Vertical and Horizontal Stretches in Function Transformations

Introduction to Vertical Stretches in Functional Notation

  • Impact of Leading Factors: When a numerical factor is placed at the front of an equation, such as y=3×f(x)y = 3\times\text{f}(x), it changes the visual representation of the graph significantly. In the example provided, the equation for a semicircle, y=3×f(x)y = 3\times\text{f}(x) where f(x)=4x2\text{f}(x) = \sqrt{4 - x^2}, is explored.

  • Definition of Vertical Stretch: The presence of the coefficient 3 results in a vertical stretch by a factor of 3 about the x-axis.

  • Exam Terminology Warning: On formal exams, specifically the diploma exam, students must write out the full phrase "vertical stretch" rather than using abbreviations. This ensures the marker recognizes the specific transformation being described.

  • The "Rubber Band" Metaphor: A vertical stretch can be visualized by imagining a graph pinned down to the x-axis. If you grab the graph and pull it vertically, it expands like a rubber band.

  • The Meaning of "Factor": In mathematical terms, the word "factor" indicates product and multiplication. When describing a transformation, leaving out the word "factor" (e.g., "the graph is stretched 3") makes the description mathematically imprecise.

Mechanics and Calculation of Vertical Stretches

  • Distance Analysis: The stretch factor is applied to the distance between each coordinate and the x-axis.

    • Example 1: If a coordinate is initially 2 units away from the x-axis (e.g., at a height of 2), a vertical stretch by a factor of 3 triples that distance, moving the coordinate to 6 units away (2×3=62 \times 3 = 6).

    • Example 2: A coordinate that was 1 unit away from the x-axis moves to 3 units away (1×3=31 \times 3 = 3).

  • Invariance: Coordinates located directly on the x-axis have a distance of 0 from the axis. Since 0×3=00 \times 3 = 0, these points do not change position.

    • The x-intercepts of a graph remains invariant (unchanged) under any vertical stretch.

  • Impact on Y-Intercepts: For the initial semicircle graph with a y-intercept at 2, a vertical stretch factor of 3 triples the intercept to 6.

Vertical Compressions (Vertical Stretches Between 0 and 1)

  • Vertical Stretch by a Factor of 1/2: If the equation is updated to y=12f(x)y = \frac{1}{2}\text{f}(x), the graph becomes shorter rather than taller.

  • Terminology Variation: While some textbooks use the term compression (for factors between 0 and 1) or expansion (for factors greater than 1), the term "stretch" is universally applicable as long as the specific factor is included (e.g., stretch by a factor of 1/21/2).

  • Observations for Factor of 1/2:

    • The x-intercepts remain invariant.

    • The y-intercept is halved (reduced to 1 if the original was 2).

Theoretical Foundation: Transformation by Replacement

  • The Replacement Principle: All functional transformations can be viewed as the result of a variable replacement.

  • Vertical Stretch Replacement: If the equation is y=af(x)y = a\text{f}(x), it can be rewritten as 1ay=f(x)\frac{1}{a}y = \text{f}(x). This implies that initial variable yy was replaced by 1ay\frac{1}{a}y.

  • The Reciprocal Rule: The stretch factor and the replacement number are always reciprocals of each other.

    • If the vertical stretch factor is 3, the replacement for yy is 13y\frac{1}{3}y.

    • If the vertical stretch factor is 12\frac{1}{2}, the replacement for yy is 2y2y.

Horizontal Stretches and the Y-Axis

  • Notation: Horizontal stretches occur when the variable within the function notation is modified, such as in y=f(bx)y = \text{f}(bx).

  • Replacement and Factor Reciprocity: Just as with vertical transformations, the replacement value and the stretch factor are reciprocals.

    • Example (f(4x)): If xx is replaced by a factor of 4, the resulting transformation is a horizontal stretch by a factor of 1/4 about the y-axis.

  • Equation Derivation: For the function f(x)=4x2\text{f}(x) = \sqrt{4 - x^2}, the substituted form f(4x)\text{f}(4x) becomes:   y=4(4x)2y = \sqrt{4 - (4x)^2}   y=416x2y = \sqrt{4 - 16x^2}

  • Visual Impact: A horizontal stretch by a factor of 1/41/4 narrows the graph. An x-intercept at 2 would move to 2×14=0.52 \times \frac{1}{4} = 0.5.

  • Horizontal Expansions: If the equation is y=f(13x)y = \text{f}(\frac{1}{3}x), the horizontal stretch factor is 3. This widens the graph.

    • Example: An x-intercept at 2-2 moves out to 6-6, and positive 2 moves out to 6.

  • Invariance: Under horizontal stretches, the y-intercept remains invariant because its distance to the y-axis is 0.

Summary of Transformation Rules

  • Vertical Stretches (y=af(x)y = a\text{f}(x)):

    • Happens about the x-axis.

    • Stretch factor is aa.

    • If 0 < a < 1, the graph undergoes compression (shorter).

    • If a > 1, the graph undergoes expansion (taller).

    • If aa is negative, there is a reflection in the x-axis in addition to the stretch.

  • Horizontal Stretches (y=f(bx)y = \text{f}(bx)):

    • Happens about the y-axis.

    • Stretch factor is 1b\frac{1}{b}.

    • If 0 < b < 1, the stretch factor is greater than 1, resulting in expansion (wider).

    • If b > 1, the stretch factor is less than 1, resulting in compression (thinner).

    • If bb is negative, there is a reflection in the y-axis in addition to the stretch.

Step-by-Step Problem Solving and Examples

Example 1: Writing Replacements and Equations
  • Task A: Horizontal stretch by factor of 6 about the y-axis.

    • Replacment: Replace xx with 16x\frac{1}{6}x.

    • Equation: y=f(16x)y = \text{f}(\frac{1}{6}x).

  • Task B: Vertical stretch by factor of 1/5 about the x-axis.

    • Replacement: Replace yy with 5y5y.

    • Preliminary Equation: 5y=f(x)5y = \text{f}(x).

    • Simplified Equation: y=15f(x)y = \frac{1}{5}\text{f}(x).

  • Task C: Reflection in the x-axis and a vertical stretch by factor of 3.

    • Replacement 1 (Stretch): Replace yy with 13y\frac{1}{3}y.

    • Replacement 2 (Reflection): Replace yy with y-y

    • Combined replacement: Replace yy with 13y-\frac{1}{3}y.

    • Simplify: 13y=f(x)y=3f(x)-\frac{1}{3}y = \text{f}(x) \rightarrow y = -3\text{f}(x).

Example 2: Describing Changes from Notation
  • Change f(4x): Horizontal stretch, factor 1/41/4, about the y-axis.

  • Change f(x) with y replaced by (1/3)y: Vertical stretch, factor 3, about the x-axis.

  • Change with constant y replaced by 6y and x by (1/3)x: Vertical stretch factor 1/61/6 about the x-axis AND horizontal stretch factor 3 about the y-axis.

Example 3: Sketching a Graph with Combined Transformations
  • Scenario: Sketching y=f(2x)y = \text{f}(-2x).

  • Transformations:

    • Horizontal stretch by a factor of 1/21/2 about the y-axis.

    • Reflection in the y-axis.

  • Process: Take each coordinate, multiply its horizontal distance to the y-axis by 1/21/2, then move it to the opposite side of the y-axis.

Advanced Algebraic Simplifications

Squaring Transformations
  • Equation: y=x2y = x^2 with horizontal stretch factor 3/43/4.

  • Replacement: Replace xx with 43x\frac{4}{3}x.

  • Transformation: y=(43x)2=169x2y = (\frac{4}{3}x)^2 = \frac{16}{9}x^2.

Radical Transformations
  • Equation: y=x3y = \sqrt{x} - 3 with horizontal stretch factor 4 and vertical stretch factor 2.

  • Horizontal replacement: x14xx \rightarrow \frac{1}{4}x.

  • Vertical replacement: y12yy \rightarrow \frac{1}{2}y.

  • Solving for yy:   12y=14x3\frac{1}{2}y = \sqrt{\frac{1}{4}x} - 3   12y=12x3\frac{1}{2}y = \frac{1}{2}\sqrt{x} - 3   y=2×(12x3)y = 2 \times (\frac{1}{2}\sqrt{x} - 3)   y=x6y = \sqrt{x} - 6

Linear Transformations
  • Equation: y=3x+7y = 3x + 7 with vertical stretch factor 1/31/3.

  • Replacement: Replace yy with 3y3y.

  • Transformation: 3y=3x+7y=x+733y = 3x + 7 \rightarrow y = x + \frac{7}{3}.

Practical Observation from Graphs

  • Identifying Transformations: When looking at a thin original line and a thick transformed line, compare key points like peaks or intercepts.

  • Vertical Case: If the original height is 6 and the new height is 3, the vertical stretch factor is 1/21/2.

  • Equation Derivation from Observation: Starting from y=6x2+1y = \frac{6}{x^2 + 1}, applying a vertical stretch factor of 1/21/2 results in the replacement of yy with 2y2y.   2y=6x2+1y=3x2+12y = \frac{6}{x^2 + 1} \rightarrow y = \frac{3}{x^2 + 1}.

Classroom Logistics

  • Instructional Note: Practice exercises are essential for mastering reciprocity between stretch factors and replacement values.

  • Exam Security: Cell phones must be stored away and are strictly prohibited during the return of unit exams; all mobile devices must stay in the classroom and cannot be taken home while exams are being reviewed.