Comprehensive Guide to Factoring Polynomials

Factoring the Greatest Common Factor

  • The fundamental step in polynomial simplification is identifying the greatest common factor (GCF). This process involves extracting the largest numerical coefficient and the highest power of each variable that divides evenly into every term of the expression.

  • Example 1: 2x2+18x2x^2+18x

    • First, assess the numerical coefficients 22 and 1818. The greatest common divisor is 22.

    • Next, assess the variables x2x^2 and xx. The greatest common factor is xx.

    • Initial extraction: 2(x2+9x)2(x^2 + 9x).

    • Complete extraction of GCF: 2x(x+9)2x(x + 9).

    • Note: In some procedural steps, terms might be grouped as 2(x+3)(x+3)2(x+3)(x+3) if misidentified as a perfect square, but the standard GCF result is 2x(x+9)2x(x + 9).

Factoring the Difference of Two Squares

  • Polynomials in the form of a2b2a^2 - b^2 are factored using the formula (ab)(a+b)(a - b)(a + b). This applies when two perfect squares are being subtracted.

  • Example 2: t2144t^2 - 144

    • Identify the square roots: t2=t\sqrt{t^2} = t and 144=12\sqrt{144} = 12.

    • Apply the identity: (t12)(t+12)(t - 12)(t + 12).

  • Example 3: 81a24981a^2 - 49

    • Identify the square roots: 81a2=9a\sqrt{81a^2} = 9a and 49=7\sqrt{49} = 7.

    • Apply the identity: (9a7)(9a+7)(9a - 7)(9a + 7).

Factoring Trinomials of the Form x2+bx+cx^2 + bx + c

  • When the leading coefficient is 11, find two integers that multiply to give the constant term cc and add together to give the middle coefficient bb.

  • Example 4: y2y20y^2 - y - 20

    • Required: Factors of 20-20 that sum to 1-1.

    • The integers are 5-5 and 44.

    • Factored form: (y5)(y+4)(y - 5)(y + 4).

  • Example 5: h2+13h+30h^2 + 13h + 30

    • Required: Factors of 3030 that sum to 1313.

    • The integers are 1010 and 33.

    • Factored form: (h+10)(h+3)(h + 10)(h + 3).

Factoring Trinomials of the Form ax2+bx+cax^2 + bx + c

  • When the leading coefficient aa is not 11, specific methods such as the "ac" method (decomposition) are used. Multiply aa and cc, then find factors of that product that sum to bb.

  • Example 6: 2e2+11e+152e^2 + 11e + 15

    • Calculate ac=2×15=30ac = 2 \times 15 = 30.

    • Find factors of 3030 that sum to 1111: 55 and 66.

    • Decomposition: 2e2+6e+5e+152e^2 + 6e + 5e + 15.

    • Grouping: 2e(e+3)+5(e+3)2e(e + 3) + 5(e + 3).

    • Factored form: (2e+5)(e+3)(2e + 5)(e + 3).

  • Example 7: 12z2z112z^2 - z - 1

    • Calculate ac=12×(1)=12ac = 12 \times (-1) = -12.

    • Find factors of 12-12 that sum to 1-1: 4-4 and 33.

    • Decomposition: 12z24z+3z112z^2 - 4z + 3z - 1.

    • Grouping: 4z(3z1)+1(3z1)4z(3z - 1) + 1(3z - 1).

    • Factored form: (4z+1)(3z1)(4z + 1)(3z - 1).

  • Example 8: 10u23u1810u^2 - 3u - 18

    • Calculate ac=10×(18)=180ac = 10 \times (-18) = -180.

    • Find factors of 180-180 that sum to 3-3: 15-15 and 1212.

    • Decomposition: 10u215u+12u1810u^2 - 15u + 12u - 18.

    • Grouping: 5u(2u3)+6(2u3)5u(2u - 3) + 6(2u - 3).

    • Factored form: (5u+6)(2u3)(5u + 6)(2u - 3).

Factoring Perfect Square Trinomials

  • A perfect square trinomial follows the pattern a2+2ab+b2=(a+b)2a^2 + 2ab + b^2 = (a + b)^2 or a22ab+b2=(ab)2a^2 - 2ab + b^2 = (a - b)^2.

  • Example 9: r2+10r+25r^2 + 10r + 25

    • Observe the first term r2=r\sqrt{r^2} = r and last term 25=5\sqrt{25} = 5.

    • Verify the middle term: 2×r×5=10r2 \times r \times 5 = 10r.

    • Factored form: (r+5)2 or (r+5)(r+5)(r + 5)^2 \text{ or } (r + 5)(r + 5).

  • Example 10: 16t240t+2516t^2 - 40t + 25

    • Observe the first term 16t2=4t\sqrt{16t^2} = 4t and last term 25=5\sqrt{25} = 5.

    • Verify the middle term: 2×4t×5=40t2 \times 4t \times 5 = 40t. Since the middle term is negative, use the subtraction identity.

    • Factored form: (4t5)2(4t - 5)^2.

Factoring Polynomials Completely

  • Complete factoring requires checking for a GCF first, then applying specific formulas (difference of squares, trinomial factoring) to the remaining expression.

  • Example 11: 2a2502a^2 - 50

    • Step 1 (GCF): Factor out 22 to get 2(a225)2(a^2 - 25).

    • Step 2 (Difference of Squares): Factor (a225)(a^2 - 25) to get (a5)(a+5)(a - 5)(a + 5).

    • Complete result: 2(a5)(a+5)2(a - 5)(a + 5).

  • Example 12: 4x3+23x2+15x4x^3 + 23x^2 + 15x

    • Step 1 (GCF): Factor out xx to get x(4x2+23x+15)x(4x^2 + 23x + 15).

    • Step 2 (Trinomial Factoring): Solve for 4x2+23x+154x^2 + 23x + 15.

      • ac=60ac = 60. Factors of 6060 that sum to 2323 are 2020 and 33.

      • Decompose: 4x2+20x+3x+154x^2 + 20x + 3x + 15.

      • Group: 4x(x+5)+3(x+5)4x(x + 5) + 3(x + 5).

      • Resulting binomials: (4x+3)(x+5)(4x + 3)(x + 5).

    • Complete result: x(4x+3)(x+5)x(4x + 3)(x + 5).

  • Example 13: 3h327h3h^3 - 27h

    • Step 1 (GCF): Factor out 3h3h to get 3h(h29)3h(h^2 - 9).

    • Step 2 (Difference of Squares): Factor (h29)(h^2 - 9) to get (h3)(h+3)(h - 3)(h + 3).

    • Complete result: 3h(h3)(h+3)3h(h - 3)(h + 3).