, enthalpy, and vapor volume.
Summary of Property Determination
- For thermodynamic analysis:
- Identify which two independent properties are known. These could include pressure (P), temperature (T), specific volume (v), internal energy (u), enthalpy (h), entropy (s), or quality (x).
- Depending on the known properties, follow the appropriate tables and calculations to find other desired properties.