LEC10 Volume Calculation Methods in Construction Surveying

Volume

Unit Area or Borrow-Pit Method

  • Used for determining the quantity of earth, gravel, rock, or other material excavated or filled, especially in projects that are not long linear route constructions.
  • The calculated quantities serve as the basis for payment to the contractor or material supplier.
  • Applicable for finding the volume of coal or other loose materials in stockpiles.

Procedure:

  1. Area Layout:
    • Lay out the area using a total station instrument and tape, or just a tape measure.
  2. Benchmark Establishment:
    • Establish a benchmark with a known or assumed elevation outside the area, in a location unlikely to be disturbed.
  3. Elevation Determination:
    • Determine elevations at all grid intersection points.
    • Designate points with letters and numbers.
  4. Cut or Fill Calculation:
    • Calculate the amount of cut or fill at each grid square corner by subtracting the desired leveled elevation from the existing elevation.
  5. Volume Calculation:
    • For each square, calculate the average height of the four corners of each prism of cut or fill.
    • Multiply the average height by the base area of the square.
  6. Total Volume Calculation:
    • Sum the individual volumes for each block.
    • Divide the total volume by 27 to convert the result to cubic yards.
    • \text{Volume (cubic yards)} = \frac{\text{Total volume (cubic feet)}}{27}

Example: Borrow-Pit Leveling

  • The task is to grade an area to an elevation of 358.0 ft for a building site.
  • Field notes containing elevation information from borrow-pit leveling are provided.
  • The area is staked in squares of 20 ft.
  • The goal is to calculate the volume of material to be excavated from the area.

Example Solution

  • Field measurements and calculations are recorded in a table.
  • Benchmark (BM) Road has a backsight (BS) of 4.22, resulting in a Height of Instrument (HI) of 364.70, and an elevation of 360.48.
  • Cut values are calculated at grid points (A,0 through D,3).
  • The average height ($\Sigma h_n$) is calculated by summing the cut values at each grid corner.
  • The table includes point identifiers, backsight readings, HI, foresight readings, elevations, and cut values.
  • To calculate the total volume that needs to be excavated use the following formula
    • \text{Volume} = \frac{\text{area of base} \times \Sigma h_n}{4} Where: area of base is 20 \times 20 = 400 ft^2
    • \text{Volume} = \frac{400 \times 22.8}{4} = 2280 ft^3
    • \text{Volume in Cubic Yards} = \frac{2280}{27} \approx 84.4 cu.yd

Contour-Area Method

  • Volumes based on contours can be determined from contour maps using a planimeter to measure the area enclosed by each contour.
  • Alternatively, CAD software can be used to determine these areas.
  • The average area of adjacent contours is calculated using the average end area method or coordinate formula.
  • The volume is obtained by multiplying the average area by the contour spacing (i.e., contour interval).
  • The prismoidal formula is used only if required for precise calculation.

Example: Contour-Area Method

  • Compute the volume of water impounded by a proposed dam.
  • The map scale is 500 ft/in, and the proposed spillway elevation is 940 ft.

Volume Computation by Contour-Area Method

  • The volume is calculated based on contour areas.
  • The contour intervals are at 10 ft increments (910 ft, 920 ft, 930 ft, 940 ft).
  • Areas within each contour are measured in square inches and converted to acres.
  • The volume between contours is calculated in acre-feet.
    • \text{Volume} = \text{Contour Interval} \times \frac{(\text{Area}1 + \text{Area}2)}{2}
  • The total volume is the sum of the individual volumes between contours.
  • Example:
    • Contour 910: Area = 1.683 in$^2$ = 9.659 acres
    • Contour 920: Area = 5.208 in$^2$ = 29.889 acres
    • Contour 930: Area = 11.256 in$^2$ = 64.598 acres
    • Contour 940: Area = 19.210 in$^2$ = 110.246 acres
  • Volume between 910 and 920:
    • \text{Volume} = 10 \times \frac{(9.659 + 29.889)}{2} = 197.7 \text{ acre-ft}
  • Volume between 920 and 930:
    • \text{Volume} = 10 \times \frac{(29.889 + 64.598)}{2} = 472.4 \text{ acre-ft}
  • Volume between 930 and 940:
    • \text{Volume} = 10 \times \frac{(64.598 + 110.246)}{2} = 874.2 \text{ acre-ft}
  • Total Volume = 197.7 + 472.4 + 874.2 = 1544.3 acre-ft

References

  • Charles D. Ghilani, Elementary Surveying: An Introduction to Geomatics, 16th edition, Pearson, 2022.
  • Planimeter, mathematical instrument, Britannica 2025