Chemical Equilibrium

  • Chemical Equilibrium

    • occurs when a reaction and its reverse proceed at the same rate

  • The Concept of Equilibrium

    • as a system approaches equilibrium, both the forward and reverse reactions are occurring

    • at equilibrium, the forward and reverse reactions are proceeding at the same rate

  • A system at equilibrium

    • once equilibrium is achieved, the amount of each reactant and product remains constant

  • The Equilibrium Constant

    • N2O4—>←-2NO2

      • Forward reaction: N2O4—>kf[N2O4]

      • Reverse reaction: kr[NO2]²

      • At equilibrium: Ratef=Rater

        • kf=[N2O4]=kr[NO2]²

          • rewriting this becomes…

            • kf/kr=[NO2]²/[N2O4]=Constant (Kc)

    • Consider the generalized reaction

      • aA+bB—>←-cC+dD

        • the equilibrium expression for this reaction would be

          • Kc=[C}^c[D]^d/[A]^a[B]^b

            • [products]/[reactants]

    • Sample Exercise 15.1

  • Evaluating Kc

    • equilibrium constant (Kc) does NOT depend on initial concentrations of reactants

    • change in temperature, alters the Kc, as rate constant is sensitive to change in temperature

  • Equilibrium Constant for Gas

    • Consider generalized reaction involving gases

      • aA+bB—>←-cC+dD

    • Since pressure is proportional to concentration for gases in a closed system, the equilibrium expression can also be written

      • kp=(Pc^c)(PD^d)/(PA^a)(PB^b)

        • P-partial pressure of respective gases

  • Kc and Kp conversions

    • From the ideal-gas law we know that

      • PV=nRT

    • Rearranging it we can get

      • P=[M]RT

        • plugging this into the expression for Kp, for each substance, the relationship between Kc and Kp becomes

          • Kp=Kc(RT)^delta n

            • delta n = (moles of gaseous product)-(moles of gaseous reactant)

    • Sample Exercise 15.2

  • Equilibrium Constants and Units

    • the ratio of [NO2]² to [N2O4] remains constant at this temperature no matter what the initial concentrations of NO2 and N2O4 are.

      • Equilibrium can be reached from either direction

        • it doesn’t matter whether we start with N2 and H2 or whether we start with NH3, we will have the same proportions of all three substances at equilibrium

  • Evaluating Kc

    • equilibrium constant (Kc) does not depend on initial concentrations of reactants

  • What Does the Value of K Mean?

    • If K>1, the reaction is product favored; product predominates at equilibrium

    • If K<1, the reaction is reactant favored; reactant predominates at equilibrium

  • Manipulating Equilibrium Constants

    • The equilibrium constant of a reaction in the reverse reaction is the reciprocal of the equilibrium constant of the forward reaction

      • N2O4—>←-2NO2

        • Kc=[NO2]²/[N2O4] = 0.212 at 100 degrees celsius

      • 2NO2—>←-N2O4

        • Kc=[N2O4]/[NO2]² = 4.72 at 100 degrees Celsius

    • the equilibrium constant for a net reaction made up of two or more steps is the product of the equilibrium constants for the individual steps

  • The Concentrations of Solids and Liquids are Essentially Constant

    • both the concentrations of solids and liquids can be obtained by multiplying the density of the substance by its molar mass-and both of these are constants at constant temperature

    • therefore, the concentrations of solids and liquids DO NOT APPEAR in the equilibrium expression

      • PbCl2(s)—>←- Pb²+(aq) + 2Cl^- (aq)

        • Kc = [Pb²+][Cl^-]²

    • ex:

      • CaCO3(s) —>←- CO2 (g) +Ca) (s)

      • as long as some CaCO3 or CaO (solids) remain in the system, the amount of CO2 (gas) above the solid will remain the same

  • An Equilibrium Problem

    • a closed system initially containing 1.000×10^-3 M H2 and 2.000 × 10^-3 M I2 at 448 degrees Celsius is allowed to reach equilibrium. Analysis of the equilibrium mixture shows that the concentration of HI is 1.87 × 10^-3 M. Calculate Kc at 448 degrees Celsius for the reaction taking place

      • H2(g) + I2(s)—>←- 2HI (g)

  • The Reaction Quotient (Q)

    • same as Kc

    • Q gives the same ratio the equilibrium expression gives, but for a system that is NOT at equilibrium

    • To calculate Q, one substitutes the initial concentrations on reactants and products into the equilibrium expression

    • If Q = K, the system is at equilibrium

      • Q<K (the reaction will form products (shift right) because there are too many reactants)

      • Q = K (the reaction is in equilibrium)

      • Q>K (the reaction will form reactants (shift left) because there is too much product)

  • Le Chatelier’s Principle

    • “If a system at equilibrium is disturbed by a change in temperature, pressure, or the concentration of one of the components, the system will shift its equilibrium position so as to counteract the effect of the disturbance”

      • how to counteract

        • Concentration

          • adding or removing a reactant or product

            • if reactant is added, the reaction will shift to the right in order to produce more product.

            • if more product produced, then the equation will shift left, in order to equal out more reactants.

        • Pressure

          • changing pressure by changing the volume

            • at a constant temperature, reducing the volume of a gaseous equilibrium mixture causes the system to shift in the direction that reduces the number of moles of gas (shift to direction with less moles)

              • initial volume + added pressure (creates a smaller volume) = system will shift to direction of fewer moles of gas

        • Temperature

          • if the temperature of a system at equilibrium is increased, the system reacts as if we added a reactant to an endothermic reaction or a product to an exothermic reaction. The equilibrium shifts in the direction that consumes the “excess reactant”, namely heat.

            • Endothermic

              • increasing T = reaction shifts right

              • decreasing T = reaction shifts left

            • Exothermic

              • increasing T = reaction shifts left

              • decreasing T = reaction shifts right

  • Haber Process

    • the transformation of nitrogen and hydrogen into ammonia (NH3) is tremendous significance in agriculture, where ammonia-based fertilizers are important.

    • if H2 is added to the system, N2 will be consumed and the two reagents will form more NH3

    • this apparatus helps push equilibrium to the right by removing the ammonia from the system as a liquid

      • decrease volume = increase pressure

      • increase volume = decrease pressure

  • Catalyst

    • increase the rate of both the forward and reverse reactions

    • when one uses a catalyst, equilibrium is achieved faster, but the equilibrium composition remains unaltered