Waves and Wave Properties - Quick Reference

Basic Wave Concepts

  • Waves transfer energy from one place to another; most require a medium, except electromagnetic (EM) waves which can travel in a vacuum.
  • A pulse is a short section of a wave.

Wave Types

  • Longitudinal: particles move parallel to the direction of wave travel (e.g. sound).
  • Transverse: particles move perpendicular to the direction of wave travel (e.g. water waves).

Wave Parameters

  • Wavelength, λ\lambda: distance from crest to crest (one complete wave).
  • Frequency, ff: waves per second (Hz).
  • Time period, TT: time for one complete wave to pass.
  • Amplitude, AA: maximum displacement (height).
  • Speed, vv: how fast the wave travels.
  • Core relation: v=fλv = f\lambda
  • Inverse relations: λ=vf,T=1f\lambda = \dfrac{v}{f}, \quad T = \dfrac{1}{f}

Electromagnetic Waves

  • EM waves travel at the speed of light in vacuum: c=3.0×108 m s1c = 3.0 \times 10^{8}\ \text{m s}^{-1}.
  • All EM waves are transverse and can travel through vacuum.
  • Visible light: red has longer wavelength and lower frequency; blue has shorter wavelength and higher frequency.
  • Light is shown to be transverse using polarising lenses.

Wavelengths of Radio and Light

  • For FM radio, f=91.3 MHzf = 91.3\ \text{MHz}; wavelength λ=cf3.0×10891.3×1063.29 m\lambda = \dfrac{c}{f} \approx \dfrac{3.0\times10^{8}}{91.3\times10^{6}} \approx 3.29\ \text{m}.
  • Similar calculation for other stations (e.g. 93.4 MHz) yields around 3.21 m3.21\ \text{m}.
  • AM wavelengths are much longer (e.g. hundreds of metres) than FM wavelengths.

Sound and Hearing

  • Audible range: approximately 40 Hz40\ \text{Hz} to 20 kHz20\ \text{kHz}.
  • Speed of sound in air: about v330 m s1v \approx 330\ \text{m s}^{-1}.
  • Corresponding wavelengths:
    • λ<em>min=vf</em>max=33020000=0.0165 m\lambda<em>{\text{min}} = \dfrac{v}{f</em>{\text{max}}} = \dfrac{330}{20000} = 0.0165\ \text{m}
    • λ<em>max=vf</em>min=33040=8.25 m\lambda<em>{\text{max}} = \dfrac{v}{f</em>{\text{min}}} = \dfrac{330}{40} = 8.25\ \text{m}

Reflection

  • Law: angle of incidence equals angle of reflection with respect to the normal.

Diffraction

  • Diffraction explains how waves bend around obstacles and through gaps; signals can be detected despite obstacles.
  • Longer wavelengths diffract more than shorter wavelengths.
  • Maximum diffraction occurs when the gap size is comparable to the wavelength; little diffraction when the gap is much larger; almost all waves are reflected when the gap is smaller than the wavelength.
  • AM (longer wavelength) diffracts more around hills/obstacles than FM (shorter wavelength).

Electromagnetic Spectrum (Key Points)

  • All EM waves share: speed ~c=3.0×108 m s1c = 3.0\times10^{8}\ \text{m s}^{-1}, travel in vacuum, and are transverse.
  • Our eyes see only a small portion of the spectrum; red light has longer wavelength than blue light; blue light has higher frequency.
  • Diffraction can be demonstrated with polarisation and diffraction experiments (e.g., around obstacles, through gaps).

Quick Reference Equations

  • v=fλv = f\lambda
  • λ=vf\lambda = \dfrac{v}{f}
  • T=1fT = \dfrac{1}{f}
  • c=3.0×108 m s1c = 3.0\times10^{8}\ \text{m s}^{-1}
  • For EM waves: v=cv = c; for radio/light waves, use λ=cf\lambda = \dfrac{c}{f}

Review Tips

  • If given frequency, find wavelength using λ=cf\lambda = \dfrac{c}{f}; if given wavelength, find frequency with f=cλf = \dfrac{c}{\lambda}.
  • To assess diffraction potential, compare gap size to wavelength: similar sizes yield maximum diffraction; much larger gap yields little diffraction.
  • Remember the audible range and corresponding wavelengths to intuit which sounds diffract more around barriers.