ch1
lnx → x, raise the whole thing to the power of e
if the function involves square roots, remember that the square root of a negative number does not exist so take that into consideration when finding the domain
in the case of f(g(x)), where g(x) is a square root, to find the domain of the final function the domain of g(x) must be taken into consideration and the final domain cannot include functions that are not allowed in g(x)
this does not apply to other fractional functions, in that case just find the domain normally and also no need to simplify (kcf)
when finding the domain for ln functions as fractions, always remember that if both the numerator and denominator are negative, the final answer is positive so it might be allowed
draw a table like the pos/neg ones and see
the domain might be a union of two domains
in piecewise functions, the domain is lowk always given so it’s just the union of the domains of the functions in the piecewise function
the domain of multiplication of two functions is what’s shared between the domains of both functions
remember that absolute value functions have two outcomes, positive and negative
when given the domain of f(x) being [this, that], to find the domain of f(a function) put:
this < a function < that
then simplify until the function becomes just x and that gives you the domain
when finding the range of a function, use the whole function same way u do for x in the domain
then multiply and add and whatever
e^x > 0 always
its domain is R
TRIG:
sin,
domain = [-pi/2 , pi/2]
range = [-1,1]
cos,
domain = [0,pi]
range = [-1,1]
domain of the inverse = range
shifting:
LEFT = f(x+a)
RIGHT = f(x-a)
UP = f(x) + a
DOWN = f(x) - a
reflection:
ABOUT THE Y AXIS = changing x → (-x,y)
ABOUT THE X AXIS = changing y → (x,-y)
shrinking:
VERTICAL = kf(x)
HORIZONTAL = f(xk)
don’t shift and reflect at the same time, shift then reflect
EVEN AND ODD FUNCTIONS
even: f(-x) = f(x)
even functions are symmetric about the y axis
odd: f(-x) = -f(x)
odd functions are symmetric about the origin
sq(x²) = |x|
(sq(x))² = x
ax²+bx+c
to find x after altering the function, use x=-b/2a
find (x,y) of both the new and old functions and to find out what happened (shifting, reflecting, etc) do NEW-OLD to get the differences in the (x,y) coordinates
if two logarithmic functions have the same base (log 5s or lns for example), subtraction means division and addition means multiplication
same base and other number means u can combine their exponents
ify = logb(x)
then b^y = x
quadratic formula: ( -b +- sq( b²-4ac ) ) / 2a
loga(b) = lnb/lna
to cancel out e^-x and e^x, multiply both sides of the equation by e^x