Torque and Newton's Laws 8B
Announcements and Updates
Lecture quiz results were excellent, with no need for in-class review of specific questions. Individual results are available for review.
Today's focus is set 8B, covering torque, Newton's laws, and the biceps curl.
Exam 3 will follow the format of Exams 1 and 2: multiple-choice and true/false questions based on lecture and practice set material.
Exam 3 Information
The theta, omega, and alpha profiles for both the forearm segment angle and the included elbow joint angle during a biceps curl will be provided.
PVNA plots of the barbell will not be provided directly, although linear kinetics and energy concepts remain relevant.
The instructor plans to cover sets 9A and 9B before the exam, which focus on single-joint systems to understand individual muscle torque production.
There will be no lecture quiz due next week to allow focus on exam preparation.
Torpedo Bat Discussion
A new "torpedo bat" design was introduced, featuring a thicker cross-section in the primary contact area that tapers towards the end, contrasting traditional bats with uniform width after widening.
The modified bat design is legal, with the shape change intended to increase mass in the hitting zone and enlarge the contact surface area.
How might this change alter the moment of inertia of the bat about the grip end?
The moment of inertia decreases because mass is relocated closer to the axis of rotation (grip end), reducing the r^2 terms in the moment of inertia calculation.
This should make the bat easier to swing and increase angular acceleration and bat speed.
The primary performance enhancement is believed to be a larger hitting area and favorable center of percussion.
Angular Kinetics and Newton's Laws
The lecture returns to angular kinetics, focusing on how torque integrates Newton's laws into angular mechanics (kinematics and kinetics).
All three of Newton's laws are relevant in this context.
Mass moment of inertia is crucial, requiring consideration of mass distribution relative to the axis of rotation.
Mass Distribution in Limbs
The mass of human long segments (arms, legs) is typically distributed closer to the proximal end.
This distribution makes rotation about the proximal end easier due to lower moment of inertia.
In throwing, striking, and kicking, this mass distribution facilitates high angular velocities and accelerations.
Reducing the moment of inertia I allows more torque \tau to contribute to angular acceleration \alpha ($\$\tau = I \alpha\$).
Static vs. Dynamic Torque
Static component: Torque due to limb weight and moment arm.
Exists even when moving (dynamically).
Reducing R_wW (moment arm times weight) reduces resistance against muscle action.
More net torque can be used for angular acceleration.
Newton's First Law (Angular Inertia)
A rotating body will continue in a state of uniform angular motion unless acted on by an external torque.
Mathematically represented as: \sum \tau = 0.
Uniform angular motion implies constant angular momentum.
Angular momentum (L) is calculated as: L = I \omega, where I is the moment of inertia and \omega is the angular velocity.
If I changes, \omega must adjust to keep L constant when \sum \tau = 0.
Angular acceleration can occur without applied torque by altering the moment of inertia.
Conservation of Angular Momentum Examples
Figure skater spinning: By drawing arms and legs inward, the skater reduces their moment of inertia (I), causing an increase in angular velocity (\omega) to conserve angular momentum (L).
Divers: By tucking (reducing I), divers increase their angular velocity; extending (increasing I) slows rotation. Gravity pulls through their center of mass, thus having no external torque.
Newton's Second Law (Angular Kinetics)
Analogous to F = MA, the angular form is: \sum \tau = I \alpha, where \sum \tau is the sum of external torques, I is the moment of inertia, and \alpha is the angular acceleration.
For this equation to hold, I must be constant.
Torques can always be summed about the object's center of mass.
Torques can be summed about an axis other than the center of mass only if the axis is linearly fixed (pure rotation).
Angular acceleration must be in radians per second squared (rad/s^2) for calculations.
Constant moment of inertia implies a rigid body (no change in size or shape).
Implications of Angular Acceleration
A negative value of \alpha indicates acceleration opposite to the drawn direction in the diagram.
For a rigid object, angular acceleration is uniform throughout the plane, regardless of the summation point.
Free Body Diagrams and Equations of Motion
Two equations of motion can be applied: linear (\sum F = MA) and angular (\sum \tau = I \alpha).
Mass must be constant for \sum F = MA to be valid, \and I must be constant for \sum \tau = I \alpha to be valid.
Even if I is not constant, the linear equation of motion can still be used.
The right-hand side of the angular equation (\tau = I \alpha) is referred to as the inertial torque.
Biceps Curl Example: Summing Torques About the Center of Mass
When summing about the center of mass, forces like the bone-on-bone force at the elbow joint, originally dismissed, now factor in due to a moment arm relative to the center of mass.
The equation becomes complex but remains mathematically valid.
Biceps Curl Example: Pure Rotation at the Elbow
In pure rotation, torques can be summed about the elbow joint: \sum \tau{elbow} = I{elbow} \alpha.
Muscle torque is positive (counterclockwise), weight torque (WRW) is negative, and the hand force torque is negative.
Simplified Biceps Curl Analysis
The barbell weight can be merged into the forearm and hand system for simplification.
The total system weight is the sum of forearm/hand and barbell weights.
The total moment of inertia is the sum of forearm/hand and barbell moments of inertia.
Benefits of Simplification
The simplified equation highlights that muscle torque offsets the torque due to the weight of the system, with any remaining torque contributing to angular acceleration.
The force at the hand is now internal to the system and not considered a torque producer.
Limitations of the Simplified Model
The model assumes only one muscle is responsible for torque generation, which isn't realistic.
Multiple muscles (biceps, brachialis, brachioradialis, pronator teres) contribute to elbow flexion.
Passive elements (ligaments, fascia) and antagonists can also produce torques.
Generalized Free Body Diagram
A technique to simplify the free body diagram while accounting for multiple forces.
Forces crossing the joint are grouped into a single joint reaction force.
The torque produced by these forces about the elbow joint is accounted for by a net muscular moment.
Net Muscular Moment
The sum of all torque-producing elements, including muscles, bone-on-bone force, ligaments, and fascia, at the elbow joint.
Mathematically represented as:
\sum (Elbow \, Flexors) - \sum (Elbow \, Extensors) + \sum (Passive \, Components)
Can represent flexor or extensor torques without focusing on individual muscles.
Angular Equation of Motion with Generalized Free Body Diagram
The equation becomes: NMM - WRW = I \alpha
NMM: Net Muscular Moment (torque produced by muscles)
WRW: Torque due to weight
I \alpha: Inertial torque
This equation includes any combination of flexor, extensor, and passive tissues creating torques at the joint.
It still accounts for weight and inertial torque.
Linear Equation of Motion with Generalized Free Body Diagram
Incorporates force arrows without addressing the torque arrow.
Addresses the forces in horizontal and vertical directions.
Torque Profiles Under Different Conditions
Net muscular moment at the elbow during a biceps curl under quasi-static conditions:
Linear and angular acclerations are zero.
Equation reduces to NMME = WRW.
Torque is greatest when weight is furthest horizontally from the elbow joint.
Uniphasic activation pattern, with flexor torque needed throughout the entire up and down phases.
Net muscular moment at the elbow during a biceps curl under dynamic conditions:
I \alpha is not zero, but is smaller than WRW.
Adding I \alpha$$ and WRW terms together.
Constant I, thus I can be constant only here.
Hill valley valley hill profile.