MATH 101.00 - Exam 4 Review Problems - Modules 10-13 Exam 4 Review Problems: Modules 10-13 Solving Quadratic Equations Square Root Property
Solve equations of the form x 2 = k x^2 = k x 2 = k by taking the square root of both sides. Remember to consider both positive and negative roots. Examples:x 2 + 10 x + 25 = 24 x^2 + 10x + 25 = 24 x 2 + 10 x + 25 = 24 can be rewritten as ( x + 5 ) 2 = 24 (x + 5)^2 = 24 ( x + 5 ) 2 = 24 , then x + 5 = ± 24 x + 5 = \pm \sqrt{24} x + 5 = ± 24 .( x − 7 ) 2 = 81 (x - 7)^2 = 81 ( x − 7 ) 2 = 81 leads to x − 7 = ± 9 x - 7 = \pm 9 x − 7 = ± 9 .5 x 2 − 45 = 0 5x^2 - 45 = 0 5 x 2 − 45 = 0 simplifies to x 2 = 9 x^2 = 9 x 2 = 9 .( 5 x + 2 ) 2 = 3 (5x + 2)^2 = 3 ( 5 x + 2 ) 2 = 3 gives 5 x + 2 = ± 3 5x + 2 = \pm \sqrt{3} 5 x + 2 = ± 3 . Completing the Square
Transform a quadratic equation into the form ( x + a ) 2 = b (x + a)^2 = b ( x + a ) 2 = b . Add ( b 2 ) 2 \left( \frac{b}{2} \right)^2 ( 2 b ) 2 to both sides of the equation to complete the square. Examples:x 2 − 10 x + 16 = 0 x^2 - 10x + 16 = 0 x 2 − 10 x + 16 = 0 can be completed as ( x − 5 ) 2 = 9 (x - 5)^2 = 9 ( x − 5 ) 2 = 9 .x 2 + 4 3 x − 1 3 = 0 x^2 + \frac{4}{3}x - \frac{1}{3} = 0 x 2 + 3 4 x − 3 1 = 0 becomes ( x + 2 3 ) 2 = 5 9 \left(x + \frac{2}{3}\right)^2 = \frac{5}{9} ( x + 3 2 ) 2 = 9 5 .2 x 2 + 5 x − 3 = 0 2x^2 + 5x - 3 = 0 2 x 2 + 5 x − 3 = 0 requires dividing by 2 first: x 2 + 5 2 x − 3 2 = 0 x^2 + \frac{5}{2}x - \frac{3}{2} = 0 x 2 + 2 5 x − 2 3 = 0 , then complete the square.5 x 2 − 20 x + 10 = 0 5x^2 - 20x + 10 = 0 5 x 2 − 20 x + 10 = 0 similarly needs division by 5: x 2 − 4 x + 2 = 0 x^2 - 4x + 2 = 0 x 2 − 4 x + 2 = 0 . Quadratic Formula
Solve equations of the form a x 2 + b x + c = 0 ax^2 + bx + c = 0 a x 2 + b x + c = 0 using the formula: x = − b ± b 2 − 4 a c 2 a x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} x = 2 a − b ± b 2 − 4 a c . Examples:2 x 2 + 4 x + 1 = 0 2x^2 + 4x + 1 = 0 2 x 2 + 4 x + 1 = 0 : a = 2 , b = 4 , c = 1 a = 2, b = 4, c = 1 a = 2 , b = 4 , c = 1 .6 x 2 + 5 x − 4 = 0 6x^2 + 5x - 4 = 0 6 x 2 + 5 x − 4 = 0 : a = 6 , b = 5 , c = − 4 a = 6, b = 5, c = -4 a = 6 , b = 5 , c = − 4 .x 2 − 6 x + 25 = 0 x^2 - 6x + 25 = 0 x 2 − 6 x + 25 = 0 : a = 1 , b = − 6 , c = 25 a = 1, b = -6, c = 25 a = 1 , b = − 6 , c = 25 .5 x + x 2 = − 7 5x + x^2 = -7 5 x + x 2 = − 7 should be rewritten as x 2 + 5 x + 7 = 0 x^2 + 5x + 7 = 0 x 2 + 5 x + 7 = 0 : a = 1 , b = 5 , c = 7 a = 1, b = 5, c = 7 a = 1 , b = 5 , c = 7 . Constructing Quadratic Equations Given a solution set { r < e m > 1 , r < / e m > 2 } \lbrace r<em>1, r</em>2 \rbrace { r < e m > 1 , r < / e m > 2 } , the quadratic equation can be written as ( x − r < e m > 1 ) ( x − r < / e m > 2 ) = 0 (x - r<em>1)(x - r</em>2) = 0 ( x − r < e m > 1 ) ( x − r < / e m > 2 ) = 0 .Examples:{ 3 , − 1 } \lbrace 3, -1 \rbrace { 3 , − 1 } : ( x − 3 ) ( x + 1 ) = 0 (x - 3)(x + 1) = 0 ( x − 3 ) ( x + 1 ) = 0 .{ 1 2 , 4 } \left\lbrace \frac{1}{2}, 4 \right\rbrace { 2 1 , 4 } : ( x − 1 2 ) ( x − 4 ) = 0 \left(x - \frac{1}{2}\right)(x - 4) = 0 ( x − 2 1 ) ( x − 4 ) = 0 .{ 2 i , − 2 i } \lbrace 2i, -2i \rbrace { 2 i , − 2 i } : ( x − 2 i ) ( x + 2 i ) = 0 (x - 2i)(x + 2i) = 0 ( x − 2 i ) ( x + 2 i ) = 0 .{ 2 + 3 , 2 − 3 } \lbrace 2 + \sqrt{3}, 2 - \sqrt{3} \rbrace { 2 + 3 , 2 − 3 } : ( x − ( 2 + 3 ) ) ( x − ( 2 − 3 ) ) = 0 (x - (2 + \sqrt{3}))(x - (2 - \sqrt{3})) = 0 ( x − ( 2 + 3 )) ( x − ( 2 − 3 )) = 0 . Graphing Quadratic Functions Vertex Form : f ( x ) = a ( x − h ) 2 + k f(x) = a(x - h)^2 + k f ( x ) = a ( x − h ) 2 + k where ( h , k ) (h, k) ( h , k ) is the vertex.Standard Form : f ( x ) = a x 2 + b x + c f(x) = ax^2 + bx + c f ( x ) = a x 2 + b x + c .Vertex can be found at x = − b 2 a x = -\frac{b}{2a} x = − 2 a b , and then find the corresponding y y y value. Intercepts y y y -intercept: Set x = 0 x = 0 x = 0 .x x x -intercepts: Set f ( x ) = 0 f(x) = 0 f ( x ) = 0 and solve for x x x .Axis of Symmetry : Vertical line through the vertex, x = h x = h x = h (in vertex form).Examples:f ( x ) = 2 ( x − 4 ) 2 − 3 f(x) = 2(x - 4)^2 - 3 f ( x ) = 2 ( x − 4 ) 2 − 3 : Vertex is ( 4 , − 3 ) (4, -3) ( 4 , − 3 ) .f ( x ) = − ( x + 3 ) 2 + 1 f(x) = -(x + 3)^2 + 1 f ( x ) = − ( x + 3 ) 2 + 1 : Vertex is ( − 3 , 1 ) (-3, 1) ( − 3 , 1 ) .f ( x ) = 3 ( x + 1 ) 2 − 2 f(x) = 3(x + 1)^2 - 2 f ( x ) = 3 ( x + 1 ) 2 − 2 : Vertex is ( − 1 , − 2 ) (-1, -2) ( − 1 , − 2 ) .f ( x ) = − x 2 + 5 f(x) = -x^2 + 5 f ( x ) = − x 2 + 5 : Vertex is ( 0 , 5 ) (0, 5) ( 0 , 5 ) .f ( x ) = − x 2 − 4 x − 8 f(x) = -x^2 - 4x - 8 f ( x ) = − x 2 − 4 x − 8 : Find the vertex using x = − b 2 a x = -\frac{b}{2a} x = − 2 a b .f ( x ) = x 2 + 2 x − 4 f(x) = x^2 + 2x - 4 f ( x ) = x 2 + 2 x − 4 f ( x ) = x 2 + x − 3 4 f(x) = x^2 + x - \frac{3}{4} f ( x ) = x 2 + x − 4 3 f ( x ) = − 2 x 2 − x + 10 f(x) = -2x^2 - x + 10 f ( x ) = − 2 x 2 − x + 10 Optimization Problems Maximizing Product : If the sum of two numbers is constant, their product is maximized when the numbers are equal.Revenue Maximization : Given a revenue function R ( p ) R(p) R ( p ) , find the price p p p that maximizes revenue by finding the vertex of the quadratic function.Area Maximization : Set up an equation for the area and use the given constraints (e.g., perimeter) to express the area in terms of one variable. Then find the maximum value.Examples:Sum of two numbers is 24: To maximize the product, both numbers should be 12. R ( p ) = − 2.5 p 2 + 500 p R(p) = -2.5p^2 + 500p R ( p ) = − 2.5 p 2 + 500 p : Find the vertex to maximize revenue.9 feet of wood for a frame: Maximize the area of the frame. 60 meters of fencing for a garden against a house: Maximize the area of the garden. h ( t ) = − 16 t 2 + 32 t h(t) = -16t^2 + 32t h ( t ) = − 16 t 2 + 32 t : Find the maximum height of a ball thrown upward.h ( t ) = − 4 t 2 + 48 t + 3 h(t) = -4t^2 + 48t + 3 h ( t ) = − 4 t 2 + 48 t + 3 : Find the maximum height of a projectile. Vertical Shift : f ( x ) + c f(x) + c f ( x ) + c shifts the graph up by c c c units.Horizontal Shift : f ( x − c ) f(x - c) f ( x − c ) shifts the graph right by c c c units.Vertical Stretch/Compression : c ⋅ f ( x ) c \cdot f(x) c ⋅ f ( x ) stretches (if c > 1) or compresses (if 0 < c < 1) the graph vertically.Reflection : − f ( x ) -f(x) − f ( x ) reflects the graph over the x-axis.Examples:g ( x ) = − ∣ x + 2 ∣ + 3 g(x) = -|x + 2| + 3 g ( x ) = − ∣ x + 2∣ + 3 : Transformations of f(x) = |x||$.g(x) = (x - 2)^2 + 3: T r a n s f o r m a t i o n s o f : Transformations of : T r an s f or ma t i o n so f f(x) = x^2. < / l i > < l i > .</li>
<li> . < / l i >< l i > g(x) = 2\sqrt{x + 3} - 2: T r a n s f o r m a t i o n s o f : Transformations of : T r an s f or ma t i o n so f f(x) = \sqrt{x}. < / l i > < l i > .</li>
<li> . < / l i >< l i > g(x) = \frac{1}{2}x^3 + 4: T r a n s f o r m a t i o n s o f : Transformations of : T r an s f or ma t i o n so f f(x) = x^3. < / l i > < / u l > < / l i > < / u l > < h 4 i d = " p i e c e w i s e f u n c t i o n s " > P i e c e w i s e F u n c t i o n s < / h 4 > < u l > < l i > G r a p h e a c h p i e c e o f t h e f u n c t i o n o v e r i t s s p e c i f i e d d o m a i n . < / l i > < l i > P a y a t t e n t i o n t o e n d p o i n t s a n d w h e t h e r t h e y a r e i n c l u d e d ( c l o s e d c i r c l e ) o r n o t ( o p e n c i r c l e ) . < / l i > < l i > E x a m p l e s : < u l > < l i > .</li></ul></li>
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<h4 id="piecewisefunctions">Piecewise Functions</h4>
<ul>
<li>Graph each piece of the function over its specified domain.</li>
<li>Pay attention to endpoints and whether they are included (closed circle) or not (open circle).</li>
<li>Examples:<ul>
<li> . < / l i >< / u l >< / l i >< / u l >< h 4 i d = " p i ece w i se f u n c t i o n s " > P i ece w i se F u n c t i o n s < / h 4 >< u l >< l i > G r a p h e a c h p i eceo f t h e f u n c t i o n o v er i t ss p ec i f i e dd o main . < / l i >< l i > P a y a tt e n t i o n t oe n d p o in t s an d w h e t h er t h ey a re in c l u d e d ( c l ose d c i rc l e ) or n o t ( o p e n c i rc l e ) . < / l i >< l i > E x am pl es :< u l >< l i > f(x) = \begin{cases} 2 & \text{if } x \leq -2 \ 2x + 3 & \text{if } x > -2 \end{cases}< / l i > < l i > </li>
<li> < / l i >< l i > f(x) = \begin{cases} 2x & \text{if } x < 1 \ -3 & \text{if } x \geq 1 \end{cases}< / l i > < l i > </li>
<li> < / l i >< l i > f(x) = \begin{cases} x^2 & \text{if } x < 3 \ 3x + 2 & \text{if } x \geq 3 \end{cases}< / l i > < l i > </li>
<li> < / l i >< l i > f(x) = \begin{cases} x^2 & \text{if } x \leq -3 \ 5 & \text{if } -3 < x < 4 \ x - 1 & \text{if } x \geq 4 \end{cases}< / l i > < / u l > < / l i > < / u l > < h 4 i d = " e x p o n e n t i a l f u n c t i o n s " > E x p o n e n t i a l F u n c t i o n s < / h 4 > < u l > < l i > F u n c t i o n s o f t h e f o r m </li></ul></li>
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<h4 id="exponentialfunctions">Exponential Functions</h4>
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<li>Functions of the form < / l i >< / u l >< / l i >< / u l >< h 4 i d = " e x p o n e n t ia l f u n c t i o n s " > E x p o n e n t ia lF u n c t i o n s < / h 4 >< u l >< l i > F u n c t i o n so f t h e f or m f(x) = a^xw h e r e where w h ere a > 0a n d and an d a \neq 1. < / l i > < l i > < s t r o n g > D o m a i n < / s t r o n g > : A l l r e a l n u m b e r s . < / l i > < l i > < s t r o n g > R a n g e < / s t r o n g > : .</li>
<li><strong>Domain</strong>: All real numbers.</li>
<li><strong>Range</strong>: . < / l i >< l i >< s t ro n g > Do main < / s t ro n g >: A ll re a l n u mb ers . < / l i >< l i >< s t ro n g > R an g e < / s t ro n g >: (0, \infty)i f if i f a > 0. < / l i > < l i > G r a p h u s i n g d a t a p o i n t s ( e . g . , .</li>
<li>Graph using data points (e.g., . < / l i >< l i > G r a p h u s in g d a t a p o in t s ( e . g . , x = -2, -1, 0, 1, 2) . < / l i > < l i > E x a m p l e s : < u l > < l i > ).</li>
<li>Examples:<ul>
<li> ) . < / l i >< l i > E x am pl es :< u l >< l i > f(x) = 2^x. < / l i > < l i > .</li>
<li> . < / l i >< l i > f(x) = 3^{-x}. < / l i > < l i > .</li>
<li> . < / l i >< l i > f(x) = 4^x. < / l i > < l i > .</li>
<li> . < / l i >< l i > f(x) = \left(\frac{1}{2}\right)^x. < / l i > < / u l > < / l i > < / u l > < h 4 i d = " c o m p o u n d i n t e r e s t " > C o m p o u n d I n t e r e s t < / h 4 > < u l > < l i > < s t r o n g > C o m p o u n d I n t e r e s t F o r m u l a < / s t r o n g > : .</li></ul></li>
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<h4 id="compoundinterest">Compound Interest</h4>
<ul>
<li><strong>Compound Interest Formula</strong>: . < / l i >< / u l >< / l i >< / u l >< h 4 i d = " co m p o u n d in t eres t " > C o m p o u n d I n t eres t < / h 4 >< u l >< l i >< s t ro n g > C o m p o u n d I n t eres tF or m u l a < / s t ro n g >: A = P\left(1 + \frac{r}{n}\right)^{nt}, w h e r e : < u l > < l i > , where:<ul>
<li> , w h ere :< u l >< l i > A= a c c u m u l a t e d v a l u e < / l i > < l i > = accumulated value</li>
<li> = a cc u m u l a t e d v a l u e < / l i >< l i > P= p r i n c i p a l < / l i > < l i > = principal</li>
<li> = p r in c i p a l < / l i >< l i > r= i n t e r e s t r a t e < / l i > < l i > = interest rate</li>
<li> = in t eres t r a t e < / l i >< l i > n= n u m b e r o f t i m e s c o m p o u n d e d p e r y e a r < / l i > < l i > = number of times compounded per year</li>
<li> = n u mb ero f t im esco m p o u n d e d p erye a r < / l i >< l i > t= n u m b e r o f y e a r s < / l i > < / u l > < / l i > < l i > < s t r o n g > C o n t i n u o u s C o m p o u n d I n t e r e s t F o r m u l a < / s t r o n g > : = number of years</li></ul></li>
<li><strong>Continuous Compound Interest Formula</strong>: = n u mb ero f ye a rs < / l i >< / u l >< / l i >< l i >< s t ro n g > C o n t in u o u s C o m p o u n d I n t eres tF or m u l a < / s t ro n g >: A = Pe^{rt} Examples:Investment of $3,000 at 4.5% compounded annually for 12 years. Investment of $18,000 at 2% compounded quarterly for 7 years. Investment of $7,200 at 6.6% compounded continuously for 3 years. Investment of $2,800 at 3.9% compounded continuously for 2 years. Function Composition (f \circ g)(x) = f(g(x))< / l i > < l i > S u b s t i t u t e </li>
<li>Substitute < / l i >< l i > S u b s t i t u t e g(x)i n t o into in t o f(x). < / l i > < l i > E x a m p l e s : < u l > < l i > .</li>
<li>Examples:<ul>
<li> . < / l i >< l i > E x am pl es :< u l >< l i > f(x) = x^2 + 2xa n d and an d g(x) = 2x + 1: F i n d : Find : F in d (f \circ g)(x). < / l i > < l i > .</li>
<li> . < / l i >< l i > f(x) = \sqrt{x}a n d and an d g(x) = x - 8: F i n d : Find : F in d (f \circ g)(x). < / l i > < l i > .</li>
<li> . < / l i >< l i > f(x) = -xa n d and an d g(x) = x^3 + 5x^2: F i n d : Find : F in d (g \circ f)(x). < / l i > < l i > .</li>
<li> . < / l i >< l i > f(x) = x^2a n d and an d g(x) = 3x^2 - 4: F i n d : Find : F in d (g \circ f)(x). < / l i > < / u l > < / l i > < / u l > < h 4 i d = " i n v e r s e f u n c t i o n s " > I n v e r s e F u n c t i o n s < / h 4 > < u l > < l i > T o v e r i f y t h a t .</li></ul></li>
</ul>
<h4 id="inversefunctions">Inverse Functions</h4>
<ul>
<li>To verify that . < / l i >< / u l >< / l i >< / u l >< h 4 i d = " in v erse f u n c t i o n s " > I n v erse F u n c t i o n s < / h 4 >< u l >< l i > T o v er i f y t ha t f(x)a n d and an d g(x)a r e i n v e r s e s , s h o w t h a t are inverses, show that a re in v erses , s h o wt ha t f(g(x)) = xa n d and an d g(f(x)) = x. < / l i > < l i > E x a m p l e s : < u l > < l i > .</li>
<li>Examples:<ul>
<li> . < / l i >< l i > E x am pl es :< u l >< l i > f(x) = 2xa n d and an d g(x) = \frac{x}{2}. < / l i > < l i > .</li>
<li> . < / l i >< l i > f(x) = (x + 4)^3a n d and an d g(x) = \sqrt[3]{x} - 4. < / l i > < l i > .</li>
<li> . < / l i >< l i > f(x) = x^2 + 7a n d and an d g(x) = \sqrt{x - 7}. < / l i > < l i > .</li>
<li> . < / l i >< l i > f(x) = \frac{3x + 11}{x + 5}a n d and an d g(x) = \frac{5x - 11}{3 - x}. < / l i > < / u l > < / l i > < / u l > < h 4 i d = " l o g a r i t h m i c a n d e x p o n e n t i a l e q u a t i o n s " > L o g a r i t h m i c a n d E x p o n e n t i a l E q u a t i o n s < / h 4 > < u l > < l i > < s t r o n g > E x p o n e n t i a l F o r m < / s t r o n g > : .</li></ul></li>
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<h4 id="logarithmicandexponentialequations">Logarithmic and Exponential Equations</h4>
<ul>
<li><strong>Exponential Form</strong>: . < / l i >< / u l >< / l i >< / u l >< h 4 i d = " l o g a r i t hmi c an d e x p o n e n t ia l e q u a t i o n s " > L o g a r i t hmi c an d E x p o n e n t ia lEq u a t i o n s < / h 4 >< u l >< l i >< s t ro n g > E x p o n e n t ia lF or m < / s t ro n g >: a = \log_b ci s e q u i v a l e n t t o is equivalent to i se q u i v a l e n tt o b^a = c. < / l i > < l i > E x a m p l e s : < u l > < l i > .</li>
<li>Examples:<ul>
<li> . < / l i >< l i > E x am pl es :< u l >< l i > 4 = \log_x 16: S o l v e f o r : Solve for : S o l v e f or x. < / l i > < l i > .</li>
<li> . < / l i >< l i > 2 = \log_8 x: S o l v e f o r : Solve for : S o l v e f or x. < / l i > < l i > .</li>
<li> . < / l i >< l i > 3 = \log_5 x: S o l v e f o r : Solve for : S o l v e f or x. < / l i > < l i > .</li>
<li> . < / l i >< l i > -2 = \log_3 x: S o l v e f o r : Solve for : S o l v e f or x. < / l i > < / u l > < / l i > < l i > < s t r o n g > L o g a r i t h m i c F o r m < / s t r o n g > : .</li></ul></li>
<li><strong>Logarithmic Form</strong>: . < / l i >< / u l >< / l i >< l i >< s t ro n g > L o g a r i t hmi c F or m < / s t ro n g >: b^c = ai s e q u i v a l e n t t o is equivalent to i se q u i v a l e n tt o \log_b a = c. < / l i > < l i > E x a m p l e s : < u l > < l i > .</li>
<li>Examples:<ul>
<li> . < / l i >< l i > E x am pl es :< u l >< l i > 3^3 = 27. < / l i > < l i > .</li>
<li> . < / l i >< l i > 2^5 = 32. < / l i > < l i > .</li>
<li> . < / l i >< l i > 10^2 = 100. < / l i > < l i > .</li>
<li> . < / l i >< l i > 4^{-3} = \frac{1}{64}. < / l i > < / u l > < / l i > < / u l > < h 4 i d = " e v a l u a t i n g l o g a r i t h m s " > E v a l u a t i n g L o g a r i t h m s < / h 4 > < u l > < l i > .</li></ul></li>
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<h4 id="evaluatinglogarithms">Evaluating Logarithms</h4>
<ul>
<li> . < / l i >< / u l >< / l i >< / u l >< h 4 i d = " e v a l u a t in g l o g a r i t hm s " > E v a l u a t in gL o g a r i t hm s < / h 4 >< u l >< l i > log_b a = xm e a n s means m e an s b^x = a. < / l i > < l i > E x a m p l e s : < u l > < l i > .</li>
<li>Examples:<ul>
<li> . < / l i >< l i > E x am pl es :< u l >< l i > \log_3 81. < / l i > < l i > .</li>
<li> . < / l i >< l i > \log_7 7^8. < / l i > < l i > .</li>
<li> . < / l i >< l i > \log_5 \frac{1}{\sqrt{5}}. < / l i > < l i > .</li>
<li> . < / l i >< l i > \ln(e^4). < / l i > < / u l > < / l i > < / u l > < h 4 i d = " g r a p h i n g l o g a r i t h m i c f u n c t i o n s " > G r a p h i n g L o g a r i t h m i c F u n c t i o n s < / h 4 > < u l > < l i > L o g a r i t h m i c f u n c t i o n s a r e i n v e r s e s o f e x p o n e n t i a l f u n c t i o n s . < / l i > < l i > < s t r o n g > D o m a i n < / s t r o n g > : .</li></ul></li>
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<h4 id="graphinglogarithmicfunctions">Graphing Logarithmic Functions</h4>
<ul>
<li>Logarithmic functions are inverses of exponential functions.</li>
<li><strong>Domain</strong>: . < / l i >< / u l >< / l i >< / u l >< h 4 i d = " g r a p hin g l o g a r i t hmi c f u n c t i o n s " > G r a p hin gL o g a r i t hmi c F u n c t i o n s < / h 4 >< u l >< l i > L o g a r i t hmi c f u n c t i o n s a re in v erseso f e x p o n e n t ia l f u n c t i o n s . < / l i >< l i >< s t ro n g > Do main < / s t ro n g >: (0, \infty)f o r for f or f(x) = \log_b x. < / l i > < l i > < s t r o n g > R a n g e < / s t r o n g > : A l l r e a l n u m b e r s . < / l i > < l i > V e r t i c a l a s y m p t o t e s a t .</li>
<li><strong>Range</strong>: All real numbers.</li>
<li>Vertical asymptotes at . < / l i >< l i >< s t ro n g > R an g e < / s t ro n g >: A ll re a l n u mb ers . < / l i >< l i > V er t i c a l a sy m pt o t es a t x = 0f o r for f or f(x) = \log_b x. < / l i > < l i > E x a m p l e s : < u l > < l i > .</li>
<li>Examples:<ul>
<li> . < / l i >< l i > E x am pl es :< u l >< l i > f(x) = \log_3 x. < / l i > < l i > .</li>
<li> . < / l i >< l i > f(x) = \log_4 x. < / l i > < l i > .</li>
<li> . < / l i >< l i > f(x) = \log_2 (x - 2). < / l i > < l i > .</li>
<li> . < / l i >< l i > f(x) = \log_3 (x + 3). < / l i > < / u l > < / l i > < / u l > < h 4 i d = " d i s t a n c e a n d m i d p o i n t f o r m u l a s " > D i s t a n c e a n d M i d p o i n t F o r m u l a s < / h 4 > < u l > < l i > < s t r o n g > D i s t a n c e F o r m u l a < / s t r o n g > : .</li></ul></li>
</ul>
<h4 id="distanceandmidpointformulas">Distance and Midpoint Formulas</h4>
<ul>
<li><strong>Distance Formula</strong>: . < / l i >< / u l >< / l i >< / u l >< h 4 i d = " d i s t an ce an d mi d p o in t f or m u l a s " > D i s t an ce an d M i d p o in tF or m u l a s < / h 4 >< u l >< l i >< s t ro n g > D i s t an ce F or m u l a < / s t ro n g >: d = \sqrt{(x2 - x 1)^2 + (y2 - y 1)^2}. < / l i > < l i > < s t r o n g > M i d p o i n t F o r m u l a < / s t r o n g > : .</li>
<li><strong>Midpoint Formula</strong>: . < / l i >< l i >< s t ro n g > M i d p o in tF or m u l a < / s t ro n g >: M = \left(\frac{x1 + x 2}{2}, \frac{y1 + y 2}{2}\right). < / l i > < l i > E x a m p l e s : < u l > < l i > D i s t a n c e b e t w e e n ( 3 , 4 ) a n d ( 2 , 2 ) . < / l i > < l i > D i s t a n c e b e t w e e n ( − 2 , 3 ) a n d ( 3 , − 9 ) . < / l i > < l i > D i s t a n c e b e t w e e n ( − 5 , 0 ) a n d ( − 2 , 2 ) . < / l i > < l i > D i s t a n c e b e t w e e n ( 2 , − 3 ) a n d ( 5 , 1 ) . < / l i > < l i > M i d p o i n t b e t w e e n ( − 8 , − 9 ) a n d ( 0 , − 3 ) . < / l i > < l i > M i d p o i n t b e t w e e n ( 5 , 3 ) a n d ( 2 , 9 ) . < / l i > < l i > M i d p o i n t b e t w e e n ( 4 , 8 ) a n d ( 0 , 12 ) . < / l i > < l i > M i d p o i n t b e t w e e n ( 2 , 5 ) a n d ( 8 , 3 ) . < / l i > < / u l > < / l i > < / u l > < h 4 i d = " c i r c l e e q u a t i o n s " > C i r c l e E q u a t i o n s < / h 4 > < u l > < l i > < s t r o n g > S t a n d a r d F o r m < / s t r o n g > : .</li>
<li>Examples:<ul>
<li>Distance between (3, 4) and (2, 2).</li>
<li>Distance between (-2, 3) and (3, -9).</li>
<li>Distance between (-5, 0) and (-2, 2).</li>
<li>Distance between (2, -3) and (5, 1).</li>
<li>Midpoint between (-8, -9) and (0, -3).</li>
<li>Midpoint between (5, 3) and (2, 9).</li>
<li>Midpoint between (4, 8) and (0, 12).</li>
<li>Midpoint between (2, 5) and (8, 3).</li></ul></li>
</ul>
<h4 id="circleequations">Circle Equations</h4>
<ul>
<li><strong>Standard Form</strong>: . < / l i >< l i > E x am pl es :< u l >< l i > D i s t an ce b e tw ee n ( 3 , 4 ) an d ( 2 , 2 ) . < / l i >< l i > D i s t an ce b e tw ee n ( − 2 , 3 ) an d ( 3 , − 9 ) . < / l i >< l i > D i s t an ce b e tw ee n ( − 5 , 0 ) an d ( − 2 , 2 ) . < / l i >< l i > D i s t an ce b e tw ee n ( 2 , − 3 ) an d ( 5 , 1 ) . < / l i >< l i > M i d p o in t b e tw ee n ( − 8 , − 9 ) an d ( 0 , − 3 ) . < / l i >< l i > M i d p o in t b e tw ee n ( 5 , 3 ) an d ( 2 , 9 ) . < / l i >< l i > M i d p o in t b e tw ee n ( 4 , 8 ) an d ( 0 , 12 ) . < / l i >< l i > M i d p o in t b e tw ee n ( 2 , 5 ) an d ( 8 , 3 ) . < / l i >< / u l >< / l i >< / u l >< h 4 i d = " c i rc l ee q u a t i o n s " > C i rc l e Eq u a t i o n s < / h 4 >< u l >< l i >< s t ro n g > St an d a r d F or m < / s t ro n g >: (x - h)^2 + (y - k)^2 = r^2, w h e r e , where , w h ere (h, k)i s t h e c e n t e r a n d is the center and i s t h ece n t er an d ri s t h e r a d i u s . < / l i > < l i > E x a m p l e s : < u l > < l i > C e n t e r ( 2 , 3 ) a n d r a d i u s 4 : W r i t e t h e s t a n d a r d f o r m e q u a t i o n . < / l i > < l i > G i v e n is the radius.</li>
<li>Examples:<ul>
<li>Center (2, 3) and radius 4: Write the standard form equation.</li>
<li>Given i s t h er a d i u s . < / l i >< l i > E x am pl es :< u l >< l i > C e n t er ( 2 , 3 ) an d r a d i u s 4 : W r i t e t h es t an d a r df or m e q u a t i o n . < / l i >< l i > G i v e n (x - 4)^2 + (y + 3)^2 = 25$$: Find the center and radius.