Gibb's free energy

  • There are two factors that can affect whether a reaction occurs

    1) Enthalpy

    2) Entropy

  • It is possible to use both of these factors together to determine a reaction’s feasibility using Gibb’s free energy

△G = △H - T△S

  • △G is the Gibb’s free energy, it is has a negative value then the reaction is feasible

  • △G < 0 then reaction is feasible

  • △H is the enthalpy change for the reaction in kJmol-1

  • T is the temperature in Kelvin

  • △S is the entropy change for the reaction in JK-1mol-1

  • You must convert entropies into kJK-1mol-1 by dividing by 1000

  • We can use △G = △H - T△S to determine what temperature a reaction become feasible

  • This happens when △G = 0

  • Rearrange the equation

    • 0 = △H - T△S

    • △H = T△S

    • △H / △S = T

  • Show rearrangement as there are often marks for it

Conditions for feasibility

△G

△H

△S

- T△S

Negative at all temperatures, always feasible

-

+

-

Negative at high temperatures, feasible at higher temperatures

+

+

-

Positive at all temperatures, never feasible

+

_

+

Negative at low temperatures, feasible at lower temperatures

-

-

+