ENGR-241 Week 1 Notes (Chapter 1: SI Units, Circuit Variables, Power & Energy)

The International System of Units (SI)

  • Memorize the boxed prefixes; they are used constantly in circuit analysis.
  • Common prefixes (SI):
    • 103=k10^3 = \text{k} (kilo), 106=M10^6 = \text{M} (mega), 109=G10^9 = \text{G} (giga), etc.
    • 103=m10^{-3} = \text{m} (milli), 106=μ10^{-6} = \mu (micro), 109=n10^{-9} = \text{n} (nano), 1012=p10^{-12} = \text{p} (pico), etc.
  • These prefixes allow us to express large and small quantities succinctly in volts, amperes, ohms, farads, henries, watts, etc.

Circuit Analysis: An Overview
  • Purpose: Introduce how circuit theory fits into broader engineering practice.
  • Key concepts likely covered here include modeling circuits with elements, sources, and interconnections, and using voltage/current variables to analyze systems.

Voltage and Current

– Part 1

  • Voltage (v): energy per unit charge created when + and - charges are separated.
  • Defining equation for voltage: v=dwdqv = \frac{d w}{d q}
    • where
    • vv is voltage in volts [V],
    • ww is energy in joules [J],
    • qq is charge in coulombs [C].
  • Relationship indicates that voltage is the differential change of energy with respect to charge.

Voltage and Current

– Part 2

  • Current (i): the time rate of change of charge flow.
  • Defining equation for current: i=dqdti = \frac{d q}{d t}
    • where
    • ii is current in amperes [A],
    • qq is charge in coulombs [C],
    • tt is time in seconds [s].
  • Intuition: current measures how quickly charge passes a point in a circuit.

The Ideal Basic Circuit Element
  • Definition of a few terms:
    • Ideal: the element can be described solely by the relationship between its voltage and current.
    • Basic: the element cannot be subdivided into simpler elements.
    • Circuit Element: an entity with two terminals that connects to other elements to form a circuit.
  • This forms the foundational abstraction used to analyze circuits (resistors, capacitors, inductors, sources are all cross-cutting concepts under this umbrella).

Power and Energy

– Part 1

  • Power (p): the time rate of change of energy.
  • Defining equation: p=dwdtp = \frac{d w}{d t}
    • where
    • pp is power in watts [W],
    • ww is energy in joules [J],
    • tt is time in seconds [s].
  • Relationship to energy: energy is the integral of power over time, i.e., w=pdtw = \int p\,dt
  • Practical implication: knowledge of either power as a function of time or energy over a period allows determination of the other.

Power and Energy

– Part 2

  • Fundamental identity: p=vip = v i

    • where
    • vv is the voltage across the element,
    • ii is the current through the element.
  • This can be equivalently written in differential form using energy: p=dwdtp = \frac{d w}{d t}

    and using the chain rule: p=vip = v i (with v and i defined consistently).

  • In many cases it is useful to remember the relationship in a compact form:

    • p=vip = v i

Power and Energy

– Part 3

  • Sign conventions are essential for correctly determining whether an element is delivering or absorbing power.
  • The passive sign convention states:
    • If the reference direction for the current in an element is the same as the reference voltage drop across the element, use a positive sign in expressions relating voltage to current.
    • If not, use a negative sign.
  • In practice: the common working form is
    • p=±vip = \pm v i
  • The sign is chosen so that positive power means absorbing (dissipating) power, and negative power means delivering (generating) power.

Power and Energy

– Part 4

  • The practical version of the passive sign convention:
    • If the current arrow points toward the + terminal of the voltage, use a + sign in the expression for power.
    • Otherwise, use a − sign.
  • For the ideal basic circuit element shown (in typical introductory circuits), the power expression becomes
    • p=+vi=vip = + v i = v i
  • Summary rule: use the sign convention that makes absorbed power positive and delivered power negative, consistent with the orientation of current and voltage.

Power and Energy

– Part 5

  • Examples of interpreting the algebraic sign of power (typical outcomes):
    • If the algebraic power value is negative, the element is delivering (supplying) power to the circuit.
    • If the algebraic power value is positive, the element is absorbing (dissipating) power from the circuit.
  • Illustrative statements:
    • p is negative -> element supplies power.
    • p is positive -> element absorbs power.

Power and Energy

– Part 6

  • Meaning of positive vs negative power:
    • Positive power means the element is absorbing (dissipating) energy from the circuit.
    • Negative power means the element is generating (delivering) energy to the circuit.
  • This interpretation helps verify circuit analyses by checking energy balance.

Power and Energy

– Part 7

  • Problem intuition examples (conceptual):
    • For a given circuit element, determine whether the element is supplying or absorbing by inspecting the direction of current with respect to the voltage polarity.
    • This is a quick sanity check in problem solving to ensure consistency with the passive sign convention.

Problem 1 (Chapter 1)

– Charge delivered to terminal 1

  • Setup: total charge entering terminal 1 is computed from current-time history: q(terminal 1)=0i(t)dtq(\text{terminal 1}) = \int_{0}^{\infty} i(t) \, dt
  • Result: the total charge entering terminal 1 is q=0.004 Cq = 0.004\ \text{C}
  • Equivalent values of 0.004 C:
    • 4 mC4\ \text{mC}
    • 4000 μC4000\ \mu\text{C}
  • Non-equivalent values (for reference):
    • 4 kC4\ \text{kC} would be 4000 C4000\ \text{C} (not equal)
    • 40,000 pC40{,}000\ \text{pC} would be 4×108 C4\times 10^{-8}\ \text{C} (not equal)
    • 0.04 C0.04\ \text{C} (not equal)
  • Takeaway: convert to common units to verify equivalence with known prefixes.

Problem 2

– Power in a circuit element

  • Given a circuit with a voltage source and current, determine power and whether it is generated or absorbed.
  • Example result using the passive sign convention:
    • If the current and voltage have the orientation such that the element is delivering energy to the rest of the circuit, then
    • p=vip = - v i and numerically this equals -80 W for the cited values.
    • If the orientation is such that the element is absorbing energy, then
    • p=+vip = + v i and numerically this equals +80 W for the cited values.
  • Practical takeaway: for a given element with voltage v and current i, compute p = v i and assign the sign according to the passive sign convention to determine generation vs absorption.

Problem 2

– Solution (conceptual approach)

  • To find the total energy delivered to a circuit element, use the energy integral over the time interval of interest:
    • w=<em>t</em>0t<em>1p(t)dt=</em>t<em>0t</em>1v(t)i(t)dtw = \int<em>{t</em>0}^{t<em>1} p(t) \, dt = \int</em>{t<em>0}^{t</em>1} v(t) i(t) \, dt
  • If explicit time-varying forms of v(t) and i(t) are given, substitute and evaluate the integral.
  • The example emphasizes that energy can be computed from the integral of power and that units and signs must be consistent.

Problem 3

– Power in a multi-element circuit

  • Task: find the power associated with each circuit element a, b, c, d, e, f given voltages and currents.
  • Procedure:
    • For each element, determine p = v i with the sign determined by the element’s current direction relative to the voltage polarity.
    • Classify each as supplying or absorbing based on the sign of p.
  • Example (illustrative values):
    • a: p = -56 W (supply)
    • b: p = -14 W (supply)
    • c: p = 150 W (absorb)
    • d: p = -50 W (supply)
    • e: p = -18 W (supply)
    • f: p = -12 W (supply)
  • Power balance principle (most important takeaway):
    • The total power supplied by all sources equals the total power absorbed by all elements:
    • p<em>supplied=p</em>absorbed\sum p<em>{\text{supplied}} = \sum p</em>{\text{absorbed}}
    • Therefore, the circuit is in power balance with no net power generation or dissipation.

Problem 3

– Solution (Part 2) – Power balance

  • Statement: The power in a circuit always balances; the total power supplied equals the total power dissipated.
  • Importance: This balance serves as a consistency check when using circuit analysis methods to find voltage and current for every element.

Assignment and Course Logistics
  • Homework due date: Thursday, 08/28/2025, at the start of class.
  • Assigned problems (Nilsson & Riedel):
    • Prob. 1.14
    • Prob. 1.18
    • Prob. 1.20
    • Prob. 1.33
    • Prob. 1.35
  • Textbook: Nilsson & Riedel, Electric Circuits, 12th ed., Pearson. ISBN-13: 978-0-13-37648375
  • Textbook and course details are from ENGR-241, Fall 2025, Week 1.

Agenda (Week 1, Chapter 1 scope)
  • The International System of Units (SI)
  • Circuit Analysis: An Overview
  • Voltage and Current
  • The Ideal Basic Circuit Element
  • Power and Energy
  • Problems

Foundational References and Context
  • Textbook source: J. W. Nilsson and S. A. Riedel, Electric Circuits, 12th ed. (Pearson)
  • This week’s material lays the groundwork for circuit variables, passive sign convention, and energy/power relationships that are used throughout ENGR-241.
  • Real-world relevance: Understanding SI units and sign conventions is essential for properly modeling and analyzing electrical circuits in engineering practice.

Key Takeaways for Exam Preparation
  • Master the definitions:
    • Voltage: v=dwdqv = \frac{d w}{d q}
    • Current: i=dqdti = \frac{d q}{d t}
    • Power: p=dwdt=vip = \frac{d w}{d t} = v i
  • Know the passive sign convention and how to apply sign to determine whether an element is delivering or absorbing power.
  • Remember the power balance principle: total power supplied equals total power absorbed in any circuit.
  • Be comfortable converting between units using SI prefixes (k, M, m, μ, n, p, etc.).
  • For problem-solving: use integrals for energy, and use p = v i with correct sign to evaluate power for each element.