Dalton: re-proposed the atom theory
Stated that mass is neither created or destroyed (law of conservation of mass discovered by Antoine Lavosier)
Compound always contains the same elements in the same proportions by mass (law of constant proportions or Proust’s Law)
When two elements can form multiple compounds the ratios of masses will remain constant for each compound (Law of multiple proportions by John Dalton)
JJ Thomson: discovered the electron through the cathode ray tube
found that atoms are not indivisible
Proposed the Plum Pudding model
Rutherford discovered the nucleus and the proton
used the gold foil experiment
Proposed planetary model
Bohr: proposed the Bohr model of the atom
Chadwick: discovered the neutron
Protons
in the nucleus
+1
has mass
Electron
in energy shells
-1
no mass
Neutron
in the nucleus
0 charge
has mass
Mass relationships in atoms:
Atomic number: the number of protons
Mass number: the number of protons + neutrons
How to find the number of electrons: number of protons = number of electrons
Isotopes: atoms with the same atomic number but different mass numbers
same number of protons
different number of neutrons
isotopes are named by their mass number
Alpha emission (\frac42He )
Makes you go two left on the periodic table and subtract 4 from the mass number
Beta emission (\frac{0}{-1}\beta )
too many neutrons (above the belt of stability)
makes you go right one
Positron emission (\frac{0}{+1}\beta )
too many protons (below the belt of stability)
makes you go left one
Gamma
Lowers from excited state
If it’s a percentage, assume it’s in grams and bring them all to the mol.
divide by the smallest mol
put together the equation
Percent composition = grams of \frac{element}{compound}\cdot100
Synthesis: A + X → AX
If it’s metal oxide + water → metal hydroxide
ex:Na_2O+H_2O\to2NaOH
Decomposition: AX → A + X
Metal chlorate → metal chloride + oxygen (O2)
Double Displacement: AX + BY → AY + BX
Single Displacement: AX + B → BX + A
Combustion: C_{x}H_{y}O_{z}+O_2\to CO_2+H_2O
All alkali metal compounds are soluble
ALl NH4+ compounds are soluble
All compounds containing NO3-, ClO3-, ClO4- are soluble
Most OH- compounds are insoluble. Alkali metal hydroxides and Ba(OH)2 are exceptions.
Most Cl-, Br-, and I- compounds are soluble. The exceptions are: Ag+, Hg2 2+, and Pb 2+
All CO3 2-, PO4 3-, and S 2- compounds are insoluble. Exceptions are alkali metal and ammonium compounds.
Most SO4 2- compounds are soluble. Exceptions are Ba 2+, Hg 2+, and Pb 2+
Soluble = aqueous
Insoluble = precipitate
KNOW HOW TO DO ELECTRON CONFIGURATIONS
Going across to the left and down the periodic table the larger the atom is
Positive ions are smaller than regular atoms
Negative ions are larger than regular atoms
Ionic Bonding: the transfer of electrons between a metal and non-metal
Covalent Bonding: the sharing of electrons between non-metals
As number of bonds increases, the bond length decreases
As number of bonds increases, the bond energy increases
Non polar covalent: the electronegativity difference is 0
Polar covalent: the electronegativity difference is < 2.0, and polarity is pulled towards the molecule with higher electronegativity
Ionic: the electronegativity difference is >= 2.0
Type | Geometry | Example | Bond angle |
AX2 | Linear | BeF2 | 180 |
AX3 | Trigonal Planar | BF3 | 120 |
AX4 | Tetrahedron | CH4 | 109.5 |
AX5 | Trigonal Bipyramid | PCl5 | 90 and 120 |
AX6 | Octahedron | SF6 | 90 |
AX3E | Trigonal Pyramid | NH3 | 107.3 |
AX2E2 | Bent | H2O or SO2 | 104.5 |
AXE3 | Linear | HCl | 180 |
Distorted tetrahedron/seesaw | SF4 | ||
T-shaped | ClF3 | ||
Linear | I3- | ||
Square Pyramid | BrF5 | ||
Square Planar | XeF4 |
Type | Hybrid | number of single bonds | Example | Shape |
AX2 | sp | 2 | BeCl2 | Linear |
AX3 | sp2 | 3 | BF3 | Trigonal Planar |
AX4 | sp3 | 4 | CH4 | Tetrahedron |
AX5 | sp3d | 5 | PCl5 | Trigonal bipyramid |
AX6 | sp3d2 | 6 | SF6 | Octahedron |
Boyle’s Law: P_1V_1=P_2V_2
Gay-Lussac’s Law: \frac{P_1}{T_1}=\frac{P_2}{T_2}
Charles Law: \frac{V_1}{T_1}=\frac{V_2}{T_2}
WHAT”S VAPOR PRESSURE AND DIFFUSION RATE????
Diffusion Rate: rate2/rate1 = sq root of M2/sq root of M1
Ion - Ion: strong force between + and - ions
Ion - Dipole: attractive force between ion and polar molecule
Dipole - Dipole: attractive force between polar molecules
Hydrogen bond: strong attractive force between hydrogen of one molecule and a highly electronegative atom of another
Strong type of dipole-dipole
Dispersion: short-range attractive force of all molecules
Strength of each force:
Dispersion < Dipole-Dipole < Hydrogen Bonding < Ion-Dipole < Ion-Ion
Viscosity: the resistance to flow.
the more cohesion of the molecules, the greater the viscosity
as temperature increases, viscosity decreases
Q=mc\Delta T is used to raise the temperature of something up to the point that it phase changes (temperature change)
m = grams
T = temperature in celsius
Q=ml is used for phase changing
Molarity = M = mol solute/L solution = mol/L
Molality = m = mol solute/kg solvent = mol/kg
Normality = N = # equivalents/L solution (often with acids and bases)
Multiply molarity by number of H+ for acids and molarity by number of OH- for bases to get normality
Soluble = if a solution can have a concentration of 0.1 M or more
Insoluble = if less than 0.1 M
Exothermic: creates bonds and releases energy
Endothermic: breaks bonds and absorbs energy
Enthalpy (\Delta H ): the amount of heat released or absorbed in a chemical reaction
Exothermic RXN: Enthalpy is negative
Endothermic RXN: Enthalpy is positive
How to calculate Enthalpy:
Measure with an experiment
Calculate using Heats of Formation data
Calculate using average bond energies
Calculate using Hess’ Law
\Delta H=Products-\operatorname{Re}ac\tan ts
see examples
\Delta H = reactants - products
see examples
Q=mc\Delta T is used to raise the temperature of something up to the point that it phase changes (temperature change)
m = grams
T = temperature in celsius
IMPORTANT: Any gas at STP: 1 mol = 22.4 L (STP = 273 K and 1 atm)
Entropy: a measure of randomness or disorder in a system
in nature everything proceeds toward maximum entropy and minimum enthalpy
Entropy increases going from solid → liquid → gas and is positive
it’s negative if it goes the opposite direction
Equation: \Delta S = products - reactants
Same thing as enthalpy with average bond energies but reversed
Favorable | Unfavorable | |
\Delta H | - | + |
\Delta S | + | - |
+ = increasing
- = decreasing
Gibb’s Free Energy (G):
If \Delta G is positive, it’s NOT spontaneous.
If \Delta G is negative, it IS spontaneous.
Equation: \Delta G=\Delta H-T\Delta S
T = temperature (K)
Convert entropy from J/K to kJ/K
Practice!!!
\Delta H | \Delta S | Spontaneous? |
+ (unfav) | + (fav) | Spontaneous when T\Delta S>\Delta H |
+ (unfav) | - (unfav) | never spontaneous |
- (fav) | + (fav) | always spontaneous |
- (fav) | - (unfav) | spontaneous when T\Delta S<\Delta H |
Rate of reaction equation: =k\left\lbrack A\right\rbrack^{x}\left\lbrack B\right\rbrack^{y}\left\lbrack C\right\rbrack^{z}
k = rate constant
x = order of reaction with respect to A
y = order of reaction with respect to B
x + y (adding all your exponents) = overall order of reaction
To find the order of a reaction:
\frac{rate_2}{rate_1}=\left\lbrack\frac{\left\lbrack A\right\rbrack_2}{\left\lbrack A\right\rbrack_1}\right\rbrack^{x}
and order (x) = 0, 1, 2, 3
1=2x → x = 0, etc etc
PRACTICE
Definition: When a system at equilibrium is disturbed by applying a stress, and new equilibrium position is attained to relieve the stress
Temperature’s effects on equilibrium:
Raising temperature (adding heat so endo):
equilibrium is shifted left to reactants
to relieve stress r must decrease and p must increase
Lowering temperature (removing heat so exo):
equilibrium is shifted to the right to products
To relieve stress, p must decrease and r must increase
Pressure’s effects on equilibrium
increasing pressure with 2NO_2\to N_2O_4
equilibrium is shifted to the side with fewer gas molecules
So it’s going towards N2O4 since there’s only one, while there’s two of NO2
Decreasing pressure:
Equilibrium is shifted to the side with a greater number of gas molecules
So it’s going towards NO2
Concentration’s effects on equilibrium:
SKIPPED COME BACK TO IT
PRACTICE QUESTIONS WITH ICE ON PG 16
Equilibrium Expression: How equilibrium is measured
Keq = Equilibrium constant (no units) is CONSTANT at a given temperature
Formula: K_{eq}=\frac{\left\lbrack products\right\rbrack}{\left\lbrack reactants\right\rbrack}
Kc (concentration): used for solutions (aq) or gases
Formula: K_{c}=\frac{\left\lbrack C\right\rbrack^{c}\cdot\left\lbrack D\right\rbrack^{d}}{\left\lbrack A\right\rbrack^{a}\cdot\left\lbrack B\right\rbrack^{b}} with the coefficients as the powers
Don’t include anything that’s not aqueous or a gas
Ex: Don’t put in H2O since it’s a liquid
Kp (Pressure): used for gases only
Formula: K_{p}=\frac{P_{C}^{c}\cdot P_{D}^{d}}{P_{A}^{a}\cdot P_{B}^{b}} with the coefficients as the powers
Don’t include anything that’s not a gas
Formula for Kp and Kc: K_{p}=K_{c}\left(RT\right)^{\Delta n}
\Delta n = # mol gas products - # mol gas reactants
T = Temp (K)
R = 0.0821
KNOW HOW TO DO ICE OR CALCULATE EQUILIBRIUM CONCENTRATIONS FROM INITIAL CONCENTRATIONS ON Pg 12
MAYBE COME BACK FOR REACTION QUOTIENT
In pure water, both [H+] and [OH-] = 1.0 × 10^-7 M
Formulas for calculating pH and pOH: pH = -log[H+], pOH = -log[OH-] (both are provided)
pH + pOH = 14 (also provided
Ka = acid dissociation constant
Formula: Kc = Ka = \frac{\left\lbrack products\right\rbrack}{\left\lbrack reactants]\right\rbrack} with coefficients as exponents
Kb = base - dissociation constant
Formula is the same thing as K, just make sure to exclude water since it’s not aqueous or a gas
PRACTICE THE QUESTIONS ON PAGES 4 and 5
IMPORTANT: K_{a}\cdot K_{b}=K_{w} (provided)
They’re acid-base conjugate pairs
As Ka increases, Kb decreases (inverse relationship)
The stronger the acid, the weaker it’s conjugate base