Neutral solution: pH at 7.0, with [H3O+] and [OH-] equal to 1.0 x 10^{-7} M.
Relationship with pOH:
pOH = 14 - pH.
Calculating [H3O+], pH, [OH-] and pOH
Use relations involving logarithmic functions to calculate these values from one another:
pHo = -log[OH^-]
Relationship: Kw = [H3O^+][OH^-], where K_w = 1.0 × 10^{-14} at 25 °C.
Example Calculation:
pH of a solution of 0.15 M HCl:
Complete dissociation gives: [H_3O^+] = 0.15.
pH = -\log [0.15] = 0.823.
Acids and their Strengths
Brønsted-Lowry Definitions:
Acid: Proton donor (H+ donor).
Base: Proton acceptor (H+ acceptor).
Conjugate Pairs:
Acid-Base reactions produce conjugate acids/bases. An acid becomes its conjugate base after donation.
Calculating pH for Weak Acids/Bases
Use an ICE table to analyze weak acid or base equilibria and calculate pH from H3O+ concentrations or use given Ka/Kb for other solutions.
QC = [H3O+][A-] / [HA] to determine Ka for the case of weak acids.
Polyprotic Acids
Concept: Acids with more than one protons to donate, with each step in dissociation being weaker.
H3PO4 \rightleftharpoons H2PO4^- + H_3O^+
Dissociation constants K{a1} > K{a2} > K_{a3} for these reactions.
Salt Solutions and Their pH
Effect of Salts on pH: Salts may yield acidic, neutral, or basic solutions depending on components.
Acidic solutions: contain conjugate acids.
Basic solutions: contain conjugate bases from weak acids.
Neutral solutions: both strong acid and base components present.
Conclusion
Understanding equilibrium principles, acid-base definitions, pH calculations, and linked concepts are fundamental for mastery in chemical equilibria and acid-base chemistry.
Master formulas are to apply them in problem-solving contexts and practice calculating various equilibrium states in chemical systems.