Comprehensive Study Notes on the Chain Rule and Function Composition

Foundations of Function Composition and the Chain Rule

  • Existing Derivative Rules:

    • Sum and Difference Rule (addition and subtraction of functions).

    • Product Rule (multiplication of functions).

    • Quotient Rule (division of functions).

    • Constant Rule and Constant Multiple Rule.

  • Function Composition:

    • Composition is an additional method for combining two functions, denoted as h(x)=f(g(x))h(x) = f(g(x))

    • Composition occurs when the range of an inner function g(x)g(x) matches the domain of an outer function f(x)f(x).

    • The inner function g(x)g(x) is substituted directly in place of the independent variable in f(x)f(x).

Mathematical Derivation of the Chain Rule

  • Definition of Derivative at a Point:

    • To find the derivative of h(x)=f(g(x))h(x) = f(g(x)) at a specific point aa, start with the limit definition of the derivative:         h′(a)=lim⁡x→ah(x)−h(a)x−ah'(a) = \lim_{x \to a} \frac{h(x) - h(a)}{x - a}

    • Substituting f(g(x))f(g(x)) for h(x)h(x) and f(g(a))f(g(a)) for h(a)h(a):         h′(a)=lim⁡x→af(g(x))−f(g(a))x−ah'(a) = \lim_{x \to a} \frac{f(g(x)) - f(g(a))}{x - a}

  • Algebraic Manipulation Using Identity Multiplication:

    • Multiply the expression by a fraction equivalent to 11:         g(x)−g(a)g(x)−g(a)\frac{g(x) - g(a)}{g(x) - g(a)}

    • This yields the expanded limit expression:         h′(a)=lim⁡x→a(f(g(x))−f(g(a))x−a×g(x)−g(a)g(x)−g(a))h'(a) = \lim_{x \to a} \left( \frac{f(g(x)) - f(g(a))}{x - a} \times \frac{g(x) - g(a)}{g(x) - g(a)} \right)

    • Swap the denominators of the two fractions:         h′(a)=lim⁡x→a(f(g(x))−f(g(a))g(x)−g(a)×g(x)−g(a)x−a)h'(a) = \lim_{x \to a} \left( \frac{f(g(x)) - f(g(a))}{g(x) - g(a)} \times \frac{g(x) - g(a)}{x - a} \right)

  • Applying Limit Laws:

    • The limit of a product is equal to the product of the individual limits, provided both limits exist:         h′(a)=(lim⁡x→af(g(x))−f(g(a))g(x)−g(a))×(lim⁡x→ag(x)−g(a)x−a)h'(a) = \left( \lim_{x \to a} \frac{f(g(x)) - f(g(a))}{g(x) - g(a)} \right) \times \left( \lim_{x \to a} \frac{g(x) - g(a)}{x - a} \right)

  • Evaluating the Individual Limits:

    • The second factor is recognized directly as the derivative of g(x)g(x) at point aa:         lim⁡x→ag(x)−g(a)x−a=g′(a)\lim_{x \to a} \frac{g(x) - g(a)}{x - a} = g'(a)

    • The first factor represents the slope of the secant line passing through the points (g(x),f(g(x)))(g(x), f(g(x))) and (g(a),f(g(a)))(g(a), f(g(a))).

    • As x→ax \to a, the term g(x)g(x) approaches g(a)g(a), making this limit evaluate to the derivative of f(x)f(x) at the point g(a)g(a):         lim⁡x→af(g(x))−f(g(a))g(x)−g(a)=f′(g(a))\lim_{x \to a} \frac{f(g(x)) - f(g(a))}{g(x) - g(a)} = f'(g(a))

    • Combining these results yields the derivative at point aa:         h′(a)=f′(g(a))×g′(a)h'(a) = f'(g(a)) \times g'(a)

  • Generalization to All Points:

    • While aa denotes a specific point, this relation holds for all arbitrary points xx in the domain:         h′(x)=f′(g(x))×g′(x)h'(x) = f'(g(x)) \times g'(x)

Verbal Definition and Tabular Framework

  • Verbal Statement:

    • The derivative of a composite function is the derivative of the outside function evaluated at the inside function, multiplied by the derivative of the inside function.

  • Symbolic Component Breakdown:

    • Derivative of outside function evaluated at inside function: f′(g(x))f'(g(x))

    • Derivative of inside function: g′(x)g'(x)

  • Tabular Method for Derivative Evaluation:

    • Identify the outside function f(x)f(x).

    • Identify the inside function g(x)g(x).

    • Compute the derivative of the outside function f′(x)f'(x).

    • Evaluate the derivative of the outside function at the inside function f′(g(x))f'(g(x)).

    • Compute the derivative of the inside function g′(x)g'(x).

    • Multiply f′(g(x))f'(g(x)) by g′(x)g'(x) to form dydx\frac{dy}{dx}.

Applied Examples and Step-by-Step Solutions

Example 1: Composite Power of a Trigonometric Function

  • Function:     y=(sin⁡(x))2y = (\sin(x))^2

  • Component Identification:

    • Outside function: f(x)=x2f(x) = x^2

    • Inside function: g(x)=sin⁡(x)g(x) = \sin(x)

  • Derivatives Computation:

    • Derivative of outside function via Power Rule (bring power to front, subtract 1 from power):         f′(x)=2x1=2xf'(x) = 2x^1 = 2x

    • Outside derivative evaluated at inside function:         f′(g(x))=2sin⁡(x)f'(g(x)) = 2\sin(x)

    • Derivative of inside function:         g′(x)=cos⁡(x)g'(x) = \cos(x)

  • Final Differentiation:

    • Multiply components:         dydx=f′(g(x))×g′(x)=2sin⁡(x)cos⁡(x)\frac{dy}{dx} = f'(g(x)) \times g'(x) = 2\sin(x)\cos(x)

    • Consistency Check: Evaluating y=(sin⁡(x))2=sin⁡(x)sin⁡(x)y = (\sin(x))^2 = \sin(x)\sin(x) via the Product Rule yields (sin⁡(x))′sin⁡(x)+sin⁡(x)(sin⁡(x))′=cos⁡(x)sin⁡(x)+sin⁡(x)cos⁡(x)=2sin⁡(x)cos⁡(x)(\sin(x))'\sin(x) + \sin(x)(\sin(x))' = \cos(x)\sin(x) + \sin(x)\cos(x) = 2\sin(x)\cos(x), confirming mathematical validity.

Example 2: Radical Function with Linear Argument

  • Function:     y=x+1y = \sqrt{x + 1}

  • Component Identification:

    • Outside function: f(x)=x=x12f(x) = \sqrt{x} = x^{\frac{1}{2}}

    • Inside function: g(x)=x+1g(x) = x + 1

  • Derivatives Computation:

    • Derivative of outside function via Power Rule:         f′(x)=12x12−1=12x−12f'(x) = \frac{1}{2}x^{\frac{1}{2} - 1} = \frac{1}{2}x^{-\frac{1}{2}}

    • Outside derivative evaluated at inside function:         f′(g(x))=12(x+1)−12=12x+1f'(g(x)) = \frac{1}{2}(x + 1)^{-\frac{1}{2}} = \frac{1}{2\sqrt{x + 1}}

    • Derivative of inside function (Sum Rule):

      • Power Rule on xx gives 1x0=11x^0 = 1

      • Constant Rule on 11 gives 00

      • g′(x)=1+0=1g'(x) = 1 + 0 = 1

  • Final Differentiation:

    • Multiply components:         dydx=f′(g(x))×g′(x)=12x+1×1=12x+1\frac{dy}{dx} = f'(g(x)) \times g'(x) = \frac{1}{2\sqrt{x + 1}} \times 1 = \frac{1}{2\sqrt{x + 1}}

Example 3: Trigonometric Function with Constant Multiple

  • Function:     y=cos⁡(3t)y = \cos(3t)

  • Component Identification (using independent variable tt):

    • Outside function: f(t)=cos⁡(t)f(t) = \cos(t)

    • Inside function: g(t)=3tg(t) = 3t

  • Derivatives Computation:

    • Derivative of outside function:         f′(t)=−sin⁡(t)f'(t) = -\sin(t)

    • Outside derivative evaluated at inside function:         f′(g(t))=−sin⁡(3t)f'(g(t)) = -\sin(3t)

    • Derivative of inside function via Constant Multiple Rule:         g′(t)=3g'(t) = 3

  • Final Differentiation:

    • Multiply components:         dydt=f′(g(t))×g′(t)=−sin⁡(3t)×3=−3sin⁡(3t)\frac{dy}{dt} = f'(g(t)) \times g'(t) = -\sin(3t) \times 3 = -3\sin(3t)

Example 4: Doubly Nested Composite Function

  • Function:     y=19sin⁡2(x7)=19(sin⁡(x7))2y = 19\sin^2(x^7) = 19(\sin(x^7))^2

  • Structural Analysis:

    • This function contains a triple composition (a function inside a function inside a function).

    • Differentiate by working systematically from the outside in.

    • The constant coefficient 1919 is factored out during differentiation.

  • Outer Level Decomposition:

    • Outside function: f(x)=x2f(x) = x^2

    • Inside function: g(x)=sin⁡(x7)g(x) = \sin(x^7)

    • Derivative of outer function: f′(x)=2xf'(x) = 2x

    • Outer derivative evaluated at inside: f′(g(x))=2sin⁡(x7)f'(g(x)) = 2\sin(x^7)

  • Inner Level Decomposition (Chain Rule applied to g(x)g(x)):

    • Let g(x)=h(k(x))g(x) = h(k(x))

    • Outer inner function: h(x)=sin⁡(x)h(x) = \sin(x)

    • Inner inner function: k(x)=x7k(x) = x^7

    • Derivative of h(x)h(x): h′(x)=cos⁡(x)h'(x) = \cos(x)

    • h′h' evaluated at k(x)k(x): h′(k(x))=cos⁡(x7)h'(k(x)) = \cos(x^7)

    • Derivative of k(x)k(x) via Power Rule: k′(x)=7x7−1=7x6k'(x) = 7x^{7-1} = 7x^6

    • Derivative of g(x)g(x):         g′(x)=h′(k(x))×k′(x)=7x6cos⁡(x7)g'(x) = h'(k(x)) \times k'(x) = 7x^6\cos(x^7)

  • Combining All Components:

    • Include initial coefficient 1919:         dydx=19×f′(g(x))×g′(x)\frac{dy}{dx} = 19 \times f'(g(x)) \times g'(x)         dydx=19×2sin⁡(x7)×7x6cos⁡(x7)\frac{dy}{dx} = 19 \times 2\sin(x^7) \times 7x^6\cos(x^7)

  • Arithmetic Multiplication Breakdown:

    • Multiply scalar constants:         19×2×7=19×1419 \times 2 \times 7 = 19 \times 14

    • Expanding 19×1419 \times 14:         (10+9)×14=100+90+40+36=266(10 + 9) \times 14 = 100 + 90 + 40 + 36 = 266

  • Final Simplified Derivative:     dydx=266x6sin⁡(x7)cos⁡(x7)\frac{dy}{dx} = 266x^6\sin(x^7)\cos(x^7)     (where x7x^7 is the explicit argument of both the sine and cosine functions).