8.4

The Dot Product of Two Vectors

  • The dot product of u=βŸ¨π‘’<em>1,𝑒</em>2⟩u = βŸ¨π‘’<em>1, 𝑒</em>2⟩ and v=βŸ¨π‘£<em>1,𝑣</em>2⟩v = βŸ¨π‘£<em>1, 𝑣</em>2⟩ is a scalar value.

  • Formula: uβ‹…v=u<em>1v</em>1+u<em>2v</em>2u β‹… v = u<em>1v</em>1 + u<em>2v</em>2

  • Properties of the Dot Product:

    1. uβ‹…v=vβ‹…uu β‹… v = v β‹… u

    2. uβ‹…(v+w)=uβ‹…v+uβ‹…wu β‹… (v + w) = u β‹… v + u β‹… w

    3. c(uβ‹…v)=(cu)β‹…v=uβ‹…(cv)c(u β‹… v) = (cu) β‹… v = u β‹… (cv)

    4. 0β‹…v=00 β‹… v = 0

    5. vβ‹…v=∣∣v∣∣2v β‹… v = ||v||^2

The Angle Between Two Vectors

  • The angle ΞΈ\theta between two nonzero vectors uu and vv can be determined from: cosΞΈ=uβ‹…v∣∣u∣∣∣∣v∣∣cos \theta = \frac{u β‹… v}{||u|| ||v||}.

  • Alternative dot product calculation: uβ‹…v=∣∣u∣∣∣∣v∣∣cosΞΈu \cdot v = ||u|| ||v|| cos \theta

  • Two vectors uu and vv are orthogonal if and only if uβ‹…v=0u β‹… v = 0.

Finding Vector Components

  • Vectors w1w1 and w2w2 are vector components of uu.

  • w1w1 is the projection of uu onto vv: projvu=uβ‹…v∣∣v∣∣2vprojvu=∣∣v∣∣2uβ‹…v​v

  • w2w2 is given by: w2=uβˆ’projvuw2=uβˆ’projv​u

Work

  • Work WW done by a constant force FF:

    1. W=∣∣F∣∣∣∣PQβ†’βˆ£βˆ£cosΞΈW = ||F|| ||\overrightarrow{PQ}|| cos \theta, where ΞΈ\theta is the angle between the force and the displacement.

    2. W=F⋅PQ→W = F ⋅ \overrightarrow{PQ}