MATH04 Pre Calculus Study Notes
Course Outcome 4
Lesson 2: Trigonometric Equations
Introduction to Trigonometric Equations
Definition: Equations that involve trigonometric functions are called trigonometric equations.
Key Concept: Solving a trigonometric equation is similar to solving an algebraic equation, involving the identification and finding of values of the variable that satisfy the equation.
Techniques for Solving:
Isolating the variable
Collecting like terms
Factoring
Substituting trigonometric identities
Types of Trigonometric Equations
Identical Trigonometric Equation
Definition: A trigonometric equation that is true for all permissible values of the unknown variable for which the equation is defined.
Example:
ext{sin}^2 x + ext{cos}^2 x = 1
Conditional Trigonometric Equation
Definition: A trigonometric equation that is true for some, but not all, permissible values of the unknown variable.
Examples:
2 ext{sin} x - 1 = 0
ext{tan}^2 2x - 1 = 0
Guidelines in Solving Trigonometric Equations
Single Function of a Single Angle: Use algebraic techniques to solve for the angle.
Quadratic Equation: If it contains a single function of the same angle, factor it; otherwise, use the quadratic formula.
Multiple Functions of the Same Angle: Substitute trigonometric identities to obtain a single function.
Multiple Angles: Substitute trigonometric identities to obtain a function of a single angle.
Exercise: Solve Each Equation for Exact Solutions in the Interval 0 ≤ x < 360°
a) 2 ext{sin}^2 x = 1
b) ext{sin}^2 x + 3 ext{sin} x + 2 = 0
c) 2 ext{cos}^2 x + 1 = -3 ext{cos} x
d) 4 ext{cos}^3 x = 3 ext{cos} x
e) 3 ext{tan}^2 x + 5 ext{tan} x - 1 = 0
Expanded Table for Special and Quadrantal Angles
Angle (Radians) | Angle (Degrees) | sin | cos | tan | csc | sec | cot
0 | 0° | 0 | 1 | 0 | Undef | 1 | Undef
rac{ ext{π}}{6} | 30° | rac{1}{2} | rac{ ext{√3}}{2} | rac{ ext{√3}}{3} | 2 | 2 rac{ ext{√3}}{3} | ext{√3}
rac{ ext{π}}{4} | 45° | rac{ ext{√2}}{2} | rac{ ext{√2}}{2} | 1 | ext{√2} | ext{√2} | 1
rac{ ext{π}}{3} | 60° | rac{ ext{√3}}{2} | rac{1}{2} | rac{ ext{√3}}{3} | 2 | rac{2 ext{√3}}{3} | 2
rac{ ext{π}}{2} | 90° | 1 | 0 | Undef | 1 | Undef | 0
rac{2 ext{π}}{3} | 120° | rac{ ext{√3}}{2} | - rac{1}{2} | - rac{ ext{√3}}{3} | -2 | - rac{2 ext{√3}}{3} | - ext{√3}
rac{3 ext{π}}{4} | 135° | rac{ ext{√2}}{2} | - rac{ ext{√2}}{2} | -1 | ext{√2} | - ext{√2} | -1
rac{5 ext{π}}{6} | 150° | rac{1}{2} | - rac{ ext{√3}}{2} | - rac{ ext{√3}}{3} | -2 | - rac{2 ext{√3}}{3} | - ext{√3}
ext{π} | 180° | 0 | -1 | 0 | -1 | 0 | -1
- … (continues for other angles)
Solutions to Exercises
a) 2 ext{sin}^2 x = 1
Step 1: Divide both sides by 2: ext{sin}^2 x = rac{1}{2}
Step 2: Taking square roots: ext{sin} x = rac{ ext{√2}}{2} ext{ or } - rac{ ext{√2}}{2}
Step 3: Solutions: x = 45°, 135°, 225°, 315°
b) ext{sin}^2 x + 3 ext{sin} x + 2 = 0
Factoring: ( ext{sin}x + 2)( ext{sin}x + 1) = 0
Solve:
ext{sin} x = -2 - No solution as sine cannot exceed these bounds.
ext{sin} x = -1
Solutions: x = 270°
c) 2 ext{cos}^2 x + 1 = -3 ext{cos} x
Substituting x= ext{cos} x:
2x^2 + 3x + 1 = 0
Factoring: (2x + 1)(x + 1) = 0
x = - rac{1}{2}
x = -1
Find angles: ext{cos} x = - rac{1}{2} ext{ or } -1
Results: Solutions: x = 120°, 240°, 180°
d) 4 ext{cos}^3 x - 3 ext{cos} x = 0
Factoring the equation:
ext{cos} x(4 ext{cos}^2 x - 3) = 0 \
Solutions for ext{cos}x = 0: x = 90°, 270°
For 4 ext{cos}^2 x - 3 = 0
ext{cos}^2 x = rac{3}{4}
ext{cos} x = rac{ ext{√3}}{2}, - rac{ ext{√3}}{2}
Resulting angles: x = 30°, 150°, 210°, 330°
e) 3 ext{tan}^2 x + 5 ext{tan} x - 1 = 0
Quadratic Formula (Letting x = ext{tan} x in the quadratic):
an x = rac{-b ext{±} ext{√}(b^2 - 4ac)}{2a}
Solutions: Use calculator: an x = 0.1805 ext{ and } -1.8471
Final Angles: x = 10.23°, 190.23°, 298.43°, -61.57° ext{ rounded into quadrant.}
Additional Exercises
ext{cos} 3x + ext{cos} 5x + ext{cos} 2x + ext{sin} 5x ext{sin} 2x - 1 = 0
ext{sin} x + ext{cos} x = ext{√2}
3 ext{cos}^2 x + 3 ext{sin}^2 x = 1
3 ext{sin}^3 x = 0
Further Exercises
Solutions in the interval [0, 2 ext{π}):
a) 2 ext{sin} x + ext{√3} = 0
b) ext{cos} x = -0.4298$$
Conclusion
Understanding and solving trigonometric equations is essential for further studies in trigonometry and calculus.
Utilizing trigonometric identities and algebraic techniques expands problem-solving capabilities in mathematics.