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Geometry Unit 13

P - Perimeter of a Base

C - Circumference of a base

l = slant height

r = radiu

B = area of base

Surface Area Formulas

Cylinder - C(h) + 2B

Cone - B + πrl

Pyramid - B + 1/2 (P)(l)

Sphere - 4πr^2

Hemisphere (no lid) - 2πr^2

Hemisphere (lid) - 3πr^2

Volume Formulas

Volume of a prism/cylinder - V = Bh

Volume of a cone/pyramid - V = Bh/3

Volume of a sphere - V = 4/3πr^3

Volume of a Hemisphere - V = 2/3πr^3

Formula for Brahmagupta's:

(A + B + C + D)/2 = S

Area = √(S-A)(S-B)(S-C)(S-D)

Heron's formula:

A = √(s(s-a)(s-b)(s-c)), where s = (a+b+c)/2.

Formula for area of equilateral triangle:

(sqrt(3)/4) x (side length)^2

Kites & Rhombuses

have perpendicular diagonals. Therefore, we can use the following formula to find the area. Hint: may have to use Pythagorean theorem to find diagonals.

1/2(d1)(d2) Diagonal

Find the area of a SEGMENT:

  1. Find the area of the sector

  2. Find the area of the triangle (may have to find height)

  3. Subtract the area of triangle from the sector

Area of sector = (Percent of circle/360) x πr²

ZB

Geometry Unit 13

P - Perimeter of a Base

C - Circumference of a base

l = slant height

r = radiu

B = area of base

Surface Area Formulas

Cylinder - C(h) + 2B

Cone - B + πrl

Pyramid - B + 1/2 (P)(l)

Sphere - 4πr^2

Hemisphere (no lid) - 2πr^2

Hemisphere (lid) - 3πr^2

Volume Formulas

Volume of a prism/cylinder - V = Bh

Volume of a cone/pyramid - V = Bh/3

Volume of a sphere - V = 4/3πr^3

Volume of a Hemisphere - V = 2/3πr^3

Formula for Brahmagupta's:

(A + B + C + D)/2 = S

Area = √(S-A)(S-B)(S-C)(S-D)

Heron's formula:

A = √(s(s-a)(s-b)(s-c)), where s = (a+b+c)/2.

Formula for area of equilateral triangle:

(sqrt(3)/4) x (side length)^2

Kites & Rhombuses

have perpendicular diagonals. Therefore, we can use the following formula to find the area. Hint: may have to use Pythagorean theorem to find diagonals.

1/2(d1)(d2) Diagonal

Find the area of a SEGMENT:

  1. Find the area of the sector

  2. Find the area of the triangle (may have to find height)

  3. Subtract the area of triangle from the sector

Area of sector = (Percent of circle/360) x πr²

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