Hypothesis Testing for Population Proportions: One-Sample and Two-Sample Inference

Foundations of Hypothesis Testing

  • Definition of Hypothesis Testing: A formal statistical procedure that enables choosing between two competing claims when there is inherent variability in measurements.
  • The Four Steps of Hypothesis Testing:
    • Hypothesize: Formulate a specific claim (the alternative hypothesis) to be tested against a neutral, skeptical baseline claim (the null hypothesis).
    • Prepare: Select the significance level (α\alpha), choose the appropriate test statistic, check that all underlying mathematical conditions and assumptions are satisfied, and confirm that the sample size is sufficiently large to minimize decision errors.
    • Compare and Compute: Gather sample data, compare the observed sample value to the null expected value, compute the test statistic, and calculate the p-value to quantify the degree of surprise under the null hypothesis.
    • Interpret: Decide whether to reject or fail to reject the null hypothesis by comparing the p-value to α\alpha, and state a clear conclusion within the real-world context of the data.
  • Introductory Coin-Spinning Example:
    • Hypothesis: A coin is spun on a flat surface. It is hypothesized that the coin is more likely to land on heads because the heads side bulges out slightly relative to the tails side.
    • Data Collection: The coin is spun 2020 times, resulting in heads on all 2020 spins.
    • Step-by-Step Breakdown:
      • Hypothesize: Test the claim that heads is more likely (p>0.50p > 0.50) against the neutral hypothesis that the coin is fair (p=0.50p = 0.50).
      • Prepare: Use the sample proportion of heads across n=20n = 20 spins as the decision metric.
      • Compare and Compute: If the coin were fair, approximately 50%50\% of spins (1010 heads) would be expected. Obtaining 2020 heads in 2020 spins is exceptionally far above expectation.
      • Interpret: Obtaining 2020 heads in 2020 spins is extremely unusual under the assumption of a fair coin. Therefore, conclude that the coin is genuinely more likely to land on heads when spun.

Formulating Null and Alternative Hypotheses

  • The Null Hypothesis (H0H_0):
    • Represents the neutral, status quo, or skeptical statement about a population parameter.
    • Always written with an equality sign (==).
    • Receives the benefit of the doubt throughout the entire testing procedure.
    • Is only rejected when the observed sample data would be extraordinarily rare or unusual if H0H_0 were true.
    • Legal Analogy: Analogous to a criminal jury trial, where a defendant is presumed innocent until proven guilty "beyond a reasonable doubt."
  • The Alternative Hypothesis (HaH_a):
    • Represents the research hypothesis or claim of change that the investigation seeks to support.
    • Always formulated using an inequality symbol: strictly less than (<<), strictly greater than (>>), or not equal to (≠\neq).
  • Structure of One-Sided and Two-Sided Hypotheses:
    • One-Sided (Left-Tailed):
      • H0:p=p0H_0: p = p_0
      • Ha:p<p0H_a: p < p_0
    • One-Sided (Right-Tailed):
      • H0:p=p0H_0: p = p_0
      • Ha:p>p0H_a: p > p_0
    • Two-Sided:
      • H0:p=p0H_0: p = p_0
      • Ha:p≠p0H_a: p \neq p_0
  • Retail Internet Sales Case Study:
    • Context: In the previous fiscal year, 30%30\% (p=0.30p = 0.30) of a retailer's total sales were generated online. The retailer subsequently invested in social media advertising and sampled sales across 2020 random days during the current fiscal year.
    • Two-Sided Question: "Has there been a change in the percentage of online sales?"
      • H0:p=0.30H_0: p = 0.30
      • Ha:p≠0.30H_a: p \neq 0.30
  • One-Sided Question: "Have sales increased?"
    • H0:p=0.30H_0: p = 0.30
    • Ha:p>0.30H_a: p > 0.30

The Test Statistic and Standard Error for Proportions

  • Conceptual Role of a Test Statistic:
    • Quantifies the difference between the observed sample outcome and the value expected under the null hypothesis.
    • Standardizes this discrepancy by expressing it in terms of standard deviations (standard errors).
    • When the test statistic lies far from zero in the direction specified by the alternative hypothesis, it provides evidence to reject H0H_0.
  • General Formula:
    • Test Statistic=Observed Value−Null ValueStandard Error\text{Test Statistic} = \frac{\text{Observed Value} - \text{Null Value}}{\text{Standard Error}}
  • One-Sample Proportion Formula (zz-Statistic):
    • z=p^−p0SEz = \frac{\hat{p} - p_0}{SE}
    • SE=p0(1−p0)nSE = \sqrt{\frac{p_0(1 - p_0)}{n}}
    • p^\hat{p}: The observed sample proportion, calculated as p^=xn\hat{p} = \frac{x}{n}, where xx is the number of successes and nn is the total number of observations.
    • p0p_0: The hypothesized population proportion from the null hypothesis (H0H_0).
    • SESE: The standard error of the sample proportion computed under the assumption that H0H_0 is true.

The p-Value and the Significance Level

  • The p-Value as a Metric of Surprise:
    • Definition: The probability of obtaining a test statistic that is as extreme as or more extreme than the observed value, assuming the null hypothesis is true.
    • A small p-value indicates that the observed sample data would be exceptionally unusual under H0H_0, casting strong doubt on the null hypothesis.
    • As the magnitude of the test statistic (∣z∣|z|) increases, the tail area beyond it decreases, resulting in a smaller p-value.
  • Determining p-Values from the Alternative Hypothesis:
    • Two-Sided Test (Ha:p≠p0H_a: p \neq p_0): The p-value equals the combined area of both tails beyond ±∣z∣\pm |z|.
    • Two-sided test normal distribution with both tails shaded
    • Right-Tailed Test (Ha:p>p0H_a: p > p_0): The p-value equals the area under the standard normal curve to the right of the test statistic (zz).
    • Right-tailed test normal distribution with right tail shaded
    • Left-Tailed Test (Ha:p<p0H_a: p < p_0): The p-value equals the area under the standard normal curve to the left of the test statistic (zz).
  • The Significance Level (α\alpha):
    • The predetermined threshold representing the maximum probability tolerated of incorrectly rejecting a true null hypothesis (Type I error).
    • Standard thresholds are commonly α=0.05\alpha = 0.05, α=0.01\alpha = 0.01, or α=0.10\alpha = 0.10.
  • Decision Rules:
    • If p<αp < \alpha: Reject H0H_0. The evidence supporting the alternative hypothesis is statistically significant.
    • If p≥αp \ge \alpha: Fail to reject H0H_0. There is insufficient evidence to conclude that H0H_0 is false.

Required Assumptions and Conditions for One-Sample Proportion Tests

  • Random Sampling Condition: The sample must be selected using a random sampling method (such as a simple random sample) to represent the target population without bias.
  • Large Sample Size (Success/Failure Condition):
    • The expected number of successes must be at least 1010: np0≥10n p_0 \ge 10.
    • The expected number of failures must be at least 1010: n(1−p0)≥10n(1 - p_0) \ge 10.
    • This condition ensures that the sampling distribution of p^\hat{p} is approximately normal.
  • Large Population Condition (10% Condition): When sampling without replacement, the total population size (NN) must be at least 1010 times larger than the sample size (nn):
    • N≥10nN \ge 10n
  • Independence Condition: Each observed individual or trial must have no influence on any other observation in the sample.

One-Sample Proportion Examples and Case Studies

  • Global Warming Cool Skeptics Example (Gallup 2001 vs. 2014):
    • Context: In 20012001, Gallup reported that 12%12\% (p0=0.12p_0 = 0.12) of Americans were "cool skeptics" who worried "a little or not at all" about global warming. In 20142014, a poll of n=500n = 500 Americans found 25%25\% (p^=0.25\hat{p} = 0.25) identifying as cool skeptics.
    • Hypotheses: H0:p=0.12H_0: p = 0.12 versus Ha:p>0.12H_a: p > 0.12 (right-tailed).
    • Count of Successes: x=n×p^=500×0.25=125x = n \times \hat{p} = 500 \times 0.25 = 125.
    • Standard Error: SE=0.12(1−0.12)500=0.12×0.88500≈0.014532722SE = \sqrt{\frac{0.12(1 - 0.12)}{500}} = \sqrt{\frac{0.12 \times 0.88}{500}} \approx 0.014532722.
    • Test Statistic Calculation:
      • z=0.25−0.120.12(1−0.12)500=0.130.014532722≈8.9453306≈8.95z = \frac{0.25 - 0.12}{\sqrt{\frac{0.12(1 - 0.12)}{500}}} = \frac{0.13}{0.014532722} \approx 8.9453306 \approx 8.95
      • The sample proportion lies 8.958.95 standard errors above the hypothesized null value.
    • p-Value and Interpretation:
      • Using the standard normal distribution, the probability of obtaining a zz-score greater than or equal to 8.958.95 is P(X≥8.95)<0.0001P(X \ge 8.95) < 0.0001 (StatCrunch output displays 00).
      • Standard normal curve showing z=8.95 and p-value of 0
      • Conclusion: Because p<0.05p < 0.05, reject H0H_0. There is sufficient evidence to conclude that the percentage of American cool skeptics has increased since 20012001.
    • StatCrunch Procedure: Navigate to Stat > Proportion Stats > One Sample > With Summary. Input 125125 successes, 500500 observations, set null proportion to 0.120.12, and select >> for HAH_A.
  • College Student Loan Dropout Rate Example:
    • Context: Time Magazine (June 11, 2012) reported that the dropout rate for all college students with loans is 30%30\%. A random sample of n=200n = 200 college students with loans reveals 6565 dropouts.
    • Hypotheses: H0:p=0.30H_0: p = 0.30 versus Ha:p≠0.30H_a: p \neq 0.30 (two-sided).
    • TI-84 1-PropZTest Results:
      • Test statistic: z=0.7715z = 0.7715
      • p-value: p=0.4404p = 0.4404
      • TI-84 1-PropZTest graph showing normal distribution with shaded tails and z=0.7715
    • Conclusion: The p-value of 0.44040.4404 is substantially larger than α=0.05\alpha = 0.05. Fail to reject H0H_0. There is insufficient evidence that the dropout rate differs from 30%30\%.
  • Support for the Death Penalty Example (Declining Trend):
    • Context: In 20092009, 63%63\% of Americans supported the death penalty. In 20142014, a Rasmussen Poll of n=943n = 943 Americans found 538538 supported it.
    • Hypotheses: Testing for a decline gives H0:p=0.63H_0: p = 0.63 versus Ha:p<0.63H_a: p < 0.63.
    • Test Metrics:
      • Sample proportion: p^=538943≈0.57051962\hat{p} = \frac{538}{943} \approx 0.57051962
      • Standard error: SE≈0.015722271SE \approx 0.015722271
      • Test statistic: z=−3.7831926z = -3.7831926
      • p-value: p<0.0001p < 0.0001
    • Conclusion: Reject H0H_0. Sufficient evidence indicates that support for the death penalty among Americans has declined since 20092009.
  • Public Library Funding Example:
    • Context: A random poll of n=250n = 250 voters in a city found 140140 favoring increased funding for public libraries. Test whether a majority (more than 50%50\%) favors funding at α=0.01\alpha = 0.01.
    • Hypotheses: H0:p=0.50H_0: p = 0.50 versus Ha:p>0.50H_a: p > 0.50.
    • Test Metrics:
      • Count: 140140, Total: 250250
      • Sample proportion: p^=140250=0.56\hat{p} = \frac{140}{250} = 0.56
      • Standard error: SE=0.50×0.50250≈0.031622777SE = \sqrt{\frac{0.50 \times 0.50}{250}} \approx 0.031622777
      • Test statistic: z=1.8973666≈1.90z = 1.8973666 \approx 1.90
      • p-value: p=0.0289p = 0.0289
    • Conclusion: Compare p=0.0289p = 0.0289 to α=0.01\alpha = 0.01. Because 0.0289≮0.010.0289 \not< 0.01, fail to reject H0H_0. The evidence is not strong enough at the 1%1\% significance level to conclude that a majority of city voters favor increased funding.
  • Sleepwalking Prevalence Example:
    • Context: Time Magazine (May 28, 2012) reported that 33%33\% of Americans have sleepwalked at least once. A sample of n=200n = 200 people found 4242 who reported sleepwalking. Test whether the proportion differs from 0.330.33 at α=0.05\alpha = 0.05.
    • Hypotheses: H0:p=0.33H_0: p = 0.33 versus Ha:p≠0.33H_a: p \neq 0.33.
    • Test Metrics:
      • Count: 4242, Total: 200200
      • Sample proportion: p^=42200=0.21\hat{p} = \frac{42}{200} = 0.21
      • Standard error: SE=0.03324906SE = 0.03324906
      • Test statistic: z=−3.6091246z = -3.6091246
      • p-value: p=0.0003p = 0.0003
    • Conclusion: Since p=0.0003<0.05p = 0.0003 < 0.05, reject H0H_0. The proportion of Americans who have sleepwalked is significantly different from 0.330.33.
  • Global Warming Belief Example (Gallup 2010):
    • Context: Historically (2001 to 2005), about 58%58\% (p0=0.58p_0 = 0.58) of Americans believed Earth's temperature was rising. A March 20102010 Gallup poll of n=1014n = 1014 adults found 527527 believing global warming was real. Test whether this proportion changed at α=0.05\alpha = 0.05.
    • Hypotheses: H0:p=0.58H_0: p = 0.58 versus Ha:p≠0.58H_a: p \neq 0.58.
    • Sample Proportion: p^=5271014≈0.51972387\hat{p} = \frac{527}{1014} \approx 0.51972387 (51.97%51.97\%), which is less than the historical 58%58\%.
    • Test Metrics:
      • Standard error: SE=0.015499571SE = 0.015499571
      • Test statistic: z=−3.8888906z = -3.8888906
      • p-value: p=0.0001p = 0.0001
    • Conclusion: Reject H0H_0. In 20102010, the percentage of Americans who believe global warming is real changed significantly from the historical baseline of 58%58\%.
  • Taxes on the Wealthy Example:
    • Context: A poll of n=500n = 500 randomly selected independent respondents found 281281 who believe the rich should pay more taxes. Test whether a majority favors higher taxes at α=0.05\alpha = 0.05.
    • Hypotheses: H0:p=0.50H_0: p = 0.50 versus Ha:p>0.50H_a: p > 0.50.
    • Test Metrics:
      • Sample proportion: p^=281500=0.562\hat{p} = \frac{281}{500} = 0.562
      • Standard error: SE=0.02236068SE = 0.02236068
      • Test statistic: z=2.7727243z = 2.7727243
      • p-value: p=0.0028p = 0.0028
      • Standard normal distribution curve with z=2.7727 and right tail shaded with p=0.0028
    • Conclusion: Because p=0.0028<0.05p = 0.0028 < 0.05, reject H0H_0. There is sufficient evidence that a majority of the population believes the rich should pay more taxes.

Decision Errors in Hypothesis Testing

  • Definitions of Decision Errors:
    • Type I Error: Rejecting the null hypothesis when H0H_0 is actually true.
      • The probability of committing a Type I error equals the significance level: P(Type I error)=αP(\text{Type I error}) = \alpha.
    • Type II Error: Failing to reject the null hypothesis when H0H_0 is actually false.
  • Hypothesis Testing Decision Matrix:
    • When H0H_0 is True & Action is Reject H0H_0: Type I error (probability =α= \alpha).
    • When H0H_0 is True & Action is Fail to Reject H0H_0: Good decision (correct inference).
    • When H0H_0 is False & Action is Reject H0H_0: Good decision (correct inference).
    • When H0H_0 is False & Action is Fail to Reject H0H_0: Type II error.
  • School Bond Ballot Measure Example:
    • Hypotheses: H0:p=0.50H_0: p = 0.50 versus Ha:p>0.50H_a: p > 0.50.
    • Type I Error Formulation: The analyst concludes that more than 50%50\% of voters favor the bond when, in reality, the actual proportion favoring the bond is 50%50\% or less.
    • Type II Error Formulation: The analyst concludes that 50%50\% or less favor the bond when, in reality, more than 50%50\% actually favor it.
    • Significance Level (α=0.05\alpha = 0.05) Meaning: There is exactly a 5%5\% probability of mistakenly concluding that a majority favors the bond when the true support is 50%50\% or less.
  • Balancing and Mitigating Errors:
    • Decreasing α\alpha lowers the probability of a Type I error, but automatically increases the probability of a Type II error.
    • The only method to simultaneously reduce the likelihood of both Type I and Type II errors is to increase the sample size (nn), which improves estimator precision.
  • Statistical versus Practical Significance:
    • A result is practically significant only if it is both statistically significant and practically meaningful.
    • Cancer Risk Metaphor: Suppose the baseline risk of developing a rare cancer is 11 in 10 million10\text{ million}. A study finds that daily cell phone usage doubles this risk to 22 in 10 million10\text{ million}. While the doubling of risk may be statistically significant in a massive sample, a risk of 22 in 10 million10\text{ million} is practically negligible and unlikely to alter human behavior.
  • Mandatory Language Cautions:
    • Because sample estimates are subject to sampling variability, absolute certainty is impossible.
    • When the p-value is greater than or equal to α\alpha, never state:
      • "We accept H0H_0."
      • "We have proved H0H_0 is true."
    • Permissible phrasing includes:
      • "We fail to reject H0H_0."
      • "We cannot reject H0H_0."

Confidence Intervals and Two-Sided Hypothesis Tests

  • Relationship and Inherent Questions:
    • Confidence Interval Question: "What is the value of this parameter?"
    • Hypothesis Test Question: "Are the data consistent with the parameter being one particular value, or might the parameter be something else?"
  • Equivalence for Two-Sided Tests:
    • A two-sided hypothesis test conducted at significance level α\alpha reaches conclusions consistent with a (1−α)×100%(1 - \alpha) \times 100\% confidence interval.
    • If the hypothesized parameter value (p0p_0) falls inside the confidence interval, fail to reject H0H_0.
    • If p0p_0 lies completely outside the confidence interval, reject H0H_0.
  • Mapping Confidence Levels to Significance Levels:
    • 90%90\% Confidence Level (1−α=0.901 - \alpha = 0.90) corresponds to a Two-Sided (≠\neq) test at α=10%\alpha = 10\% (0.100.10).
  • 95%95\% Confidence Level (1−α=0.951 - \alpha = 0.95) corresponds to a Two-Sided (≠\neq) test at α=5%\alpha = 5\% (0.050.05).
  • 99%99\% Confidence Level (1−α=0.991 - \alpha = 0.99) corresponds to a Two-Sided (≠\neq) test at α=1%\alpha = 1\% (0.010.01).
  • Death Penalty Example (Two-Sided Synthesis):
    • Hypotheses: H0:p=0.63H_0: p = 0.63 versus Ha:p≠0.63H_a: p \neq 0.63.
  • Sample Data: n=943n = 943, x=538x = 538, p^≈0.57051962\hat{p} \approx 0.57051962.
  • Hypothesis Test Output: Test statistic z=−3.7831926z = -3.7831926, p-value =0.0002= 0.0002. Since p<0.05p < 0.05, reject H0H_0.
  • 95% Confidence Interval Construction:
    • Using the Standard-Wald method:
    • Lower Limit: 0.538926010.53892601
    • Upper Limit: 0.602113220.60211322
    • Interval: (0.54,0.60)(0.54, 0.60)
  • Synthesis: The null value p0=0.63p_0 = 0.63 is not contained within the 95%95\% confidence interval (0.54,0.60)(0.54, 0.60). This directly confirms the hypothesis test rejection, proving that American support for the death penalty has changed.

Comparing Proportions Across Two Independent Populations

  • Assumptions and Conditions for Two-Sample Tests:
    • Large Samples: Both sample sizes must be large enough to ensure normal approximations for each sample proportion.
    • Random Samples: Both samples must be selected randomly.
    • Independent within Samples: Observations within sample 1 must be independent of one another, and observations within sample 2 must be independent of one another.
    • Independent Samples: The two groups being compared must be completely independent of each other.
  • Hypothesis Formulations for Two Proportions:
    • H0:p1=p2H_0: p_1 = p_2 (or equivalently, H0:p1−p2=0H_0: p_1 - p_2 = 0)
    • Alternative options:
      • Ha:p1<p2H_a: p_1 < p_2 (or p1−p2<0p_1 - p_2 < 0)
      • Ha:p1>p2H_a: p_1 > p_2 (or p1−p2>0p_1 - p_2 > 0)
      • Ha:p1≠p2H_a: p_1 \neq p_2 (or p1−p2≠0p_1 - p_2 \neq 0)
  • Economic Confidence Example (Gallup 2014 vs. 2015):
    • Context: In January 20142014, Gallup reported that 45%45\% of Americans felt "pretty good" about their spending money (n1=3500n_1 = 3500). In January 20152015, Gallup reported 49%49\% felt this way (n2=3500n_2 = 3500). Test whether economic confidence improved at α=0.05\alpha = 0.05.
    • Hypotheses: H0:p1−p2=0H_0: p_1 - p_2 = 0 versus Ha:p1−p2<0H_a: p_1 - p_2 < 0.
    • Success Counts:
      • x1=n1p1=3500×0.45=1575x_1 = n_1 p_1 = 3500 \times 0.45 = 1575
      • x2=n2p2=3500×0.49=1715x_2 = n_2 p_2 = 3500 \times 0.49 = 1715
    • StatCrunch Output Results:
      • Sample difference: p^1−p^2=−0.04\hat{p}_1 - \hat{p}_2 = -0.04
      • Standard error: SE=0.011930753SE = 0.011930753
      • Test statistic: z=−3.3526804≈−3.35z = -3.3526804 \approx -3.35
      • p-value: p=0.0004p = 0.0004 (0.000404060.00040406)
      • Left-tail normal distribution curve for economic confidence test
    • Conclusion: Because p=0.0004<0.05p = 0.0004 < 0.05, reject H0H_0. The population proportion who felt confident was significantly higher in 20152015 than in 20142014.
    • StatCrunch Procedure: Navigate to Stat > Proportion Stats > Two Sample > With Summary. Enter Sample 1 (15751575 successes, 35003500 observations) and Sample 2 (17151715 successes, 35003500 observations). Select << under the hypothesis test for p1−p2p_1 - p_2.
  • Gender Differences in Texting While Driving Example:
    • Context: A survey investigates whether texting while driving varies by gender. Data is collected from a random sample of n1=80n_1 = 80 men and n2=60n_2 = 60 women. Of the men, x1=38x_1 = 38 texted while driving; of the women, x2=27x_2 = 27 texted while driving. Test at α=0.05\alpha = 0.05.
    • Hypotheses: H0:p1−p2=0H_0: p_1 - p_2 = 0 versus Ha:p1−p2≠0H_a: p_1 - p_2 \neq 0.
  • StatCrunch Output Results:
    • Sample proportions: p^1=3880=0.475\hat{p}_1 = \frac{38}{80} = 0.475, p^2=2760=0.45\hat{p}_2 = \frac{27}{60} = 0.45
    • Sample difference: p^1−p^2=0.475−0.45=0.025\hat{p}_1 - \hat{p}_2 = 0.475 - 0.45 = 0.025 (2.5%2.5\%)
    • Standard error: SE=0.085173143SE = 0.085173143
    • Test statistic: z=0.29351975≈0.29z = 0.29351975 \approx 0.29
    • p-value: p=0.7691≈0.77p = 0.7691 \approx 0.77
  • Conclusion: With p=0.77≥0.05p = 0.77 \ge 0.05, fail to reject H0H_0. An observed sample difference of 2.5%2.5\% is expected to occur frequently by chance when the true proportions are equal. There is insufficient evidence of a difference in texting while driving rates between men and women.

Conceptual Checks and Review Problems

  • Extreme Test Statistics in Left-Tailed Tests:
    • Question: In a left-tailed test, which test statistic provides the strongest evidence against H0H_0: −2.78-2.78, −1.64-1.64, 0.0010.001, or 2.952.95?
    • Answer: −2.78-2.78. The value farthest from 00 in the negative direction provides the smallest left-tail area and lowest p-value. (In a right-tailed test, 2.952.95 would provide the strongest evidence).
  • Strong Evidence Metric:
    • In hypothesis testing, strong evidence against the null hypothesis occurs when the p-value is close to 00.
  • Stricter Gun Laws Example:
    • Context: In 20102010, 48%48\% of voters favored stricter gun control. A researcher tested Ha:p>0.48H_a: p > 0.48, obtaining z=1.27z = 1.27 and p=0.10p = 0.10.
    • Correct Interpretation: At α=0.05\alpha = 0.05, there is not enough evidence to conclude that the proportion has increased. (It is incorrect to state that "the proportion is still 48%48\%" because a hypothesis test never proves H0H_0).
  • Public Smiling Frequency by Gender Example:
    • Context: A researcher tests whether men (Population 1) smile less often in public than women (Population 2). Alternative hypothesis: Ha:p1<p2H_a: p_1 < p_2. Output yields z=−6.13z = -6.13 and p<0.0001p < 0.0001.
    • Correct Interpretation: Evidence indicates that men smile less often in public than women.