Graph Intercepts & Symmetry
Graph Intercepts
Intercepts are points where a graph crosses or touches an axis.
x-intercept(s): Point(s) where the graph crosses the x-axis (). Represented as .
y-intercept(s): Point(s) where the graph crosses the y-axis (). Represented as .
Interpreting Intercepts and Maxima in Context
When analyzing graphs representing real-world scenarios:
The y-intercept typically represents the starting value or initial condition (e.g., initial height when horizontal distance is zero).
The x-intercept typically represents a final state or a specific condition when the dependent variable is zero (e.g., total horizontal distance traveled when height is zero).
A maximum point indicates the peak value of the dependent variable and the corresponding independent variable at which it occurs (e.g., maximum height and the horizontal distance at which it's achieved).
Finding Intercepts Algebraically
To find intercepts for an equation:
x-intercept(s): Set and solve for .
y-intercept(s): Set and solve for .
Examples:
For :
x-intercepts: $0 = x^2 + 1
ightarrow x^2 = -1y = 0^2 + 1
ightarrow y = 1(0, 1)y = x^2 + 810 = x^2 + 81
ightarrow x^2 = -81y = 0^2 + 81
ightarrow y = 81(0, 81)y = x^3 - 5120 = x^3 - 512
ightarrow x^3 = 512
ightarrow x = 8(8, 0)y = 0^3 - 512
ightarrow y = -512(0, -512)(x, y)(x, -y)y-y(x, y)(-x, y)x-x(x, y)(-x, -y)x-xy-yy = x^2 + 81-y = x^2 + 81
ightarrow y = -x^2 - 81y = (-x)^2 + 81
ightarrow y = x^2 + 81-y = (-x)^2 + 81
ightarrow -y = x^2 + 81
ightarrow y = -x^2 - 81y = x^3 - 512-y = x^3 - 512
ightarrow y = -x^3 + 512y = (-x)^3 - 512
ightarrow y = -x^3 - 512-y = (-x)^3 - 512
ightarrow -y = -x^3 - 512
ightarrow y = x^3 + 512$$. No.