Calc formula quiz 3/5
Integral Formulas
∫eu du=eu+C\int e^u \, du = e^u + C
∫1u du=ln∣u∣+C\int \frac{1}{u} \, du = \ln |u| + C
∫secutanu du=secu+C\int \sec u \tan u \, du = \sec u + C
∫tanu du=ln∣secu∣+C\int \tan u \, du = \ln |\sec u| + C
∫secu du=ln∣secu+tanu∣+C\int \sec u \, du = \ln |\sec u + \tan u| + C
∫cosu du=sinu+C\int \cos u \, du = \sin u + C
∫csc2u du=−cotu+C\int \csc^2 u \, du = -\cot u + C
∫sec2u du=tanu+C\int \sec^2 u \, du = \tan u + C
∫cscucotu du=−cscu+C\int \csc u \cot u \, du = -\csc u + C
∫cotu du=ln∣sinu∣+C\int \cot u \, du = \ln |\sin u| + C
∫cscu du=ln∣cscu−cotu∣+C\int \csc u \, du = \ln |\csc u - \cot u| + C
∫sinu du=−cosu+C\int \sin u \, du = -\cos u + C
∫au du=aulna+C\int a^u \, du = \frac{a^u}{\ln a} + C, where a>0a > 0, a≠1a \neq 1
Derivative Formulas
ddxlnu=1u⋅dudx\frac{d}{dx} \ln u = \frac{1}{u} \cdot \frac{du}{dx}
ddxlogau=1ulna⋅dudx\frac{d}{dx} \log_a u = \frac{1}{u \ln a} \cdot \frac{du}{dx}
ddxau=aulna⋅dudx\frac{d}{dx} a^u = a^u \ln a \cdot \frac{du}{dx}
Fundamental Theorem of Calculus (FTC)
First FTC:
ddx∫axf(t) dt=f(x)\frac{d}{dx} \int_{a}^{x} f(t) \, dt = f(x)Second FTC:
∫abf(x) dx=F(b)−F(a)\int_{a}^{b} f(x) \, dx = F(b) - F(a)Second FTC (Chain Rule Version):
ddx∫g(x)h(x)f(t) dt=f(h(x))h′(x)−f(g(x))g′(x)\frac{d}{dx} \int_{g(x)}^{h(x)} f(t) \, dt = f(h(x)) h'(x) - f(g(x)) g'(x)
Average Value Theorem
f(c)=1b−a∫abf(x) dxf(c) = \frac{1}{b-a} \int_{a}^{b} f(x) \, dx