Intermolecular Forces, Gas Solubility, and Phase Equilibria Notes

Intermolecular vs. Intramolecular Forces

  • Intramolecular Forces:

    • Forces that operate directly between atoms within a single molecule.

    • Significantly stronger than intermolecular forces.

  • Intermolecular Forces:

    • Forces that exist between neighboring atoms or separate molecules (e.g., interaction between a water molecule H2OH_2O and another water molecule H2OH_2O).

    • Generally much weaker than intramolecular chemical bonds.

Types of Intermolecular Forces

  • Dispersion (London) Forces:

    • The weakest type of intermolecular force.

    • Arises due to rapid, instantaneous fluctuations in electron density within non-polar molecules.

    • This is the only type of intermolecular force present in purely non-polar molecules.

    • Polarizability:

      • Refers to how easily the electron cloud of a molecule, ion, or atom can be distorted by an external electric field or nearby particle.

      • Larger atoms and molecules possess greater polarizability than smaller ones.

      • Higher polarizability leads to stronger London dispersion forces, which results in higher boiling points.

    • Surface Area Influence:

      • An increased molecular surface area allows for increased intermolecular contact points.

      • Greater surface area produces stronger dispersion interactions compared to molecules of smaller surface area or more compact geometries.

  • Dipole-Induced Dipole Interactions:

    • Comparable in strength to London dispersion forces.

    • Occurs when a polar molecule approaches a non-polar molecule, inducing a temporary dipole moment in the non-polar species.

    • This force is responsible for enabling non-polar gases (such as oxygen gas, O2O_2) to dissolve in polar solvents (such as liquid water, H2OH_2O).

  • Dipole-Dipole Interactions:

    • Occurs exclusively between polar molecules containing permanent dipoles.

    • Note: Non-polar molecules can still contain polar covalent bonds if the molecular geometry cancels out the individual bond dipoles.

    • Dipole Moment (μ\mu): A quantitative value indicating the degree of polarity of a molecule.

Determining Molecular Polarity and Hydrogen Bonding

  • Determining Polarity:

    • Molecular polarity is determined by evaluating both the molecular geometry via Valence Shell Electron Pair Repulsion (VSEPR) theory and the individual bond polarities derived from electronegativity differences.

  • Hydrogen Bonding:

    • The strongest specific type of dipole-dipole interaction.

    • Requirements: Hydrogen must be directly covalently bonded to a highly electronegative atom—specifically Oxygen (O\text{O}), Nitrogen (N\text{N}), or Fluorine (F\text{F})—or actively interacting with one of these electronegative atoms in an adjacent molecule.

Comparative Boiling Points and Physical Properties

  • Relative Strength and Boiling Point Trends:

    • Propane (CH3−CH2−CH3CH_3-CH_2-CH_3): Possesses only London dispersion forces; exhibits the weakest intermolecular interactions and consequently the lowest boiling point (BPBP).

    • Methoxyethane (CH3−O−CH2−CH3CH_3-O-CH_2-CH_3): Possesses permanent dipole-dipole forces; exhibits an intermediate boiling point higher than non-polar alkanes.

    • Methanol (CH3OHCH_3OH): Features strong hydrogen bonding, resulting in a high boiling point.

    • Ethanol (CH3CH2OHCH_3CH_2OH): Contains hydrogen bonding as well as a larger chain with more total chemical bonds and surface area, requiring more thermal energy to disrupt interactions, thereby yielding a higher overall boiling point.

Ion-Dipole Interactions and General Consequences of Intermolecular Forces

  • Ion-Dipole Interactions:

    • Electrostatic attractions between an ionic species (charge Q1Q_1) and a polar molecule with a permanent dipole (charge Q2Q_2).

    • Extremely strong interactions, proportional to charge magnitude and dielectric/permittivity factors (Q1Q2E×K\frac{Q_1 Q_2}{E \times K}).

  • Consequences of Intermolecular Forces:

    • Melting Points and Boiling Points: Both increase systematically as the overall strength of intermolecular forces increases.

    • Solubility: Dictates the mechanism and extent to which substances dissolve in one another.

      • Caveat: The presence of hydrogen bonding capability does not automatically guarantee complete solubility in water.

    • Density: Influences relative density and buoyancy behaviors (whether a substance floats or sinks).

Gas Solubility and Henry's Law

  • Henry's Law:

    • Relates the equilibrium concentration of a dissolved gas in a liquid to the partial pressure of that gas above the liquid.

    • Equation:         Cgas=kH×PgasC_{\text{gas}} = k_H \times P_{\text{gas}}

      • CgasC_{\text{gas}}: Concentration of the dissolved gas (mol/L\text{mol/L}).

      • kHk_H: Henry's Law constant (mol/L/atm\text{mol/L/atm}).

      • PgasP_{\text{gas}}: Partial pressure of the gas above the solution (atm\text{atm}).

    • Key Relationships:

      • A larger kHk_H constant denotes a substantially more soluble gas.

      • Increasing the partial pressure PgasP_{\text{gas}} raises the frequency of gas-liquid molecular collisions, thereby increasing gas solubility.

    • Calculation Example:

      • Given kH=6.7×10−4 mol/L/atmk_H = 6.7 \times 10^{-4}\,\text{mol/L/atm}, Pgas=0.78 atmP_{\text{gas}} = 0.78\,\text{atm}, and molar mass M=28.014 g/molM = 28.014\,\text{g/mol}:

      • Molar concentration: Cgas=(6.7×10−4 mol/L/atm)×0.78 atm=5.226×10−4 mol/LC_{\text{gas}} = (6.7 \times 10^{-4}\,\text{mol/L/atm}) \times 0.78\,\text{atm} = 5.226 \times 10^{-4}\,\text{mol/L}.

      • Mass basis calculation yields 7.8×10−3 g7.8 \times 10^{-3}\,\text{g}.

Vapor Pressure of Pure Liquids

  • Vapor Pressure (VPVP):

    • The pressure exerted by a vapor in dynamic equilibrium with its liquid phase inside a closed system.

    • Temperature Dependence: Increasing temperature (↑T\uparrow T) results in a non-linear exponential increase in vapor pressure (↑VP\uparrow VP).

  • Boiling Point Relationship:

    • A liquid boils when its internal vapor pressure equals the surrounding ambient atmospheric pressure.

    • The boiling point of a liquid varies based on external pressure. For example, at the high altitude of Mount Everest where ambient atmospheric pressure is significantly lower, water boils at approximately 70 ∘C70\,^\circ\text{C}.

The Clausius-Clapeyron Equation and Quantitative Calculations

  • Standard Clausius-Clapeyron Form (for 1 mol1\,\text{mol} of liquid transitioning to vapor at normal boiling point):     ln⁡(Pvap)=(−ΔHvapR)×(1T)+C\ln(P_{\text{vap}}) = \left(-\frac{\Delta H_{\text{vap}}}{R}\right) \times \left(\frac{1}{T}\right) + C

    • Plotting ln⁡(Pvap)\ln(P_{\text{vap}}) versus 1T\frac{1}{T} yields a straight line where:

      • Slope=−ΔHvapR\text{Slope} = -\frac{\Delta H_{\text{vap}}}{R}

      • Y-intercept=C\text{Y-intercept} = C

  • Two-Point Clausius-Clapeyron Equation:     ln⁡(Pvap,1Pvap,2)=(ΔHvapR)×(1T2−1T1)\ln\left(\frac{P_{\text{vap},1}}{P_{\text{vap},2}}\right) = \left(\frac{\Delta H_{\text{vap}}}{R}\right) \times \left(\frac{1}{T_2} - \frac{1}{T_1}\right)     (Derived from ln⁡(x)−ln⁡(y)=ln⁡(xy)\ln(x) - \ln(y) = \ln\left(\frac{x}{y}\right))

  • Quantitative Problem Example:

    • Given Parameters:

      • ΔHvap=19.04 kJ/mol=19,040 J/mol\Delta H_{\text{vap}} = 19.04\,\text{kJ/mol} = 19,040\,\text{J/mol}

      • R=8.314 J/mol⋅KR = 8.314\,\text{J/mol} \cdot \text{K}

      • T1=−42 ∘C=231 KT_1 = -42\,^\circ\text{C} = 231\,\text{K}

      • T2=25 ∘C=298 KT_2 = 25\,^\circ\text{C} = 298\,\text{K}

      • Pvap,1=1 atmP_{\text{vap},1} = 1\,\text{atm} at T1=231 KT_1 = 231\,\text{K}

    • Execution:         ln⁡(1Pvap,2)=(19,040 J/mol8.314 J/mol⋅K)×(1298 K−1231 K)\ln\left(\frac{1}{P_{\text{vap},2}}\right) = \left(\frac{19,040\,\text{J/mol}}{8.314\,\text{J/mol} \cdot \text{K}}\right) \times \left(\frac{1}{298\,\text{K}} - \frac{1}{231\,\text{K}}\right)         ln⁡(1Pvap,2)=2290.112×(−0.0009733)=−2.228\ln\left(\frac{1}{P_{\text{vap},2}}\right) = 2290.112 \times (-0.0009733) = -2.228         1Pvap,2=e−2.228=0.108\frac{1}{P_{\text{vap},2}} = e^{-2.228} = 0.108         Pvap,2=9.3 atm at 25 ∘CP_{\text{vap},2} = 9.3\,\text{atm}\text{ at } 25\,^\circ\text{C}

Phase Diagrams and Unique Physical Properties of Water

  • Phase Diagram:

    • A graphical representation displaying the physical states of matter (solid, liquid, gas) and their phase transitions as a function of temperature (TT) and pressure (PP).

  • Unique Properties of Water (H2OH_2O):

    • Density Anomaly: Solid ice is less dense than liquid water, causing ice to float (noted as sinking in comparison to higher density anomalies); this unique density behavior is singular to H2OH_2O among common liquids.

    • Surface Tension: Directly proportional to intermolecular forces (↑intermolecular forces→↑surface tension\uparrow \text{intermolecular forces} \rightarrow \uparrow \text{surface tension}).

    • Viscosity: Defined as a liquid's internal resistance to flow or its degree of liquid thickness.

    • Meniscus: The characteristic curvature of a liquid column surface in a tube, displaying either a convex or concave (U\text{U}-shaped) profile depending on adhesive versus cohesive forces.