BIO 340 General Genetics - Transmission Genetics I Notes
Overview of Transmission Genetics I
BIO 340 General Genetics, Transmission Genetics I (Mendelian genetics)
Focus: how genes pass from one generation to the next, using Mendelian principles
Sources in slides: Lecture content, genetic analysis perspectives, and Mendel’s experiments with peas
Reading assignment reference: Genetic Analysis, Sanders and Bowman (3rd ed), Chapter 2 (2.3, 2.5) and quizzes
Defining a gene: three perspectives
Molecular genetics perspective
Genes are the chemistry and molecular nature of DNA
Example sequence and translation: coding strand, template strand, mRNA, codons, and amino acids
Coding strand example: 5' ext{ATG ACA CTG GGT ACG CTT TAA} 3'
Template strand example (complement): 3' ext{TAC TGT GAC CCA TGC GAA ATT} 5'
mRNA transcribed: 5' ext{AUG ACA CUG GGU ACG CUU UAA} 3'
Codons and amino acids: MET, THR, LEU, GLY, THR, LEU; stop codon marks end of translation
Population genetics perspective
Allelic frequencies in populations and how they change over generations (population dynamics of genes)
Visual example: frequency changes across generations in populations
Transmission (Mendelian) genetics perspective
The fundamental unit of heredity (gene) that passes information from parents to offspring
Emphasis on patterns of inheritance across generations
Genotype vs. Phenotype
Phenotype: observable characteristics of an organism (e.g., tall vs. dwarf, purple vs. white flowers)
Genotype: the specific allelic makeup at a gene locus (e.g., AA, Aa, aa)
Relationship nuances
Not strictly one-to-one: the same phenotype can arise from different genotypes under varying environments (e.g., identical twins in different environments)
Genotype informs phenotype, but environment can modulate expression
Key genetic terms: gene, locus, allele, genotype
Gene: fundamental unit of heredity
Locus: physical location of a gene on a chromosome
Allele: variant form of a gene at a given locus
Genotype: allelic state of an individual at a locus
For diploids (2n):
Genotypes can be homozygous (two identical alleles) or heterozygous (two different alleles)
Example: single locus with two alleles A and a
Alleles: A, a
Genotype examples: AA, Aa, aa
When multiple alleles exist at a locus (e.g., A1, A2, A3), genotypes include combinations like A1A2, A2A3, etc.
Quick Quiz: alleles vs. genotype (concept check)
Question: How do alleles relate to genotype?
Answer: A. Genotype consists of the alleles an organism has for a particular gene
Rationale: A genotype is the set of alleles present at a locus (e.g., AA, Aa, aa). Alleles are the variants that compose the genotype.
Mendel and his innovations
Historical context: 19th-century belief in blending inheritance was inadequate to explain results
Gregor Mendel: mid-1800s, founder of genetic science; studied natural sciences and entered the priesthood to pursue education
Model organism: Mendel used pea plants (Pisum sativum) to deduce general principles of heredity
Mendel’s achievements with peas: studied phenotypes, counted offspring, and inferred underlying units of inheritance
Five innovations that drove Mendel’s success:
1) Rigorous control of crossesChose a suitable species; many offspring per cross; short generation time; easy to mate;
self-pollination can produce true-breeding lines
2) Use of discontinuous (dichotomous) traitsTraits with clear-cut categories (purple vs white, yellow vs green, etc.)
Avoided intermediates for clean counting
3) Use of pure-breeding strainsTrue-breeding lines produce offspring resembling the parent when selfed
Cultivated closed flowers to prevent cross-pollination; established stable lines
4) Quantification of resultsLarge data sets from many crosses; precise counts of phenotypes
Identified consistent phenotypic ratios that revealed underlying patterns
5) Use of replicate, reciprocal, and test crossesReplicates to increase data reliability
Reciprocal crosses swapped parental sexes to test inheritance independent of parent sex
Test crosses to reveal unknown genotypes by crossing with homozygous recessive
What Mendel learned from each innovation
Controlled crosses enabled reliable data and generation tracking
Discontinuous traits allowed straightforward counting (no intermediates)
Pure-breeding strains established stable parental phenotypes across generations
Quantification revealed consistent ratio patterns across traits
Replicate, reciprocal, and test crosses helped validate patterns and reveal genotype information
Using monohydrids crosses to understand inheritance
Monohybrid cross: focusing on one trait at a time (e.g., flower color)
Terminology:
P (Parental generation): pure-breeding strains*
F1 (First filial generation): offspring of P cross
F2 (Second filial generation): offspring from F1 crosses
Monohybrid cross: cross between two heterozygotes (e.g., Aa x Aa) or between a heterozygote and a homozygous recessive (as a test cross for genotype discovery)
Classic monohybrid cross result (Aa x Aa): phenotypes segregate in a 3:1 ratio; genotypes segregate in a 1:2:1 ratio
Example data for several traits (selected):
Seed shape: round vs wrinkled → F1 all round; F2 ~ 3:1 round:wrinkled
Seed color: yellow vs green → F1 all yellow; F2 ~ 3:1 yellow:green
Pod shape: full vs constricted → F1 all full; F2 ~ 3:1 full:constricted
Pod color: green vs yellow → F1 all green; F2 ~ 3:1 green:yellow
Flower color: violet vs white → F1 all violet; F2 ~ 3:1 violet:white
Flower position: axial vs terminal → F1 all axial; F2 ~ 3:1 axial:terminal
Stem height: tall vs dwarf → F1 all tall; F2 ~ 3:1 tall:dwarf
Mendel’s data supported the idea that traits are discrete units (genes) with two versions (alleles) per gene per individual
Mendel’s Law of Segregation
Core idea: during gamete formation, each copy of a gene separates (segregates) equally so that each gamete carries one allele
During fertilization, gametes unite at random, so offspring have two alleles for each gene, one from each parent
Formal statement:
Part I: In gamete formation, copies of a gene segregate so that each gamete carries one member of the pair
Part II: In fertilization, randomly formed gametes unite without regard to which copy they carry
Classic 2x2 Punnett cross for Aa x Aa
Gametes from each parent: A or a
Offspring genotypes: AA, Aa, Aa, aa
Genotype ratio: 1:2:1
Phenotype ratio (dominant vs recessive): 3:1 when one allele is completely dominant over the other
Visualization with gametes and zygotes
Gametes: A or a from each parent
Zygotes: AA, Aa, Aa, aa
Resulting phenotype distribution reflects dominance and recessivity
How to visualize gene transmission: Punnett squares
Example: Aa x Aa cross
Parental genotypes: Aa and Aa
Possible offspring genotypes: AA, Aa, Aa, aa
Phenotypic outputs depend on dominance; typically 3:1 for dominant phenotype to recessive phenotype
More general approach
Each parent contributes one allele per gene per gamete (haploid gametes)
Fertilization pairs alleles to form diploid offspring
Test crosses: predicting genotypes
Test cross purpose: determine unknown genotype of an individual with known phenotype
Method: cross an individual with an unknown genotype but dominant phenotype with a homozygous recessive (aa)
Interpretations:
If offspring are all heterozygous (Aa) with dominant phenotype, the unknown parent is AA
If offspring are 1:1 Aa:aa, the unknown parent is Aa
Notation example: Aa x aa
If unknown parent is AA: all offspring will be Aa
If unknown parent is Aa: offspring will be 1:1 Aa:aa
Practice questions (selected from lecture)
Question 1: alleles vs genotype
Answer: A. Genotype consists of the alleles an organism has for a particular gene
Question 2: Mendel’s helpful strategies
Answer: C. Only II and IV (many offspring per generation and discontinuous traits)
Question 3: Mendel’s Law of Segregation illustration
Answer: B. A pea plant with Aa genotype produces half A gametes and half a gametes
Question 4: Guinea pig coat color cross (true-breeding black x true-breeding white; F1 all black; F1 x F1)
White progeny proportion in F2: frac{1}{4} (1/4 white)
Question 5: In the black coat color cross (Bb x Bb) among black F2 progeny, proportion that are homozygous
Answer: frac{1}{3} (BB among black phenotypes is 1 of 3 equally likely black genotypes: BB, Bb, Bb)
Question 6: Cross of black (B_) with white (bb) in F1 phenotype
Answer: A. All black (F1 are Bb)
Genotypes and alleles: deeper definitions
Heterozygous for a gene A
Genotype: Aa
Homologous chromosomes carry copies of the same gene
In a diploid organism, each individual has two alleles per gene locus (one from each parent)
Visual: Gene A on homologous chromosome pair; maternal and paternal chromosomes provide alleles A and a in a heterozygote
Summary of Mendel’s inheritance framework
Genes exist in discrete units (not blending) and are inherited in predictable patterns
Each individual carries two alleles per gene; offspring receive one allele from each parent
Dominant and recessive relationships determine phenotype in heterozygotes
Pure-breeding lines and controlled crosses enable clear interpretation of inheritance patterns
The Law of Segregation underpins all Mendelian inheritance and is illustrated by 3:1 phenotypic ratios and 1:2:1 genotypic ratios in monohybrid crosses
Real-world relevance and connections
Mendelian genetics provides foundational models for inheritance, but many traits are polygenic or influenced by the environment
The use of model organisms (e.g., peas) demonstrates how simple systems can reveal general genetic principles applicable to more complex organisms
Transmission genetics informs breeding programs, medicine (genetic testing, risk assessment), and evolutionary biology
Ethical, philosophical, and practical implications (not deeply covered in these slides) include: implications of genetic testing, privacy, eugenics concerns, gene editing, and how genetic information shapes societal decisions
Practical note: The slides emphasize fundamental concepts needed to understand transmission genetics, with reading assignments for deeper exploration of 2.3 and 2.5 in the Sanders and Bowman text
Quick reference: key equations and ratios (LaTeX)
Mendel’s Law of Segregation concepts:
Gamete allele probability: P( ext{A}) = frac{1}{2}, \, P( ext{a}) = frac{1}{2}
Offspring genotype ratio for Aa x Aa: ext{AA}: ext{Aa}: ext{aa} = 1:2:1
Corresponding phenotype ratio for a dominance relationship: 3:1 (dominant:recessive)
Monohybrid cross phenotype/genotype summary:
Phenotype with dominance: 3:1 (dominant:recessive)
Genotype: 1:2:1 (AA:Aa:aa)
Test cross interpretation:
If unknown genotype is AA: offspring with aa will be all Aa (phenotype dominant)
If unknown genotype is Aa: offspring will be in a 1:1 ratio Aa:aa
Reading to be done before next lecture
Genetic Analysis, Sanders and Bowman (3rd ed)
Chapter 2: Transmission genetics 2.3, 2.5
Complete Reading Quizzes 2 before Thursday’s class