Volume Calculations: Pyramids and Cones

Volume of a Pyramid

  • Formula: V=13AhV = \frac{1}{3}Ah, where:
    • AA = Area of the base
    • hh = Perpendicular height
  • The base can be any shape; use the appropriate area formula.
  • If the height isn't directly given, Pythagoras' theorem may be needed to find the perpendicular height.

Example: Pyramid Volume Calculation

  1. Identify the base area
    • If the base is a square with side ss, then A=s2A = s^2
  2. Substitute values into the volume formula
    • V=13AhV = \frac{1}{3} Ah
  3. Calculations
    *If A=16m2A = 16 m^2 and h=6mh = 6 m, then V=13166=32m3V = \frac{1}{3} * 16 * 6 = 32 m^3

Volume of a Cone

  • Formula: V=13πr2hV = \frac{1}{3}πr^2h
    • rr = Radius of the circular base
    • hh = Perpendicular height
  • The perpendicular height is needed for volume, not the slant height.

Volume vs Surface Area of Cone

  • Volume and surface area are different:
    • Volume uses perpendicular height hh.
    • Surface area uses slant height ll in the formula SA=πr2+πrlSA = πr^2 + πrl.

Example: Cone Volume Calculation

  1. Identify the radius and height
    • Make sure to halve the diameter to get the radius.
    • Ensure the height is perpendicular.
  2. Substitute values into the volume formula
    • V=13πr2hV = \frac{1}{3} π r^2 h

Capacity and Volume

  • 1 cubic centimeter (cm^3) = 1 milliliter (mL)
  • 1 cubic meter = 1 kiloliter
  • Converting volume to capacity is straightforward with cubic centimeters to milliliters.

Finding Height or Radius Using the Volume of a Cone

  1. Write down the formula: V=13πr2hV = \frac{1}{3}πr^2h
  2. Substitute known values
  3. Rearrange and solve

Finding Slant Height

  • Use Pythagoras' theorem if needed: c2=a2+b2c^2 = a^2 + b^2 to find the slant height (ll) given the radius (rr) and height (hh).