Algebra 2/Trig Semester Review Notes

Section 6.1: Roots and Radical Expressions

  • Value of -0.027:

    • The cube root of -0.027 is -0.3, since (0.3)3=0.027(-0.3)^3 = -0.027.
  • Simplified form of 4x2y4\sqrt{4x^2y^4}:

    • 4x2y4=2xy2\sqrt{4x^2y^4} = 2|x|y^2 because the square root of 44 is 22, the square root of x2x^2 is x|x| (absolute value of xx), and the square root of y4y^4 is y2y^2.
  • Real solutions of the equation x4=81x^4 = 81:

    • The real solutions are x=3x = -3 and x=3x = 3, since (3)4=81(-3)^4 = 81 and (3)4=81(3)^4 = 81.

Section 6.2: Multiplying and Dividing Radical Expressions

  • Simplest form of 449x5-4\sqrt{49x^5} / 7x2\sqrt{7x^2}:

    • 449x5/7x2=47x2x/(x7)=28x2x/(x7)=4x49x4-4\sqrt{49x^5} / \sqrt{7x^2} = -4 * 7x^2\sqrt{x} / (x\sqrt{7}) = -28x^2\sqrt{x} / (x\sqrt{7}) = -4x\sqrt{49x^4} simplified form can be 7x7x-7x\sqrt{7x}
  • Simplest form of 80x7y6\sqrt{80x^7y^6}:

    • 80x7y6=165x6xy6=4x3y35x\sqrt{80x^7y^6} = \sqrt{16 * 5 * x^6 * x * y^6} = 4x^3y^3\sqrt{5x}.
  • Simplest form of 25xy215x4\sqrt{25xy^2} * \sqrt{15x^4}:

    • 25xy215x4=5yxx215=5x2y15x\sqrt{25xy^2} * \sqrt{15x^4} = 5y\sqrt{x} * x^2\sqrt{15} = 5x^2y\sqrt{15x}.
  • Simplest form of 75x5/12xy2\sqrt{75x^5} / \sqrt{12xy^2}:

    • 75x5/12xy2=(5x23x)/(2y3x)=(5x2)/(2y)\sqrt{75x^5} / \sqrt{12xy^2} = (5x^2\sqrt{3x}) / (2y\sqrt{3x}) = (5x^2) / (2y).
  • Simplest form of 4xy2/2xy2\sqrt{4xy^2} / \sqrt{2xy^2}:

    • 4xy2/2xy2=2\sqrt{4xy^2} / \sqrt{2xy^2} = \sqrt{2}.

Section 6.3: Binomial Radical Expressions

  • Simplest form of 2723322\sqrt{72} - 3\sqrt{32}:

    • 272332=23623162=262342=122122=02\sqrt{72} - 3\sqrt{32} = 2\sqrt{36 * 2} - 3\sqrt{16 * 2} = 2 * 6\sqrt{2} - 3 * 4\sqrt{2} = 12\sqrt{2} - 12\sqrt{2} = 0.
  • Simplest form of (27)(1+27)(2 - \sqrt{7})(1 + 2\sqrt{7}):

    • (27)(1+27)=2+47727=2+3714=12+37(2 - \sqrt{7})(1 + 2\sqrt{7}) = 2 + 4\sqrt{7} - \sqrt{7} - 2 * 7 = 2 + 3\sqrt{7} - 14 = -12 + 3\sqrt{7}.
  • Simplest form of (2+7)(27)(\sqrt{2} + \sqrt{7})(\sqrt{2} - \sqrt{7}):

    • (2+7)(27)=27=5(\sqrt{2} + \sqrt{7})(\sqrt{2} - \sqrt{7}) = 2 - 7 = -5.
  • Simplest form of 7/(2+5)7 / (2 + \sqrt{5}):

    • 7/(2+5)=7(25)/((2+5)(25))=7(25)/(45)=7(25)/(1)=14+757 / (2 + \sqrt{5}) = 7 * (2 - \sqrt{5}) / ((2 + \sqrt{5})(2 - \sqrt{5})) = 7(2 - \sqrt{5}) / (4 - 5) = 7(2 - \sqrt{5}) / (-1) = -14 + 7\sqrt{5}.
  • Simplest form of 8545258\sqrt{5} - 4\sqrt{5} - 2\sqrt{5}:

    • 854525=(842)5=258\sqrt{5} - 4\sqrt{5} - 2\sqrt{5} = (8 - 4 - 2)\sqrt{5} = 2\sqrt{5}.

Section 6.4: Rational Exponents

  • Simplest form of 1252/3125^{2/3}:

    • 1252/3=(53)2/3=52=25125^{2/3} = (5^3)^{2/3} = 5^2 = 25.
  • Simplest form of x1/3y2/3x^{1/3} * y^{2/3}:

    • There missing a options to answer in the text. Need more information to answer.
  • Simplest form of x1/3/x3/4x^{1/3} / x^{3/4}:

    • x1/3/x3/4=x(1/33/4)=x(4/129/12)=x5/12=1/x5/12x^{1/3} / x^{3/4} = x^{(1/3 - 3/4)} = x^{(4/12 - 9/12)} = x^{-5/12} = 1 / x^{5/12}.
  • Simplest form of (x2y4)1/2(x^2y^4)^{1/2}:

    • (x2y4)1/2=xy2(x^2y^4)^{1/2} = xy^2 .
  • Simplest form of (32x10y35)1/5(-32x^{10}y^{35})^{1/5}:

    • (32x10y35)1/5=2x2y7(-32x^{10}y^{35})^{1/5} = -2x^2y^7.

Section 6.5: Solving Square Root and Other Radical Equations

  • Solve for x: 2x43=1\sqrt{2x - 4} - 3 = 1

    • 2x4=4\sqrt{2x - 4} = 4
    • 2x4=162x - 4 = 16
    • 2x=202x = 20
    • x=10x = 10
  • Solve for x: 4(x2)3/2=1004(x - 2)^{3/2} = 100

    • (x2)3/2=25(x - 2)^{3/2} = 25
    • x2=252/3x - 2 = 25^{2/3}
    • x=252/3+2x = 25^{2/3} + 2
  • Solve for x: 12x6=3x12x - 6 = 3 - x

    • There is no radical in this equation.
    • 13x=913x = 9
    • x=9/13x = 9/13
  • Solve for x: 2(x+3)3/5=542(x+3)^{3/5} = 54

    • (x+3)3/5=27(x+3)^{3/5} = 27
    • x+3=275/3x+3 = 27^{5/3}
    • x+3=(33)5/3x+3 = (3^3)^{5/3}
    • x+3=35x+3 = 3^5
    • x+3=243x+3 = 243
    • x=240x = 240

Section 6.7: Inverse Relations and Functions

  • Inverse of the relation: (2,3),(1,1),(0,1),(2,2){( -2, 3), (-1, 1), (0, -1), (2, -2) }

    • To find the inverse, swap the x and y coordinates of each ordered pair.
    • Inverse: (3,2),(1,1),(1,0),(2,2){(3, -2), (1, -1), (-1, 0), (-2, 2) }
  • Inverse of the function: y=5(x3)y = 5(x - 3)

    • Swap x and y: x=5(y3)x = 5(y - 3)
    • Solve for y: x/5=y3x/5 = y - 3
    • y=(x/5)+3y = (x/5) + 3
  • Function with domain x5x \ge 5 that is the inverse of y=x+5y = \sqrt{x + 5}:

    • Swap x and y: x=y+5x = \sqrt{y + 5}
    • Solve for y: x2=y+5x^2 = y + 5
    • y=x25y = x^2 - 5
    • Since the original function has a range of y0y \ge 0, the inverse has a domain of x0x \ge 0. But there stated domain is x5x \ge 5. Need more info to solve.
    • I Think it's a mistake and the answer is y=x25y = x^2 - 5
  • Domain and range of the inverse of the function: y=x5y = \sqrt{x - 5}

    • The original function has a domain of x5x \ge 5 and a range of y0y \ge 0.
    • Therefore, the inverse function has a domain of x0x \ge 0 and a range of y5y \ge 5.

Section 6.8: Graphing Radical Functions

  • Graph of y=x+4y = \sqrt{x + 4}:

    • The graph is a square root function shifted 4 units to the left.
  • Graph of y=x32y = \sqrt{x - 3} - 2:

    • The graph is a square root function shifted 3 units to the right and 2 units down.
  • Graph of y=1x+3y = 1 - \sqrt{x + 3}:

    • The graph is a square root function shifted 3 units to the left, reflected over the x-axis, and shifted up 1 unit.
  • Description of y=9x3y = \sqrt{9x - 3} to make it easy to graph using transformations of its parent function:

    • y=9x3=9(x1/3)=3x1/3y = \sqrt{9x - 3} = \sqrt{9(x - 1/3)} = 3\sqrt{x - 1/3}. This is the graph of y=3xy = 3\sqrt{x}, shifted right 1/3 unit.

Chapter 7: Semester Review

Section 7.1: Exploring Exponential Models

  • Function representing exponential decay with a y-intercept of 2:

    • Exponential decay has a base between 0 and 1. A y-intercept of 2 means the function is of the form y=2(b)xy = 2(b)^x where 0 < b < 1.
    • y=2(12)xy= 2(\frac{1}{2})^x
  • Determine whether each function represents exponential growth or decay, and determine the y-intercept for each function.

    • a. y=3(7)xy = 3(7)^x: Exponential growth, y-intercept is 3.
    • b. y=4(2.5)xy = 4(2.5)^x: Exponential growth, y-intercept is 4.
    • c. y=5(0.75)xy = 5(0.75)^x: Exponential decay, y-intercept is 5.
    • d. y=0.5(0.2)xy = 0.5(0.2)^x: Exponential decay, y-intercept is 0.5.
  • Deposit of $3000 in a savings account with a 4% annual interest rate after 10 years:

    • A=P(1+r)tA = P(1 + r)^t where A is the amount after t years, P is the principal, r is the interest rate, and t is the time in years.
    • A = 3000(1 + 0.04)^{10} = 3000(1.04)^{10} \approx $4440.73
  • Population of Bainsville is 2000. The population is supposed to grow by 10% each year for the next 5 years. How many people will live in Bainsville in 5 years?

    • A=P(1+r)tA = P(1 + r)^t A=2000(1+0.10)5=2000(1.10)53221A = 2000(1 + 0.10)^{5} = 2000(1.10)^{5} \approx 3221
  • Manufacturer bought a new rolling press for $48,000. It has depreciated in value at an annual rate of 15%. What is its value 5 years after purchase? Round to the nearest hundred dollars.

    • A=P(1r)tA = P(1 - r)^t A=48000(10.15)5=48000(0.85)521,300A = 48000(1 - 0.15)^{5} = 48000(0.85)^{5} \approx 21,300

Section 7.2: Properties of Exponential Functions

  • Sarah received a paycheck for $1200. She deposited 1/4 of the money into a bank account. The account has an interest rate of 6% compounded continuously. This is the first and last deposit that Sarah makes into this account. How much money will be in the account in 15 years?

    • Principal Deposit: 1200 * (1/4) = $300
    • Formula for the continuous compounded interest is: A=PertA = Pe^{rt} , where P is the principal, r is the annual interest rate, and t is the time in years.
    • A = 300 * e^{0.06 * 15} = $300 * e^{0.9} \approx $736.64
  • Bram invested $10,000 in an account that earns simple 5% interest annually.

    • a. How much interest does the account earn in the first 10 years? Round to the nearest dollar.
      • Simple Interest Formula: I=PrtI = Prt , where P is the principal, r is the annual interest rate, and t is the time in years.
      • I= 10000 * 0.05 * 10 = $5000
    • b. How much more would the account earn in interest in the first 10 years if the interest compounded continuously? Round to the nearest dollar.
      • A=PertA= Pe^{rt}, where P is the principal, r is the annual interest rate, and t is the time in years.
      • A=10000e0.0510A = 10000 * e^{0.05 * 10}
      • A=10000e0.5A = 10000 * e^{0.5}
      • A \approx $16,487.21
      • Interest Earned with Compound Continuously: Interest = A - P = $16487.21 - $10000 = $6487.21
      • Additional Interest Earned: $6487.21 - $5000 = $1487.21

Section 7.3: Logarithmic Functions as Inverses

  • Write each equation in logarithmic form.

    • 100=102100 = 10^2 is equivalent to log10100=2log_{10}100 = 2
    • 93=7299^3 = 729 is equivalent to log9729=3log_{9}729 = 3
    • 644364^{\frac{4}{3}} is equivalent to log644=23log_{64}4 = \frac{2}{3}
    • 19=32\frac{1}{9} = 3^{-2} is equivalent to log3(19=2)log_{3}(\frac{1}{9} = -2)
  • Evaluate each logarithm.

    • log1000log 1000 is equivalent to log101000=3log_{10}1000 = 3
    • log4256=4log_{4}256 = 4 is because 44=2564^4 = 256
    • log279=23log_{27}9 = \frac{2}{3} is because (27)23=9(27)^{\frac{2}{3}} = 9
    • log126=2log_{\frac{1}{2}}6 = -2 is because (12)2=4(\frac{1}{2})^{-2} = 4

Section 7.4: Properties of Logarithms

  • Write each expression as a single logarithm.

    • log8+log3=log(83)=log24log 8 + log 3 = log(8*3) = log 24
    • 4(log<em>2x+log</em>23)=4log<em>2(x3)=log</em>2(3x)4=log2(81x4)4(log<em>{2}x + log</em>{2}3) = 4log<em>{2}(x*3) = log</em>{2}(3x)^4 = log_{2}(81x^4)
    • log4+log2log5=log((42)/5)=log(85)log 4 + log 2 - log5 = log((4*2)/5) = log(\frac{8}{5})
  • Expand each logarithm.

    • log<em>b3m2p2=log</em>b3+2log<em>bm+2log</em>bplog<em>{b}3m^2p^2 = log</em>{b}3 + 2log<em>{b}m + 2log</em>{b}p
    • log((xy)42)=4logx+4logylog2log(\frac{(xy)^4}{2}) = 4logx + 4logy - log2
    • log(4mn)3=3log4+3logm+3lognlog(4mn)^3 = 3log4 + 3logm + 3logn
  • Which expression is the correct expansion of log4(3x)2log_{4}(3x)^2 ?

    • 2(log<em>43+log</em>4x)2(log<em>{4}3 + log</em>{4}x)
  • Which statement correctly expresses 4log3x+7logy4log_{3}x + 7logy as a single logarithm?

    • log3(x4y7)log_{3}(x^4y^7)

Section 7.5: Exponential and Logarithmic Equations

  • If 9x=2439^x = 243, what is the value of x?

    • 9x=2439^x = 243 can be written as (32)x=35(3^2)^x = 3^5
    • 32x=353^{2x} = 3^5
    • 2x=52x = 5
    • x=52=2.5x = \frac{5}{2} = 2.5
  • If 23x+2=642^{3x+2} = 64, what is the value of x?

    • 23x+2=642^{3x+2} = 64
    • 23x+2=262^{3x+2} = 2^6
    • 3x+2=63x+2 = 6
    • 3x=43x = 4
    • x=43x = \frac{4}{3}
  • If log(3x+25)=2log(3x+25) = 2, what is the value of x?

    • Assuming the base is 10, log10(3x+25)=2log_{10}(3x+25) = 2
    • 3x+25=1023x+25 = 10^2
    • 3x+25=1003x+25 = 100
    • 3x=753x = 75
    • x=25x = 25
  • Which best approximates the solution of 162x=12416^{2x} = 124?

    • 162x=12416^{2x} = 124
    • log(162x)=log(124)log(16^{2x}) = log(124)
    • 2xlog(16)=log(124)2x*log(16) = log(124)
    • x=log1242log16x = \frac{log124}{2log16}
    • x1.150x \approx 1.150

Section 7.6: Natural Logarithms

  • In 2007, the population of Tallahassee, Florida was 168,979. Some researchers believe that the population of Tallahassee will increase at a rate of 1% each year for the 10 years following this. If the researchers are correct, how many years will it take for the population of Tallahassee to reach 180,000?

    • P(t)=P0ertP(t) = P_0e^{rt}
    • 180000=168979e0.01t180000 = 168979e^{0.01t}
    • 180000168979=e0.01t\frac{180000}{168979} = e^{0.01t}
    • ln(180000168979)=0.01tln(\frac{180000}{168979}) = 0.01t
    • t=ln(180000168979)0.01t = \frac{ln(\frac{180000}{168979})}{0.01}
    • t6.34t \approx 6.34

Algebra 2/Trig Chapter 13: Semester Review

Trigonometry Problems

Coterminal Angles:
  1. Coterminal Angles: Angles that share the same terminal side.

    • a. 20°20°
      • Positive coterminal angle: 20°+360°=380°20° + 360° = 380°
      • Negative coterminal angle: 20°360°=340°20° - 360° = -340°
    • b. 265°265°
      • Positive coterminal angle: 265°+360°=625°265° + 360° = 625°
      • Negative coterminal angle: 265°360°=95°265° - 360° = -95°
    • c. 305°305°
      • Positive coterminal angle: 305°+360°=665°305° + 360° = 665°
      • Negative coterminal angle: 305°360°=55°305° - 360° = -55°
Coordinates on the Unit Circle:
  1. Unit Circle: A circle with a radius of 1 centered at the origin.

    • a. 150°-150°
      • Coordinates: (32,12)(\frac{-\sqrt{3}}{2}, \frac{-1}{2})
    • b. 30°30°
      • Coordinates: (32,12)(\frac{\sqrt{3}}{2}, \frac{1}{2})
    • c. 120°120°
      • Coordinates: (12,32)(\frac{-1}{2}, \frac{\sqrt{3}}{2})
Radian to Degree Conversion:
  1. Radian-Degree Conversion: To convert radians to degrees, multiply by 180π\frac{180}{π}.

    • a. π6\frac{π}{6}
      • Degrees: π6180π=30°\frac{π}{6} * \frac{180}{π} = 30°
    • b. 3π5\frac{3π}{5}
      • Degrees: 3π5180π=108°\frac{3π}{5} * \frac{180}{π} = 108°
    • c. 5π12\frac{5π}{12}
      • Degrees: 5π12180π=75°\frac{5π}{12} * \frac{180}{π} = 75°
Exact Values of Cosine and Sine:
  1. Cosine and Sine Values: Determining exact values for given angles.

    • a. π6\frac{π}{6}
      • cos(π6)=32,sin(π6)=12cos(\frac{π}{6}) = \frac{\sqrt{3}}{2}, sin(\frac{π}{6}) = \frac{1}{2}
    • b. 3π4\frac{3π}{4}
      • cos(3π4)=22,sin(3π4)=22cos(\frac{3π}{4}) = \frac{-\sqrt{2}}{2}, sin(\frac{3π}{4}) = \frac{\sqrt{2}}{2}
    • c. 2π3\frac{2π}{3}
      • cos(2π3)=12,sin(2π3)=32cos(\frac{2π}{3}) = \frac{-1}{2}, sin(\frac{2π}{3}) = \frac{\sqrt{3}}{2}
    • d. π3-\frac{π}{3}
      • cos(π3)=12,sin(π3)=32cos(-\frac{π}{3}) = \frac{1}{2}, sin(-\frac{π}{3}) = -\frac{\sqrt{3}}{2}
    • e. 5π6\frac{5π}{6}
      • cos(5π6)=32,sin(5π6)=12cos(\frac{5π}{6}) = \frac{-\sqrt{3}}{2}, sin(\frac{5π}{6}) = \frac{1}{2}
    • f. 7π4\frac{7π}{4}
      • cos(7π4)=22,sin(7π4)=22cos(\frac{7π}{4}) = \frac{\sqrt{2}}{2}, sin(\frac{7π}{4}) = \frac{-\sqrt{2}}{2}
Amplitude and Period of Sine Functions:
  1. Amplitude and Period: Key characteristics of sine functions.

    • a. y=12sin(3θ)y = \frac{1}{2}sin(3θ)
      • Amplitude: 12\frac{1}{2}, Period: 2π3\frac{2π}{3}
    • b. y=sin(5θ)y = sin(5θ)
      • Amplitude: 11, Period: 2π5\frac{2π}{5}
    • c. y=4sin(π3θ)y = 4sin(\frac{π}{3}θ)
      • Amplitude: 44, Period: 2ππ3=6\frac{2π}{\frac{π}{3}} = 6
    • d. y=35sin(θ)y = -\frac{3}{5}sin(θ)
      • Amplitude: 35\frac{3}{5}, Period: 2π
    • e. y=2sin(13θ)y = -2sin(\frac{1}{3}θ)
      • Amplitude: 22, Period: 2π13=6π\frac{2π}{\frac{1}{3}} = 6π
    • f. y=πsin(2θ)y = πsin(2θ)
      • Amplitude: ππ, Period: 2π2=π\frac{2π}{2} = π
Graphs of Cosine Functions:
  1. Sketching Cosine Functions: Over the interval from 0 to 2π.

    • a. y=cos(2θ)y = cos(2θ)
      • The graph of y=cos(2θ)y = cos(2θ) completes two full cycles in the interval from 0 to 2π.
    • b. y=3cos(12θ)y = -3cos(\frac{1}{2}θ)
      • The graph of y=3cos(12θ)y = -3cos(\frac{1}{2}θ) is vertically stretched by a factor of 3, reflected over the x-axis, and completes half a cycle in the interval from 0 to 2π.
Exact Values of Tangent Functions:
  1. Tangent Values: Using the unit circle.

    • a. tan(π6)=33tan(\frac{π}{6}) = \frac{\sqrt{3}}{3}
    • b. tan(π3)=3tan(\frac{π}{3}) = \sqrt{3}
    • c. tan(3π4)=1tan(\frac{3π}{4}) = -1
    • d. tan(5π6)=33tan(\frac{5π}{6}) = -\frac{\sqrt{3}}{3}
    • e. tan(π4)=1tan(-\frac{π}{4}) = -1
Period and Asymptotes of Tangent Functions:
  1. Tangent Function Analysis: Period and asymptote determination.

    • a. y=2tan(θ2)y = 2tan(\frac{θ}{2})
      • Period: π12=2π\frac{π}{\frac{1}{2}} = 2π
      • Asymptotes: at θ=πθ = π and θ=3πθ = 3π
    • b. y=tan(2θ)y = -tan(2θ)
      • Period: π2\frac{π}{2}
      • Asymptotes: at θ=π4θ = \frac{π}{4} and θ=3π4θ = \frac{3π}{4}
    • c. y=4tan(2θ)y = 4tan(2θ)
      • Period: π2\frac{π}{2}
      • Asymptotes: at θ=π4θ = \frac{π}{4} and θ=3π4θ = \frac{3π}{4}
Transformations of Trigonometric Graphs:
  1. Transformations: Describing graph changes.

    • a. y=3cosx+2y = 3cos x + 2
      • Vertical stretch by a factor of 3, vertical shift up 2.
    • b. y=3sin2x7y = -3sin 2x - 7
      • Vertical stretch by a factor of 3, reflection over the x-axis, horizontal compression by a factor of 2, vertical shift down 7.
    • c. y=5cos(12x)+4y = 5cos(\frac{1}{2}x) + 4
      • Vertical stretch by a factor of 5, horizontal stretch by a factor of 2, vertical shift up 4.
Equations from Transformations:
  1. Writing Equations: Based on described transformations.

    • a. Sine function reflected over the x-axis, stretched vertically by a factor of 4, shifted up 5:
      y = -4sin(x) + 5
    • b. Cosine function stretched vertically by a factor of 2, horizontally stretched by a factor of 3, and shifted down 4:
      y = 2cos(\frac{1}{3}x) - 4
Writing Cosine Functions from Graphs:
  1. Cosine Equations: Matching graphs.

    • Analyze the amplitude, period, and any vertical shifts to write the appropriate cosine function for each graph.
Writing Sine Functions from Graphs:
  1. Sine Equations: Matching graphs.

    • Analyze the amplitude, period, and any vertical shifts to write the appropriate sine function for each graph.
Graphing Sine Functions:
  1. Graphing Procedures: Over the interval from 0 to 2π.

    • a. y=4sinx+5y = 4sin x + 5
      • Graph a sine function with amplitude 4, shifted vertically up by 5 units.
    • b. y=2sin2x+2y = -2 sin 2x + 2
      • Graph a sine function with amplitude 2, reflected over the x-axis, compressed horizontally by a factor of 2, and shifted vertically up by 2 units.
    • c. y=sinx4y = - sin x - 4
      • Graph a sine function reflected over the x-axis, and shifted vertically down by 4 units.
Writing Tangent Functions from Graphs:
  1. Tangent Equations: Analyze the period and asymptotes to write the tangent function for each graph.
Period Lengths of Trigonometric Functions:
  1. Period Lengths:

    • a. y=2sin2x+2y = -2 sin 2x + 2
      • Period: 2π2=π\frac{2π}{2} = π
    • b. y=4cos(13x)7y = 4cos(\frac{1}{3}x) - 7
      • Period: 2π13=6π\frac{2π}{\frac{1}{3}} = 6π
    • c. y=tanπxy = tan πx
      • Period: ππ=1\frac{π}{π} = 1