The solutions for energy eigenstates violate the condition that the wave function must be differentiable at all values of x.
For example, l2sin(l3πx) is a solution, but its graph shows it's piecewise continuous, not differentiable at x=0 because the slope changes abruptly.
The slope of the wave function has physical meaning, and the square of the wave function is the probability density.
Addressing the Differentiability Issue
The non-differentiability is not a serious concern because the infinite potential used is unrealistic; a finite potential is more physical.
With a finite potential (large but finite) for x<0 and x>l, the functions smooth out.
The function exhibits exponential decay to the left of x=0 and to the right of x=l.
The length of this exponential decay is related to the size of the potential; the higher the potential, the smaller the width of the decay.
Particle in a Finite Well
The particle in a finite well problem involves a potential function with a finite height V0.
Different potential functions lead to different problems in quantum mechanics.
The solutions have a slightly different mathematical form but still represent the shape of the wave function.
For instance, if x=0 is at the center of the well, the solution is a cosine function, not a sine function.
Energy Levels in the Finite Well
Energy levels: Below V<em>0, discrete energy eigenvalues (e.g., E</em>1, E2) exist.
Above V0, the energy levels become continuous, resembling free particle problems.
Infinite well: Only certain energy levels are allowed (e.g., E<em>2=4E</em>1, E<em>3=9E</em>1).
Distinction: Discrete (quantized) vs. continuous energy values.
Classical vs. Quantum Connection
If the energy level is below V0, classically, the particle is trapped, leading to discrete energy values.
If the energy level is above V0, classically, the particle can escape, behaving more like a free particle.
There are connections between classical and quantum mechanics; the solutions have similarities.
Bound vs. Unbound States
Bound states: When a particle cannot escape to infinity. If it's in one of these energy eigenstates, it will never be found at ±∞ .
Unbound states: The particle is not confined and can exist at infinity.
Mathematical Formulation of the Finite Well Problem
Solutions are sought in the region between 2−l and 2+l, similar to the infinite well problem.
In this region, V=0, and the solutions are the same as before.
The general solution involves sine and cosine functions:
c<em>1sin(k</em>ex)
c<em>2cos(k</em>ex)
c<em>3eik</em>ex
c<em>4e−ik</em>ex
ke=ℏ22mE, which has units of wave number.
Solutions Outside the Well
For x > \frac{l}{2} or x < \frac{-l}{2}, the differential equation is different because V=0.
The differential equation becomes: −2mℏ2dx2d2ϕ(x)+V0ϕ(x)=Eϕ(x)
If E < V0, the term E−V</em>0 is negative.
Introducing Alpha
Define α2=ℏ22m(V0−E).
The solutions outside the well are:
c3e−αx
c4eαx
Physical Considerations for Solutions
In the region x > \frac{l}{2}, the solution must be a decaying exponential function: c3e−αx
The solution eαx is not physically realistic because it increases without bound as x goes to infinity.
Lowest Energy Solution
The lowest energy solution involves the cosine function and has exponential tails on either side.
In the limit that V0 goes to infinity, the solution for the finite well problem converges to the solution for the infinite well problem.
Characteristic Length
α determines the characteristic length over which the exponential decays.
Analogy to capacitor discharge, where τ is the time for the charge to decrease by 63%.
The characteristic length is α1, with units in meters.
We can write the solution form as e1/α−x, where α1 is the length at which the function decays by 63%.
Finding Discrete Energy Values
In the infinite well, energy values were restricted because the sine functions had to be zero at the boundaries.
In the finite well, the functions must meet certain conditions at the boundaries.
The functions must be continuous and differentiable.
Boundary Conditions
At x=2l, the solution inside and outside the well must be equal: ϕ<em>inside(x=2l)=ϕ</em>outside(x=2l)
The derivatives of the solutions inside and outside the well must also be equal: dxdϕ<em>inside(x=2l)=dxdϕ</em>outside(x=2l)
Equations and Unknowns
These conditions yield four equations and four unknowns.
Two equations come from the continuity and differentiability at x=2l.
Two more equations come from similar conditions at x=2−l.
The constants c<em>1, c</em>2, c<em>3, and c</em>4 are the unknowns.
If the first solution doesn't have a zero at the origin, then c2 is not zero.