Learn Like a GEM Unit 6 Collecting Data GL Practice Study Guide

Learning Objectives and Outcomes

The "Learn Like a GEM" program for Unit-6 (dated 5-26) focuses on "Collecting Data" through GL Assessment practice. This training is designed to enable students to:

  • Practice for GL Assessments to improve reasoning and problem-solving abilities.

  • Enhance literacy and numeracy skills.

  • Develop exam confidence and accuracy.

  • Build overall exam readiness through the Knowledge Component of the curriculum.

Number Representation and Place Value

Comprehensive understanding of numerical notation and the value of digits within large numbers is verified through the following examples:

  • Figures to Words Conversion: The number "five thousand, one hundred and nine" is written in figures as 51095109.

  • Place Value Identification: In the number 72407240, the value of the digit 77 is identified as 7 thousands7\text{ thousands}.

  • Number Line Estimation: On a number line scaled between 12001200 and 14001400, a specific point (Point C) represents the value 12501250.

  • Roman Numerals and Multi-Step Arithmetic: Calculating the product of Roman numerals requires conversion to Arabic numerals:

    • XXVI=26XXVI = 26

    • XLI=41XLI = 41

    • Calculation: 26×41=106626 \times 41 = 1066

    • The resulting Roman numeral is MLXVIMLXVI.

Arithmetic, Sequences, and Algebraic Logic

  • Number Sequences: Logic patterns involve identifying constant differences. In the sequence 393,384,375,,357393, 384, 375, \dots, 357, the pattern is an arithmetic progression with a common difference of 9-9. The missing number is 3759=366375 - 9 = 366. (Note: Assessment option D provided was 369369, but the mathematical logic follows the 9-9 rule).

  • Properties of One and Zero: Operation identity is tested with equations like 123÷=123123 \div \square = 123, where the missing value is the identity element 11.

  • Basic Algebra: Solving for unknown variables, such as in the equation a9=10a - 9 = 10. Solving for aa leads to a=10+9=19a = 10 + 9 = 19.

  • Reverse Operations (Inverse Thinking): In a "think of a number" problem:

    1. Take a number xx.

    2. Multiply by 22 (2x2x).

    3. Subtract 44 (2x4=102x - 4 = 10).

    4. Solve: 2x=14x=72x = 14 \rightarrow x = 7.

  • Multiplying by Powers of Ten: Simple decimal shift operations, such as 3.6×10=363.6 \times 10 = 36.

  • Multiplication and Division: Determining quotients like 105÷=21105 \div \square = 21 entails finding the factor 55. Complex multiplication, such as finding the total travel of a ship going 528 nautical miles/day528 \text{ nautical miles/day} for 15 days15\text{ days}, results in 7920 nautical miles7920 \text{ nautical miles}.

  • Indices and Square Numbers:

    • The square of a number, denoted as 323^2, is calculated as 3×3=93 \times 3 = 9.

    • Recognition of square numbers is essential; for example, the numbers 99, 3636, and 8181 are alike because they are all square numbers (323^2, 626^2, and 929^2).

  • Logical Comparative Instructions: Given a starting number of 55, different instructions aim for a target of 1717:

    • Halve (2.52.5), add six (8.58.5), double (1717).

    • Multiply by four (2020), subtract three (1717).

    • Triple (1515), add two (1717).

    • Add three (88), double (1616) — This instruction fails to reach 17.

    • Multiply by ten (5050), subtract sixteen (3434), halve (1717).

  • Algebraic Manipulations with Large Components: Solving for missing values in equations like 27×99=270027 \times 99 = 2700 - \square. Since 27×99=27×(1001)=27002727 \times 99 = 27 \times (100 - 1) = 2700 - 27, the missing value is 2727.

Fractions, Decimals, and Percentages

  • Shaded Areas: Fractions of a whole are determined by counting shaded segments versus total segments (e.g., 3/83/8 of a shape being shaded).

  • Percentage Calculations: To find what percentage 50p50p is of £5\pounds 5, the conversion is 50500=110=10%\frac{50}{500} = \frac{1}{10} = 10\%.

  • Fraction of a Quantity: Taking 23\frac{2}{3} of a set of 36 sweets36 \text{ sweets} is calculated as (36÷3)×2=24 sweets(36 \div 3) \times 2 = 24 \text{ sweets}.

  • Ordering Fractions: Arranging fractions by finding common denominators. Sorting from largest to smallest: 78,34(68),58,12(48),14(28)\frac{7}{8}, \frac{3}{4} (\frac{6}{8}), \frac{5}{8}, \frac{1}{2} (\frac{4}{8}), \frac{1}{4} (\frac{2}{8}).

  • Percentage of Quantity: Finding 60%60\% of 5050 is calculated as 0.60×50=300.60 \times 50 = 30.

  • Composite Fraction Problems: Sharing a pizza with 66 equal pieces:

    • Ali eats 13\frac{1}{3} of the total: 13×6=2 pieces\frac{1}{3} \times 6 = 2 \text{ pieces}.

    • Remainder is 4 pieces4 \text{ pieces}.

    • Sister eats 12\frac{1}{2} of the remaining pieces: 12×4=2 pieces\frac{1}{2} \times 4 = 2 \text{ pieces}.

    • Pieces left: 622=2 pieces6 - 2 - 2 = 2 \text{ pieces}, which represents 26\frac{2}{6} or 13\frac{1}{3} of the pizza.

Measurement, Time, and Rates

  • Length Addition: An individual at 1.43 metres1.43 \text{ metres} who grows another 2 centimetres2 \text{ centimetres} (0.02 m0.02 \text{ m}) becomes 1.45 m1.45 \text{ m} tall.

  • Volume and Estimation:

    • Subtraction of liquid volumes: A juggling of units where a 1 litre (1000 ml)1 \text{ litre } (1000 \text{ ml}) jug fills a 700 ml700 \text{ ml} jar, leaving 300 ml300 \text{ ml} or 0.3 litres0.3 \text{ litres} in the jug.

    • General estimation for daily objects: A standard mug holds approximately 300 millilitres300 \text{ millilitres}.

  • Weight Conversion: Calculating the total mass of 5 boxes5 \text{ boxes} weighing 800 grams800 \text{ grams} each: 5×800 g=4000 g5 \times 800 \text{ g} = 4000 \text{ g}, which equals 4 kg4 \text{ kg}.

  • Chronological Calculations:

    • 12-hour vs 24-hour time: "Quarter past seven in the evening" corresponds to 19:1519:15.

    • Journey duration: A train departing at 10.2010.20 and arriving at 11.1511.15 has a travel time of 55 minutes55 \text{ minutes}.

    • Timetable analysis: A train leaving East Croydon at 23:2723:27 and arriving at Victoria at 23:4323:43 takes 16 minutes16 \text{ minutes}.

  • Cost Analysis and Savings:

    • Wendy saving £2.50\pounds 2.50 per week for a target of £20\pounds 20: £20÷£2.50=8 weeks\pounds 20 \div \pounds 2.50 = 8 \text{ weeks}.

    • Newspaper delivery rates: Paying £1.40\pounds 1.40 per 100 papers100 \text{ papers}. For 250 papers250 \text{ papers}, the calculation is (2.5×100)×£1.40=2.5×1.40=£3.50(2.5 \times 100) \times \pounds 1.40 = 2.5 \times 1.40 = \pounds 3.50.

    • Discount economics: A swimming pool charges £3.60\pounds 3.60 for entry. A card costs £5\pounds 5 and saves 16\frac{1}{6} of entry (£0.60\pounds 0.60 saved per visit). To recoup the £5\pounds 5 cost, Ken visits until savings exceed the card price relative to individual visits; effectively 5÷0.60=8.335 \div 0.60 = 8.33, though logic in problem context may vary based on net spending comparisons.

  • Temperature: Mateo\'s base temperature of 37.5C37.5^{\circ}C rising by 3C3^{\circ}C results in a fever of 40.5C40.5^{\circ}C.

  • Cooking Procedures (Time and Mass Ratios):

    • Rule: Cook for 30 mins30 \text{ mins} at high temp, then 30 mins30 \text{ mins} per 450 g450 \text{ g}.

    • If total time is 2 hours (120 mins)2 \text{ hours } (120 \text{ mins}):

    • Initial time: 30 mins30 \text{ mins}.

    • Remaining time: 12030=90 mins120 - 30 = 90 \text{ mins}.

    • Weight calculation: 9030×450 g=3×450 g=1350 g\frac{90}{30} \times 450 \text{ g} = 3 \times 450 \text{ g} = 1350 \text{ g} or 1.35 kg1.35 \text{ kg}.

Geometry and Spatial Reasoning

  • Coordinates: Reading locations on a grid (e.g., Hills at (3,4)(3, 4), identifying the lighthouse at (1,6)(1, 6)).

  • Shape Filling: Determining how many small triangles are required to fill a regular hexagon (6 triangles6 \text{ triangles}).

  • Area and Tiling: Calculating how many 1 cm21 \text{ cm}^2 squares fit into a rectangle of dimensions 6 cm×3 cm6 \text{ cm} \times 3 \text{ cm} (Total area 18 cm2=18 squares18 \text{ cm}^2 = 18 \text{ squares}).

  • Identification of Polygons:

    • Quadrilaterals are four-sided shapes; identifying non-quadrilaterals among a set.

    • Identifying 3D shapes: Distinguishing a cuboid from other polyhedra.

  • Angle Classification: Observations of geometric angles:

    • Acute angles: < 90^{\circ}

    • Right angles: =90= 90^{\circ}

    • Obtuse angles: Between 9090^{\circ} and 180180^{\circ}

    • Reflex angles: > 180^{\circ}

  • Ratios in Geometry: In a class of 27 children27 \text{ children} with a boy-to-girl ratio of 2:12:1. The class is divided into 3 parts3 \text{ parts} (27÷3=927 \div 3 = 9). Boys comprise 2 parts2 \text{ parts} (18 boys18 \text{ boys}); girls comprise 1 part1 \text{ part} (9 girls9 \text{ girls}).

  • Geometric Progressions: A frog jumping towards the edge of a pond (12 m12 \text{ m} across, so 6 m6 \text{ m} from center to edge). Each jump halves the distance to the edge:

    • Start: 6 m6 \text{ m} from edge.

    • Jump 1: 3 m3 \text{ m} remain.

    • Jump 2: 1.5 m1.5 \text{ m} remain.

    • Jump 3: 0.75 m0.75 \text{ m} (75 cm75 \text{ cm}) remain.

Data Interpretation

  • Pictograms and Tables: Identifying differences in quantity (e.g., comparing number of ships in Dock A vs. Dock C where one symbol equals 12 ships12 \text{ ships}).

  • Bar Charts:

    • Calculating total hours from categories (e.g., total "out of door" hours by summing football, fishing, and cycling).

    • Proportional analysis: Given a total class size of 2828, determining which transportation category represents exactly 4 children4 \text{ children} by analyzing the height of bars.

  • Line Graphs:

    • Tracking growth: Analyzing a baby's weight over 8 weeks8 \text{ weeks} to identify which specific week showed the greatest weight gain.

    • Historical data: Population graphs for Britain from 17001700. Identifying the year when the population became double that of the year 18001800.

  • Weather Data: Analyzing a 12-hour chart to identify the total duration of dry conditions (e.g., 10 hours10 \text{ hours}).

  • Set Theory (Venn Diagrams): Sorting numbers into overlapping categories such as "Multiples of 4" and "Multiples of 3". A number that fits the intersection (the shaded section) must be a multiple of both (1212, the Lowest Common Multiple).

Tables and Pricing Models

Heritage Membership Offer Pricing:

Type of Membership

Normal Price

Offer Price

Individual Member

£47.90\pounds 47.90

£35.63\pounds 35.63

Joint Membership (2 adults)

£79.50\pounds 79.50

£59.63\pounds 59.63

Family Group (2 adults + children <18)

£82.00\pounds 82.00

£61.50\pounds 61.50

Family One Adult (1 adult + children <18)

£62.00\pounds 62.00

£46.50\pounds 46.50

Young person (aged 13-25)

£21.50\pounds 21.50

£16.13\pounds 16.13

Scenario Application: Mrs. Ward joining with three children (aged 10, 12, and 15) utilizes the "Family One Adult" category, resulting in a total payment of £46.50\pounds 46.50.