Quantum Mechanics Notes

Differentiability of Wave Functions

  • The solutions for energy eigenstates violate the condition that the wave function must be differentiable at all values of xx.
  • For example, 2lsin(3πxl)\sqrt{\frac{2}{l}} \sin(\frac{3 \pi x}{l}) is a solution, but its graph shows it's piecewise continuous, not differentiable at x=0x = 0 because the slope changes abruptly.
  • The slope of the wave function has physical meaning, and the square of the wave function is the probability density.

Addressing the Differentiability Issue

  • The non-differentiability is not a serious concern because the infinite potential used is unrealistic; a finite potential is more physical.
  • With a finite potential (large but finite) for x<0x < 0 and x>lx > l, the functions smooth out.
  • The function exhibits exponential decay to the left of x=0x = 0 and to the right of x=lx = l.
  • The length of this exponential decay is related to the size of the potential; the higher the potential, the smaller the width of the decay.

Particle in a Finite Well

  • The particle in a finite well problem involves a potential function with a finite height V0V_0.
  • Different potential functions lead to different problems in quantum mechanics.
  • The solutions have a slightly different mathematical form but still represent the shape of the wave function.
  • For instance, if x=0x = 0 is at the center of the well, the solution is a cosine function, not a sine function.

Energy Levels in the Finite Well

  • Energy levels: Below V<em>0V<em>0, discrete energy eigenvalues (e.g., E</em>1E</em>1, E2E_2) exist.
  • Above V0V_0, the energy levels become continuous, resembling free particle problems.
  • Infinite well: Only certain energy levels are allowed (e.g., E<em>2=4E</em>1E<em>2 = 4E</em>1, E<em>3=9E</em>1E<em>3 = 9E</em>1).
  • Distinction: Discrete (quantized) vs. continuous energy values.

Classical vs. Quantum Connection

  • If the energy level is below V0V_0, classically, the particle is trapped, leading to discrete energy values.
  • If the energy level is above V0V_0, classically, the particle can escape, behaving more like a free particle.
  • There are connections between classical and quantum mechanics; the solutions have similarities.

Bound vs. Unbound States

  • Bound states: When a particle cannot escape to infinity. If it's in one of these energy eigenstates, it will never be found at ±\pm \infty .
  • Unbound states: The particle is not confined and can exist at infinity.

Mathematical Formulation of the Finite Well Problem

  • Solutions are sought in the region between l2\frac{-l}{2} and +l2\frac{+l}{2}, similar to the infinite well problem.
  • In this region, V=0V = 0, and the solutions are the same as before.
  • The general solution involves sine and cosine functions:
    • c<em>1sin(k</em>ex)c<em>1 \sin(k</em>e x)
    • c<em>2cos(k</em>ex)c<em>2 \cos(k</em>e x)
    • c<em>3eik</em>exc<em>3 e^{i k</em>e x}
    • c<em>4eik</em>exc<em>4 e^{-i k</em>e x}
  • ke=2mE2k_e = \sqrt{\frac{2mE}{\hbar^2}}, which has units of wave number.

Solutions Outside the Well

  • For x > \frac{l}{2} or x < \frac{-l}{2}, the differential equation is different because V0V \neq 0.
  • The differential equation becomes:
    22md2ϕ(x)dx2+V0ϕ(x)=Eϕ(x)-\frac{\hbar^2}{2m} \frac{d^2 \phi(x)}{dx^2} + V_0 \phi(x) = E \phi(x)
  • If E < V0, the term EV</em>0E - V</em>0 is negative.

Introducing Alpha

  • Define α2=2m(V0E)2\alpha^2 = \frac{2m(V_0 - E)}{\hbar^2}.
  • The solutions outside the well are:
    • c3eαxc_3 e^{-\alpha x}
    • c4eαxc_4 e^{\alpha x}

Physical Considerations for Solutions

  • In the region x > \frac{l}{2}, the solution must be a decaying exponential function:
    c3eαxc_3 e^{-\alpha x}
  • The solution eαxe^{\alpha x} is not physically realistic because it increases without bound as xx goes to infinity.

Lowest Energy Solution

  • The lowest energy solution involves the cosine function and has exponential tails on either side.
  • In the limit that V0V_0 goes to infinity, the solution for the finite well problem converges to the solution for the infinite well problem.

Characteristic Length

  • α\alpha determines the characteristic length over which the exponential decays.
  • Analogy to capacitor discharge, where τ\tau is the time for the charge to decrease by 63%.
  • The characteristic length is 1α\frac{1}{\alpha}, with units in meters.
  • We can write the solution form as ex1/αe^{\frac{-x}{1/\alpha}}, where 1α\frac{1}{\alpha} is the length at which the function decays by 63%.

Finding Discrete Energy Values

  • In the infinite well, energy values were restricted because the sine functions had to be zero at the boundaries.
  • In the finite well, the functions must meet certain conditions at the boundaries.
  • The functions must be continuous and differentiable.

Boundary Conditions

  • At x=l2x = \frac{l}{2}, the solution inside and outside the well must be equal:
    ϕ<em>inside(x=l2)=ϕ</em>outside(x=l2)\phi<em>{inside}(x = \frac{l}{2}) = \phi</em>{outside}(x = \frac{l}{2})
  • The derivatives of the solutions inside and outside the well must also be equal:
    ddxϕ<em>inside(x=l2)=ddxϕ</em>outside(x=l2)\frac{d}{dx} \phi<em>{inside}(x = \frac{l}{2}) = \frac{d}{dx} \phi</em>{outside}(x = \frac{l}{2})

Equations and Unknowns

  • These conditions yield four equations and four unknowns.
  • Two equations come from the continuity and differentiability at x=l2x = \frac{l}{2}.
  • Two more equations come from similar conditions at x=l2x = \frac{-l}{2}.
  • The constants c<em>1c<em>1, c</em>2c</em>2, c<em>3c<em>3, and c</em>4c</em>4 are the unknowns.
  • If the first solution doesn't have a zero at the origin, then c2c_2 is not zero.