Comprehensive Study Notes: Mathematical Functions, Geometry, and Trigonometry

Factoring Techniques

  • Greatest Common Factor (GCF) and Difference of Two Squares (DOTS):

    • Example 1: 100m216100m^2 - 16

      • Step 1 (GCF): Factor out 44 to get 4(25n24)4(25n^2 - 4).

      • Step 2 (DOTS): 25n225n^2 and 44 are perfect squares. Factor as 4(5n+2)(5n2)4(5n + 2)(5n - 2).

  • Trinomial Factoring (a=1a = 1):

    • Example 2: 4n2+32n+644n^2 + 32n + 64

      • Step 1 (GCF): Factor out 44 to get 4(n2+8n+16)4(n^2 + 8n + 16).

      • Step 2 (Trinomial): Look for numbers that multiply to 1616 and add to 88. Factors as 4(n+4)(n+4)4(n + 4)(n + 4) or 4(n+4)24(n + 4)^2.

  • Factoring by Grouping:

    • Example 3: 18k4+48k2+3218k^4 + 48k^2 + 32

      • Step 1 (GCF): Factor out 22 to get 2(9k4+24k2+16)2(9k^4 + 24k^2 + 16).

      • Step 2 (Grouping): Split the middle term: 2((9k4+12k2)+(12k2+16))2((9k^4 + 12k^2) + (12k^2 + 16)).

      • Step 3: Factor each group: 2(3k2(3k2+4)+4(3k2+4))2(3k^2(3k^2 + 4) + 4(3k^2 + 4)).

      • Step 4: Final form: 2(3k2+4)(3k2+4)=2(3k2+4)22(3k^2 + 4)(3k^2 + 4) = 2(3k^2 + 4)^2.

    • Example 6: 5p3+10p27p145p^3 + 10p^2 - 7p - 14

      • Group into pairs: (5p3+10p2)(7p+14)(5p^3 + 10p^2) - (7p + 14).

      • Factor: 5p2(p+2)7(p+2)5p^2(p + 2) - 7(p + 2).

      • Result: (5p27)(p+2)(5p^2 - 7)(p + 2).

  • Sum and Difference of Cubes:

    • Formulas used: (a3+b3)=(a+b)(a2ab+b2)(a^3 + b^3) = (a + b)(a^2 - ab + b^2) and (a3b3)=(ab)(a2+ab+b2)(a^3 - b^3) = (a - b)(a^2 + ab + b^2).

    • Example 4 (Sum of Cubes): 27x3+12527x^3 + 125

      • a=3xa = 3x, b=5b = 5.

      • Steps: Square the front (9x29x^2), multiply them (15x15x), square the back (2525). Change the sign of the middle term.

      • Result: (3x+5)(9x215x+25)(3x + 5)(9x^2 - 15x + 25).

    • Example 5 (Difference of Cubes): 8x327y38x^3 - 27y^3

      • a=2xa = 2x, b=3yb = 3y.

      • Result: (2x3y)(4x2+6xy+9y2)(2x - 3y)(4x^2 + 6xy + 9y^2).

  • Factoring with Negative and Fractional Exponents:

    • Example 7: 6x3/2+x1/22x1/26x^{3/2} + x^{1/2} - 2x^{-1/2}

      • Step 1: Factor out the variable with the smallest exponent: x1/2x^{-1/2}.

      • Step 2: x1/2(6x2+x2)x^{-1/2}(6x^2 + x - 2).

      • Step 3: Factor the trinomial by decomposition: 6x2+4x3x26x^2 + 4x - 3x - 2.

      • Step 4: 2x(3x+2)1(3x+2)2x(3x + 2) - 1(3x + 2).

      • Final result: x1/2(2x1)(3x+2)x^{-1/2}(2x - 1)(3x + 2).

Quadratic Inequalities

  • Example 8: Solve 5x^2 - 2x - 3 > 0.

    • Step 1: Find critical values by setting the expression to zero: 5x25x+3x3=05x^2 - 5x + 3x - 3 = 0.

    • Step 2: Factor as 5x(x1)+3(x1)=05x(x - 1) + 3(x - 1) = 0, leading to (5x+3)(x1)=0(5x + 3)(x - 1) = 0.

    • Critical values: x=35x = -\frac{3}{5} and x=1x = 1.

    • Step 3: Test intervals. The inequality is satisfied when x < -\frac{3}{5} or x > 1.

    • Interval Notation: (inf,35) U (1,inf)(-\text{inf}, -\frac{3}{5}) \text{ U } (1, \text{inf}).

Operations with Radicals and Complex Numbers

  • Simplifying Radicals:

    • Example 9a: 28x3y5\sqrt{28x^3y^5}

      • 4x2y4×7xy=2xy27xy\sqrt{4x^2y^4} \times \sqrt{7xy} = 2xy^2\sqrt{7xy}.

    • Example 9b: 135a8b73\sqrt[3]{135a^8b^7}

      • 27a6b63×5a2b3=3a2b25a2b3\sqrt[3]{27a^6b^6} \times \sqrt[3]{5a^2b} = 3a^2b^2 \sqrt[3]{5a^2b}.

    • Example 9c: 500x5y64\sqrt[4]{500x^5y^6}

      • 6254\sqrt[4]{625} is not a factor; using 125125 for cube roots but here it is a 4th root problem. Correction: 625x4y44\sqrt[4]{625x^4y^4} is $5xy$, but for 500500, simplification depends on perfect 4th powers (16,81,256,62516, 81, 256, 625). The transcript shows: 20xyx2420xy \sqrt[4]{x^2}.

  • Complex Numbers in a+bia + bi form:

    • Simplifying expressions:

      • 64+1604100-\sqrt{64} + \sqrt{-160} - \sqrt{-4} - \sqrt{-100}

      • 8+4i102i10i-8 + 4i\sqrt{10} - 2i - 10i

      • Result: 812i+4i10=812i+410i-8 - 12i + 4i\sqrt{10} = -8 - 12i + 4\sqrt{10}i

    • Multiplying radicals with imaginaries:

      • (420)(6i6)(4\sqrt{-20})(-6i - 6)

      • (4(2i5))(6i6)=(8i5)(6i6)(4(2i\sqrt{5}))(-6i - 6) = (8i\sqrt{5})(-6i - 6)

      • 48i2548i5-48i^2\sqrt{5} - 48i\sqrt{5}

      • Since i2=1i^2 = -1, result is 485485i48\sqrt{5} - 48\sqrt{5}i.

Sum and Product of Roots

  • Finding the Quadratic Equation:

    • Formula: x2(sum)x+(product)=0x^2 - (\text{sum})x + (\text{product}) = 0.

    • Relationships: Sum=ba\text{Sum} = -\frac{b}{a} and Product=ca\text{Product} = \frac{c}{a}.

    • Example 10: Sum =3= -3, Product =9= -9.

      • Equation: x2+3x9=0x^2 + 3x - 9 = 0.

      • Scaling the equation: 2x2+6x18=02x^2 + 6x - 18 = 0 also meets these requirements (Option 3).

Geometry: Lines and Segments

  • Angle Bisectors:

    • A ray that bisects an angle cuts it into two equal pieces.

    • Example 12: Ray EFEF bisects DEG\angle DEG. If mFEG=6x7m\angle FEG = 6x - 7 and mFED=2x+41m\angle FED = 2x + 41, find mFEGm\angle FEG.

      • Set equal: 2x+41=6x748=4xx=122x + 41 = 6x - 7 \rightarrow 48 = 4x \rightarrow x = 12.

      • mFEG=6(12)7=65m\angle FEG = 6(12) - 7 = 65^\circ.

  • Midpoint and Distance Formulas:

    • Midpoint: (x1+x22,y1+y22)(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}).

      • Example 13: Endpoints (2,5)(2, -5) and (8,3)(8, 3). Midpoint is (2+82,5+32)=(5,1)(\frac{2+8}{2}, \frac{-5+3}{2}) = (5, -1).

    • Distance: D=(x2x1)2+(y2y1)2D = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}.

      • Example 14: R(2,3)R(-2, 3) and S(4,5)S(4, 5).

      • D=(4(2))2+(53)2=62+22=36+4=40=210D = \sqrt{(4 - (-2))^2 + (5 - 3)^2} = \sqrt{6^2 + 2^2} = \sqrt{36 + 4} = \sqrt{40} = 2\sqrt{10}.

  • Equations of Perpendicular Lines:

    • Perpendicular lines have negative reciprocal slopes.

    • Example 15: Line through (3,3)(3, 3) perpendicular to y=12x+2y = -\frac{1}{2}x + 2.

      • Original slope m=12m = -\frac{1}{2}; Perpendicular slope m=2m_{\perp} = 2.

      • Equation: y3=2(x3)y - 3 = 2(x - 3) or y=2x3y = 2x - 3.

    • Perpendicular Bisector:

      1. Find midpoint of segment.

      2. Find slope of original segment.

      3. Use negative reciprocal slope with the midpoint.

      • Example 16: Points (0,5)(0, 5) and (8,9)(8, 9).

      • Midpoint: (4,7)(4, 7).

      • Slope: 9580=12\frac{9 - 5}{8 - 0} = \frac{1}{2}; m=2m_{\perp} = -2.

      • Equation: y7=2(x4)y - 7 = -2(x - 4) or y=2x+15y = -2x + 15.

Transversals, Transformations, and Triangles

  • Parallel Lines and Transversals:

    • Theorem: Same-Side Interior angles are supplementary (180180^\circ).

    • Example 17: mMTU=3x18m\angle MTU = 3x - 18 and mTUN=4x12m\angle TUN = 4x - 12.

      • 3x18+4x12=1807x30=1807x=210x=303x - 18 + 4x - 12 = 180 \rightarrow 7x - 30 = 180 \rightarrow 7x = 210 \rightarrow x = 30.

      • mTUN=4(30)12=108m\angle TUN = 4(30) - 12 = 108^\circ.

      • mMTS=108m\angle MTS = 108^\circ because corresponding angles are congruent.

  • Midsegments and Trapezoids:

    • Example 18: Triangle ABCABC with midpoints L,M,NL, M, N.

      • If MN=8MN = 8, then BC=16BC = 16 (base is twice the midsegment). Since LL is the midpoint, BL=LC=8BL = LC = 8.

      • Side lengths are given as MN=8MN = 8, ML=5ML = 5, NL=6NL = 6.

      • Trapezoid BMNCBMNC perimeter: MN+NC+BC+BM=8+6+16+5=35MN + NC + BC + BM = 8 + 6 + 16 + 5 = 35.

  • Transformations:

    • Reflections: Reflection over the y-axis changes (x,y)(x, y) to (x,y)(-x, y).

      • Example 19: Point (2,3)(2, -3) reflected across y-axis results in (2,3)(-2, -3).

    • Dilations: Multiply both coordinates by the scale factor.

      • Example 20: Dilation by 1/31/3 of (12,9)(-12, -9) centered at origin results in (4,3)(-4, -3).

Circle Geometry

  • Angles in Circles:

    • Inscribed Angle: Equal to half the measure of its intercepted arc.

      • Example 21: Major arc ABC=268ABC = 268^\circ. Total circle is 360360^\circ. Remaining arc AC=360268=92AC = 360 - 268 = 92^\circ.

      • mABC=922=46m\angle ABC = \frac{92}{2} = 46^\circ.

    • Central Angle: Equal to the intercepted arc (mAOB=mABm\angle AOB = mAB).

    • Angle Vertex Outside Circle: Big ArcLittle Arc2\frac{\text{Big Arc} - \text{Little Arc}}{2}.

      • Example 23: Arc AB=117AB = 117^\circ, Arc ACB=243ACB = 243^\circ.

      • x=2431172=1262=63x = \frac{243 - 117}{2} = \frac{126}{2} = 63^\circ.

  • Equations of Circles (Standard Form):

    • Completing the square to find center (h,k)(h, k) and radius rr.

    • Example 22a: x2+8x+y24y=16x^2 + 8x + y^2 - 4y = -16

      • (x2+8x+16)+(y24y+4)=16+16+4(x^2 + 8x + 16) + (y^2 - 4y + 4) = -16 + 16 + 4

      • (x+4)2+(y2)2=4(x + 4)^2 + (y - 2)^2 = 4

      • Center: (4,2)(-4, 2), Radius: 22.

    • Example 22b: x2+y210y=75x^2 + y^2 - 10y = 75

      • x2+(y210y+25)=75+25x^2 + (y^2 - 10y + 25) = 75 + 25

      • x2+(y5)2=100x^2 + (y - 5)^2 = 100

      • Center: (0,5)(0, 5), Radius: 1010.

Trigonometry Fundamentals

  • Ratios (SOHCAHTOA and Reciprocals):

    • sin(A)=opphyp\sin(A) = \frac{\text{opp}}{\text{hyp}}, cos(A)=adjhyp\cos(A) = \frac{\text{adj}}{\text{hyp}}, tan(A)=oppadj\tan(A) = \frac{\text{opp}}{\text{adj}}.

    • csc(A)=1sin(A)\csc(A) = \frac{1}{\sin(A)}, sec(A)=1cos(A)\sec(A) = \frac{1}{\cos(A)}, cot(A)=1tan(A)\cot(A) = \frac{1}{\tan(A)}.

    • Example 24: Triangle with side 2121, 2020, hypotenuse 2929.

      • sin(A)=2129\sin(A) = \frac{21}{29}, cos(A)=2029\cos(A) = \frac{20}{29}, tan(A)=2120\tan(A) = \frac{21}{20}.

      • csc(A)=2921\csc(A) = \frac{29}{21}, sec(A)=2920\sec(A) = \frac{29}{20}, cot(A)=2021\cot(A) = \frac{20}{21}.

  • Special Right Triangles:

    • 45459045-45-90 Triangle: Side ratios are x,x,x2x, x, x\sqrt{2}.

    • 30609030-60-90 Triangle: Side ratios are x,x3,2xx, x\sqrt{3}, 2x.

    • Example 25a: Given side 99 opposite 4545^\circ. Other side is 99, hypotenuse is 929\sqrt{2}.

    • Example 25c: Given hypotenuse 5\sqrt{5} in a 30609030-60-90. Short side x=52x = \frac{\sqrt{5}}{2}, long side x3=152x\sqrt{3} = \frac{\sqrt{15}}{2}.

Law of Sines and Ambiguous Case (SSA)

  • Determining number of possible triangles:

    • Example 26a: mC=63,b=9,c=12m\angle C = 63^\circ, b = 9, c = 12.

      • 9sin(B)=12sin(63)sin(B)=9sin(63)120.668\frac{9}{\sin(B)} = \frac{12}{\sin(63)} \rightarrow \sin(B) = \frac{9\sin(63)}{12} \approx 0.668.

      • B41.9B \approx 41.9^\circ or 138.1138.1^\circ.

      • 138.1 + 63 > 180, so only one triangle exists.

    • Example 26b: mB=35,a=24,b=6m\angle B = 35^\circ, a = 24, b = 6.

      • 24sin(A)=6sin(35)sin(A)=24sin(35)62.29\frac{24}{\sin(A)} = \frac{6}{\sin(35)} \rightarrow \sin(A) = \frac{24\sin(35)}{6} \approx 2.29.

      • \sin(A) > 1 is impossible. No triangles exist.

    • Example 26c: mA=29,c=18,a=17m\angle A = 29^\circ, c = 18, a = 17.

      • sin(C)=18sin(29)170.513\sin(C) = \frac{18\sin(29)}{17} \approx 0.513.

      • C30.9C \approx 30.9^\circ or 149.1149.1^\circ.

      • Both 30.9 + 29 < 180 and 149.1 + 29 < 180. Two triangles exist.

Advanced Equation Solving

  • Fractional Exponent Equations:

    • Example 28a: 354=10(m10)3/23 - 54 = -10 - (m - 10)^{3/2}

      • 64=(m10)3/264=(m10)3/2-64 = -(m - 10)^{3/2} \rightarrow 64 = (m - 10)^{3/2}.

      • Raise to the reciprocal power 2/32/3: 642/3=m1016=m10m=2664^{2/3} = m - 10 \rightarrow 16 = m - 10 \rightarrow m = 26.

    • Example 28b: 5126=55(3x+22)5/3-5126 = -5 - 5(3x + 22)^{5/3}.

      • 5120=5(3x+22)5/31024=(3x+22)5/3-5120 = -5(3x + 22)^{5/3} \rightarrow 1024 = (3x + 22)^{5/3}.

      • Raise to power 3/53/5: 10243/5=3x+2264=3x+22x=141024^{3/5} = 3x + 22 \rightarrow 64 = 3x + 22 \rightarrow x = 14.

  • Radical Equations:

    • Example 28c: Solve 2k+40=162k\sqrt{2k+40} = -16 - 2k.

      • Square both sides: 2k+40=(162k)22k + 40 = (-16 - 2k)^2. Check for extraneous roots.

      • Result found: k=14k = -14.

    • Example 28d: x+8=3x+8\sqrt{x+8} = \sqrt{3x+8}.

      • x+8=3x+80=2xx=0x + 8 = 3x + 8 \rightarrow 0 = 2x \rightarrow x = 0.

  • Absolute Value Inequalities:

    • Theorem: |X| < a means -a < X < a.

    • Example 28e: 9|m - 8| - 10 < 26

      • 9|m - 8| < 36 \rightarrow |m - 8| < 4.

      • -4 < m - 8 < 4 \rightarrow 4 < m < 12. Interval: (4,12)(4, 12).

    • Example 28f: 9|x + 8| + 10 < 55

      • 9|x + 8| < 45 \rightarrow |x + 8| < 5.

      • -5 < x + 8 < 5 \rightarrow -13 < x < -3. Interval: (13,3)(-13, -3).

Mathematical Proofs and Geometry Logic

  • Quadrants for Trig Functions:

    • ASTC (All, Sine, Tangent, Cosine) identifies positivity in quadrants I, II, III, IV respectively.

    • Example 29: If \sin(\theta) > 0 (Quadrant I or II) and \sec(\theta) < 0 (Quadrant II or III), the terminal side lies in Quadrant II.

  • Parallelogram Properties:

    1. Opposite sides are parallel and congruent.

    2. Opposite angles are congruent.

    3. Consecutive angles are supplementary.

    • Example 30a: If one angle is 7878^\circ, the opposite angle z=102z = 102^\circ (Wait, consecutive angles are supplementary, so 18078=102180 - 78 = 102). Alternate interior angles are equal: x=29,y=73x = 29^\circ, y = 73^\circ.

    • Proof of non-parallelogram: If opposite sides are not equal (e.g., 10810 \neq 8) or opposite angles are not equal (e.g., 135130135 \neq 130), it is not a parallelogram.

  • Geometric Proof (ASA):

    • Given: JKLMLK\angle JKL ≅ \angle MLK and JLKMKL\angle JLK ≅ \angle MKL.

    • Goal: Prove JKMLJK ≅ ML.

    • Steps:

      1. JKLMLK,JLKMKL\angle JKL ≅ \angle MLK, \angle JLK ≅ \angle MKL (Given).

      2. KLKLKL ≅ KL (Reflexive Property).

      3. ΔJKLΔMLK\Delta JKL ≅ \Delta MLK (Angle-Side-Angle or ASA).

      4. JKMLJK ≅ ML (Corresponding Parts of Congruent Triangles are Congruent or CPCTC).

Unit Circle and Quadratic Roots

  • Unit Circle Coordinates (x, y) = (̄\cos ̄\theta, ̄\sin ̄\theta).

    • 30(π/6)30^\circ (π/6): (32,12)(\frac{\sqrt{3}}{2}, \frac{1}{2})

    • 45(π/4)45^\circ (π/4): (22,22)(\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2})

    • 60(π/3)60^\circ (π/3): (12,32)(\frac{1}{2}, \frac{\sqrt{3}}{2})

    • 90(π/2)90^\circ (π/2): (0,1)(0, 1)

    • 180(π)180^\circ (π): (1,0)(-1, 0)

    • 270(3π/2)270^\circ (3π/2): (0,1)(0, -1)

  • Quadratic Formula Roots:

    • Example 33: x23x+10=0x^2 - 3x + 10 = 0.

      • x=(3)±(3)24(1)(10)2(1)x = \frac{-(-3) \pm \sqrt{(-3)^2 - 4(1)(10)}}{2(1)}.

      • x=3±312=3±i312x = \frac{3 \pm \sqrt{-31}}{2} = \frac{3 \pm i\sqrt{31}}{2}.

  • Radians and Degrees:

    • Multiply by 180π\frac{180}{\pi}.

    • Example 32: 19π18=19×18018=190\frac{19\pi}{18} = \frac{19 \times 180}{18} = 190^\circ (Quadrant III).