Calculus 2 Integration Techniques and Review

Basic Integration and Integration by Parts

  • Example: Integration involving Exponentials and Roots     * Evaluate the integral: xexdx\int \sqrt{x} e^{\sqrt{x}} \, dx

  • Example: Integration by Parts with Polynomial and Trigonometric Factors     * Evaluate the integral: (2x2+6x)sin(2x)dx\int (2x^2 + 6x) \sin(2x) \, dx

  • Example: Integration by Parts with Logarithmic Functions     * Evaluate the integral: x2(ln(x))2dx\int x^2 (\ln(x))^2 \, dx

  • Example: Inverse Trigonometric Functions     * Evaluate the integral: arctan(x)dx\int \arctan(x) \, dx

  • Example: Looping Integration by Parts     * Evaluate the integral: sin(x)exdx\int \sin(x) e^x \, dx

Trigonometric Integrals

  • Example: Product of Sine and Cosine with Odd and Even Powers     * Evaluate: sin(7x)cos8(7x)dx\int \sin(7x) \cos^8(7x) \, dx

  • Example: Squared Sine Functions     * Evaluate: sin2(3x)dx\int \sin^2(3x) \, dx

  • Example: Products of Even Powers of Sine and Cosine     * Evaluate: sin4(3x)cos2(3x)dx\int \sin^4(3x) \cos^2(3x) \, dx

  • Example: High Odd Powers of Sine     * Evaluate: sin5(2x)dx\int \sin^5(2x) \, dx

  • Example: Tangent and Secant Integrals     * Integral 1: tan3(x)sec2(x)dx\int \tan^3(x) \sec^2(x) \, dx     * Integral 2: tan3(x)sec3(x)dx\int \tan^3(x) \sec^3(x) \, dx

  • Example: Cotangent and Cosecant Integrals     * Evaluate: cot2(x)csc2(x)dx\int \cot^2(x) \csc^2(x) \, dx

Trigonometric Substitution and Fundamental Identities

  • Essential Trigonometric Identities     * Relationship between Sine and Cosine: cos2(θ)=1sin2(θ)\cos^2(\theta) = 1 - \sin^2(\theta)     * Relationship between Secant and Tangent (Identity 1): sec2(θ)=1+tan2(θ)\sec^2(\theta) = 1 + \tan^2(\theta)     * Relationship between Secant and Tangent (Identity 2): tan2(θ)=sec2(θ)1\tan^2(\theta) = \sec^2(\theta) - 1

  • Example Problems using Trigonometric Substitution     * Integral containing (x29)3/2(x^2 - 9)^{3/2}: 1(x29)3/2dx\int \frac{1}{(x^2 - 9)^{3/2}} \, dx     * Integral containing x2+1\sqrt{x^2 + 1}: 1xx2+1dx\int \frac{1}{x \sqrt{x^2 + 1}} \, dx     * Integral with square of radical: 1(1+x2)2dx\int \frac{1}{(1 + x^2)^2} \, dx     * Integral with root of negative square: x349x2dx\int x^3 \sqrt{4 - 9x^2} \, dx     * Integral with root of positive square: 4x29xdx\int \frac{\sqrt{4x^2 - 9}}{x} \, dx

Partial Fraction Decomposition (PFD)

  • Decomposition Setup (No Coefficient Determination Required)     * Case A: 3x+20x3+3x210x\frac{-3x + 20}{x^3 + 3x^2 - 10x}     * Case B: x3x(x+1)3(x2+5)\frac{x - 3}{x(x+1)^3 (x^2 + 5)}     * Case C: x2+2x+7x4+2x2+1\frac{x^2 + 2x + 7}{x^4 + 2x^2 + 1}     * Case D: 2x+1(x+3)(x2+1)2\frac{2x + 1}{(x+3)(x^2 + 1)^2}

  • Integrals Involving Partial Fractions     * Integral 1: 3x+20x3+3x210xdx\int \frac{-3x + 20}{x^3 + 3x^2 - 10x} \, dx     * Integral 2: 1x3+x2dx\int \frac{1}{x^3 + x^2} \, dx     * Integral 3: x37x2+2x+8x3+4x2dx\int \frac{x^3 - 7x^2 + 2x + 8}{x^3 + 4x^2} \, dx     * Integral 4: x+1(x+3)(x+4)dx\int \frac{x+1}{(x+3)(x+4)} \, dx

Improper Integrals and Comparison Theorem

  • Definite and Improper Integrals     * Integration involving substitution and trigonometric bounds: 0π/2cos(x)1+sin2(x)dx\int_0^{\pi/2} \frac{\cos(x)}{1 + \sin^2(x)} \, dx     * Infinite upper bound (Type 1): 11(x+3)1.5dx\int_1^{\infty} \frac{1}{(x+3)^{1.5}} \, dx     * Discontinuity at lower bound (Type 2): 081x3dx\int_0^8 \frac{1}{\sqrt[3]{x}} \, dx

  • Convergence Testing via Comparison Theorem     * Check convergence for: 113x21dx\int_1^{\infty} \frac{1}{3x^2 - 1} \, dx     * Check convergence for: 1exx4dx\int_1^{\infty} \frac{e^{-x}}{x^4} \, dx     * Check convergence for: 0πsin(x)xdx\int_0^{\pi} \frac{\sin(x)}{\sqrt{x}} \, dx

  • Special Substitutions     * Evaluate the integral: 13+2cos(2x)dx\int \frac{1}{3 + 2\cos(2x)} \, dx

To solve the integral xexdx\int \sqrt{x} e^{\sqrt{x}} \, dx using the tabular method of integration by parts, we can follow these steps:

  1. Set up the table with derivatives of one function and integrals of the other:

    • Choose:

      • Function (Choose u): u=exu = e^{\sqrt{x}} (since it simplifies upon differentiation)

      • Derivative (du): Differentiate until you reach 0:

      • First derivative: du=12xexdxdu = \frac{1}{2\sqrt{x}} e^{\sqrt{x}} \, dx

      • Second derivative: du=14x3/2exdxdu = -\frac{1}{4x^{3/2}} e^{\sqrt{x}} \, dx

      • Continue this until a simple expression is reached.

    • Choose:

      • Function (Choose dv): dv=xdxdv = \sqrt{x} \, dx

      • Integral (v): Integrate:

      • First integral: v=23x3/2v = \frac{2}{3} x^{3/2}

      • Second integral: v=112x5/2v = \frac{1}{12} x^{5/2}

  2. Construct the Tabular Method:

    • This will give a table that looks like this:

    Derivative

    Integral

    e^{\sqrt{x}}

    \frac{2}{3} x^{3/2}

    \frac{1}{2\sqrt{x}} e^{\sqrt{x}}

    \frac{1}{12} x^{5/2}

    (Continue until 0)

    (Continue)

  3. Sign Alternation: Attach alternating signs (starting with +) to each term:

    • The first product will be added, the second will be subtracted, and so on.

  4. Final Expression:

    • Combine these products according to the pattern established:

    • This will yield:
      xexdx=ex23x3/2(next product)dx+C\int \sqrt{x} e^{\sqrt{x}} \, dx = e^{\sqrt{x}} \cdot \frac{2}{3} x^{3/2} - \int (\text{next product}) \, dx + C

    • Continue simplifying as necessary based on remaining integrals until you arrive at a solution.

This method efficiently organizes the integration by parts process, especially for functions that require repeated applications of the technique.