U3 Ionic Compounds
Formation of Ions
Formation of ions is driven by the desire of atoms to achieve a stable electronic configuration, often an octet (eight electrons) in their valence shell, akin to noble gases.
Exception: Hydrogen, with only two electrons, considers this a full valence shell.
Metals vs. Non-Metals in Ion Formation
Metals:
Achieve an octet by losing electrons and thereby become positively charged ions.
Example: Sodium (Na) loses one electron to become Na+ (sodium ion).
Non-Metals:
Achieve an octet by gaining electrons and form negatively charged ions.
Example: Chlorine (Cl) gains one electron to become Cl- (chloride ion).
This electron transfer occurs simultaneously between metals and non-metals, resulting in the formation of both positive and negative ions.
Ionic Bonds and Ionic Compounds
Opposite charges attract, forming ionic bonds.
An ionic compound consists of one or more positive ions (cations) and negative ions (anions).
Types of Ions
Positive Ions (Cations):
Generally metals, i.e., Main Group Metals (e.g., sodium, calcium) or Transition Metals (e.g., copper, iron).
Exception: Ammonium ion (NH4+) is the only positive polyatomic ion prevalent in ionic compounds.
Negative Ions (Anions):
Can be single element ions (e.g., nitride N3-, chloride Cl-, sulfide S2-) or polyatomic ions (e.g., nitrate NO3-).
Many of these ions play crucial roles in biological systems and agriculture (e.g., ammonium, nitrate in fertilizers).
Naming Ions
It is essential to learn both the names and charges of common ions, as they'll be referenced extensively throughout chemistry courses.
Example summary of formation:
Sodium Atom: 1 valence electron
Chlorine Atom: 7 valence electrons
Formation Example
Sodium Chloride Formation:
Na transfers an electron to Cl, losing an electron to become Na+ and gaining an electron to become Cl-, forming the ionic compound Sodium Chloride.
Naming: Positive ions come first, negative ions second in the chemical name (sodium chloride).
Charge Balancing in Ionic Compounds
The formula for ionic compounds should reflect a neutral charge overall:
Example 1: Magnesium and Chlorine.
Magnesium (Mg) has 2 valence electrons and loses them to achieve an octet, becoming Mg2+.
Chlorine (Cl) gains one electron to become Cl-.
Two Cl- ions are needed for one Mg2+ to balance the charges (MgCl2).
Example 2: Potassium and Sulfur
Potassium (K) needs to lose one electron: K+
Sulfur (S) gains two electrons to become S2-.
Two K+ ions form K2S.
Crisscross Method for Ionic Compound Formulas
To derive the formula from ion charges:
Write the positive and negative ions, aligning their charges.
Cross the charges to create subscripts (do not write 1).
Example: For K+ and S2-
Crisscross yields K2S: 2 potassium ions for each sulfide ion.
Practice Problems
Ionic Compounds from Elements
Determine charges from groups, use charges to formulate compounds and name them.
Example pairs:
Sodium and Bromide:
Na+ + Br- → NaBr (Sodium Bromide).
Aluminum and Bromide:
Al3+ + Br- → AlBr3 (Aluminum Bromide).
Lowest common ratio method applied: A 3:3 ratio simplifies to 1:1 for aluminum nitride, resulting in AlN (Aluminum Nitride).
Reverse Engineering from Chemical Formulas
Given a formula, deduce ionic charges based on subscript ratios.
Example: Al2(SO4)3
Recognize Aluminum as Al3+ and Sulfate as SO42- to find that the compound is Aluminum Sulfate.
Transition Metals and Charge Notation
Transition metals (e.g., copper) may have multiple charges:
Specify charge in names (Cu+1 or Cu+2 → Copper(I) or Copper(II)).
Understanding Naming and Formulating Ionic Compounds
The proportionality of charges helps determine the subscripts.
Check the periodic table for confirmation of elemental charges.
Always identify and name the ions first, then combine based on charge neutrality.