CHM 111 General Chemistry - Introduction to Chemistry, Scientific Method, and Measurement

Course Overview and Academic Resources

  • Course Designation: CHM 111
  • Academic Support Contacts and Campus Resources:
    • STEM Center: ST318, Phone: 985-5654
    • Tutoring Services: Academic Link located in Brown Library
    • Counseling Services: Kimberly Stafford, Phone: 857-6711
    • Writing Center
  • Core Course Platforms and References:
    • Canvas Learning Management System
    • Official Course Syllabus
    • Instructor Office Hours
    • MindTap Online Homework System
    • Khan Academy Online Resources
    • LibreTexts Chemistry Textbook Platform

Strategies for Success in Science Courses

  • Dedicated Study Time: Allocate approximately 3 hours3\,\text{hours} of study time outside of class for every 1 credit1\,\text{credit} hour of enrollment.
  • Textbook Reading: Consistently read assigned textbook sections to solidify concepts.
  • Time Management: Avoid last-minute cramming; maintain a steady study schedule.
  • Deep Understanding: Focus on understanding core concepts rather than relying exclusively on rote memorization.
  • Critical Analysis: Actively sharpen tools for critical analysis and logical reasoning.
  • Visual Data Literacy: Carefully analyze graphs, tables, and figures from lectures and readings.
  • Laboratory Preparation: Prepare thoroughly for laboratory experiments prior to attending lab sessions.
  • Practice Execution: Solve extensive practice problems repeatedly to master calculations and concepts.
  • Active Inquiry: Ask questions immediately when encountering confusing or unclear material.

Chapter 1 Overview: Chemistry and Matter on the Atomic Scale

  • Chapter Scope:
    • Section 1.1: What Is Chemistry?
    • Section 1.2: Classification of Matter
    • Section 1.3: Units and Measurement
    • Section 1.4: Unit Conversions
  • Chemistry Scale Comparison:
    • A human is approximately 99 orders of magnitude larger than an aspirin molecule.
    • This scale difference corresponds to a factor of 10910^9, or 1 billion1\,\text{billion} times larger.

Scientific Method and Research Methodology

  • Sequential Steps of the Scientific Method:
    • Observation: Identifying a phenomenon in the physical world.
    • Question: Formulating a specific inquiry based on physical observations.
    • Research: Investigating existing literature surrounding the observed trend.
    • Hypothesis: Establishing a testable explanation guided by inductive reasoning.
    • Experiment: Testing predictions under controlled experimental conditions.
    • Data Collection: Gathering objective quantitative and qualitative measurements.
    • Conclusion: Analyzing collected data to corroborate or refute the hypothesis.
  • Categorization of Observations:
    • Subjective Observations: Statements based on personal feelings, judgments, or opinions rather than verifiable facts.
    • Example: Starbucks Coffee is amazing.
    • Example: Nirvana is an awesome band.
    • Example: Tennessee is an awesome football team.
    • Example: It is about 2 miles2\,\text{miles} to I-581 from campus.
    • Objective Observations: Statements grounded strictly in measurable or verifiable facts (required for scientific inquiry).
    • Example: Fishburn Hall is beside Brown Library.
    • Example: 81 is an interstate highway.
    • Example: There is a Starbucks Coffee store on the VWCC campus.
    • Example: There are 100 centimeters100\,\text{centimeters} in 1 meter1\,\text{meter}.
  • Literature Research Rules:
    • Review peer-reviewed journal articles related to the initial observation.
    • Evaluate whether other researchers have observed similar trends and proposed valid explanations.
    • Utilize gathered information to structure a testable hypothesis and design controlled experiments.
    • Avoid non-peer-reviewed sources or open-wiki websites.
  • Scientific Hypotheses:
    • Definition: A rational accounting for a set of observations, guided by inductive reasoning ("an explanation on trial").
    • Must yield specific predictions that can be empirically tested via further observations or controlled experimentation.
  • Experimental Variables and Controls:
    • Controlled Experiment: Compares an experimental group against an untreated control group.
    • Experimental Variables: Factors that are altered or measured within the experimental system.
    • Independent Variable: The specific factor directly manipulated by researchers.
    • Dependent Variable: The observed effect or response resulting from manipulation of the independent variable.
  • Data Analysis and Reporting:
    • Analyze data using mathematical equations, graphical representations, data tables, and error analysis.
    • Draw logical conclusions that either corroborate (support) or refute the starting hypothesis.
    • Publish and report findings to the scientific community.

Classification and States of Matter

  • Atomic Scale Classification of Matter:
    • Pure Substance: Matter composed of only a single type of atom or molecule.
    • Element: A pure substance that cannot be broken down into simpler substances by chemical reactions (e.g., copper atoms on a silica surface visualized via Scanning Tunneling Microscope).
    • Compound: A pure substance composed of two or more distinct elements chemically combined in fixed proportions.
  • Categorization Practice (Elements vs. Compounds):
    • Fe\text{Fe}: Element
    • CH4\text{CH}_4: Compound
    • O2\text{O}_2: Element
    • FeCl3\text{FeCl}_3: Compound
  • Macroscopic States of Matter:
    • Solid State:
    • Characterized by a rigid, defined shape and fixed volume.
    • Examples: Ice, iron (Fe\text{Fe}), gold (Au\text{Au}).
    • Crystalline Solid: Atoms or molecules are arranged in long-range, repeating geometric patterns (e.g., diamond, graphite).
    • Amorphous Solid: Atoms or molecules lack any long-range positional order (e.g., glass, plastic).
    • Liquid State:
    • Characterized by a definite volume but no definite shape; takes the shape of its container while maintaining a free surface.
    • Particles are packed closely together but possess freedom of movement past one another.
    • Gas State:
    • Characterized by having neither a definite shape nor a definite volume.
    • Expands completely to occupy the shape and volume of its container; easily compressible due to large interparticle spacing.
  • Scale Categorization Practice:
    • An RNA molecule: Atomic scale
    • A mercury atom: Atomic scale
    • A sample of liquid mercury: Macroscopic scale

Physical and Chemical Changes and Properties

  • Physical vs. Chemical Changes:
    • Physical Change: A process that alters state or appearance without altering chemical composition.
    • Example: Liquid water boiling on a stove into gaseous steam:

H2O(l)→H2O(g)\text{H}_2\text{O}(l) \rightarrow \text{H}_2\text{O}(g)

  • Chemical Change: A process that alters the chemical composition of matter, converting it into entirely different substances.
    • Example: An iron nail rusting, where iron combines with oxygen to yield iron(II) oxide:

2 Fe(s)+O2(g)→2 FeO(s)2\,\text{Fe}(s) + \text{O}_2(g) \rightarrow 2\,\text{FeO}(s)

  • Physical vs. Chemical Properties:
    • Physical Property: A property displayed by a substance without changing its chemical composition.
    • Examples: Melting point, boiling point, density, odor.
    • Chemical Property: A property displayed by a substance only through changing its chemical composition via a chemical reaction.
    • Examples: Flammability, corrosiveness, acidity, toxicity, reaction of alkali metals with water.
  • Property Classification Practice:
    • Evaporation of rubbing alcohol: Physical change (Physical property)
    • Burning of lamp oil: Chemical change (Chemical property)
    • Bleaching of hair with hydrogen peroxide: Chemical change (Chemical property)
    • Forming of frost on a cold night: Physical change (Physical property)

Classification and Separation of Mixtures

  • Mixture Definition: Matter composed of two or more different types of atoms or molecules combined in continuously variable proportions.
  • Types of Mixtures:
    • Heterogeneous Mixture: A mixture in which the physical composition varies from one region to another.
    • Homogeneous Mixture (Solution): A mixture in which the physical composition is uniform throughout.
  • Physical Separation Methods:
    • Separation by Density: Decantation and centrifugation
    • Separation by Boiling Point: Distillation
    • Separation by State of Matter: Filtration
    • Separation by Intermolecular Forces: Chromatography
    • Separation by Vapor Pressure: Evaporation
    • Separation by Magnetism: Magnets
    • Separation by Solubility: Filtration

Measurement, Units, and SI Prefixes

  • Units Overview: Standard quantities used to express physical measurements across the English system, Metric system, and International System of Units (SI).
  • Mandatory SI Prefixes (Atto- to Exa-):
    • atto- (a\text{a}): 10−1810^{-18}
    • femto- (f\text{f}): 10−1510^{-15}
    • pico- (p\text{p}): 10−1210^{-12}
    • nano- (n\text{n}): 10−910^{-9}
    • micro- (μ\mu): 10−610^{-6}
    • milli- (m\text{m}): 10−310^{-3}
    • centi- (c\text{c}): 10−210^{-2}
    • deci- (d\text{d}): 10−110^{-1}
    • deka- (da\text{da}): 10110^{1}
    • hecto- (h\text{h}): 10210^{2}
    • kilo- (k\text{k}): 10310^{3}
    • mega- (M\text{M}): 10610^{6}
    • giga- (G\text{G}): 10910^{9}
    • tera- (T\text{T}): 101210^{12}
    • peta- (P\text{P}): 101510^{15}
    • exa- (E\text{E}): 101810^{18}
    • Note: SI prefix factors must be fully memorized. English-to-English and metric-to-English conversions are provided on exams.
  • Standard Physical Units:
    • Length: The SI base unit is the meter (m\text{m}).
    • Defined by the exact speed of light in a vacuum:

c=299  ⁣792  ⁣458 m/sc = 299\,\!792\,\!458\,\text{m/s}

* Length equalities:

100 cm=1 m100\,\text{cm} = 1\,\text{m}

1 cm=10−2 m1\,\text{cm} = 10^{-2}\,\text{m}

1 nm=10−9 m1\,\text{nm} = 10^{-9}\,\text{m}

  • Volume: Measure of space occupied by matter.
    • Expressed in cubic centimeters (cm3\text{cm}^3), liters (L\text{L}), and milliliters (mL\text{mL}).
    • Essential identity:

1 cm3=1 mL1\,\text{cm}^3 = 1\,\text{mL}

  • Mass: Measure of matter contained within an object (distinct from weight).
    • Units: Milligrams (mg\text{mg}), grams (g\text{g}), kilograms (kg\text{kg}).

Temperature Scales and Energy

  • Temperature and Heat Flow:
    • Temperature determines the direction of heat flow; heat flows spontaneously from high temperature to low temperature.
    • Chemistry temperature scales: Celsius (∘C^{\circ}\text{C}) and Kelvin (K\text{K}).
    • Temperature conversion formulas:

tF=1.8×tC+32∘t_{\text{F}} = 1.8 \times t_{\text{C}} + 32^{\circ}

TK=tC+273.15T_{\text{K}} = t_{\text{C}} + 273.15

  • Temperature Scale Comparison Points:
    • Water Boiling Point: 212∘F=100∘C=373.15 K212^{\circ}\text{F} = 100^{\circ}\text{C} = 373.15\,\text{K}
    • Water Freezing Point: 32∘F=0∘C=273.15 K32^{\circ}\text{F} = 0^{\circ}\text{C} = 273.15\,\text{K}
    • Coincidence Point: −40∘F=−40∘C=233.15 K-40^{\circ}\text{F} = -40^{\circ}\text{C} = 233.15\,\text{K}
    • Temperature Intervals: An interval of 180 Fahrenheit degrees180\,\text{Fahrenheit degrees} equals 100 Celsius degrees100\,\text{Celsius degrees} and 100 kelvins100\,\text{kelvins}.
  • Energy Principles:
    • Energy: The capacity to do work.
    • Total Energy: Sum of kinetic energy and potential energy.
    • Work: Action of a force through a distance.
    • Kinetic Energy: Energy associated with object motion.
    • Potential Energy: Energy associated with an object's position or chemical composition.
    • Thermal Energy: Energy associated with temperature (a form of kinetic energy).
    • Law of Conservation of Energy: Energy is neither created nor destroyed.
    • SI Unit of Energy: Joule (J\text{J}), defined as the energy needed to accelerate a 1 kg1\,\text{kg} mass using a 1 N1\,\text{N} force across 1 m1\,\text{m}:

1 J=1 kg×m2s2=1 N⋅m1\,\text{J} = 1\,\text{kg} \times \frac{\text{m}^2}{\text{s}^2} = 1\,\text{N} \cdot \text{m}

Density and Physical Quantities

  • Density Definition and Formula:
    • Density is an intensive physical property of matter:

Density=MassVolume\text{Density} = \frac{\text{Mass}}{\text{Volume}}

  • Standard units: g/mL\text{g/mL} or g/cm3\text{g/cm}^3 for solids and liquids; g/L\text{g/L} for gases.
    • Intensive vs. Extensive Properties:
  • Intensive Property: Independent of sample size (e.g., density, temperature).
  • Extensive Property: Dependent on sample size (e.g., mass, volume).
    • Density Comparison Example:
  • Material A: Mass=10.0 g\text{Mass} = 10.0\,\text{g}, Volume=2.00 L=2000 mL\text{Volume} = 2.00\,\text{L} = 2000\,\text{mL}

dA=10.0 g2000 mL=0.00500 g/mLd_{\text{A}} = \frac{10.0\,\text{g}}{2000\,\text{mL}} = 0.00500\,\text{g/mL}

  • Material B: Mass=5.00 g\text{Mass} = 5.00\,\text{g}, Volume=10.0 cm3\text{Volume} = 10.0\,\text{cm}^3

dB=5.00 g10.0 cm3=0.500 g/cm3d_{\text{B}} = \frac{5.00\,\text{g}}{10.0\,\text{cm}^3} = 0.500\,\text{g/cm}^3

  • Material C: Sinks in ethanol (d=0.789 g/cm3d = 0.789\,\text{g/cm}^3) and floats on water (d=1.00 g/cm3d = 1.00\,\text{g/cm}^3)

0.789 g/cm3<dC<1.00 g/cm30.789\,\text{g/cm}^3 < d_{\text{C}} < 1.00\,\text{g/cm}^3

  • Conclusion: Material C possesses the largest density.

Significant Figures, Precision, and Accuracy

  • Significant Figures Principles:
    • Reflect experimental uncertainty in measured values.
    • Examples: 8.00 mL8.00\,\text{mL} (33 significant figures), 760±10 mg760 \pm 10\,\text{mg}, 5.47×10−2 mL5.47 \times 10^{-2}\,\text{mL} (33 significant figures).
  • Mathematical Rules for Calculations:
    • Multiplication and Division: Answer retains the same number of significant figures as the factor with the fewest significant figures.
    • Practice 1:

5.03 mL×2.1 mL×10.04 mL=106.05252 mL35.03\,\text{mL} \times 2.1\,\text{mL} \times 10.04\,\text{mL} = 106.05252\,\text{mL}^3

* Smallest significant figures in input is 22 (from 2.1 mL2.1\,\text{mL}). Reported answer: 1.1×102 mL31.1 \times 10^2\,\text{mL}^3 (or 110 mL3110\,\text{mL}^3).
* Practice 2:

2.543 cm×5.81 cm0.02 cm×1.1 cm=671.5831\frac{2.543\,\text{cm} \times 5.81\,\text{cm}}{0.02\,\text{cm} \times 1.1\,\text{cm}} = 671.5831

* Smallest significant figures in input is 11 (from 0.02 cm0.02\,\text{cm}). Reported answer: 7 \times 10^2$.\n  * Addition and Subtraction: Answer retains the same number of decimal places as the term with the fewest decimal places.\n    * Practice:\n\n1.12 + 0.1 + 2.567 = 3.787\n\n    * Smallest decimal places in input is 1(from(from0.1).Reportedanswer:). Reported answer:3.8$.
  • Intermediate Rounding Rule:
    • Keep all digits during multi-step calculations; underline the least significant digit at each step, and round only at the final step.
  • Exact Numbers:
    • Defined values or counts do not limit the significant figures of a calculation.
    • Example: Force on a dropped 10.1 kg10.1\,\text{kg} mass:

F=m×g=10.1 kg×9.8 m/s2=98.98 kg⋅m/s2F = m \times g = 10.1\,\text{kg} \times 9.8\,\text{m/s}^2 = 98.98\,\text{kg} \cdot \text{m/s}^2

  • Reported to 22 significant figures: 99 N99\,\text{N}.
    • Precision vs. Accuracy:
  • Precision: Closeness of agreement among multiple experimental measurements under identical conditions.
  • Accuracy: Closeness of a measured value to the true or accepted value.

General Problem-Solving Strategy

  • Step 1: Write down given values with explicit units and labels.
  • Step 2: Clearly identify the target variable to solve for.
  • Step 3: Determine required formulas, conversion factors, and constants.
  • Step 4: Perform calculations using dimensional analysis and verify that the final answer is physically reasonable.

Comprehensive Practice Problems and Solutions

  • Practice Problem 1: Converting Units Raised to Powers
    • Task: Convert 4.85 cm34.85\,\text{cm}^3 to in3\text{in}^3.
    • Calculation:

4.85 cm3×(1 in2.54 cm)3=4.85 cm3×1 in316.387 cm3=0.29596 in34.85\,\text{cm}^3 \times \left(\frac{1\,\text{in}}{2.54\,\text{cm}}\right)^3 = 4.85\,\text{cm}^3 \times \frac{1\,\text{in}^3}{16.387\,\text{cm}^3} = 0.29596\,\text{in}^3

  • Final Answer (3 sig figs): 0.296 in30.296\,\text{in}^3

    • Practice Problem 2: Metric Unit Conversions
  • Convert 7.5 cm7.5\,\text{cm} to m\text{m}:

7.5 cm×10−2 m1 cm=0.075 m7.5\,\text{cm} \times \frac{10^{-2}\,\text{m}}{1\,\text{cm}} = 0.075\,\text{m}

  • Convert 1.75 mg1.75\,\text{mg} to g\text{g}:

1.75 mg×10−3 g1 mg=0.00175 g1.75\,\text{mg} \times \frac{10^{-3}\,\text{g}}{1\,\text{mg}} = 0.00175\,\text{g}

  • Convert 2.95×106 L2.95 \times 10^6\,\text{L} to ML\text{ML}:

2.95×106 L×1 ML106 L=2.95 ML2.95 \times 10^6\,\text{L} \times \frac{1\,\text{ML}}{10^6\,\text{L}} = 2.95\,\text{ML}

  • Practice Problem 3: Density Unit Conversion (Example 1.4.3)
    • Task: Use the density of diamond (d=3.52 g/cm3d = 3.52\,\text{g/cm}^3) to find the volume of a 1.2-carat1.2\text{-carat} diamond (1 carat=0.200 g1\,\text{carat} = 0.200\,\text{g}).
    • Mass calculation:

1.2 carats×0.200 g1 carat=0.24 g1.2\,\text{carats} \times \frac{0.200\,\text{g}}{1\,\text{carat}} = 0.24\,\text{g}

  • Volume calculation:

V=md=0.24 g3.52 g/cm3=0.06818 cm3V = \frac{m}{d} = \frac{0.24\,\text{g}}{3.52\,\text{g/cm}^3} = 0.06818\,\text{cm}^3

  • Final Answer (2 sig figs): 0.068 cm30.068\,\text{cm}^3

    • Practice Problem 4: Distance Unit Conversion
  • Task: Convert 125 miles125\,\text{miles} to meters.

  • Calculation:

125 mi×1.60934 km1 mi×1000 m1 km=201  ⁣167.5 m125\,\text{mi} \times \frac{1.60934\,\text{km}}{1\,\text{mi}} \times \frac{1000\,\text{m}}{1\,\text{km}} = 201\,\!167.5\,\text{m}

  • Final Answer (3 sig figs): 2.01×105 m2.01 \times 10^5\,\text{m}

    • Practice Problem 5: Nickel Atom Calculations
  • Part A: Radius of a nickel atom is 125 pm125\,\text{pm}. Convert to centimeters.

125 pm×10−12 m1 pm×100 cm1 m=1.25×10−8 cm125\,\text{pm} \times \frac{10^{-12}\,\text{m}}{1\,\text{pm}} \times \frac{100\,\text{cm}}{1\,\text{m}} = 1.25 \times 10^{-8}\,\text{cm}

  • Part B: Single nickel atom mass is 9.75×10−23 g9.75 \times 10^{-23}\,\text{g}. Determine how many nickel atoms lined up side-by-side are required to span 48.5 cm48.5\,\text{cm} (19 inches19\,\text{inches}).
    • Atomic Diameter:

Diameter=2×r=2×(1.25×10−8 cm)=2.50×10−8 cm/atom\text{Diameter} = 2 \times r = 2 \times (1.25 \times 10^{-8}\,\text{cm}) = 2.50 \times 10^{-8}\,\text{cm/atom}

* Number of Atoms:

Atoms=48.5 cm2.50×10−8 cm/atom=1.94×109 atoms\text{Atoms} = \frac{48.5\,\text{cm}}{2.50 \times 10^{-8}\,\text{cm/atom}} = 1.94 \times 10^9\,\text{atoms}

  • Part C: Mass of nickel required for this span in grams:

Mass=(1.94×109 atoms)×(9.75×10−23 g/atom)=1.8915×10−13 g\text{Mass} = (1.94 \times 10^9\,\text{atoms}) \times (9.75 \times 10^{-23}\,\text{g/atom}) = 1.8915 \times 10^{-13}\,\text{g}

  • Final Answer (3 sig figs): 1.89×10−13 g1.89 \times 10^{-13}\,\text{g}