Lecture 3: Forces and Dynamics
Dynamics
Dynamics
- Deals with the study of forces and their effect on motion.
Newton's Second Law
- F = ma is the fundamental equation.
- F represents force.
- m represents mass.
- a represents acceleration.
- Applies to a point mass or an object that can be treated as a point mass.
Non-inertial Reference Frames
- Lab reference frame is considered a non-inertial reference frame.
- In a non-inertial reference frame, the equation F_{net} = ma does not hold true directly. A fictitious force needs to be introduced.
- Fictitious Force: F_{fictitious} = -mA, where A is the acceleration of the non-inertial reference frame.
- The transformation of acceleration from an inertial frame to a non-inertial frame is given by: a = a' + A, where:
- a is the acceleration in the inertial frame.
- a' is the acceleration in the non-inertial frame.
- A is the acceleration of the non-inertial frame with respect to the inertial frame.
- Therefore, a' = a + (-A) = a - A
- The net force in the inertial frame is F_{net} = m(a'+ A)
- In the non-inertial frame, the modified Newton's second law is:
- F_{net} + (-mA) = ma'
- F{net} + F{fictitious} = ma'
- If one were to use the non-intertial reference frame, then F_{net} = ma'
Example: Pendulum in an Accelerating Car
- Consider a pendulum inside a car accelerating with acceleration A.
- The tension in the string is T.
- In the non-inertial frame (inside the car), the forces acting on the pendulum bob are:
- Tension T.
- Weight mg.
- Fictitious force -mA.
- The pendulum will deflect at an angle such that the net force balances.
- T_x = mA
- T_y = mg
- The time period of the pendulum is T = 2\pi \sqrt{\frac{l}{g{eff}}}, where g{eff} is the effective acceleration due to gravity.
- Here, g_{eff} = \sqrt{g^2 + A^2}
Steps to Solve F = ma Problems
- Applicable to n-object systems.
- Write down F = ma for each object. This will give you n equations.
- Identify all unknown variables (n+m in total).
- Identify all forces acting on each object.
- Identify constraints on the motion of the objects. These constraints will give you m additional equations.
- Solve the system of equations to find the unknowns.
Example: Two Blocks Connected by a String
- Two blocks with masses M and m are connected by a string over a pulley.
- M is on a horizontal surface, and m is hanging vertically.
- Forces on M: Tension T and friction.
- Forces on m: Tension T and weight mg.
- Equations for M:
- \sum Fx = T = Max
- \sum F_y = N - Mg = 0
- Equations for m:
- Constraint: ax = ay = a
- Solve for T and a.
Example: Block on an Inclined Plane in an Accelerating System
- A block of mass m is on an inclined plane (angle θ) inside an accelerating system (acceleration Ax). The acceleration in y direction is zero (Ay = 0).
- The acceleration in the non-inertial frame is a = a' + A
- ax = a'x + (-A_x)
- ay = a'y + 0
- Forces: Normal force N, weight mg.
- Equations:
- N \sin(\theta) = m a_x (∑Fx = max)
- N \cos(\theta) = mg (∑Fy = may)
- Constraint Example: Two masses connected by a string over a pulley.
- m1 and m2 are connected by the string the constraints that relate the acceleration is a1 = -a2
- m1 a1 = T - m_1g
- m2 a2 = m_2g -T
- \frac{d^2x1}{dt^2} = - \frac{d^2x2}{dt^2}