Rates of Change and Limits Notes

Rates of Change and Limits

Learning Goals

  • Describe rates of change in a variety of ways.
  • Describe connections between average rate of change and secant lines.
  • Make connections between points on a graph and instantaneous rate of change.

Calculus Definition

  • CALCULUS is the study of continuous change.

The Two Fundamental Problems of Calculus

  • The Area Problem: Finding the area under a curve.
  • The Tangent Problem: Finding the tangent to a curve at a point.
Tangent Definition
  • The tangent to a curve at a point PP is the straight line through PP that most resembles the curve at PP.
  • The goal is to find the rate of change (slope of the tangent) at different given points.
  • To find the tangent, we search for a point QQ close to point PP.

What is a Limit?

  • Imagine trying to find the circumference and area of a circle in 300 BC.
  • Approximations improve with more sides added to the polygon.
  • Let:
    • bb = side lengths of the polygons
    • hh = the height of the triangle
    • nn = the number of sides
  • As nn gets large:
    • Perimeter approaches the circumference.
  • Area of the circle:
    • None of the individual calculations for the area of the polygon will equal the area of the circle.

Average Rate of Change

  • Average Rate of Change: The rate of change that takes place over an interval.
  • Secant Line: The line connecting two points on a curve.
Example 1
  • A rock is tossed upward from a cliff that is 120120 m above the water.
  • The height of the rock above the water is modeled by H(t)=5t2+10t+120H(t) = -5t^2 + 10t + 120, where H(t)H(t) is the height in metres and tt is time in seconds.
    • a) Find the average rate of change during the first second.
    • b) Find the average rate of change between 1 and 6 seconds.

Estimated Instantaneous Rate of Change:

  • To calculate the rate of change at a specific point, we use the estimated instantaneous rate of change.
  • Tangent Line: A line that touches a curve only at one point.
Example 2
  • Estimate the slope of the function f(x)=x2f(x) = x^2 at P(2,4)P(2, 4).
  • Choose two points (point PP and point QQ) on either side of x=2x = 2.
  • The closer we get to 2, the better the approximation will be.
  • Choose P(1.99,)P(1.99, …) and Q(2.01,)Q(2.01, …)

Instantaneous Rate of Change

  • For the function f(x)f(x), we will use two points PP and QQ, to find the instantaneous rate of change.
  • Let’s say that we want the tangent to point P(a,f(a))P(a, f(a)).
  • We will express QQ as a generic point very close to PP.
  • We add a very small, non-zero amount called hh to the xx-value of PP: Q(a+h,f(a+h))Q(a + h, f(a + h))
  • The smaller hh gets, the more accurate our tangent is.
  • Ultimately, we want h0h \rightarrow 0 (hh to approach zero).
Example 3
  • Find the slope of the tangent at P(3,9)P(3, 9) for f(x)=x2f(x) = x^2.

Limit of a Function

  • In general, the slope of a tangent to a curve y=f(x)y = f(x) at any point of tangency P(x,f(x))P(x, f(x)) is:
Example 4
  • Find the slope of the tangent of the curve f(x)=7x1xf(x) = \frac{7x-1}{x} at P(1,6)P(1, 6).
Example 5
  • Find the slope of the tangent to the curve f(x)=xf(x) = \sqrt{x} at x=16x = 16.
Example 6
  • Find the slope of the tangent to y=2x24xy = 2x^2 - 4x at the point (2,0)(2, 0).
Example 7
  • Find the slope of the tangent to f(x)=xf(x) = \sqrt{x} when x=4x = 4.
Example 8
  • A toy rocket is launched in the air so that its height, ss, at time tt is measured by s(t)=5t2+30t+2s(t) = -5t^2 + 30t + 2. What is the instantaneous velocity at 4 seconds?