Ideal Gas Law & Maxwell-Boltzmann Distribution (Lecture Notes)

Ideal Gas Law and Related Concepts

  • Start from empirical gas laws: Boyle's, Charles's, and Avogadro's laws lead to a relationship where volume and pressure are connected to the number of moles and temperature: PV ∝ nT.
    • To turn the proportionality into an equality, introduce a constant: PV=nRT.PV = nRT.
    • Here, R is the ideal gas constant, determined experimentally; its value depends on the chosen units for P, V, and T. Examples:
    • In SI units: R=8.314 Jmol1K1R \,=\, 8.314\ \mathrm{J\,mol^{-1}\,K^{-1}}
    • In L·atm units: R=0.082057 Latmmol1K1R \,=\, 0.082057\ \mathrm{L\,atm\,mol^{-1}\,K^{-1}}
    • Boltzmann constant kB relates microscopic and macroscopic scales: k</em>B=1.38×1023 JK1.k</em>B = 1.38 \times 10^{-23}\ \mathrm{J\,K^{-1}}. The macroscopic constant R is related to kB by R=N</em>AkB.R = N</em>A k_B.
  • Standard pressure conventions and molar quantities
    • The standard pressure convention: a circle drawn on a variable in diagrams often indicates 1 bar of pressure (standard pressure for the context).
    • Molar volume: Vm=VnV_m = \frac{V}{n} (volume per mole).
    • Molar enthalpy and molar entropy: H<em>m=Hn,S</em>m=Sn.H<em>m = \frac{H}{n},\quad S</em>m = \frac{S}{n}.
  • Standard states: STP vs SATP
    • STP (older standard): T=0C=273.15 K,P=1 atm.T = 0^{\circ}\mathrm{C} = 273.15\ \mathrm{K},\quad P = 1\ \mathrm{atm}.
    • SATP (more common nowadays): T=25C=298.15 K,P=1 atm.T = 25^{\circ}\mathrm{C} = 298.15\ \mathrm{K},\quad P = 1\ \mathrm{atm}.
    • Molar volumes at these conditions:
    • At STP: Vm22.414 Lmol1.V_m \approx 22.414\ \mathrm{L\,mol^{-1}}.
    • At SATP: Vm24.465 Lmol1.V_m \approx 24.465\ \mathrm{L\,mol^{-1}}.
  • Gas mixtures and Dalton’s law (partial pressures)
    • In a container with multiple ideal gases, the total pressure is the sum of the individual (partial) pressures:
    • Partial pressure of component j: P<em>j=n</em>jRTV.P<em>j = \frac{n</em>j RT}{V}. (Ideal gas law applied to each component.)
    • Total moles: n=<em>jn</em>j.n = \sum<em>j n</em>j. (moles add up in the mixture)
    • Mole fractions: x<em>j=n</em>jn,<em>jx</em>j=1.x<em>j = \frac{n</em>j}{n},\quad \sum<em>j x</em>j = 1.
    • Total pressure: P=<em>jP</em>j.P = \sum<em>j P</em>j. (Dalton’s law of partial pressures)
    • Equivalently, P<em>j=x</em>jP.P<em>j = x</em>j P.
  • Consistency checks for mixtures
    • Sum of mole fractions equals one: <em>jx</em>j=1.\sum<em>j x</em>j = 1.
    • Sum of partial pressures equals total pressure: P=<em>jP</em>j.P = \sum<em>j P</em>j.
  • Conceptual picture: ideal gas as kinetic theory toy model
    • Assumptions for the ideal gas model (molecules):
    • Point particles with mass, in ceaseless random motion, obeying classical mechanics (momentum, kinetic energy).
    • Collisions are elastic; there are no intermolecular potential energies that affect the motion in the ideal gas approximation.
    • The total pressure arises from momentum transfer of many molecules colliding with container walls.
    • In real gases, interactions (London dispersion, dipole-dipole, hydrogen bonding) introduce potential energy and deviations from ideal behavior.
    • The mixture example: each gas contributes to total pressure; the total pressure is the sum of the contributions from each gas if the ideal gas assumptions hold.
  • From macroscopic to microscopic view: a preview of the Maxwell–Boltzmann framework
    • The macroscopic quantities we measure (P, T) are connected to microscopic molecular speeds, masses, and collisions with container walls.
    • The goal is to derive an equation of state from kinetic theory by describing the speed distribution of molecules and relating it to pressure.
    • Outline of the pathway: speed -> momentum -> force -> pressure.
  • Maxwell–Boltzmann distribution of speeds (topic 1b)
    • Intuition: molecules have a distribution of speeds; some slow, some fast, with most around a most probable speed depending on temperature.
    • Define a probability density for speeds: the area under the curve between v1 and v2 gives the probability of finding a molecule with speed in that range.
    • Boltzmann distribution of energy (foundation): for energy E, the probability density is proportional to eE/(k<em>BT).e^{-E/(k<em>B T)}. For kinetic energy, E=12mv2,E = \tfrac{1}{2} m v^2, so the energy distribution is proportional to emv22k</em>BT.e^{-\frac{m v^2}{2 k</em>B T}}.
    • Step 1: distribution for a single velocity component (e.g., along x) is Gaussian
    • f(v<em>x)=m2πk</em>BT  emv<em>x22k</em>BT.f(v<em>x) = \sqrt{\frac{m}{2 \pi k</em>B T}}\; e^{-\frac{m v<em>x^2}{2 k</em>B T}}.
    • This distribution is normalized: <em>f(v</em>x)dvx=1.\int<em>{-\infty}^{\infty} f(v</em>x)\, dv_x = 1.
    • Step 2: combine x, y, z components to get a distribution in 3D velocity space
    • The joint distribution in vector form is
      • f(v)=(m2πk<em>BT)3/2em(v</em>x2+v<em>y2+v</em>z2)2kBT.f(\mathbf{v}) = \left(\frac{m}{2 \pi k<em>B T}\right)^{3/2} e^{-\frac{m(v</em>x^2 + v<em>y^2 + v</em>z^2)}{2 k_B T}}.
    • Transition from velocity components to speed: in velocity space, the volume element is d3v=dv<em>xdv</em>ydvz.d^3 v = dv<em>x \, dv</em>y \, dv_z. The transformation to a radial speed variable uses spherical coordinates, where the angular integration gives a factor of 4π and the radial part is 4π v^2 dv, i.e. d3v=4πv2dvd^3 v = 4\pi v^2 \, dv when integrating over directions and focusing on the speed magnitude v.
    • Step 3: obtain the speed distribution f(v) for v ≥ 0 by integrating over directions (angle integration) and normalizing
    • Resulting Maxwell–Boltzmann speed distribution:
      • f(v)=4π(m2πk<em>BT)3/2v2exp(mv22k</em>BT),v0.f(v) = 4\pi \left(\frac{m}{2 \pi k<em>B T}\right)^{3/2} v^2 \exp\left(-\frac{m v^2}{2 k</em>B T}\right), \quad v \ge 0.
    • Normalization condition: 0f(v)dv=1.\int_{0}^{\infty} f(v)\, dv = 1.
    • Notes about normalization and constants
    • The Gaussian form for each velocity component and the Jacobian for the transformation to speed lead to the prefactor (m2πkBT)3/2\left(\frac{m}{2 \pi k_B T}\right)^{3/2} and the extra factor of 4πv24\pi v^2 for the speed distribution.
    • The distribution for a single component is Gaussian: a bell-shaped curve with width set by temperature and mass; higher T broadens the distribution, higher m narrows it.
    • Physical interpretation and implications
    • The MB distribution provides the statistical distribution of molecule speeds in an ideal gas at temperature T.
    • It is consistent with the kinetic theory picture where pressure arises from repeated molecular collisions with container walls.
    • Most probable speed, mean speed, and root-mean-square speed depend on T and m, e.g. the rms speed scales as v<em>rms=v2=3k</em>BTm.v<em>{\mathrm{rms}} = \sqrt{\langle v^2 \rangle} = \sqrt{\frac{3 k</em>B T}{m}}. (Note: this exact relation is a standard MB result; the lecture notes indicate the direction of deriving such relationships.)
    • Practical caveats
    • The lecture describes the derivation as an “ugly derivation” and notes the expectation to finish it in a subsequent session.
    • The ultimate aim is to connect speeds to momentum, momentum to forces, and forces to pressure, culminating in a molecular-level understanding of the ideal gas law.
  • Quick takeaways and connections
    • The ideal gas law PV = nRT marries macroscopic observables with a microscopic constant R that encapsulates molecular properties (via NA and kB).
    • In mixtures, Dalton’s law allows us to decompose pressure into partial pressures with the relationships between nj, xj, and P.
    • The molar quantities (Vm, Hm, S_m) provide a per-mole perspective that often simplifies comparisons between gases.
    • The Maxwell–Boltzmann distribution provides the probabilistic backbone for predicting how molecular speeds contribute to macroscopic properties like pressure in kinetic theory.
  • Practical implications for exam preparation
    • Be able to derive and manipulate: PV=nRT,PV = nRT, P<em>j=n</em>jRTV,P=<em>jP</em>j,x<em>j=n</em>jn,<em>jx</em>j=1.P<em>j = \frac{n</em>j RT}{V},\quad P = \sum<em>j P</em>j,\quad x<em>j = \frac{n</em>j}{n},\quad \sum<em>j x</em>j = 1.
    • Recall standard states and molar quantities, including typical numerical values for R and kB and the relationships R=N</em>AkB.R = N</em>A k_B.
    • Understand the logic behind the Maxwell–Boltzmann distributions for both velocity components and speed, and the role of the normalization integrals in determining the prefactors.