Newton's Laws of Motion and Applications
Lesson Objectives
- At the end of the discussion, students are expected to:
- Compare and contrast theory and law.
- Explain Newton’s Three Laws of Motion.
- Give examples of the application of each law.
Newton’s Laws of Motion
1st Law of Motion (Law of Inertia)
- Definition: An object at rest remains at rest and an object in motion remains in motion unless acted upon by an external unbalanced force.
- Key Concept: Inertia is the tendency of an object to resist changes in its state of motion.
2nd Law of Motion (Law of Acceleration)
- Definition: The acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
- Formula: F = m imes a
- Where,
- F = Force (in Newtons, N)
- m = Mass (in kilograms, kg)
- a = Acceleration (in meters per second squared, m/s²)
- Key Relationships:
- Acceleration is directly proportional to force: a ext{ is directly proportional to } F
- Acceleration is inversely proportional to mass: a ext{ is inversely proportional to } m
3rd Law of Motion (Law of Interaction)
- Definition: For every action, there is an equal and opposite reaction.
- Key Concept: Forces always occur in pairs; if object A exerts a force on object B, object B exerts an equal and opposite force on object A.
Theory vs Law
Theory:
- Explains why natural phenomena occur.
- Based on hypotheses, can be revised and used to make predictions.
Law:
- Summarizes a set of observations about natural phenomena.
- Represents a fundamental principle of nature that holds true under specific conditions.
Law of Inertia Applications
- Examples of applications include:
- A ball rolling on the ground will eventually stop due to friction.
- A book on a table remains at rest until someone pushes it.
Law of Acceleration Applications
- Example Calculations:
- Example 1: A man pushes a 10-kg box forward at an acceleration of 2 ext{ m/s}^2.
- Given: m = 10 kg, a = 2 m/s²
- Formula: F = m imes a
- Solution: F = 10 ext{ kg} imes 2 ext{ m/s}^2 = 20 ext{ N}
- Answer: The man exerts a force of 20 N.
- Example 2: Louisa rolls a 20-kg ball with a force of 31 N. To find its acceleration:
- Given: m = 20 kg, F = 31 N
- Formula: a = rac{F}{m}
- Solution: a = rac{31 ext{ N}}{20 ext{ kg}} = 1.55 ext{ m/s}^2
- Answer: The ball will accelerate at approximately 1.55 m/s².
Law of Interaction Applications
- Examples of applications include:
- A rocket taking off demonstrates action-reaction pairs (exhaust gases pushing down and rocket moving up).
- Walking: Your foot exerts a backward force against the ground, and the ground exerts an equal and opposite force to push you forward.
Mass vs. Weight
- Mass:
- The amount of matter in an object, measured in kilograms (kg).
- Weight:
- The gravitational pull on that mass, measured in Newtons (N).
- Formula: ext{Weight} = ext{mass} imes g
- Where g is the acceleration due to gravity (approx. 9.81 ext{ m/s}^2 on Earth).
Challenge Question
- If your mass on Earth is 85 kg:
- What is your weight on Earth?
- ext{Weight} = 85 ext{ kg} imes 9.81 ext{ m/s}^2 = 833.85 ext{ N}
- What is your mass on another planet having gravitational pull one-fifth that of Earth?
- Your mass would still be 85 kg since mass does not change with location, only weight does!