Normal Force Calculation for a 25.0 kg Object on a Frictionless Surface

Problem Statement: A 25.0 kg object is being pulled along a frictionless horizontal surface by a horizontal net force of 15.0 N.
Given Data:
- Mass of the object, ( m = 25.0 \, \text{kg} )
- Horizontal net force, ( F = 15.0 \, \text{N} )
Objective: Determine the normal force acting on the object.

Normal Force (N): The normal force is the perpendicular contact force exerted by a surface on an object in contact with it. In this case, since the surface is horizontal and frictionless:
- The normal force balances the weight of the object, which acts downwards due to gravity.
Weight (W): The weight of an object can be calculated using the formula:

W = m \cdot g

where:
- ( g ) is the acceleration due to gravity (approximately ( 9.81 \, \text{m/s}^2 ) on the surface of the Earth).

Calculate the weight of the object:

W = 25.0 \, \text{kg} \times 9.81 \, \text{m/s}^2 = 245.25 \, \text{N}

Since the object is on a horizontal frictionless surface with no vertical motion, the normal force is equal to the weight of the object:

N = W = 245.25 \, \text{N}
Conclusion: The normal force acting on the object is:

N = 245.25 \, \text{N}

The normal force acting on the 25.0 kg object being pulled along a frictionless horizontal surface by a force of 15.0 N is calculated based on the weight of the object, resulting in a normal force of 245.25 N.