Whenever you have h(u(x)), to take the derivative, you take the derivative first of h′(u(x)), then you multiply that by u′(x). So the derivative of a quantity of the type h, you know, and then you have some quantity is derivative of the of f evaluated at that quantity times the derivative of the quantity.
Example
f(x)=3x+10.1
h(x)=x0.1
u(x)=3x+1
f′(x)=h′(u(x))∗u′(x)
h′(x)=0.1∗x−0.9
u′(x)=3
f′(x)=0.1∗(3x+1)−0.9∗3=0.3∗(3x+1)−0.9
Generalized Power Rule
Whenever you want to take the derivative of u(x)n, that would always be n∗u(x)n−1∗u′(x).
Example
Find the derivative of 3x+1.
Rewrite as (3x+1)1/2, then apply the generalized power rule.
(1/2)∗(3x+1)−1/2∗3=(3/2)∗(3x+1)−1/2
Chain Rule for Marginal Product
Chain rule can be used to find the marginal product dNdP, where P is a function of Q, and Q is a function of N.