Advanced Physics Midterm

Falling From a Tower

a = g which is + 9.80m/s²

$y=\frac12at^2$

>——————<

Thrown From a Tower

$y=Vo\cdot t+\frac12a\cdot t^2$

Velocity after time passes → $V=Vo+a\cdot t$

>———————<

Ball Thrown Upward

y → positivie in an upward direction and negative in a downward reaction (accerlaation due to gravity will have a negative sign -9.80 m/s²)

As ball rises, speed decreases until it reaches the highest point where speed = 0, then decesends with increasing speed
Max Height → calculate when ball velocity equals zero (v = 0 at highest point)
look at thise

V → final velocity, velocity, Vo → original velocity, a→ acceleration, t → time, x→ distance,

$V^2=Vo+at$

$x=Vot+\frac12at^2$

$V^2=Vo^2+2ax$