SAT Geometry & Trigonometry Quick Reference

1. What You Need to Know

Geometry and trig on the SAT are mostly about spotting the right relationship fast: angle facts, triangle similarity/congruence, circle relationships, coordinate geometry, and a small set of trig ideas (mostly right-triangle trig plus radians/arc length/sector area).

Your job is usually to translate a diagram (or word problem) into equations using a few high-yield theorems:

  • Angles (vertical, linear pair, parallel lines)
  • Triangles (sum of angles, Pythagorean theorem, special right triangles, similarity)
  • Circles (radius/diameter, arc/sector, inscribed angles)
  • Coordinate geometry (slope, distance, midpoint)
  • Trig (SOHCAHTOA, inverse trig, radians basics)

Critical reminder: SAT diagrams are not necessarily to scale unless stated. Don’t “eyeball” lengths or angles.

Core idea you use constantly

When you can show two triangles are similar, you get:

  • equal corresponding angles
  • proportional corresponding sides

This is one of the biggest time-savers on SAT geometry.

2. Step-by-Step Breakdown

A) General geometry attack plan (works on most questions)
  1. Redraw cleanly (even if it’s already drawn). Mark given lengths/angles.
  2. Label unknowns with variables (use one variable when possible).
  3. Identify the shape family: triangle, circle, parallel lines, coordinate plane, 3D solid.
  4. Write the fastest relationship:
    • triangle: angle sum, Pythagorean, special triangle ratios, area formulas
    • circle: central vs inscribed angles, tangent-radius right angle, arc/sector formulas
    • coordinate: slope, distance, midpoint
  5. Look for similarity/congruence triggers:
    • parallel lines create equal angles
    • shared angle in nested triangles
    • right angles in circles (diameter subtends a right angle)
  6. Solve algebraically and check units/reasonableness.
B) Similar triangles workflow (high frequency)
  1. Prove similarity using one of:
    • AA (two angles)
    • SAS (including angle equal and sides proportional)
    • SSS (all sides proportional)
  2. Write a correspondence statement (match vertices carefully).
  3. Set up a proportion of corresponding sides.
  4. Solve for scale factor, then get requested length/ratio.

Micro-example (setup only):
If triangles are similar with scale factor kk (big : small), then:

  • each corresponding side satisfies bigsmall=k\frac{\text{big}}{\text{small}} = k
  • areas satisfy AbigAsmall=k2\frac{A_{\text{big}}}{A_{\text{small}}} = k^2
C) Right-triangle trig workflow
  1. Confirm it’s a right triangle.
  2. Choose the trig ratio based on given/needed sides:
    • sin⁡(θ)=oppositehypotenuse\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}
    • cos⁡(θ)=adjacenthypotenuse\cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}}
    • tan⁡(θ)=oppositeadjacent\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}
  3. Plug in and solve. Use special triangles when possible (faster than decimals).
  4. If angle is asked, use inverse trig:
    • θ=sin⁡−1(x)\theta = \sin^{-1}(x), cos⁡−1(x)\cos^{-1}(x), or tan⁡−1(x)\tan^{-1}(x)
D) Circle arc/sector workflow
  1. Convert degrees to radians if using radian formulas.
  2. Use:
    • arc length: s=rθs = r\theta (with θ\theta in radians)
    • sector area: A=12r2θA = \frac{1}{2}r^2\theta (with θ\theta in radians)
  3. If working in degrees, use fraction-of-circle:
    • s=θ360∘⋅2πrs = \frac{\theta}{360^\circ}\cdot 2\pi r
    • A=θ360∘⋅πr2A = \frac{\theta}{360^\circ}\cdot \pi r^2

3. Key Formulas, Rules & Facts

A) Angles and lines
RuleWhen to useNotes
Linear pair sum=180∘\text{Linear pair sum} = 180^\circadjacent angles on a linesupplementary
Vertical angles are equal\text{Vertical angles are equal}intersecting linesfastest equality
Angles around a point=360∘\text{Angles around a point} = 360^\circfull rotationgood for multi-ray diagrams
Parallel lines: corresponding angles equaltransversal across parallelsalso alternate interior angles equal
Same-side interior angles sum to 180∘180^\circtransversal across parallelsoften used with algebra
B) Triangles (core)
Formula / factWhen to useNotes
a+b>ca+b>c (and permutations)triangle inequalityfor possible side lengths
Angle sum=180∘\text{Angle sum} = 180^\circany triangleimmediate equation
Exterior angle equals sum of remote interior anglesextended sidefast angle chase
Pythagorean theorem: a2+b2=c2a^2+b^2=c^2right trianglescc is hypotenuse
Area: A=12bhA = \frac{1}{2}bhany trianglechoose convenient base-height
Area with two sides and included angle: A=12absin⁡(C)A = \frac{1}{2}ab\sin(C)trig/oblique triangleless common but appears
C) Special right triangles (must memorize)
TriangleSide ratiosQuick notes
45∘−45∘−90∘45^\circ-45^\circ-90^\circ1:1:21:1:\sqrt{2}hypotenuse =leg⋅2= \text{leg}\cdot \sqrt{2}
30∘−60∘−90∘30^\circ-60^\circ-90^\circ1:3:21:\sqrt{3}:2short leg opposite 30∘30^\circ
D) Similarity and congruence
ConceptWhen to useNotes
Similarity: AA, SAS, SSStriangles same shapegives proportional sides
Congruence: SSS, SAS, ASA, AAS, HLtriangles same shape and sizeHL is right triangles only
If scale factor is kk, then perimeters scale by kksimilar figureslinear measures scale by kk
If scale factor is kk, then areas scale by k2k^2similar figuresvery common trap
If scale factor is kk, then volumes scale by k3k^3similar solidsless common but testable
E) Quadrilaterals and polygons
FactWhen to useNotes
Sum of interior angles of an nn-gon: (n−2)⋅180∘(n-2)\cdot 180^\circpolygon angle sumsinterior total
Each interior angle (regular): (n−2)⋅180∘n\frac{(n-2)\cdot 180^\circ}{n}regular polygonsequal angles
Each exterior angle (regular): 360∘n\frac{360^\circ}{n}regular polygonsexterior sum always 360∘360^\circ
Parallelogram: opposite sides parallel/equalcoordinate or diagramopposite angles equal
Rectangle: diagonals equalrectanglesplus right angles
Rhombus: diagonals perpendicularrhombiplus all sides equal
Trapezoid median: m=b1+b22m = \frac{b_1+b_2}{2}trapezoidsmedian connects leg midpoints
F) Circles
Rule / formulaWhen to useNotes
Circumference: C=2πrC = 2\pi rcircle perimeteralso C=πdC = \pi d
Area: A=πr2A = \pi r^2circle areamemorize
Arc length (degrees): s=θ360∘⋅2πrs = \frac{\theta}{360^\circ}\cdot 2\pi rarc with degreesθ\theta is central angle
Sector area (degrees): A=θ360∘⋅πr2A = \frac{\theta}{360^\circ}\cdot \pi r^2sector with degreescentral angle
Inscribed angle equals half intercepted arcchords/angles on circle∠=12 arc\angle = \frac{1}{2}\,\text{arc}
Tangent is perpendicular to radius at point of tangencytangentscreates right triangle
Chords equidistant from center are equalchord problemsalso equal chords have equal distances
G) Coordinate geometry
FormulaWhen to useNotes
Slope: m=y2−y1x2−x1m = \frac{y_2-y_1}{x_2-x_1}line steepnessvertical line undefined
Distance: d=(x2−x1)2+(y2−y1)2d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}segment lengthfrom Pythagorean
Midpoint: (x1+x22,y1+y22)\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)midpoint coordinatescommon in geometry proofs
Parallel lines: m1=m2m_1=m_2compare slopessame slope
Perpendicular lines: m1m2=−1m_1m_2=-1right angle in coordinate planenegative reciprocals
H) Trigonometry essentials
FactWhen to useNotes
sin⁡2(θ)+cos⁡2(θ)=1\sin^2(\theta)+\cos^2(\theta)=1relate trig valuesmostly with right triangles
Complementary angles: sin⁡(θ)=cos⁡(90∘−θ)\sin(\theta)=\cos(90^\circ-\theta)right trianglesalso cos⁡(θ)=sin⁡(90∘−θ)\cos(\theta)=\sin(90^\circ-\theta)
Radians conversion: π rad=180∘\pi\,\text{rad} = 180^\circarc/sector with radiansconvert cleanly
Arc length (radians): s=rθs=r\thetaarc lengthθ\theta in radians
Sector area (radians): A=12r2θA=\frac{1}{2}r^2\thetasector areaθ\theta in radians

4. Examples & Applications

Example 1: Similar triangles from parallel lines

A line parallel to one side of a triangle creates a smaller similar triangle. Suppose in triangle ABCABC, a segment DEDE is drawn with DD on ABAB and EE on ACAC, and DE∥BCDE \parallel BC. If AD=3AD=3, AB=12AB=12, and AE=4AE=4, find ACAC.

Key insight: Similar triangles: △ADE∼△ABC\triangle ADE \sim \triangle ABC.

Set up proportion:
ADAB=AEAC\frac{AD}{AB}=\frac{AE}{AC}
Substitute:
312=4AC\frac{3}{12}=\frac{4}{AC}
Solve:
14=4AC\frac{1}{4}=\frac{4}{AC}
AC=16AC=16

Example 2: Coordinate geometry distance

Find the distance between (−1,2)(-1,2) and (5,−6)(5,-6).

Use distance formula:
d=(5−(−1))2+(−6−2)2d=\sqrt{(5-(-1))^2+(-6-2)^2}
d=62+(−8)2d=\sqrt{6^2+(-8)^2}
d=36+64d=\sqrt{36+64}
d=100d=\sqrt{100}
d=10d=10

SAT pattern: Many coordinate problems hide a right triangle; distance is just Pythagorean.

Example 3: Right-triangle trig (height)

From a point on the ground, the angle of elevation to the top of a building is 30∘30^\circ. The point is 4040 units from the base. Find the building height.

Key insight: Opposite is height, adjacent is 4040.

Use tangent:
tan⁡(30∘)=h40\tan(30^\circ)=\frac{h}{40}
Use special triangle value:
tan⁡(30∘)=13\tan(30^\circ)=\frac{1}{\sqrt{3}}
So:
13=h40\frac{1}{\sqrt{3}}=\frac{h}{40}
h=403h=\frac{40}{\sqrt{3}}
Rationalized (if desired):
h=4033h=\frac{40\sqrt{3}}{3}

Example 4: Arc length and sector area

A circle has radius 66. A sector has central angle 150∘150^\circ. Find arc length.

Use degree arc formula:
s=150∘360∘⋅2π⋅6s=\frac{150^\circ}{360^\circ}\cdot 2\pi\cdot 6
Simplify:
s=512⋅12πs=\frac{5}{12}\cdot 12\pi
s=5πs=5\pi

Variation: If they give θ\theta in radians, go straight to s=rθs=r\theta.

5. Common Mistakes & Traps

  1. Trusting the picture (not to scale).

    • What goes wrong: You assume a line “looks” perpendicular or a triangle “looks” isosceles.
    • Why wrong: SAT can draw misleading diagrams.
    • Fix: Only conclude special properties if given or proven (right-angle box, tick marks, explicit statements).
  2. Mixing up opposite/adjacent in trig.

    • What goes wrong: You pick adjacent relative to the wrong angle.
    • Why wrong: “Adjacent” depends on which acute angle you’re using.
    • Fix: Circle the angle θ\theta, then label opposite/adjacent from that angle.
  3. Forgetting the hypotenuse is always opposite the right angle.

    • What goes wrong: Plugging the wrong side into sin⁡(θ)\sin(\theta) or cos⁡(θ)\cos(\theta).
    • Fix: Find the right angle first; the side across from it is the hypotenuse.
  4. Using degree formulas with radians (or vice versa).

    • What goes wrong: You use s=rθs=r\theta with θ\theta in degrees.
    • Why wrong: s=rθs=r\theta requires radians.
    • Fix: If you see π\pi in an angle measure, it’s radians; otherwise convert using π=180∘\pi=180^\circ.
  5. Area/volume scaling mistakes in similar figures.

    • What goes wrong: If lengths scale by kk, you scale area by kk.
    • Why wrong: area scales by k2k^2, volume by k3k^3.
    • Fix: Ask “Is this a length, area, or volume?” before scaling.
  6. Incorrect triangle similarity matching.

    • What goes wrong: You set up proportions with mismatched corresponding sides.
    • Why wrong: Even if triangles are similar, wrong correspondence gives wrong equations.
    • Fix: Write a vertex matching statement (for example, △ABC∼△DEF\triangle ABC \sim \triangle DEF means A↔DA\leftrightarrow D, B↔EB\leftrightarrow E, C↔FC\leftrightarrow F).
  7. Slope errors (sign and order).

    • What goes wrong: You compute y1−y2x2−x1\frac{y_1-y_2}{x_2-x_1} inconsistently.
    • Why wrong: Swapping only one order flips the sign.
    • Fix: Use the same order on top and bottom: y2−y1x2−x1\frac{y_2-y_1}{x_2-x_1}.
  8. Radius vs diameter confusion in circles.

    • What goes wrong: You use diameter where radius is needed in πr2\pi r^2 or 2πr2\pi r.
    • Fix: If given diameter dd, convert with r=d2r=\frac{d}{2}.

6. Memory Aids & Quick Tricks

Trick / mnemonicHelps you rememberWhen to use
SOHCAHTOAsin⁡\sin, cos⁡\cos, tan⁡\tan definitionsright-triangle trig
“3030 short, 6060 long”In 30∘−60∘−90∘30^\circ-60^\circ-90^\circ, short leg opposite 30∘30^\circspecial triangles
4545 means equal legs45∘−45∘−90∘45^\circ-45^\circ-90^\circ has legs equalspecial triangles
“Inscribed is half”inscribed angle =12=\frac{1}{2} intercepted arccircle angles
“Tangent to radius makes 90∘90^\circ”tangent is perpendicular to radiustangents
“Perp slopes multiply to −1-1”m1m2=−1m_1m_2=-1coordinate perpendicular lines
“Exterior sum 360∘360^\circ”sum of exterior angles (any polygon)polygon problems
Convert degrees to radians by multiplying π180∘\frac{\pi}{180^\circ}degree to radian conversionarc/sector with radians

7. Quick Review Checklist

  • You can do angle-chasing with: vertical angles, linear pairs, parallel line angle rules.
  • You remember triangle facts: angle sum 180∘180^\circ, Pythagorean theorem, triangle inequality.
  • You have special triangles memorized: 1:1:21:1:\sqrt{2} and 1:3:21:\sqrt{3}:2.
  • You can prove and use similarity (AA is the most common SAT trigger).
  • You know circle basics: C=2πrC=2\pi r, A=πr2A=\pi r^2, inscribed angle is half its arc, tangent-radius is 90∘90^\circ.
  • You can use coordinate formulas: slope, distance, midpoint; parallel m1=m2m_1=m_2, perpendicular m1m2=−1m_1m_2=-1.
  • You can use trig ratios correctly relative to the chosen angle.
  • You won’t mix radians and degrees: s=rθs=r\theta and A=12r2θA=\frac{1}{2}r^2\theta require radians.

You’ve got this: stay systematic, write the relationship first, and let the algebra finish the job.