Exam and Torque Summary
Third Exam Details:
Date: Tuesday, March 25, at 6:00 PM
Location: Refer to February 17 email
Requirements: UM ID (or other ID), #2 pencils
Closed-book, 75 minutes, multiple-choice (15 questions, no penalty for guessing)
Allowed: Three 3"×5" notecards (double-sided), calculator
Prohibited: Laptops, cell phones, smartwatches, communication devices
Scope: Sections 8.1–10.3
Torque Formula:
Magnitude of torque: ( \tau = rF \sin \phi )
Units: N·m
Torque Cases Comparison:
Case 1: Force pushing perpendicular at distance ( L/2 ) from axis
Case 2: Force pushing at 30° at distance ( L ) from axis
Torque is greatest in Case 1.
Rotating Bar Scenario:
As a horizontal bar with a hanging mass rotates to vertical, torque changes:
- The magnitude of torque increases as it rotates.
Torque Direction:
Determined by the right-hand rule:
- Clockwise vs. Counterclockwise distinctions affect direction using ( \tau = r \times F ).
Rotational Dynamics:
No total torque means no angular acceleration.
( \sum \tau = I \alpha )
Moment of inertia depends on axis of rotation.
Acceleration of Wheels:
For wheels with different radii but same mass, the force comparison must be determined for identical angular accelerations.
Example Problem for Torque:
Block attached to a rope and disk that rotates due to gravity:
- Torque on pulley is affected by tension in the rope and is typically less than mgR.
Problem Solving Procedure:
- Draw a picture.
- Identify independent bodies.
- Identify forces on each body.
- Draw free-body diagrams.
- Write Newton’s 2nd law in vector form.
- Choose a coordinate system.
- Rewrite Newton’s 2nd law in components.
- Identify constraints (e.g., a = Rα).
- Count equations and unknowns.
- Solve equations analytically (variables).
- Substitute values to find numerical answers.