The Integral Test
10.3 The Integral Test
Introduction to Series Convergence
The main question regarding series with nonnegative terms is whether they converge.
A series of nonnegative terms converges if the sequence of its partial sums is bounded from above.
We examine the error involved in using partial sums to approximate the total sum of a convergent series.
Nondecreasing Partial Sums
For an infinite series with nonnegative terms, each partial sum is at least the same as its predecessor, resulting in a nondecreasing sequence.
Corollary of Theorem 6 (Monotonic Sequence Theorem): A series of nonnegative terms converges if and only if its partial sums are bounded from above.
Example 1: Harmonic Series
The harmonic series diverges despite the fact that the nth term (1/n) approaches zero.
The partial sums grow without bound, shown through grouping terms:
1st group: 1, 2nd group: 1/3 + 1/4 > 1/2, 3rd: 1/5 to 1/8 > 1/2, etc.
General trend: The sum of 2n terms is > 1/2, making the partial sums unbounded, confirming divergence.
The Integral Test
The Integral Test is applied to series in the context of functions.
Example 2: Analyze convergence of ( (1/n^2) ) by comparing with the function f(x) = 1/x², interpreting values as rectangle areas under the graph.
This shows the series converges because the sum of areas is bounded from above (by 2).
Theorem 9: The Integral Test
For a series ( a_n = f(n) ) where f is a continuous, positive, decreasing function:
If the series converges, so does the integral ( , \int f(x) , dx )
The reverse is also true.
Example 3: The p-Series Test
A p-series ( \sum_{n=1}^{\infty} \frac{1}{n^p} ) converges if p > 1; diverges if p ≤ 1.
For p > 1, ( f(x) = 1/x^p ) is positive and decreasing, confirming convergence.
If p = 1: Harmonic series diverges.
Example 4: Non p-Series Convergence
For the series of ( 1/(x^2 + 1) ):
f(x) is positive, continuous, decreasing for x ≥ 1.
Converges by the Integral Test but does not specify the series' sum.
Convergence and Divergence Assessment
Example 5: Applications of Integral Test
Example (a): Series converges; (b): Series diverges based on the Integral Test results.
Error Estimation in Convergent Series
Notably, we cannot always determine the exact sum for a convergent series.
We can estimate the size of the remainder ( R_n = S - S_n ) using the bounds found in the Integral Test, which helps infer the error in approximation.
Bounds for the Remainder
For positive terms, we establish:
Lower and upper bounds can be set for the remainder Rn.
This approach assists in determining how close ( S_n ) is to ( S ), the total sum.
Example 6: Estimating the Series Sum
Estimate the sum of the series ( (1/n^2) ) using previous results with n=10 to yield bounds: 1.64068 < S < 1.64977.
Resulting approximation provides an error margin, emphasizing precision in summation estimation.
Conclusion and Exercises
Utilize the Integral Test to assess convergence/divergence for diverse series.
Verify conditions of the Integral Test are satisfied in each case.