Uniform Circular Motion

Uniform Circular Motion

  • Object travels in a circle at constant speed.
  • Example: Points on a spinning propeller, hands of a watch.
  • Points on rotating objects are accelerating, even if the rotation rate is constant.

Centripetal Acceleration

  • In 2D/3D kinematics, constant speed can still mean acceleration on a curved path.
  • Particle moving counterclockwise on a circular path of radius rr.
  • Velocity vector is tangent to the path.
  • Change in velocity is proportional to change in radius: Δvv=Δrr\frac{\Delta v}{v} = \frac{\Delta r}{r}.
  • Centripetal acceleration: a=limΔt0ΔvΔt=v2Ra = \lim_{\Delta t \to 0} \frac{\Delta v}{\Delta t} = \frac{v^2}{R}.

Period of Circular Motion

  • Period (T): Time for one complete revolution.
  • T=2πRvT = \frac{2\pi R}{v}

Angular Speed

  • Rate of change of angle with respect to time: Ω=2πT\Omega = \frac{2\pi}{T}.
  • v=ΩRv = \Omega R
  • Centripetal acceleration in terms of angular speed: AC=v2R=Ω2RA_C = \frac{v^2}{R} = \Omega^2 R

Sample Problem: Earth's Orbit

  • Earth's revolution: 365 days (3.15×1073.15 \times 10^7 seconds).
  • Distance from Earth to Sun: 1.496×10111.496 \times 10^{11} meters.
  • Centripetal acceleration: AC=v2R=0.00595ms2A_C = \frac{v^2}{R} = 0.00595 \frac{m}{s^2}
  • Angular speed: Ω=2πT=1.995×107rads\Omega = \frac{2\pi}{T} = 1.995 \times 10^{-7} \frac{rad}{s}

Tangential and Radial Acceleration

  • Non-uniform circular motion involves changing speed.
  • Tangential acceleration (A<em>TA<em>T): Acceleration tangent to the circle, due to changing speed. A</em>T=dVdtA</em>T = \frac{dV}{dt}
  • Centripetal acceleration (ARA_R) is always directed inward.
  • Total acceleration: A=A<em>T+A</em>RA = A<em>T + A</em>R.
  • Magnitude of total acceleration: A=A<em>T2+A</em>R2A = \sqrt{A<em>T^2 + A</em>R^2}

Sample Problem: Car on a Rise

  • Constant tangential acceleration: 0.3ms20.3 \frac{m}{s^2}.
  • Radius of curvature: 500 meters.
  • Velocity at top: 6ms6 \frac{m}{s}.
  • Centripetal acceleration: AR=v2R=0.072ms2A_R = \frac{v^2}{R} = 0.072 \frac{m}{s^2}.
  • Total acceleration: A=A<em>R2+A</em>T2=0.3085ms2A = \sqrt{A<em>R^2 + A</em>T^2} = 0.3085 \frac{m}{s^2}