U7 AAC Test Review Notes
Energy Level Diagrams
- Be able to sketch endothermic and exothermic energy level diagrams.
- Label reactants, products, and change in enthalpy.
- If the diagram has a bump at the start, it represents an exothermic reaction.
- If the diagram has a bump at the end, it represents an endothermic reaction.
Heat vs. Temperature
- Explain the difference between heat and temperature.
- Heat is the measurement of thermal energy in a substance.
- Temperature is the measurement of the average kinetic energy.
Endothermic vs. Exothermic Reactions
- Based on a scenario, decide if a reaction is endothermic or exothermic.
- If a reaction releases cold (like ice), it is endothermic because heat is absorbed from the surroundings.
- If a reaction releases heat (like fire), it is exothermic because heat is released to the surroundings.
Thermochemical Equations
- Decide if a thermochemical equation is endothermic or exothermic.
- Write \Delta H separately, including the correct sign and units.
- If \Delta H is negative, the reaction is exothermic.
- If \Delta H is positive, the reaction is endothermic.
Specific Heat Calculations
- Calculate the specific heat of an unknown substance given the energy change, the temperature change, and the mass.
Units for Temperature and Heat
- Be able to tell the correct units for temperature and heat.
- Temperature: \degree C or K
- Heat: J or kJ
- Specific Heat: \frac{J}{g \cdot \degree C} (Joules per gram Celsius)
- \frac{kJ}{mol}: Kilojoules per mole
Energy Absorption or Release
- Calculate the amount of energy absorbed or released as an item heats or cools if you know its mass and temperature change.
Enthalpy Change Using Bond Energies
- Calculate an enthalpy change using bond energies.
- \Delta H = \sum{(\text{Bond energies of reactants})} - \sum{(\text{Bond energies of products})}
- Example:
- Reactants: \sum{\text{Bond energies of reactants}} = 4 \times 413 + 2 \times 498 = 2648 \, kJ
- Products: \sum{\text{Bond energies of products}} = 2 \times 799 + 4 \times 463 = 3450 \, kJ
- \Delta H = 2648 - 3450 = -802 \, kJ (Exothermic)
Enthalpy Change Using Heats of Formation
- Calculate an enthalpy change using heats of formation.
- \Delta H{rxn}^{\circ} = \sum{\Delta H{f}^{\circ} \text{(products)}} - \sum{\Delta H_{f}^{\circ} \text{(reactants)}}
Enthalpy Change Using Calorimetry
- Calculate an enthalpy change of a reaction using lab data from calorimetry.
- q = mc\Delta T
- Where:
- q is the heat absorbed or released
- m is the mass
- c is the specific heat capacity
- \Delta T is the change in temperature
- Where:
- Example:
- 100 mL HCl + 100 mL NaOH \rightarrow \Delta T = 6.8 \, \degree C
- Mass = 200 g (assuming density = 1 g/mL)
- q = 200 \times 4.18 \times 6.8 = 5684.8 \, J = 5.68 \, kJ
- Moles of reaction = 0.1 mol \rightarrow \Delta H = \frac{-5.68}{0.1} = -56.8 \, kJ/mol
- q = mc\Delta T
Enthalpy Change Using Hess’s Law
- Calculate an enthalpy change of a target reaction using Hess’s Law and the step reactions.
- Key Idea: Sum the \Delta H of step reactions to get the \Delta H of the target reaction.
- Example:
- Target: C + \frac{1}{2}O_2 \rightarrow CO
- Given:
- (1) C + O2 \rightarrow CO2 (\Delta H = -393.5 \, kJ)
- (2) CO + \frac{1}{2}O2 \rightarrow CO2 (\Delta H = -283.0 \, kJ)
- Reverse (2): CO2 \rightarrow CO + \frac{1}{2}O2 (\Delta H = +283.0 \, kJ)
- Add to (1): \Delta H = -393.5 + 283.0 = -110.5 \, kJ