Gibb's free energy
There are two factors that can affect whether a reaction occurs
1) Enthalpy
2) Entropy
It is possible to use both of these factors together to determine a reaction’s feasibility using Gibb’s free energy
△G = △H - T△S
△G is the Gibb’s free energy, it is has a negative value then the reaction is feasible
△G < 0 then reaction is feasible
△H is the enthalpy change for the reaction in kJmol-1
T is the temperature in Kelvin
△S is the entropy change for the reaction in JK-1mol-1
You must convert entropies into kJK-1mol-1 by dividing by 1000
We can use △G = △H - T△S to determine what temperature a reaction become feasible
This happens when △G = 0
Rearrange the equation
0 = △H - T△S
△H = T△S
△H / △S = T
Show rearrangement as there are often marks for it
Conditions for feasibility
△G | △H | △S | - T△S |
Negative at all temperatures, always feasible | - | + | - |
Negative at high temperatures, feasible at higher temperatures | + | + | - |
Positive at all temperatures, never feasible | + | _ | + |
Negative at low temperatures, feasible at lower temperatures | - | - | + |