Chemical Thermodynamics and the 1st Law of Thermodynamics

Lesson 1: CHEMICAL THERMODYNAMICS AND THE 1ST LAW OF THERMODYNAMICS

General Concepts

  • Thermodynamics
    • Represents the movement of thermal energy within a system/universe.
    • Related to the forces due to heat.
    • Involves the flow of heat into or out of a system during physical or chemical transformations.
  • Chemical Thermodynamics
    • Studies the interrelation of heat and work with chemical reactions or states of matter within the confines of thermodynamic laws.
    • Essentially, it refers to the study of heat and work changes during chemical and physical processes.

Fundamental Definitions

Heat

  • Definition: Transfer of thermal energy between two bodies at different temperatures.
  • Note: Heat is NOT equal to thermal energy itself.
  • Representation: denoted by q.
  • Unit: Joules (J).

Work

  • Definition: Force applied to transfer energy between a system and its surroundings.
  • Essential for creating heat and transferring thermal energy.
  • Representation: denoted by w.
  • Unit: Joules (J).

Jargons / Terms in Chemical Thermodynamics

  • System:
    • Defined as the “focus” of study, any part of the universe we wish to monitor.
    • May be separated from the rest of the universe by a boundary (real or imaginary).
    • Example: A notebook.
  • Surroundings:
    • Everything external to the system.
    • Example: Air surrounding the notebook.
  • Universe:
    • Comprises the entirety of the system and surroundings.
    • Example: The classroom containing the notebook and air.

Overview of the Laws of Thermodynamics

  1. Zeroth Law:
    • If two systems are in equilibrium with a third system, they are in thermal equilibrium with each other.
  2. First Law:
    • The energy of the universe is constant.
    • Energy can be transformed but cannot be created or destroyed.
  3. Second Law:
    • The entropy of the universe increases in a spontaneous process and remains unchanged in an equilibrium process.
  4. Third Law:
    • At absolute zero, the entropy of a perfect crystal is zero.
    • The entropy of a perfect crystalline substance is zero at the absolute zero of temperature.

Thermodynamic Properties

Examples of Exothermic and Endothermic Reactions

Exothermic Reactions

  • Definition: Processes that release energy in the form of heat.
  • Examples:
    • Combustion of fuels (e.g., wood, petrol, LPG, candle burning).
    • Respiration in living organisms converting glucose to energy.
    • Neutralization between acids and bases (e.g., HCl and NaOH reaction).
    • Rusting of iron in moist air.
    • Explosion of fireworks releasing light, heat, and sound.
    • Thermite reaction producing molten iron.
    • Hand warmers generating heat via chemical reactions.
    • Dissolving certain salts like CaCl2 releases heat.

Endothermic Reactions

  • Definition: Processes that absorb energy in the form of heat.
  • Examples:
    • Melting ice into water requires heat input.
    • Sublimation of dry ice (solid CO2) turning directly into gas.
    • Photosynthesis in plants absorbing sunlight to produce oxygen and glucose.
    • Cooking or baking processes absorbing heat.
    • Ice packs used for injury cooling absorb heat from surroundings.

First Law of Thermodynamics

  • Energy Representation:
    egin{align} ext{Change in energy of a system} & : \, \Delta E{sys} = - \Delta E{sur} \, \end{align}
  • Energy Change Equation:
    • The change in energy of a system equals the heat absorbed (q) plus the work done on it (w):
      \Delta E = q + w
    • Rearranged:
      egin{align} w & = \Delta E - q \, \text{ and }\, \ q = \Delta E - w \, \end{align}

Numerical Examples

  1. Example 1
    • Given:
      • \Delta E = 49 J
      • w = -35 J
    • Solution:
      • \Delta E = -q + w
  2. Example 2
    • Given:
      • q = 47 J
      • \Delta E = 12 J
    • Solution:
      • Compute work: w = \Delta E - q = 12 J - 47 J = -35 J
  3. Example 3
    • Given:
      • q = 62 J
      • w = 474 J
    • Solution:
      • \Delta E = q + w = 62 J + 474 J = 536 J
  4. Example 4
    • Given:
      • \Delta E = -23 J
      • w = 45 J
    • Solution:
      • Compute heat: q = \Delta E - w = -23 J - 45 J = -68 J

Lesson 2: SPONTANEOUS AND NON-SPONTANEOUS PROCESS

Important Points

  1. Awareness of whether calculations pertain to the surroundings or system.
    • Example: If surroundings gain 67 J of heat, then q = -67 J for the system.
  2. Significant figures must be retained based on the least significant figures provided in the problem.

Definitions

  • Spontaneous Process:
    • A process requiring no energy input to occur; a physical or chemical change that happens by itself.
  • Non-Spontaneous Process:
    • A process requiring energy input to occur; one needing outside intervention.

Lesson 3: ENTROPY

Spontaneous & Non-Spontaneous Process Examples

Spontaneous Processes

  • Examples:
    • Rusting of metals (e.g., iron in moist air).
    • Decaying of radioisotopes.
    • Drying of leaves.
    • Fireworks.
    • Oxidation of gold.
    • Dissolving salt.

Non-Spontaneous Processes

  • Examples:
    • Separation of sugar from coffee grounds.
    • Charging of a battery.
    • Dissolution of sand in water.

Entropy

  • Definition: A measure of disorder within a system or energy that is unavailable to perform work.
  • Behavior:
    • Higher disorder of molecules indicates increased entropy; lower disorder indicates decreased entropy.
  • Notation:
    • Increasing entropy is denoted by +; decreasing entropy is denoted by -.

Law of Disorder

  1. Entropy of the gaseous phase is greater than that of the liquid or solid phases.
    • In summary: Solid < Liquid < Gas (in terms of increasing entropy).
  2. Chemical reactions that yield more product molecules than reactants lead to increased entropy.
  3. Entropy increases when substances divide; for instance, NaCl dissolving in water.
  4. Entropy tends to increase with rising temperatures; molecular speed increases, resulting in greater disorder.
    • Relationship: ↑ ext{ Temperature} = ↑ ext{ Entropy} = ↑ ext{ disorder}

Processes Accompanied by Entropy Change

  • Processes:
    • Melting: Solid → Liquid
    • Vaporization: Liquid → Vapor
    • Dissolving: Solute → Solution
    • Heating: System at T₁ → System at T₂ (where T₂ > T₁)

Example Conditions Illustrating Entropy

  • Examples:
    • Oxidation of nitrogen.
    • Sublimation of mothballs.
    • Reduction of silicon.
    • Lighting of candles.

Change in Entropy in the Universe

  • Entropy change in the universe (∆S{univ}) can be defined as the sum of entropy change in the system (∆S{sys}) and the surroundings (∆S{sur}): ∆S{univ} = ∆S{sys} + ∆S{sur}
    • If ∆S_{univ} > 0: Process is spontaneous.
    • If ∆S_{univ} = 0: Equilibrium is achieved.
    • If ∆S_{univ} < 0: Reverse process occurs spontaneously.

Standard Entropy of Reaction

  • Formula: ∆S° = ΣS°(products) - ΣS°(reactants)
    • In terms of coefficients, small letters are used as coefficients, while capital letters represent products and reactants.
    • Example:
      ∆S° = [cS°(C) + dS°(D)] - [aS°(A) + bS°(B)]

Lesson 4: GIBBS FREE ENERGY

Definitions

  • Gibbs Free Energy:
    • Introduced by American physicist Josiah Gibbs, also known as Free Energy.
    • Denoted by the letter G.
  • Formula: G = H - TS
    • Where:
    • G = free energy
    • H = enthalpy
    • T = temperature
    • S = entropy (quantities pertain to the system only).
  • Change in Free Energy (for constant temperature): ∆G = ∆H - T∆S
    • For chemical reactions:
      ∆G°_{rxn} = Σ∆H° - T∆S°
  • Spontaneity and Equilibrium Conditions:
    • ∆G < 0: Reaction is spontaneous.
    • ∆G > 0: Reaction is non-spontaneous.
    • ∆G = 0: System is at equilibrium.

Examples in Agriculture

  • Importance of the Gibbs free energy reaction between nitrogen gas and hydrogen gas to produce ammonia, essential for plant production.
  • Example Calculation:
    • For reaction N2(g) + 3H2(g) → 2NH_3(g), with given standard enthalpy and entropy values.
    • Resulting free-energy change indicates reaction spontaneity:
      • ∆H° = -92.6 kJ/mol
      • ∆S° = -0.1985 kJ/(K ext{ mol})
      • Computed ∆G = -33.45 kJ/mol denotes the reaction is spontaneous in the forward direction.