Phosphorus-31: Protons, Neutrons, and Electrons
- Isotope notation basics
- In isotope notation, the mass number A is placed on top and the atomic number Z on the bottom, with the element symbol to the right: ZAX
- For phosphorus with mass number 31 and atomic number 15, the symbol is 1531P
- Phosphorus facts used here
- Phosphorus atomic number: Z=15
- Phosphorus mass number given: A=31
- The goal: find numbers of protons, neutrons, and electrons for a neutral phosphorus atom with A = 31
- Key relationships (foundational formulas)
- Total nucleons (protons + neutrons): A=Z+N
- Neutron count: N=A−Z
- For a neutral atom, electrons equal protons: E=Z
- Step-by-step calculation for ^{31}_{15}P
- Protons (p): Z=15
- Neutrons (n): N=A−Z=31−15=16
- Electrons in a neutral atom (e): E=Z=15
- Isotope notation confirmation
- The complete isotope symbol for this phosphorus atom is: 1531P
- Summary of counts for neutral phosphorus-31
- Protons: 15
- Neutrons: 16
- Electrons: 15
- Special cases
- If the phosphorus atom is ionized with charge +1, electrons would be E=Z−1=14
- If ionized with charge -1, electrons would be E=Z+1=16
- Quick cross-check
- Total nucleons check: p+n=15+16=31=A
- Charge balance for neutral atom: net charge = 0 since protons and electrons are equal in number
- Context and significance
- Phosphorus-31 is the only stable isotope of phosphorus, with 15 protons and 16 neutrons
- The 31P nucleus geometry and neutron count influence nuclear stability and nuclear magnetic resonance properties
- In biology and chemistry, phosphorus is essential (e.g., ATP, DNA backbones); isotope 31P is often used in 31P NMR spectroscopy for studying biochemical processes
- Practical takeaway
- To determine subatomic counts from A and Z: use p=Z, n=A−Z, e=Z (for neutral atoms)
- To write the isotope symbol: top = A, bottom = Z, symbol = element
- Connections to broader concepts
- Distinction between mass number A and atomic mass: A is an integer count of nucleons; atomic mass is a weighted average of isotopes
- Isotopes share chemical properties but differ in mass and nuclear properties
- Example recap (for memory)
- Given: A=31,Z=15
- Protons: p=Z=15
- Neutrons: n=A−Z=16
- Electrons (neutral): e=Z=15
- Key formulas to memorize
- A=Z+N
- N=A−Z
- E=Z (neutral atom)
- Final answer for the transcript prompt
- Protons = 15, Neutrons = 16, Electrons (neutral) = 15
- Note on notation used in the transcript
- Writing the symbol with mass number on top and atomic number on bottom is a standard isotope notation approach, corroborated here by the example 1531P