Sampling Distributions and Central Limit Theorem Laboratory

Laboratory Activity Overview and Data Structure

  • Group Allocations:

    • Students are organized using a random group generator into eight groups (Groups 1 through 8).
    • Group composition consists of one group of two individuals, with all remaining groups consisting of three individuals.
  • Variable Definition:

    • The random variable xx represents the length of time in days that a recipe lasts at a restaurant before being changed by the chef.
    • The underlying data set consists of 6060 total recipes (numbered 1 through 60).
    • The observations are presented in a table containing four columns of xx values.
    • Pre-calculated population parameters are provided directly on the activity sheet for subsequent theoretical comparison:
    • Population mean: μ=3.57\mu = 3.57
    • Population standard deviation: σ=2.17\sigma = 2.17

Population Data and Initial Histogram Construction

  • Histogram Graphical Specifications:

    • Horizontal Axis (xx-axis): Labeled as "Number of days the recipe lasted."
    • Vertical Axis (yy-axis): Labeled as "Frequency" (representing the count of recipes), scaled in increments of 55.
    • Class Boundaries / Bins: Formatted using decimal boundaries offset by 0.50.5 to isolate discrete integer values: 0.5,1.5,2.5,3.5,4.5,5.5,…0.5, 1.5, 2.5, 3.5, 4.5, 5.5, \dots
    • Bin Mapping:
    • The interval from 0.50.5 to 1.51.5 captures recipes that lasted exactly 11 day.
    • The interval from 1.51.5 to 2.52.5 captures recipes that lasted exactly 22 days (excluding 22 from the preceding bin).
    • Days with zero recorded recipes have a frequency of 00, represented by a flat line directly on the horizontal axis.
    • For the 11-day bin (0.50.5 to 1.51.5), the counted frequency is 1313 recipes.
  • Distribution Shape and Curve Fitting:

    • A smooth continuous curve is traced over the top profile of the histogram bars.
    • The curve exhibits a prominent peak on the lower end with a tail extending toward larger values.
    • The overall shape of the population distribution is identified as skewed to the right (right-skewed).

Sampling Procedure and Central Limit Theorem Simulation (n=5n = 5)

  • Random Sampling Mechanism:

    • Samples are drawn using a random number generator (e.g., via a mobile search engine or generator tool) configured to produce integers uniformly distributed between 11 and 6060.
    • Each generated integer identifies the recipe number from the population table, from which the corresponding duration in days (xx) is recorded.
  • Step-by-Step Sample Generation:

    1. Generate five random integers between 11 and 6060.
    2. Extract the xx value (days) for each selected recipe:
    • Example: Recipe #5 lasted 66 days (x=6x = 6).
    • Example: Recipe #48 lasted 1111 days (x=11x = 11).
    • Example: Recipe #30 lasted 22 days (x=2x = 2).
    • Example: Recipe #58 lasted 33 days (x=3x = 3).
    • Additional sample pulls observed: Recipe #46, Recipe #38, Recipe #52.
    1. Construct Sample 1 consisting of n=5n = 5 observations (e.g., values 11,2,5,2,311, 2, 5, 2, 3).
    2. Calculate the sample mean: xˉ=∑xn\bar{x} = \frac{\sum x}{n}
    3. Repeat the sampling process independently to produce Sample 2, Sample 3, and Sample 4, resulting in four distinct sample means (e.g., values including 4.84.8, 4.44.4, etc.).

Group Data Sharing and Sample Mean Distribution Analysis

  • Data Pooling:

    • Each group records their four calculated sample means on item number 4 of the activity sheet.
    • Groups pair with the nearest adjacent group to exchange their sets of sample means.
    • Combining both sets produces a collective dataset of 88 sample means (N=8N = 8).
  • Statistical Computation of Pooled Means:

    • The grand mean of the eight sample means (xˉxˉ\bar{x}_{\bar{x}}) is calculated by summing all eight means and dividing by 88:     xˉxˉ=∑xˉ8\bar{x}_{\bar{x}} = \frac{\sum \bar{x}}{8}
    • The sample standard deviation of these eight sample averages (sxˉs_{\bar{x}}) is determined via spreadsheet software or manual formulas.
  • Histogram Construction of Sample Means (n=5n = 5):

    • A secondary histogram is established to display the distribution of the pooled sample means.
    • Interval bins are configured in steps of 0.50.5, bounded at quarter decimals to avoid ambiguous edge cases:
    • Bin 1: 2.752.75 to 3.253.25
    • Bin 2: 3.253.25 to 3.753.75
    • Bin 3: 3.753.75 to 4.254.25
    • Bin 4: 4.254.25 to 4.754.75
    • Values falling within intermediate ranges (e.g., 3.33.3 and 3.43.4) are assigned to the bin spanning 3.253.25 to 3.753.75.
    • Single occurrences (e.g., a mean of 3.43.4) receive a bar height of 11, while multiple occurrences receive proportional bar heights (e.g., height of 22 or 33).

Second Sampling Phase (n=10n = 10) and Computational Tools

  • Sample Expansion:

    • The sampling protocol is repeated with an increased sample size of n=10n = 10 random selections per sample.
    • Sampled recipes and recorded durations include:
    • Recipe #35: 66 days
    • Recipe #34: 66 days
    • Recipe #14: 33 days
    • Recipe #11: 88 days
    • Recipe #22: 55 days
    • Recipe #29: 66 days
    • Recipe #18: 44 days
    • Recipe #51: 44 days
    • Recipe #31: 33 days
    • Recipe #54: 11 day
    • Recipe #39: 55 days
    • Recipe #44: 66 days
    • Recipe #56: 22 days
    • Additional sampled recipes: #25, #59, #27, #55, #60, #36.
    • Derived sample means for repeated sets yield values such as 3.33.3, 3.43.4, and 2.42.4.
  • Spreadsheet Implementation:

    • Mean computation formula: =AVERAGE(data_range)
    • Standard deviation computation formula: =STDEV(data_range)
    • Execution involves highlighting the eight sample mean values and applying =STDEV(...), yielding empirical values such as 0.790.79.

Theoretical Sampling Distributions and Formulas

  • Central Limit Theorem Parameters:

    • Given a population with mean μ\mu and standard deviation σ\sigma, the theoretical sampling distribution of the sample mean (xˉ\bar{x}) for a sample size nn possesses:
    • Theoretical Mean of the Sampling Distribution:       μxˉ=μ=3.57\mu_{\bar{x}} = \mu = 3.57
    • Theoretical Standard Error of the Sampling Distribution:       σxˉ=σn\sigma_{\bar{x}} = \frac{\sigma}{\sqrt{n}}
  • Theoretical Computations by Sample Size:

    • For Sample Size n=5n = 5:σxˉ=2.175≈0.9705≈0.97\sigma_{\bar{x}} = \frac{2.17}{\sqrt{5}} \approx 0.9705 \approx 0.97
    • For Sample Size n=10n = 10:σxˉ=2.1710≈0.6862≈0.69\sigma_{\bar{x}} = \frac{2.17}{\sqrt{10}} \approx 0.6862 \approx 0.69
  • Computational Formatting and Precision:

    • Calculations in handheld calculators require explicit parentheses around the denominator term (e.g., dividing by (\sqrt{5})) to preserve operational order.
    • Standard reporting conventions require rounding numerical results to two decimal places (22 decimal digits).
  • Distinction Between Sampling Distributions and Normal Probabilities:

    • Defining the sampling distribution entails identifying μxˉ\mu_{\bar{x}} and calculating σxˉ\sigma_{\bar{x}}.
    • Finding the probability of a sample mean falling within a specified numerical range (e.g., between 8585 and 9292) requires standardizing the interval via zz-scores:     z=xˉ−μxˉσxˉz = \frac{\bar{x} - \mu_{\bar{x}}}{\sigma_{\bar{x}}}
    • Standard normal distribution probability tables are not utilized when solely defining the sampling distribution parameters.

Questions & Discussion: Empirical Anomalies versus Theoretical Principles

  • Question on Sample Distribution Discrepancies:
    • Prompt: Why does the sample standard deviation for n=5n = 5 appear smaller than or close to that of n=10n = 10 in the observed student data, and how does this relate to the theoretical distributions and the Law of Large Numbers?
    • Response: Theoretical models dictate that the standard error of the mean must decrease as sample size increases, because the population standard deviation is divided by a larger denominator (since 10>5\sqrt{10} > \sqrt{5}, 2.1710≈0.69\frac{2.17}{\sqrt{10}} \approx 0.69 is strictly smaller than 2.175≈0.97\frac{2.17}{\sqrt{5}} \approx 0.97).
    • Response on Empirical Data: In small random sample sizes, individual empirical draws may display sampling error where an observed sample standard deviation for n=5n = 5 (e.g., 0.790.79 or 0.560.56) appears smaller than expected. In reporting results, the student must document the exact empirical values obtained from their data while noting that theoretically, an increase in sample size from n=5n = 5 to n=10n = 10 systematically reduces the spread of the sampling distribution due to division by a larger root divisor.