Electrochemistry Notes

Electrochemistry

Objectives

  • Review the concepts of oxidation and reduction.
  • Define the term "cell potential."
  • Illustrate the Standard Hydrogen Electrode (SHE) and standard electrode (reduction) potentials.

What is Electrochemistry?

  • Electrochemistry is the study of chemical reactions and their associated electrical changes.
  • It also examines chemical changes that an electrical current can bring about.

Transfer of Electrons

  • Electrochemistry involves the transfer of electrons.
  • Oxidation: Compound A loses electrons.
    • A is a reducing agent and becomes oxidized.
  • Reduction: Compound B gains electrons.
    • B is an oxidizing agent and becomes reduced.

Half Cell

  • A half-cell consists of a metal electrode, MM, partially immersed in an aqueous solution of its ions, Mn+M^{n+}.
  • The anions required to maintain electrical neutrality in the solution are not shown.
  • This is limited to metals that do not react with water.
  • Oxidation: M<br/>Mr+M <br />\nrightarrow M^{r+}
  • Reduction: Mn+<br/>MM^{n+} <br />\nrightarrow M

Cell Potential

  • If a strip of metal (electrode) is placed in a solution of its ions, the metal loses electrons to form its cation: M(s)<br/>Mn+(aq)+neM(s) <br />\nrightarrow M^{n+}(aq) + ne^{-}
  • The cations in solution may accept some of the lost electrons and get reduced to the metal atoms: Mn+(aq)+ne<br/>M(s)M^{n+}(aq) + ne^{-} <br />\nrightarrow M(s)
  • At equilibrium, the charge difference that develops between the metal strip and the solution is called a potential difference: Mn+(aq)+ne<br/>M(s)M^{n+}(aq) + ne^{-} <br />\nleftrightarrow M(s)

Cell Potential Definition

  • Cell potential (measured in Volts, V), also known as electromotive force (emf), is the tendency of species to lose or gain electrons.
  • E° represents the standard electrode potential, which is the potential of a species compared with the potential of a Standard Hydrogen Electrode.
  • 2H++2e<br/>H<em>22H^+ + 2e^- <br />\nleftrightarrow H<em>2 E°</em>cell=0.00VE°</em>{cell} = 0.00V

Standard Hydrogen Electrode (SHE)

  • The Standard Hydrogen Electrode (S.H.E.) consists of Hydrogen gas at 298K and 1 atm bubbling over a platinum electrode immersed in a solution of H+H^+ ions with concentration 1 moldm3moldm^{-3}.
  • 2H^+(aq) + 2e^-
    rightleftharpoons H_2 (g, 1 atm) E°=0.00VE° = 0.00 V

Relative Cell Potential

  • More reactive metals lose electrons with greater ease, so the equilibrium position of the redox reaction lies more to the left: M^{n+}(aq) + ne^-
    rightleftharpoons M(s)
  • More reactive metals possess more negative reduction potentials, and less reactive metals possess more positive reduction potential differences.

Standard Cell Potential of Zn Half Cell

  • Zn (s)
    rightleftharpoons Zn^{2+}(aq) + 2e^- E°=+0.76VE° = +0.76 V
  • Zn^{2+}(aq) + 2e^-
    rightleftharpoons Zn (s) E°=0.76VE° = -0.76 V

Cell Potential and Oxidizing/Reducing Agents

  • Species with a positive E° value have a tendency to be reduced and are strong oxidizing agents (usually non-metals).
  • Species with a negative E° value have a tendency to be oxidized and are strong reducing agents (usually metals).

Table of Standard Reduction Potentials

  • The table lists various reduction half-reactions and their corresponding standard reduction potentials (E° in Volts).
  • Stronger oxidizing agents are at the top of the table (more positive E° values), while stronger reducing agents are at the bottom (more negative E° values).
  • Examples of half-reactions and their E° values:
    • F2(g)+2e<br/>2F(aq)F_2(g) + 2e^- <br />\nrightarrow 2F^-(aq), E°=2.87VE° = 2.87 V
    • H<em>2O</em>2(aq)+2H+(aq)+2e<br/>2H2O(l)H<em>2O</em>2(aq) + 2H^+(aq) + 2e^- <br />\nrightarrow 2H_2O(l), E°=1.78VE° = 1.78 V
    • MnO<em>4(aq)+8H+(aq)+5eMn2+(aq)+4H</em>2O(l)MnO<em>4^-(aq) + 8H^+(aq) + 5e^- \nrightarrow Mn^{2+}(aq) + 4H</em>2O(l), E°=1.51VE° = 1.51 V
    • Cl2(g)+2e<br/>2Cl(aq)Cl_2(g) + 2e^- <br />\nrightarrow 2Cl^-(aq), E°=1.36VE° = 1.36 V
    • Cr<em>2O</em>72(aq)+14H+(aq)+6e<br/>2Cr3+(aq)+7H2O(l)Cr<em>2O</em>7^{2-}(aq) + 14H^+(aq) + 6e^- <br />\nrightarrow 2Cr^{3+}(aq) + 7H_2O(l), E°=1.36VE° = 1.36 V
    • O<em>2(g)+4H+(aq)+4e2H</em>2O(l)O<em>2(g) + 4H^+(aq) + 4e^- \nrightarrow 2H</em>2O(l), E°=1.23VE° = 1.23 V
    • Br2(aq)+2e<br/>2Br(aq)Br_2(aq) + 2e^- <br />\nrightarrow 2Br^-(aq), E°=1.09VE° = 1.09 V
    • Ag+(aq)+e<br/>Ag(s)Ag^+(aq) + e^- <br />\nrightarrow Ag(s), E°=0.80VE° = 0.80 V
    • Fe3+(aq)+e<br/>Fe2+(aq)Fe^{3+}(aq) + e^- <br />\nrightarrow Fe^{2+}(aq), E°=0.77VE° = 0.77 V
    • O<em>2(g)+2H+(aq)+2eH</em>2O2(aq)O<em>2(g) + 2H^+(aq) + 2e^- \nrightarrow H</em>2O_2(aq), E°=0.70VE° = 0.70 V
    • I2(s)+2e<br/>2I(aq)I_2(s) + 2e^- <br />\nrightarrow 2I^-(aq), E°=0.54VE° = 0.54 V
    • O<em>2(g)+2H</em>2O(l)+4e<br/>4OH(aq)O<em>2(g) + 2H</em>2O(l) + 4e^- <br />\nrightarrow 4OH^-(aq), E°=0.40VE° = 0.40 V
    • Cu2+(aq)+2e<br/>Cu(s)Cu^{2+}(aq) + 2e^- <br />\nrightarrow Cu(s), E°=0.34VE° = 0.34 V
    • Sn2+(aq)+2e<br/>Sn2+(aq)Sn^{2+}(aq) + 2e^- <br />\nrightarrow Sn^{2+}(aq), E°=0.15VE° = 0.15 V
    • 2H+(aq)+2e<br/>H2(g)2H^+(aq) + 2e^- <br />\nrightarrow H_2(g), E°=0VE° = 0 V
    • Pb2+(aq)+2e<br/>Pb(s)Pb^{2+}(aq) + 2e^- <br />\nrightarrow Pb(s), E°=0.13VE° = -0.13 V
    • Ni2+(aq)+2e<br/>Ni(s)Ni^{2+}(aq) + 2e^- <br />\nrightarrow Ni(s), E°=0.26VE° = -0.26 V
    • Cd2+(aq)+2e<br/>Cd(s)Cd^{2+}(aq) + 2e^- <br />\nrightarrow Cd(s), E°=0.40VE° = -0.40 V
    • Fe2+(aq)+2e<br/>Fe(s)Fe^{2+}(aq) + 2e^- <br />\nrightarrow Fe(s), E°=0.45VE° = -0.45 V
    • Zn2+(aq)+2e<br/>Zn(s)Zn^{2+}(aq) + 2e^- <br />\nrightarrow Zn(s), E°=0.76VE° = -0.76 V
    • 2H<em>2O(l)+2eH</em>2(g)+2OH(aq)2H<em>2O(l) + 2e^- \nrightarrow H</em>2(g) + 2OH^-(aq), E°=0.83VE° = -0.83 V
    • Al3+(aq)+3e<br/>Al(s)Al^{3+}(aq) + 3e^- <br />\nrightarrow Al(s), E°=1.66VE° = -1.66 V
    • Mg2+(aq)+2e<br/>Mg(s)Mg^{2+}(aq) + 2e^- <br />\nrightarrow Mg(s), E°=2.37VE° = -2.37 V
    • Na+(aq)+e<br/>Na(s)Na^+(aq) + e^- <br />\nrightarrow Na(s), E°=2.71VE° = -2.71 V
    • Li+(aq)+e<br/>Li(s)Li^+(aq) + e^- <br />\nrightarrow Li(s), E°=3.04VE° = -3.04 V

Cell Potential Calculation

  • The total cell potential can be expressed as: E°<em>cell=E°</em>ox+E°redE°<em>{cell} = E°</em>{ox} + E°_{red}
  • Example: Zn(s)+Cu2+(aq)Zn2+(aq)+Cu(s)Zn(s) + Cu^{2+}(aq) \nleftrightarrow Zn^{2+}(aq) + Cu(s)
    • E°_{Zn^{2+}(aq) + 2e^-
      rightleftharpoons Zn (s)} = -0.76V
    • E°_{Cu^{2+}(aq) + 2e^-
      rightleftharpoons Cu (s)} = +0.34V
    • Thus: E°cell=(0.76+0.34)V=1.10VE°_{cell} = (0.76 + 0.34)V = 1.10V

Practice Problem

  • What is the standard cell potential for the reaction:
    2 Ag^+(aq) + Cu (s)
    rightleftharpoons 2 Ag (s) + Cu^{2+}(aq)