Comprehensive Study Notes on Thermodynamics and Chemical Energetics

Introduction to Thermodynamics

  • Thermodynamics is the only physical theory of universal content which, within the framework of the applicability of its basic concepts, will never be overthrown, as stated by Albert Einstein.

  • Energy stored by molecules as chemical energy can be released as heat during chemical reactions, such as the burning of methane, cooking gas, or coal in air.

  • Chemical energy can be utilized to do mechanical work (in an engine) or to provide electrical energy (through a galvanic cell like a dry cell).

  • Thermodynamics is the study of the interrelation and transformation of various forms of energy.

  • The laws of thermodynamics deal with macroscopic systems involving a large number of molecules rather than microscopic systems containing only a few molecules.

  • Thermodynamics focuses on the initial and final states of a system undergoing change, rather than the specific rate at which energy transformations occur.

  • The laws apply only when a system is in equilibrium or moving from one equilibrium state to another.

  • In an equilibrium state, macroscopic properties such as pressure and temperature do not change over time.

Thermodynamic Terms: System and Surroundings

  • A system refers to the specific part of the universe in which observations are being made.

  • The surroundings include everything else in the universe other than the system.

  • The Universe is the sum of the system and the surroundings: Universe=System+Surroundings\text{Universe} = \text{System} + \text{Surroundings}.

  • In practice, surroundings are the portion of the remaining universe that can interact with the system, typically the immediate neighborhood of the system.

  • The boundary is the real or imaginary surface that separates the system from the surroundings, allowing for the control and tracking of matter and energy movements.

Types of Thermodynamic Systems

  • Open System: In this system, there is an exchange of both energy and matter between the system and the surroundings. An example is reactants kept in an open beaker.

  • Closed System: There is no exchange of matter, but an exchange of energy is possible between the system and its surroundings. An example is reactants in a closed vessel made of conducting material (e.g., copper or steel).

  • Isolated System: There is no exchange of either energy or matter between the system and the surroundings. An example is reactants kept in a thermos flask or a closed insulated vessel.

The State of the System and State Functions

  • To describe a system, quantitative properties such as pressure (pp), volume (VV), temperature (TT), and composition must be specified.

  • Thermodynamics deals with average measurable properties rather than the motion of individual particles.

  • State Functions (or State Variables): These are macroscopic properties whose values depend only on the current state of the system and not on the path taken to reach that state. Examples include pressure (pp), volume (VV), temperature (TT), and amount (nn).

  • Fixing a minimum number of macroscopic properties automatically defines the values of the remaining properties.

Internal Energy as a State Function

  • Internal Energy (UU): This represents the total energy of a system, including chemical, electrical, mechanical, or any other type of energy. It is a state function.

  • Internal energy changes when:

    • Heat passes into or out of the system.

    • Work is done on or by the system.

    • Matter enters or leaves the system.

Work and Adiabatic Processes

  • Adiabatic Process: A process in which there is no transfer of heat between the system and surroundings (q=0q = 0). The system is separated from its surroundings by an adiabatic wall.

  • Experiments by J. P. Joule (1840–1850) showed that a specific amount of work done on a system produces the same change in internal energy regardless of the method (mechanical or electrical).

  • Adiabatic Work (wadw_{ad}): The work required to bring about a change of state is equal to the difference in internal energy: ΔU=U2−U1=wad\Delta U = U_2 - U_1 = w_{ad}.

  • Sign Convention for Work:

    • Work done on the system (ww) is positive (++), leading to an increase in internal energy.

    • Work done by the system (ww) is negative (−-), leading to a decrease in internal energy.

Heat and Internal Energy Change

  • Heat (qq): The exchange of energy resulting from a temperature difference between the system and surroundings through thermally conducting walls.

  • If no work is done at constant volume, the change in internal energy equals the heat absorbed: ΔU=q\Delta U = q.

  • Sign Convention for Heat:

    • Heat transferred from surroundings to the system (qq) is positive (++), increasing internal energy.

    • Heat transferred from the system to surroundings (qq) is negative (−-), decreasing internal energy.

The First Law of Thermodynamics

  • The general case for changing the state of a system involves both work and heat: ΔU=q+w\Delta U = q + w.

  • This equation is the mathematical statement of the First Law of Thermodynamics, which states that the energy of an isolated system is constant.

  • It is also known as the Law of Conservation of Energy: Energy can neither be created nor destroyed.

  • While absolute values of internal energy (UU) cannot be specified, the changes in internal energy (ΔU\Delta U) can be accurately measured.

Pressure-Volume Work

  • Work done during the compression or expansion of a gas is called mechanical or pressure-volume (pVpV) work.

  • For a gas in a cylinder with a frictionless piston and cross-sectional area (AA), if the piston moves a distance (ll) under external pressure (pexp_{ex}):

    • Work (w)=force×distance=pex×A×l\text{Work } (w) = \text{force} \times \text{distance} = p_{ex} \times A \times l

    • ΔV=(Vf−Vi)\Delta V = (V_f - V_i). Since compression involves a decrease in volume, the expression is: w=−pex×(Vf−Vi)=−pexΔVw = -p_{ex} \times (V_f - V_i) = -p_{ex} \Delta V.

  • If volume decreases (compression), ΔV\Delta V is negative, so ww is positive (work done on the system).

  • If volume increases (expansion), ΔV\Delta V is positive, so ww is negative (work done by the system).

Reversible and Irreversible Processes

  • Reversible Process: A process that can be reversed at any moment by an infinitesimal change. It proceeds infinitely slowly through a series of equilibrium states where the system and surroundings are always in near equilibrium.

  • Irreversible Process: Any process that is not reversible.

  • For a reversible process, the work done is: wrev=−∫ViVfpindVw_{rev} = - \int_{V_i}^{V_f} p_{in} dV.

  • For an ideal gas at constant temperature (isothermal process):

    • pV=nRTpV = nRT

    • wrev=−2.303nRTlog⁡(VfVi)w_{rev} = -2.303 nRT \log\left(\frac{V_f}{V_i}\right).

  • Free Expansion: The expansion of a gas into a vacuum (pex=0p_{ex} = 0). Here, w=0w = 0. If it is also isothermal, ΔU=0\Delta U = 0 and q=0q = 0.

Enthalpy: A New State Function

  • Most reactions occur at constant pressure rather than constant volume. We define Enthalpy (HH) as: H=U+pVH = U + pV.

  • Change in enthalpy at constant pressure is equal to the heat absorbed (qpq_p):

    • ΔH=qp\Delta H = q_p

    • For finite changes at constant pressure: ΔH=ΔU+pΔV\Delta H = \Delta U + p \Delta V.

  • Relationship for reactions involving gases:

    • Using the ideal gas law (pV=nRTpV = nRT) at constant temperature and pressure: pΔV=ΔngRTp \Delta V = \Delta n_g RT.

    • Hence, ΔH=ΔU+ΔngRT\Delta H = \Delta U + \Delta n_g RT, where Δng\Delta n_g is the difference between moles of gaseous products and gaseous reactants.

  • Exothermic reactions evolve heat and have a negative ΔH\Delta H. Endothermic reactions absorb heat and have a positive ΔH\Delta H.

Extensive and Intensive Properties

  • Extensive Property: A property whose value depends on the quantity or size of matter in the system. Examples: mass, volume, internal energy, enthalpy, heat capacity.

  • Intensive Property: A property that does not depend on the quantity or size of matter. Examples: temperature, density, pressure.

  • Molar Property (χm\chi_m): The value of an extensive property for 1 mole of substance, which is an intensive property (χm=χn\chi_m = \frac{\chi}{n}).

Heat Capacity and Its Specific Forms

  • Heat Capacity (CC): The coefficient relating heat absorbed to temperature rise (q=CΔTq = C \Delta T). It is an extensive property.

  • Molar Heat Capacity (CmC_m): The heat required to raise the temperature of one mole of a substance by 1∘C1^{\circ} C (or 1 K1\,K).

  • Specific Heat Property (cc): The heat required to raise the temperature of one unit mass of a substance by 1∘C1^{\circ} C (or 1 K1\,K).

  • q=c×m×ΔT=CΔTq = c \times m \times \Delta T = C \Delta T.

  • Relationship between CpC_p and CVC_V for an Ideal Gas:

    • At constant volume: qV=CVΔT=ΔUq_V = C_V \Delta T = \Delta U.

    • At constant pressure: qp=CpΔT=ΔHq_p = C_p \Delta T = \Delta H.

    • For one mole of an ideal gas: ΔH=ΔU+Δ(RT)=ΔU+RΔT\Delta H = \Delta U + \Delta(RT) = \Delta U + R \Delta T.

    • Substituting heat capacities: CpΔT=CVΔT+RΔTC_p \Delta T = C_V \Delta T + R \Delta T.

    • Thus: Cp−CV=RC_p - C_V = R.

Calorimetry and Measuring Energy Changes

  • Calorimetry is an experimental technique to measure energy changes in a vessel called a calorimeter submerged in a liquid.

  • ΔU\Delta U Measurements: Carried out in a bomb calorimeter. A combustible substance is burned in oxygen inside a sealed steel vessel (bomb). Because volume is constant (ΔV=0\Delta V = 0), no work is done. The temperature change is converted to qVq_V using the heat capacity of the calorimeter.

  • ΔH\Delta H Measurements: Carried out at constant pressure. The heat change measured (qpq_p) is the enthalpy of reaction (ΔrH\Delta_r H).

Enthalpy of Reaction (ΔrH\Delta_r H)

  • ΔrH=(∑enthalpies of products)−(∑enthalpies of reactants)\Delta_r H = (\sum \text{enthalpies of products}) - (\sum \text{enthalpies of reactants}).

  • Mathematically: ΔrH=∑iaiHproducts−∑ibiHreactants\Delta_r H = \sum_{i} a_i H_{products} - \sum_{i} b_i H_{reactants}, where aia_i and bib_i are stoichiometric coefficients.

  • Standard Enthalpy of Reaction (ΔrHo\Delta_r H^{\small o}): The enthalpy change when all participating substances are in their standard states.

  • Standard State: The pure form of a substance at 1 bar1\,bar pressure and a specified temperature (usually 298 K298\,K).

Phase Transformations and Their Enthalpies

  • Standard Enthalpy of Fusion (ΔfusHo\Delta_{fus} H^{\small o}): Enthalpy change for melting one mole of a solid substance in its standard state. It is always positive.

  • Standard Enthalpy of Vaporization (ΔvapHo\Delta_{vap} H^{\small o}): Heat required to vaporize one mole of a liquid at constant temperature and standard pressure.

  • Standard Enthalpy of Sublimation (ΔsubHo\Delta_{sub} H^{\small o}): Enthalpy change when one mole of a solid sublimes at constant temperature and standard pressure.

  • The magnitude of these changes depends on intermolecular interactions (e.g., hydrogen bonding in water vs. dipole-dipole in acetone).

Standard Molar Enthalpy of Formation (ΔfHo\Delta_f H^{\small o})

  • This is the enthalpy change for the formation of one mole of a compound from its constituent elements in their most stable states of aggregation (reference states).

  • By convention, ΔfHo\Delta_f H^{\small o} of an element in its reference state is taken as zero.

  • Reference states at 25∘C25^{\circ} C and 1 bar1\,bar: H2 (g)\text{H}_2\,(g), O2 (g)\text{O}_2\,(g), Cgraphite (s)\text{C}_{graphite}\,(s), Srhombic (s)\text{S}_{rhombic}\,(s).

  • ΔrHo=∑aiΔfHo(products)−∑biΔfHo(reactants)\Delta_r H^{\small o} = \sum a_i \Delta_f H^{\small o}(products) - \sum b_i \Delta_f H^{\small o}(reactants).

Hess’s Law of Constant Heat Summation

  • Since enthalpy is a state function, the change in enthalpy for a reaction is independent of the path.

  • Hess’s Law: If a reaction takes place in several steps, the standard reaction enthalpy is the sum of the standard enthalpies of the intermediate reactions.

  • Example: Enthalpy for C(graphite)+12O2(g)→CO(g)\text{C}(graphite) + \frac{1}{2} \text{O}_2(g) \rightarrow \text{CO}(g) can be calculated by combining enthalpies of forming CO2\text{CO}_2 from carbon and then reacting CO\text{CO} with oxygen to form CO2\text{CO}_2.

Bond Enthalpy and Enthalpy of Atomization

  • Enthalpy of Atomization (ΔaHo\Delta_a H^{\small o}): Enthalpy change on breaking one mole of bonds completely to obtain gaseous atoms.

  • Bond Dissociation Enthalpy: For diatomic molecules, this is the enthalpy required to break one mole of covalent bonds in the gas phase. It is identical to the enthalpy of atomization for diatomic species.

  • Mean Bond Enthalpy: In polyatomic molecules like CH4\text{CH}_4, breaking successive C-H\text{C-H} bonds requires different amounts of energy. The mean bond enthalpy is the average of these values (14ΔaHo\frac{1}{4} \Delta_a H^{\small o} for CH4\text{CH}_4).

  • ΔrHo=∑(bond enthalpies of reactants)−∑(bond enthalpies of products)\Delta_r H^{\small o} = \sum (\text{bond enthalpies of reactants}) - \sum (\text{bond enthalpies of products}).

Lattice Enthalpy and Born-Haber Cycle

  • Lattice Enthalpy (ΔlatticeHo\Delta_{lattice} H^{\small o}): The enthalpy change when one mole of an ionic compound dissociates into its gaseous ions.

  • Lattice enthalpies cannot be measured directly. They are determined via the Born-Haber Cycle, which involves steps such as:

    1. Sublimation of metal (ΔsubHo\Delta_{sub} H^{\small o}).

    2. Ionization of metal atoms (ΔiHo\Delta_i H^{\small o}).

    3. Dissociation of non-metal molecules (12ΔbondHo\frac{1}{2} \Delta_{bond} H^{\small o}).

    4. Electron gain by non-metal atoms (ΔegHo\Delta_{eg} H^{\small o}).

    5. Formation of lattice (ΔlatticeHo\Delta_{lattice} H^{\small o}).

  • Example for NaCl(s)\text{NaCl}(s): ΔlatticeHo=+788 kJ/mol\Delta_{lattice} H^{\small o} = +788\,kJ/mol.

Enthalpies of Solution and Dilution

  • Enthalpy of Solution (ΔsolHo\Delta_{sol} H^{\small o}): The enthalpy change when one mole of a substance dissolves in a specified amount of solvent.

  • Infinite Dilution: Enthalpy change when interactions between ions/solute molecules are negligible as they are in an infinite amount of solvent.

  • ΔsolHo=ΔlatticeHo+ΔhydHo\Delta_{sol} H^{\small o} = \Delta_{lattice} H^{\small o} + \Delta_{hyd} H^{\small o}, where ΔhydHo\Delta_{hyd} H^{\small o} is the enthalpy of hydration.

  • Enthalpy of Dilution: The heat withdrawn from surroundings when additional solvent is added to a solution. It depends on original concentration and the amount of solvent added.

Spontaneity and Entropy

  • Spontaneous Process: An irreversible process that proceeds without external assistance. It has the potential to occur but may occur slowly.

  • Decrease in enthalpy (ΔH<0\Delta H < 0) is a contributory factor to spontaneity (exothermic reactions), but not the sole criterion (some endothermic reactions are spontaneous).

  • Entropy (SS): A thermodynamic function measuring the degree of randomness or disorder in a system. For an isolated system, the tendency to become more disordered drives spontaneous change.

  • Entropy Change (ΔS\Delta S): For a reversible process, ΔS=qrevT\Delta S = \frac{q_{rev}}{T}.

  • Entropy order: Solid<Liquid<Gas\text{Solid} < \text{Liquid} < \text{Gas}.

  • For a spontaneous process in an isolated system, ΔStotal>0\Delta S_{total} > 0, where ΔStotal=ΔSsystem+ΔSsurroundings\Delta S_{total} = \Delta S_{system} + \Delta S_{surroundings}.

The Second and Third Laws of Thermodynamics

  • Second Law of Thermodynamics: The entropy of the universe (or an isolated system) increases during a spontaneous process.

  • In exothermic reactions, heat released increases the disorder of the surroundings, making ΔStotal\Delta S_{total} positive.

  • Third Law of Thermodynamics: The entropy of any pure crystalline substance approaches zero as the temperature approaches absolute zero (0 K0\,K).

  • This law allows for the calculation of absolute entropy values for pure substances.

Gibbs Energy Change (ΔG\Delta G)

  • Gibbs Function (GG): Defined as G=H−TSG = H - TS. It is an extensive property and a state function.

  • Gibbs Equation: at constant temperature, ΔG=ΔH−TΔS\Delta G = \Delta H - T \Delta S.

  • Criteria for Spontaneity:

    • If ΔG<0\Delta G < 0 (negative), the process is spontaneous.

    • If ΔG>0\Delta G > 0 (positive), the process is non-spontaneous.

    • If ΔG=0\Delta G = 0, the system is in equilibrium.

  • ΔG\Delta G represents the net energy available to do useful work, also known as the "free energy" of the reaction.

Gibbs Energy and Equilibrium

  • For a reversible chemical reaction A+B⇌C+D\text{A} + \text{B} \rightleftharpoons \text{C} + \text{D}, equilibrium occurs when Gibbs energy is at a minimum (ΔrG=0\Delta_r G = 0).

  • Relationship between standard Gibbs energy (ΔrGo\Delta_r G^{\small o}) and the equilibrium constant (KK):

    • ΔrGo=−RTln⁡K=−2.303RTlog⁡K\Delta_r G^{\small o} = -RT \ln K = -2.303 RT \log K.

  • Strongly exothermic reactions (ΔrHo\Delta_r H^{\small o} large and negative) usually have negative ΔrGo\Delta_r G^{\small o} and large KK, going near completion.

  • Strongly endothermic reactions (ΔrHo\Delta_r H^{\small o} large and positive) usually have much smaller KK values, forming little product unless compensated by large entropy increases at high temperatures.

Questions and Discussion

  • Problem 5.1: Expressing internal energy change.

    • (i) No heat absorbed (q=0q=0), work done on system (ww): ΔU=wad\Delta U = w_{ad}, wall is adiabatic.

    • (ii) No work done (w=0w=0), heat taken out (−q-q): ΔU=−q\Delta U = -q, walls are thermally conducting.

    • (iii) Work done by system (ww) and heat supplied (qq): ΔU=q−w\Delta U = q - w, system is closed.

  • Problem 5.2: Two litres of ideal gas expand isothermally into a vacuum. Work (w)=−pexΔV=0(8)=0\text{Work } (w) = -p_{ex}\Delta V = 0(8) = 0. Heat (q)=−w=0\text{Heat } (q) = -w = 0.

  • Problem 5.5: Internal energy change for vaporizing $1\,mol of water at $1\,bar and 100∘C100^{\circ} C:

    • ΔH=41 kJ/mol\Delta H = 41\,kJ/mol, Δng=1\Delta n_g = 1.

    • ΔU=ΔH−ΔngRT=41.00 kJ/mol−(1×8.314×10−3×373)=37.904 kJ/mol\Delta U = \Delta H - \Delta n_g RT = 41.00\,kJ/mol - (1 \times 8.314 \times 10^{-3} \times 373) = 37.904\,kJ/mol.

  • Problem 5.10: Entropy trends.

    • (i) Liquid crystallizes: Entropy decreases (more ordered).

    • (ii) Crystalline solid 0 K to 115 K: Entropy increases (more disorder/oscillation).

    • (iv) H2(g)→2H(g)\text{H}_2(g) \rightarrow 2\text{H}(g): Entropy increases (more particles).

  • Problem 5.14: N2O4\text{N}_2\text{O}_4 dissociation at 60∘C60^{\circ} C (333 K333\,K). If $50\% dissociated, mole fractions $x_{\text{N}_2\text{O}_4} = 0.33 and $x_{\text{NO}_2} = 0.67.Equilibriumconstant. Equilibrium constantK_p = 1.33\,atm.Standardfreeenergychange. Standard free energy change\Delta_r G^{\small o} = -RT \ln K_p = -763.8\,kJ/mol$$.