Integration and Antiderivatives

Integration: Finding Antiderivatives

Power Rule for Derivatives

The power rule states that the derivative of xnx^n is nxn1nx^{n-1}.

Power Rule for Integration

The power rule for finding antiderivatives is:

xndx=xn+1n+1+C\int x^n dx = \frac{x^{n+1}}{n+1} + C

Where:

  • nn is a constant exponent.
  • CC is the constant of integration.

Examples

Example 1: Antiderivative of 3x23x^2
  1. Add 1 to the exponent: 2+1=32 + 1 = 3. The expression becomes 3x33x^3.
  2. Divide by the new exponent: 3x33=x3\frac{3x^3}{3} = x^3.
  3. Add the constant of integration: x3+Cx^3 + C.
Example 2: Antiderivative of x4x^4

x4dx=x4+14+1+C=x55+C=15x5+C\int x^4 dx = \frac{x^{4+1}}{4+1} + C = \frac{x^5}{5} + C = \frac{1}{5}x^5 + C

Example 3: Antiderivative of x2x^2

x2dx=x2+12+1+C=x33+C\int x^2 dx = \frac{x^{2+1}}{2+1} + C = \frac{x^3}{3} + C

Example 4: Antiderivative of x7x^7

x7dx=x7+17+1+C=x88+C\int x^7 dx = \frac{x^{7+1}}{7+1} + C = \frac{x^8}{8} + C

Example 5: Antiderivative of xx

xdx=x1+11+1+C=x22+C\int x dx = \frac{x^{1+1}}{1+1} + C = \frac{x^2}{2} + C

Antiderivative with Fractions

Example 1: Antiderivative of x4\frac{x}{4}x4dx=14xdx=14x22+C=18x2+C\int \frac{x}{4} dx = \frac{1}{4} \int x dx = \frac{1}{4} \cdot \frac{x^2}{2} + C = \frac{1}{8}x^2 + C
Example 2: Antiderivative of 8x38x^3

8x3dx=8x3dx=8x3+13+1+C=8x44+C=2x4+C\int 8x^3 dx = 8 \int x^3 dx = 8 \cdot \frac{x^{3+1}}{3+1} + C = 8 \cdot \frac{x^4}{4} + C = 2x^4 + C

Antiderivative of a Constant

To find the antiderivative of a constant, add the variable of integration to the constant:

4dx=4x+C\int 4 dx = 4x + C
5dy=5y+C\int 5 dy = 5y + C

Explanation

We can rewrite 4 as 4x04x^0, because any number to the power of 0 is 1, so 41=44 \cdot 1 = 4.

Then, following the power rule, we have 4x0+10+1=4x11=4x\frac{4x^{0+1}}{0+1} = \frac{4x^1}{1} = 4x

Example

7dz=7z+C\int -7 dz = -7z + C

Antiderivative of a Binomial

To find the antiderivative of a binomial, integrate each term separately:

(7x6)dx=7xdx6dx=7x226x+C\int (7x - 6) dx = \int 7x dx - \int 6 dx = \frac{7x^2}{2} - 6x + C

Antiderivative of a Trinomial

(6x2+4x7)dx=6x2dx+4xdx7dx=6x33+4x227x+C=2x3+2x27x+C\int (6x^2 + 4x - 7) dx = \int 6x^2 dx + \int 4x dx - \int 7 dx = \frac{6x^3}{3} + \frac{4x^2}{2} - 7x + C = 2x^3 + 2x^2 - 7x + C

Antiderivatives of Radical Functions

Example 1: Antiderivative of x\sqrt{x}
  1. Rewrite the radical as a rational exponent: x=x12\sqrt{x} = x^{\frac{1}{2}}.
  2. Apply the power rule:
    x12dx=x12+112+1+C=x3232+C=23x32+C\int x^{\frac{1}{2}} dx = \frac{x^{\frac{1}{2} + 1}}{\frac{1}{2} + 1} + C = \frac{x^{\frac{3}{2}}}{\frac{3}{2}} + C = \frac{2}{3} x^{\frac{3}{2}} + C
  3. Rewrite back in radical form: 23x3+C\frac{2}{3} \sqrt{x^3} + C
Example 2: Antiderivative of x43\sqrt[3]{x^4}
  1. Rewrite the radical as a rational exponent: x43=x43\sqrt[3]{x^4} = x^{\frac{4}{3}}.
  2. Apply the power rule:

x43dx=x43+143+1+C=x7373+C=37x73+C\int x^{\frac{4}{3}} dx = \frac{x^{\frac{4}{3} + 1}}{\frac{4}{3} + 1} + C = \frac{x^{\frac{7}{3}}}{\frac{7}{3}} + C = \frac{3}{7} x^{\frac{7}{3}} + C

  1. Rewrite back in radical form: 37x73+C\frac{3}{7} \sqrt[3]{x^7} + C
Example 3: Antiderivative of x74\sqrt[4]{x^7}
  1. Rewrite the radical as a rational exponent: x74=x74\sqrt[4]{x^7} = x^{\frac{7}{4}}.
  2. Apply the power rule:

x74dx=x74+174+1+C=x114114+C=411x114+C\int x^{\frac{7}{4}} dx = \frac{x^{\frac{7}{4} + 1}}{\frac{7}{4} + 1} + C = \frac{x^{\frac{11}{4}}}{\frac{11}{4}} + C = \frac{4}{11} x^{\frac{11}{4}} + C

  1. Rewrite back in radical form: 411x114+C\frac{4}{11} \sqrt[4]{x^{11}} + C

Integrals of Trigonometric Expressions

  • cos(x)dx=sin(x)+C\int \cos(x) dx = \sin(x) + C
  • sin(x)dx=cos(x)+C\int -\sin(x) dx = \cos(x) + C
  • sin(x)dx=cos(x)+C\int \sin(x) dx = -\cos(x) + C
  • sec2(x)dx=tan(x)+C\int \sec^2(x) dx = \tan(x) + C
  • csc2(x)dx=cot(x)+C\int -\csc^2(x) dx = \cot(x) + C
  • csc2(x)dx=cot(x)+C\int \csc^2(x) dx = -\cot(x) + C
  • sec(x)tan(x)dx=sec(x)+C\int \sec(x)\tan(x) dx = \sec(x) + C
  • csc(x)cot(x)dx=csc(x)+C\int \csc(x)\cot(x) dx = -\csc(x) + C
Example

(4sin(x)5cos(x)+3sec2(x))dx=4cos(x)5sin(x)+3tan(x)+C\int (4 \sin(x) - 5 \cos(x) + 3 \sec^2(x)) dx = -4 \cos(x) - 5 \sin(x) + 3 \tan(x) + C

Indefinite vs. Definite Integrals

  • Indefinite Integral: Results in an algebraic expression with a constant of integration (C). f(x)dx=F(x)+C\int f(x) dx = F(x) + C
  • Definite Integral: Results in a numerical value. It has a lower and upper limit of integration. abf(x)dx=F(b)F(a)\int_a^b f(x) dx = F(b) - F(a)
    The constant of integration is not needed for definite integrals because it cancels out during evaluation.
Example of Indefinite Integral

6x2dx=2x3+C\int 6x^2 dx = 2x^3 + C

Example of Definite Integral

<em>126x2dx=[2x3]</em>12=2(23)2(13)=162=14\int<em>1^2 6x^2 dx = [2x^3]</em>1^2 = 2(2^3) - 2(1^3) = 16 - 2 = 14

Example 2

<em>23(8x3)dx=[4x23x]</em>23=(4(32)3(3))(4(22)3(2))=(369)(166)=2710=17\int<em>2^3 (8x - 3) dx = [4x^2 - 3x]</em>2^3 = (4(3^2) - 3(3)) - (4(2^2) - 3(2)) = (36 - 9) - (16 - 6) = 27 - 10 = 17

Fundamental Theorem of Calculus

The fundamental theorem of calculus states that if f(x)f(x) is a continuous function on the closed interval [a,b][a, b], then:

abf(x)dx=F(b)F(a)\int_a^b f(x) dx = F(b) - F(a)

Where F(x)F(x) is the antiderivative of f(x)f(x), i.e., F(x)=f(x)F'(x) = f(x).

Also,

f(x)dx=F(x)+C\int f(x) dx = F(x) + C

Exponential Functions

The derivative of eue^u is euue^u \cdot u'. For antiderivatives, if uu is a linear function ax+bax + b, then:

eudx=euu+C\int e^u dx = \frac{e^u}{u'} + C

Where uu' is the derivative of uu with respect to xx.

Example 1

e3xdx=e3x3+C\int e^{3x} dx = \frac{e^{3x}}{3} + C

Example 2

e5xdx=e5x5+C\int e^{5x} dx = \frac{e^{5x}}{5} + C

Example 3

e7xdx=e7x7+C\int e^{-7x} dx = \frac{e^{-7x}}{-7} + C

Example 4

e3x5dx=e3x53+C\int e^{3x - 5} dx = \frac{e^{3x - 5}}{3} + C

U-Substitution

U-substitution is a technique used to find the antiderivative of composite functions.

Example 1

Find the antiderivative of e8xe^{8x}.

  1. Let u=8xu = 8x.
  2. Find dudx=8\frac{du}{dx} = 8, so du=8dxdu = 8 dx.
  3. Solve for dxdx: dx=du8dx = \frac{du}{8}.
  4. Substitute: e8xdx=eudu8=18eudu\int e^{8x} dx = \int e^u \frac{du}{8} = \frac{1}{8} \int e^u du.
  5. Integrate: 18eu+C\frac{1}{8} e^u + C.
  6. Substitute back: 18e8x+C\frac{1}{8} e^{8x} + C.
Example 2

Find the antiderivative of 4xex24x e^{x^2}.

  1. Let u=x2u = x^2.
  2. Find dudx=2x\frac{du}{dx} = 2x, so du=2xdxdu = 2x dx.
  3. Solve for dxdx: dx=du2xdx = \frac{du}{2x}.
  4. Substitute: 4xex2dx=4xeudu2x=2eudu\int 4x e^{x^2} dx = \int 4x e^u \frac{du}{2x} = 2 \int e^u du.
  5. Integrate: 2eu+C2 e^u + C.
  6. Substitute back: 2ex2+C2 e^{x^2} + C.

Antiderivatives of Rational Functions

Example 1

Find the antiderivative of 1x2\frac{1}{x^2}.

  1. Rewrite: 1x2=x2\frac{1}{x^2} = x^{-2}.
  2. Apply the power rule: x2dx=x11+C=1x+C\int x^{-2} dx = \frac{x^{-1}}{-1} + C = -\frac{1}{x} + C
Example 2

Find the antiderivative of 1x3\frac{1}{x^3}.

  1. Rewrite: 1x3=x3\frac{1}{x^3} = x^{-3}.
  2. Apply the power rule: x3dx=x22+C=12x2+C\int x^{-3} dx = \frac{x^{-2}}{-2} + C = -\frac{1}{2x^2} + C
Example 3

Find the antiderivative of 8x4\frac{8}{x^4}.

  1. Rewrite: 8x4=8x4\frac{8}{x^4} = 8x^{-4}.
  2. Apply the power rule: 8x4dx=8x33+C=83x3+C\int 8x^{-4} dx = 8 \frac{x^{-3}}{-3} + C = -\frac{8}{3x^3} + C
Example 4

What is the antiderivative of 1(4x3)2\frac{1}{(4x - 3)^2}?

  1. Let u=4x3u = 4x - 3.
  2. Then dudx=4\frac{du}{dx} = 4, so dx=du4dx = \frac{du}{4}.
  3. Substituting gives: 1u2du4=14u2du\int \frac{1}{u^2} \frac{du}{4} = \frac{1}{4} \int u^{-2} du.
  4. Integrating: 14u11+C=14u+C\frac{1}{4} \frac{u^{-1}}{-1} + C = -\frac{1}{4u} + C.
  5. Substituting back gives: 14(4x3)+C\frac{-1}{4(4x - 3)} + C
Example 5

What is the antiderivative of 7(5x3)4\frac{7}{(5x - 3)^4}?

  1. Let u=5x3u = 5x - 3.
  2. Then dudx=5\frac{du}{dx} = 5, so dx=du5dx = \frac{du}{5}.
  3. Substituting gives: 7u4du5=75u4du\int \frac{7}{u^4} \frac{du}{5} = \frac{7}{5} \int u^{-4} du.
  4. Integrating: 75u33+C=715u3+C\frac{7}{5} \frac{u^{-3}}{-3} + C = -\frac{7}{15u^3} + C.
  5. Substituting back gives: 715(5x3)3+C\frac{-7}{15(5x - 3)^3} + C

Antiderivative of 1x\frac{1}{x}

The antiderivative of 1x\frac{1}{x} is ln(x)\ln(x).

1xdx=ln(x)+C\int \frac{1}{x} dx = \ln(x) + C

Rationale

Since the derivative of ln(u)\ln(u) is uu\frac{u'}{u}, the derivative of ln(x)\ln(x) is 1x\frac{1}{x}.

Example 1

Find the antiderivative of 7x\frac{7}{x}:

7xdx=71xdx=7ln(x)+C\int \frac{7}{x} dx = 7 \int \frac{1}{x} dx = 7 \ln(x) + C

Example 2

Find the antiderivative of 1x+5\frac{1}{x + 5}:

1x+5dx=ln(x+5)+C\int \frac{1}{x + 5} dx = \ln(x + 5) + C

Using u-substitution:

  1. Let u=x+5u = x + 5.
  2. Then du=dxdu = dx.
  3. So, 1udu=ln(u)+C=ln(x+5)+C\int \frac{1}{u} du = \ln(u) + C = \ln(x + 5) + C