Continuity JEE Mathematics Notes
Core Identity and Overview
- Core identity of continuity at a point x=a:
limx→af(x)=f(a)
- For a function to be continuous at x=a, three values must exist and be identically equal: the left-hand limit (LHL), the right-hand limit (RHL), and the actual function value f(a).
- Key focus areas for problem-solving:
- Piecewise functions and boundary point evaluations.
- Determination of unknown parameters.
- Modulus function ∣x∣.
- Greatest Integer Function (GIF) [x].
- Fractional part function {x}.
- Signum function sgn(x).
- Application of standard limits.
- Classification of discontinuities.
- Intermediate Value Theorem (IVT) and Bolzano's Theorem.
- Relationship between continuity and differentiability.
Limits Required for Continuity
- Meaning of a limit:
- The expression limx→af(x)=L signifies that as x approaches the value a, the corresponding output f(x) approaches the value L.
- The actual function value f(a) does not need to exist for the limit limx→af(x) to exist.
- Even when f(a) exists, it is not required to equal the value of the limit for the limit itself to exist.
- Left-Hand Limit (LHL):
- Represented as limx→a−f(x).
- Describes the behavior of f(x) as x approaches a through values strictly smaller than a.
- Example: x→2− denotes approaching 2 through values such as 1.9, 1.99, 1.999, and so forth.
- Right-Hand Limit (RHL):
- Represented as limx→a+f(x).
- Describes the behavior of f(x) as x approaches a through values strictly greater than a.
- Existence of a two-sided limit:
- A finite two-sided limit limx→af(x) exists if and only if both one-sided limits are finite and equal:
LHL=RHL
- Standard limits required for evaluation:
- Trigonometric limit 1:
limx→0xsin(x)=1
- Trigonometric limit 2:
limx→0xtan(x)=1
- Scaled trigonometric limit 1:
limx→0xsin(ax)=a
- Scaled trigonometric limit 2:
limx→0sin(bx)sin(ax)=ba
- Cosine limit:
limx→0x21−cos(x)=21
- Exponential limit 1:
limx→0xex−1=1
- Exponential limit 2:
limx→0xax−1=ln(a)
- Logarithmic limit:
limx→0xln(1+x)=1
- Power limit:
limx→0x(1+x)n−1=n
- Algebra of limits:
- Limit laws for sum, difference, product, and quotient can be applied directly provided individual component limits exist.
- For quotient operations, the limit of the denominator must be non-zero.
Definition and Conditions of Continuity
- Mathematical definition:
- A function f is defined as continuous at x=a if and only if:
limx→af(x)=f(a)
- The three necessary conditions for continuity at x=a:
- The function value f(a) exists (i.e., a belongs to the domain of f).
- The limit limx→af(x) exists, requiring LHL=RHL.
- The limiting value equals the actual function value: limx→af(x)=f(a).
- Master condition for continuity at x=a:
LHL=RHL=f(a)
- Distinction between limit and function value:
- Consider the function:
f(x)=x−1x2−1
- For all x=1, the algebraic expression simplifies to x+1.
- The limit as x→1 is:
limx→1x−1x2−1=2
- However, the original function f(x) is completely undefined at x=1 because of division by zero.
Left and Right Continuity
- Left continuity definition:
- A function f is left-continuous at x=a if:
limx→a−f(x)=f(a)
- Right continuity definition:
- A function f is right-continuous at x=a if:
limx→a+f(x)=f(a)
- Full continuity requirement:
- Full continuity requires simultaneous left and right continuity at x=a:
LHL=f(a)=RHL
Continuity on Intervals
- Continuity on an open interval (a,b):
- A function f is continuous on (a,b) if it is continuous at every individual point within the interval (a,b).
- Continuity on a closed interval [a,b]:
- Continuous at every interior point x∈(a,b).
- Right-continuous at the left endpoint x=a:
limx→a+f(x)=f(a)
- Left-continuous at the right endpoint x=b:
limx→b−f(x)=f(b)
- Continuity on half-open intervals:
- Requires ordinary continuity across all interior points.
- Requires the appropriate one-sided continuity condition (left or right) at whichever endpoint is included in the set.
Discontinuity and Its Classification
- Removable discontinuity:
- Definition: Occurs when the two-sided limit limx→af(x) exists (meaning LHL=RHL is finite), but either limx→af(x)=f(a) or f(a) is completely undefined.
- Repair: This discontinuity can be removed or repaired simply by defining or redefining f(a) to match the limiting value limx→af(x).
- Jump discontinuity:
- Definition: Occurs when both LHL and RHL exist as finite values, but are not equal:
LHL=RHL
- Infinite discontinuity:
- Definition: Occurs when f(x) grows without bound (approaches ∞ or −∞) as x approaches a.
- Example: The function f(x)=x−a1 exhibits an infinite discontinuity at x=a, creating a vertical asymptote.
- Oscillatory discontinuity:
- Definition: Occurs when the function oscillates endlessly between fixed bounds near a point without settling on a single limiting value.
- Example: The function f(x)=sin(x1) at x=0.
Continuity of Standard Functions
- Polynomial functions:
- Every polynomial function is continuous for all real numbers x∈R.
- Rational functions:
- A rational function q(x)p(x) (where p and q are polynomials) is continuous at all real numbers where the denominator q(x)=0.
- Exponential functions:
- Functions of the form ax (where a>0) are continuous for all real numbers x∈R.
- Logarithmic functions:
- Functions of the form loga(x) are continuous for all x>0 in their domain.
- Trigonometric functions:
- sin(x) and cos(x) are continuous for all real numbers x∈R.
- tan(x), cot(x), sec(x), and csc(x) are continuous at every point throughout their defined domains.
- Inverse trigonometric functions:
- Every standard inverse trigonometric function (such as sin−1(x), cos−1(x), tan−1(x)) is continuous throughout its respective domain.
- Key habit for analysis:
- Always verify the domain of a function before analyzing continuity; a function cannot be declared continuous at any point where it is undefined.
Modulus Function
- Piecewise definition:
- ∣x∣=x for x≥0
- ∣x∣=−x for x<0
- Continuity properties:
- The modulus function ∣x∣ is continuous for all real numbers x∈R.
- Evaluation at x=0:
LHL=limx→0−(−x)=0RHL=limx→0+(x)=0f(0)=∣0∣=0LHL=RHL=f(0)=0
- General composite modulus:
- If a function f(x) is continuous at a point, then its absolute value function ∣f(x)∣ is also continuous at that point.
- When solving equations involving ∣f(x)∣, construct piecewise branches by splitting cases where f(x)≥0 and f(x)<0
- Strategic focus:
- For expressions containing ∣f(x)∣, locate all real zeros of f(x) to determine the boundary points for piecewise evaluation.
Greatest Integer Function
- Definition:
- The Greatest Integer Function [x] or floor(x) evaluates to the greatest integer less than or equal to x.
- Numerical examples:
[2.7]=2[3]=3[−1.2]=−2
- Behavior at integer points n∈Z:
- Left-hand limit:
limx→n−[x]=n−1
- Right-hand limit:
limx→n+[x]=n
- Continuity profile:
- The function [x] is continuous at every non-integer real number.
- The function [x] is discontinuous at every integer point n∈Z.
- Composite GIF analysis:
- For composite expressions [g(x)]\, identify all points where g(x) approaches an integer value; these points are primary candidates for discontinuity.
Fractional Part Function
- Definition:
- The fractional part function is defined as:
{x}=x−[x]
- Range restriction:
0≤{x}<1
- Behavior at integer points n∈Z:
- Left-hand limit:
limx→n−{x}=1
- Right-hand limit:
limx→n+{x}=0
- Discontinuous at every integer point n∈Z.
- Behavior between integers:
- Behaves linearly between consecutive integers and is continuous throughout every open interval (n,n+1).
Signum Function
- Piecewise definition:
- sgn(x)=−1 for x<0
- sgn(x)=0 for x=0
- sgn(x)=1 for x>0
- Continuity profile:
- Evaluation at x=0:
LHL=limx→0−(−1)=−1RHL=limx→0+(1)=1
- Since LHL=RHL, sgn(x) has a jump discontinuity at x=0.
- The function is continuous at all non-zero real numbers x=0
Algebra of Continuous Functions
- Let f and g be continuous functions at x=a:
- Sum and Difference:
f+g and f−g are continuous at x=a
- Product:
f×g is continuous at x=a
- Constant Multiple:
c×f is continuous at x=a for any real constant c
- Quotient:
gf is continuous at x=a provided g(a)=0
Composite Functions
- Main Theorem:
- If g is continuous at x=a and f is continuous at g(a), then the composite function (f∘g)(x)=f(g(x)) is continuous at x=a
- Application examples:
- sin(x2+1): Inner function g(x)=x2+1 is continuous everywhere; outer function f(u)=sin(u) is continuous everywhere. Thus, the composite is continuous everywhere.
- esin(x): Continuous for all real x
- log(1+x2): Inner function 1+x2≥1>0, continuous for all real x
Piecewise Functions
- Primary significance:
- The boundary points (joining points) where the function changes algebraic definitions represent the primary candidate locations for discontinuity.
- Standard procedure for checking continuity at a joining point x=a:
- Step 1: Identify the joining point x=a
- Step 2: Calculate LHL using the left-hand branch expression (x<a).
- Step 3: Calculate RHL using the right-hand branch expression (x>a).
- Step 4: Calculate actual value f(a) using the branch containing the equality (x≥a or x≤a).
- Step 5: Impose the continuity equation:
LHL=RHL=f(a)
- Comprehensive Example:
- Define piecewise function f(x):
f(x)=x2+k for x<1f(x)=3x+2 for x≥1
- Evaluate at joining point x=1:
LHL=limx→1−(x2+k)=1+kRHL=limx→1+(3x+2)=3(1)+2=5f(1)=3(1)+2=5
- Impose continuity condition 1+k=5:
k=4
- Multiple joining points:
- If a function transitions definitions at multiple distinct points (e.g., x=a and x=b), carry out the five-step procedure independently for each point.
Finding Unknown Parameters
- Single parameter problems:
- Set up the continuity relation LHL=RHL=f(a) at the critical boundary point to create a single algebraic equation, then solve for the parameter.
- Multiple parameter problems:
- Multiple joining points or extra constraints yield a system of simultaneous equations. Solve the linear or non-linear system for all unknown constants.
- Fast setup strategy:
- Immediately write down the full statement LHL=RHL=f(a) before carrying out algebraic manipulations.
Finding Points of Discontinuity
- Rational expressions:
- Set the denominator expression equal to zero and identify all roots; check if those points lie in the function domain.
- Logarithmic expressions:
- Determine where the argument is non-positive (argument≤0) and evaluate boundary points.
- Square root expressions:
- Apply domain constraint expression≥0 and evaluate points where the interior vanishes or fails definition.
- Greatest Integer Functions (GIF):
- Locate all values of x where the argument inside [g(x)] evaluates to an integer.
- Piecewise definitions:
- Test every individual point where the formula changes branches.
- Trigonometric denominators:
- Locate points where denominator expressions like cos(x) or sin(x) become zero.
- Theorem Statement:
- If f is a continuous function on the closed interval [a,b], and N is any real number strictly between f(a) and f(b), then there exists at least one value c∈[a,b] such that:
f(c)=N
- Geometric Interpretation:
- A continuous function cannot transition from one value to another without taking on every single intermediate value between them.
- Root existence corollary:
- If f is continuous on [a,b] and the endpoint values have opposite signs (f(a)f(b)<0), then there exists at least one real root c∈(a,b) such that f(c)=0
- Key limitation:
- The Intermediate Value Theorem proves the existence of at least one root; it does not calculate the numerical value of the root nor guarantee that the root is unique.
Bolzano's Theorem
- Theorem Statement:
- If f is continuous on the closed interval [a,b] and f(a)f(b)<0, then there exists at least one point c∈(a,b) satisfying:
f(c)=0
- Execution Procedure:
- Calculate endpoint values f(a) and f(b).
- Verify that f is continuous on the entire interval [a,b].
- Demonstrate a sign change across endpoints (f(a)f(b)<0).
- Conclude that at least one real root exists in (a,b).
Continuity Versus Differentiability
- Fundamental implication:
- If a function f is differentiable at x=a, then f is guaranteed to be continuous at x=a:
Differentiable at a⟹Continuous at a
- Fallacy of the converse:
- Continuity at a point does NOT imply differentiability at that point:
Continuous at a⟹Differentiable at a
- Standard counterexample:
- The function f(x)=∣x∣ is continuous at x=0 (LHL=RHL=f(0)=0).
- However, f(x)=∣x∣ is non-differentiable at x=0 because the graph exhibits a sharp corner (the left derivative is −1 and the right derivative is 1).
Graph-Based Questions
- Visual representation of discontinuity types on a graph:
- Hole in graph: Represents a removable discontinuity.
- Vertical jump: Indicates a jump discontinuity where left and right limits differ.
- Vertical asymptote: Represents an infinite discontinuity where branches approach ±∞
- Continuous oscillations: Represents an oscillatory discontinuity where the graph fails to settle on a single value.
- Information retrieval from graphs:
- Determine f(a) from the solid dot or filled point at x=a
- Determine LHL from the curve approaching x=a from the left.
- Determine RHL from the curve approaching x=a from the right.
- Compare LHL, RHL, and f(a) to establish continuity status.
Problem-Solving Algorithms
- Algorithm 1: Solving Parameter Problems for Continuity:
- Identify boundary / joining point a
- Evaluate LHL=limx→a−f(x)
- Evaluate RHL=limx→a+f(x)
- Evaluate actual value f(a)
- Equate LHL=RHL=f(a)
- Solve the algebraic equation(s) for the unknown parameter(s).
- Algorithm 2: Evaluating Discontinuities in Complex Expressions:
- Determine domain of the function.
- List candidate points for discontinuity (denominators vanishing, GIF arguments matching integers, branch transitions).
- Calculate one-sided limits only at suspect points.
- Algorithm 3: Handling GIF and Modulus Functions:
- For GIF [g(x)]\, locate integer crossings of g(x).
- For modulus ∣f(x)∣, locate real zeros of f(x) for case-splitting.
- Algorithm 4: Root-Existence Problems:
- Verify continuity on interval [a,b].
- Compute endpoint values f(a) and f(b).
- Check if f(a)f(b)<0
- Apply IVT / Bolzano's Theorem to conclude root existence.
- Continuity condition at x=a:
limx→af(x)=f(a)⟺LHL=RHL=f(a)
- Left continuity:
limx→a−f(x)=f(a)
- Right continuity:
limx→a+f(x)=f(a)
- Removable discontinuity condition:
LHL=RHL=f(a)orf(a) is undefined
- Jump discontinuity condition:
LHL=RHL(both limits finite)
- Greatest Integer Function [x]:
- Discontinuous at every integer n∈Z
- Continuous at every non-integer x∈/Z
- Fractional Part Function {x}=x−[x]:
- Discontinuous at every integer n∈Z
- Differentiability-Continuity relation:
Differentiable⟹ContinuousContinuous⟹Differentiable
- Bolzano's Theorem condition:
Continuous on [a,b]andf(a)f(b)<0⟹∃c∈(a,b) such that f(c)=0
Final Checklist and Study Order
- Core Concepts Checklist:
- Limits, LHL, RHL
- Definition of continuity
- One-sided continuity
- Interval continuity
- Classification of discontinuities
- Standard Functions Checklist:
- Polynomials, rational, exponential, logarithmic, trigonometric, inverse trigonometric, modulus
- Special Functions Checklist:
- GIF [x], fractional part {x}, signum sgn(x), composite forms
- Problem Types Checklist:
- Piecewise functions, finding parameters, multiple joining points, graph-based questions, standard-limit continuity, domain-based discontinuities
- Theorems Checklist:
- Algebra of continuous functions, composition theorem, IVT, Bolzano's theorem
- One-Minute Revision Summary:
- Continuity at a: LHL=RHL=f(a)
- Left continuity: LHL=f(a)
- Right continuity: RHL=f(a)
- Removable: LHL=RHL=f(a) or f(a) undefined
- Jump: LHL=RHL
- GIF: Discontinuous at all integers
- Fractional part: {x}=x−[x], discontinuous at all integers
- Differentiability: Differentiable⟹Continuous
- IVT: Continuous + intermediate value condition ⟹ existence
- Bolzano: Continuous + sign change (f(a)f(b)<0) ⟹ at least one root
- Recommended Study Sequence:
- Limits
- LHL / RHL
- Definition of Continuity
- Piecewise Functions
- Parameter Problems
- Modulus Function
- GIF / Fractional Part / Signum
- Standard Functions
- Composite Functions
- Types of Discontinuities
- IVT / Bolzano's Theorem
- Continuity + Differentiability